Formatting Doubles with Scientific Notation Depending on Exponent Size

Hi there. I was just wondering if there was a better way to do the following:
DecimalFormat fmt;
if (v>=1.0E9 || v<=-1.0E9 || (v>-1.0E-8 && v<1.0E-8 && v!=0.0 && v!=-0.0))
fmt = new DecimalFormat("0.########E0");
else fmt = new DecimalFormat("0.########");
return fmt.format(v);

I'm not an expert on DecimalFormat, so I may have missed something, but the only improvement I can see is to remove the v!=-0.0 check. 0.0==-0.0, so it's unnecessary.

Similar Messages

DecimalFormat bug (?) with scientific notation

Hi there,
i'm currently developing an application dealing with scientific notation of double values.
When i was curious about forcing the DecimalFormat formatter to print an explicit sign character in the exponential part, i found this strange behaviour:
Source code (example generated to show effect):
import java.text.*;
public class DecimalFormatBugTest {
public static void main(String[] arguments) {
DecimalFormat decimalFormat = new DecimalFormat("+0.00000E00");
double testValue1 = 1.23456d;
double testValue2 = 0.98765d;
System.out.println("Test 1: " + testValue1 + " --> " + decimalFormat.format(testValue1));
System.out.println("Test 2: " + testValue2 + " --> " + decimalFormat.format(testValue2));
Output:
Test 1: 1.23456 --> +1,23456E+00
Test 2: 0.98765 --> +9,87650E-+01
This is what i don't understand:
The "workaround" with the explicit "+" in front of the whole format expression is already strange, but when the exponent turns negative, i have output like "E-+00" which is completly senseless.
This output was generated using Java2 1.4.0 @ Win2k.
Thanks for your comments!
Greets, Marvin

i have no clue why thats behaving that way but i can tell u another workaroun for doing what u want...
I think u got to take that "+" sign off from the format u are giving while constructing the object DecimalFormat. Convert the result of decimalFormat.format(testValue1) into string and check for the character at 0. If its negative then prefix the result with '-' else with '+'.

Double in Scientific Notation after Marshal

Hi,
I have an element defined as an xsd:double. If I try and place a value say 100 into the element and then I marshal it I get an output of <Quantity>100.0</Quantity>... That is fine....
However, if I put a value in of say 1000000000, I get an output of <Quantity>1.0E9</Quantity> when I marshal.
Can I turn a setting on (or off) so the output does not get converted into scientific notation?
-j

I also verified the XML standard and you are right that the values are legal xsd:double values. What made this a problem for me is that the XSLT functions that use XPATH number() to process these values failed because XPATH specifies that a number is:
Number ::= Digits ( '.' Digits?)? | '.' Digits
which does not handle the exponents at all. So the XML documents produced could not be handled by XSLT processors.
For fun, I redefined my schema definition to replace xsd:double with:
<xs:simpleType name="simpleDouble">
 <xs:restriction base="xs:double">
 <xs:pattern value="(-)?[0-9]*(.[0-9]+)?" />
 </xs:restriction>
</xs:simpleType>
which is essentially a non-exponent based double. JAXB rendered the document, but then the validator complained that the output did not match the pattern. So JAXB does not use this pattern as a method of determining output, only as a method of validation.
This is why I replaced the DoubleType class for my solution. The alternative of using the jaxb:globalBindings is probably a cleaner approach. I think I'll switch my implementation. Thanks for the pointer!
-Allan

Double and scientific notation

Hi,
I am using a Double to store data but when i output it the value
is printed in scientific notation example, 2.3333E5..I want to print it as decimal without the 'E' notation, is there a way to format it or set the precision in Java???
Many Thanks

You can have a look at NumberFormat and also search this forum because it's a frequently asked question.

Converting from a double to scientific notation

does anyone know how I can convert a double value to scientific notation?

java.text.DecimalFormat can do that.

DecimalFormat issues/Scientific notation

I have 2 issues with formatting numbers with scientific notation via the DecimalFormat class
ISSUE 1: Disregard of the number of MAXIMUM FRACTOINAL DIGITS
     in the code:
                                 NumberFormat nf = NumberFormat.getInstance();
                                DecimalFormat df = (DecimalFormat)nf;
                                df.applyPattern("#00.#E0");
                                System.out.println( df.format(12345678));
                                   it printed: 12.35E6
     Why does it violate my request for one significant digit beyond the decimal
     point?. (Note, this problem
only seems to occur when when the sum of MAX integer and Max fractional
digits in my pattern is 4)
ISSUE 2:
Number of significant digits displayed:- I really just need a sanity check on this one
The 1.4.2 API for DecimalFormat states
?     The number of significant digits in the mantissa is the sum of the minimum integer and
maximum fraction digits, and is unaffected by the maximum integer digits. For example,
12345 formatted with "##0.##E0" is "12.3E3". To show all digits, set the significant digits
count to zero. The number of significant digits does not affect parsing.
I tried this ? it displays 123.45E3, or 5 significant digits? Looks like the number of significant digits
is MAX integer + MAX fractional digits in a pattern. Am I correct (and the API not correct)?
thanks
carol

Thanks. I'm assuming you're responding to issue #1. I did try it, and it worked, as expected. I never seem to have an issue when all symbols
preceding the decimal are 0. My issue, I suppose, is the inconsistency of how the formatting
works, when it comes to the number of fractional digit positions. Most of the times it 'behaves' and
only prints out the number of digits you ask, but sometimes it does not.
I've tested quite a few combinations. I'm attaching the code (in case you need help sleeping tonight).
The only 'pattern' I've noticed is that this issue only occurs when the total number of digits specified
in the pattern (before and after decimal) is 4. (exception ... if all digits specified before the decimal
are 0s, this never occurs)
I know a simple solution ... make sure I never have
a total of 4 #s and 0s in my pattern. But again, my question is why ... and/or ... does this type of
inconsistency crop up elsewhere.
import java.util.*;
import java.text.*;
public class x {
     public static void main(String [] args) {
          NumberFormat nf = NumberFormat.getInstance();
          DecimalFormat df = (DecimalFormat)nf;
          // these 3 work like I'd expect: 3 digits to the left, one to the right w/ rounding
          // signif digits = max int digits + max fractional digits
          df.applyPattern("000.#E0");
          System.out.println( df.format(12345678)); // 123.5E5
          df.applyPattern("00.#E0");
          System.out.println( df.format(12345678)); // 12.3E6
          df.applyPattern("0.#E0");
          System.out.println( df.format(12345678)); // 1.2E7
          // signif digits = TOTAL int digits + max fractional digits
     System.out.println("X");
          df.applyPattern("###.#E0");                    // how did it decide to place decimal where it did?
          System.out.println( df.format(12345678)); // 12.35E6    // why did it violate my "1 max fractional digit"
                                             // request? I would have expected 123.5E5
          df.applyPattern("##.#E0");
          System.out.println( df.format(12345678)); // 12.3E6
          df.applyPattern("#.#E0");
          System.out.println( df.format(12345678)); // 1.2E7
          //signif digits - TOTAL int digits + max fractional didgits
     System.out.println("");
     System.out.println("XXXXXXXX");
          df.applyPattern("#000.#E0");
          System.out.println( df.format(12345678)); // 1234.6E4
          df.applyPattern("#00.#E0");
          System.out.println( df.format(12345678)); // 12.35E6      // how did it decide to place decimal where it did?
                                             // why did it violate my "1 max fractional digit"
                                             // request? I would have expected 123.5E5
          df.applyPattern("#0.#E0");
          System.out.println( df.format(12345678)); // 12.3E6
          // significant digtis = TOTAL int digits + max fractional digits
     System.out.println("");
          df.applyPattern("###0.#E0");
          System.out.println( df.format(12345678)); // 1234.6E4
          df.applyPattern("##0.#E0");                    // how did it decide to place decimal where it did?
          System.out.println( df.format(12345678)); // 12.35E6     // why did it violate my "1 max fractional digit"
                                             // request? I would have expected 123.5E5
          System.out.println( df.format(12345678)); // 12.35E6
          df.applyPattern("##.#E0");
          System.out.println( df.format(12345678)); // 12.3E6
//API example from DecimaFormat RE Scientific Notation.. api says this will print 12.3E3
          df.applyPattern("###.##E0");
          System.out.println( df.format(12345)); //12.345E3   //violates max fractiona digit request
//NOTE DOCS ARE WRONG ... the number of significant digits is = to max integer digits (number of # and 0 prior
// to decimal point) PLUS max number of digits after the decimal point... NOT Min. Integer digits + Max fractional digits
          // suggested pattern
          df.applyPattern("000000.##E0");
          System.out.println( df.format(12345678)); //123456.78

Decimal Format and Scientific Notation

I am trying to print numbers in scientific notation using the Decimal Format class. What follows is a simple test program I wrote to find the bug. So far, I have not found a solution.
import java.text.*;
public class formatted {
public static void main (String Arguments[]) {
DecimalFormat form = new DecimalFormat("0.###E0");
double numb = 123456.789;
System.out.println("Nuber is: " +
form.format(numb));
The output of this program is... Nuber is: 123456E
The output is the same if numb is an int, float, or double. If I format the number as "#####.0" or "#####.00" the output is correct. I think that I am following the rules for formatting a number in scientific notation as the process is outlined in the documentation (provided below).
***** From Decimal Format under Scientific Notation ***
Numbers in scientific notation are expressed as the product of a mantissa and a power of ten, for
example, 1234 can be expressed as 1.234 x 10^3. The mantissa is often in the range 1.0 <= x < 10.0,
but it need not be. DecimalFormat can be instructed to format and parse scientific notation only via a
pattern; there is currently no factory method that creates a scientific notation format. In a pattern,
the exponent character immediately followed by one or more digit characters indicates scientific
notation. Example: "0.###E0" formats the number 1234 as "1.234E3".
Anyone understand how the short program is incorrectly written?
Marc

The problem is
format = "0.###E0"
input number = 123456.789
output = 123456E (not scientific notation!)
This is not scientific notation at all. There is no decimal point given and no value in the exponent.
I understand entirely that by adding more #'es will provide more precision. The bug I have is the output is not printed in the scientific format; other formats work.
MArc

Calculator.app Version 4.5.3 (99.2) and Scientific Notation

I want to enter a number with scientific notation.
2.71e1 doesn't return 27.1, but rather 0.999...
It seems that Calculator.app is dividing by e.
This is not a common operation.
2.71E1 gives 27.1great! But ...
2.71E-1 does not return 0.271 neither does
2.71E(-1)
I have yet to figure out how to use negative exponents in Scientific notation.
This seems to be a bug in Calculator.app Version 4.5.3 (99.2)

All my spaces were deleted.
Take two.
My input ======= Calculator
2 ============ 2
2. ============ 2.
2.7 =========== 2.7
2.7E ========== 2.7 E 0
2.7E- ========== 2.7 (and the small - subscript indicating a negative number)
2.7E-1 ========= 1 (and the small - subscript indicating a negative number)
Now hitting enter === 1.7 (it appears to have subtracted 1 from 2.7)
Do our version of Calculator match?
Thanks for being interested.

Create an NSString for number in scientific notation from double?

Hi
Given a double, I want to create a string in scientific notation.
e.g for a double with a value of 123.456, I want the NSString to be "1.23456e+2" for entering in to a UITextField.
I've looked through the docs but can't find a formatter. (There is mention of "%a" being scientific format, but it produces hex output.)
Thanks for any clues.
Steve

Here, you should find what you are looking for:
http://developer.apple.com/mac/library/documentation/Cocoa/Conceptual/Strings/Ar ticles/FormatStrings.html#//apple_ref/doc/uid/20000943
http://developer.apple.com/mac/library/documentation/Cocoa/Conceptual/Strings/Ar ticles/FormatStrings.html#//apple_ref/doc/uid/20000943
http://developer.apple.com/mac/library/documentation/Cocoa/Reference/Foundation/ Classes/NSStringClass/Reference/NSString.html#//appleref/occ/clm/NSString/stringWithFormat:

External table.How to load numbers (decimal and scientific notation format)

Hi all, I need to load inside an external table records that contain 7 fields. The last field is called AMOUNT and it's represented in some records with the decimal format, in others records with the scientific notation format as, for example, below:
CY001_STATU;2009;Jan;11220020GR;'03900;CYZ900;-9,99999999839929e-03
CY001_STATU;2009;Jan;11200100;'60800;CYZ900;41380,77
The External table's script is the following:
CREATE TABLE HYP_DATA
COUNTRY VARCHAR2(50 BYTE),
YEAR VARCHAR2(20 BYTE),
PERIOD VARCHAR2(20 BYTE),
ACCOUNT VARCHAR2(50 BYTE),
DEPT VARCHAR2(20 BYTE),
ACTIVITY_LOC VARCHAR2(20 BYTE),
AMOUNT VARCHAR2(50 BYTE)
ORGANIZATION EXTERNAL
( TYPE ORACLE_LOADER
DEFAULT DIRECTORY HYP_DATA_DIR
ACCESS PARAMETERS
( RECORDS DELIMITED BY NEWLINE
BADFILE 'HYP_BAD_DIR':'HYP_LOAD.bad'
DISCARDFILE 'HYP_DISCARD_DIR':'HYP_LOAD.dsc'
LOGFILE 'HYP_LOG_DIR':'HYP_LOAD.log'
SKIP 0
FIELDS TERMINATED BY ";"
MISSING FIELD VALUES ARE NULL
REJECT ROWS WITH ALL NULL FIELDS
"COUNTRY" Char,
"YEAR" Char,
"PERIOD" Char,
"ACCOUNT" Char,
"DEPT" Char,
"ACTIVITY_LOC" Char,
"AMOUNT" Char
LOCATION (HYP_DATA_DIR:'Total.txt')
REJECT LIMIT UNLIMITED
NOPARALLEL
NOMONITORING;
If, for the field AMOUNT I use the datatype VARCHAR (as above), the table is loaded but I have some records rejected, and all these records contain the last field AMOUNT with the scientific notation as:
CY001_STATU;2009;Jan;11220020GR;'03900;CYZ900;-9,99999999839929e-03
CY001_STATU;2009;Feb;11220020GR;'03900;CYZ900;-9,99999999839929e-03
CY001_STATU;2009;Mar;11220020GR;'03900;CYZ900;-9,99999999839929e-03
CY001_STATU;2009;Dec;11220020GR;'03900;CYZ900;-9,99999999839929e-03
All the others records with a decimal AMOUNT are loaded correctly.
So, my problem is that I NEED to load all the records (with the decimal and the scientific notation format) together (without records rejected), but I don't know which datatype I have to use for the AMOUNT field....
Anybody has any idea ???
Any help would be appreciated
Thanks in advance
Alex

@OP,
What version of Oracle are you using?
Just cut'n'paste of you script and example woked FINE for me.
however my quation is... An external table will LOAD all data or none at all. How are you validating/concluding that...
I have some records rejected, and all these records contain the last field AMOUNT with the scientific notation
select * from v$version where rownum <2;
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
select * from mydata;
CY001_STATU 2009 Jan 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Feb 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Jan 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Jan 11200100 '60800 CYZ900 41380,77
CY001_STATU 2009 Mar 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Dec 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Jan 11220020GR '03900 CYZ900 -9,99999999839929e-03
CY001_STATU 2009 Jan 11200100 '60800 CYZ900 41380,77MYDATA table script is...
drop table mydata;
CREATE TABLE mydata
COUNTRY VARCHAR2(50 BYTE),
YEAR VARCHAR2(20 BYTE),
PERIOD VARCHAR2(20 BYTE),
ACCOUNT VARCHAR2(50 BYTE),
DEPT VARCHAR2(20 BYTE),
ACTIVITY_LOC VARCHAR2(20 BYTE),
AMOUNT VARCHAR2(50 BYTE)
ORGANIZATION EXTERNAL
( TYPE ORACLE_LOADER
DEFAULT DIRECTORY IN_DIR
ACCESS PARAMETERS
( RECORDS DELIMITED BY NEWLINE
BADFILE 'IN_DIR':'HYP_LOAD.bad'
DISCARDFILE 'IN_DIR':'HYP_LOAD.dsc'
LOGFILE 'IN_DIR':'HYP_LOAD.log'
SKIP 0
FIELDS TERMINATED BY ";"
MISSING FIELD VALUES ARE NULL
REJECT ROWS WITH ALL NULL FIELDS
"COUNTRY" Char,
"YEAR" Char,
"PERIOD" Char,
"ACCOUNT" Char,
"DEPT" Char,
"ACTIVITY_LOC" Char,
"AMOUNT" Char
LOCATION (IN_DIR:'total.txt')
REJECT LIMIT UNLIMITED
NOPARALLEL
NOMONITORING;vr,
Sudhakar B.

Importing data in scientific notation format

Hi,
I've got some data files produced by some ancient laboratory software. In the files, numbers are formatted like this:
+7.60609E-02
+8.18901E-03
etc.
When I import the data into Numbers, Numbers does not seem to recognize that the data points represent numbers, rather than strings (I can't create plots from the data, for example). If I edit the cells to prepend "=" to the entry, then Numbers evaluates the entry as if it were scientific notation (which is what I want), so that +7.60609E-02 becomes 0.760609. Is there a way to indicate to Numbers that the data I am importing is in scientific notation format, and should be treated as such? Because I'm not too excited about manually prepending "=" to everything.
Thanks

If the file is a comma separated values file, you have two choices:
1) Make a Numbers sheet that is formatted the way you want it, including formatting the cells in the column to be scientific. Drag the file from Finder and drop it on cell A1 of the table or, if not A1, the top-left cell of where you wantthe data to begin in the table, like maybe cell B2. Or,
2) Open the CSV file with Numbers. After import, select the column of numbers and format it as scientific.

Double.parseDouble(String) - problems when string is in scientific notation

Hello guys,
I'm doing some numerical calculations and I wonder whether it is possible for Double.parseDouble(String) to parse string in the scientific notation i.e. 1.0824234234E-10. Is it the notation itself causing the exception : NumberFormatException or the number is just too big/small and double can't hold it ?
If it's just the notation how can I fix it ?
Regards

i'm not quite sure whether double odoes not allow it.
perhaps consider the api Double.valueOf() and the testing code provided; reproduced below:To avoid calling this method on a invalid string and having a NumberFormatException be thrown, the regular expression below can be used to screen the input string:
        final String Digits     = "(\\p{Digit}+)";
final String HexDigits = "(\\p{XDigit}+)";
        // an exponent is 'e' or 'E' followed by an optionally
        // signed decimal integer.
        final String Exp        = "[eE][+-]?"+Digits;
        final String fpRegex    =
            ("[\\x00-\\x20]*"+ // Optional leading "whitespace"
             "[+-]?(" + // Optional sign character
             "NaN|" +           // "NaN" string
             "Infinity|" +      // "Infinity" string
             // A decimal floating-point string representing a finite positive
             // number without a leading sign has at most five basic pieces:
             // Digits . Digits ExponentPart FloatTypeSuffix
             // Since this method allows integer-only strings as input
             // in addition to strings of floating-point literals, the
             // two sub-patterns below are simplifications of the grammar
             // productions from the Java Language Specification, 2nd
             // edition, section 3.10.2.
             // Digits ._opt Digits_opt ExponentPart_opt FloatTypeSuffix_opt
             "((("+Digits+"(\\.)?("+Digits+"?)("+Exp+")?)|"+
             // . Digits ExponentPart_opt FloatTypeSuffix_opt
             "(\\.("+Digits+")("+Exp+")?)|"+
       // Hexadecimal strings
       "((" +
        // 0[xX] HexDigits ._opt BinaryExponent FloatTypeSuffix_opt
        "(0[xX]" + HexDigits + "(\\.)?)|" +
        // 0[xX] HexDigits_opt . HexDigits BinaryExponent FloatTypeSuffix_opt
        "(0[xX]" + HexDigits + "?(\\.)" + HexDigits + ")" +
        ")[pP][+-]?" + Digits + "))" +
             "[fFdD]?))" +
             "[\\x00-\\x20]*");// Optional trailing "whitespace"
if (Pattern.matches(fpRegex, myString))
            Double.valueOf(myString); // Will not throw NumberFormatException
        else {
            // Perform suitable alternative action
http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Double.html

Formating scientific notation

Hi,
I'm working with a small program where at one point a number, in scientific notation will need to be formated into a string containing plane numbers.
I use the code below, and it works in up to large numbers where the formatting doesen't do aything at all.
String InputValue = "7,584995286E7";
NumberFormat format = NumberFormat.getNumberInstance();
Number number = format.parse(InputValue);
String OutputValue = number.toString();
System.out.println(OutputValue);The example above gives the result input back as output value: 7.584995286E7
With the value 7,584995286E6 the result is: 7584995.286 just as I want it to work.
What can I do to solve this?
All help is appreciated.
Thanks
/H�kan

Hi ,
Below is the code posted by you.
String InputValue = "7,584995286E7";
NumberFormat format = NumberFormat.getNumberInstance();
Number number = format.parse(InputValue);
String OutputValue = number.toString();
System.out.println(OutputValue);Add these two methods, and you will get the code working as you needed.
format .setMaximumFractionDigits(3)
format .setMinimumFractionDigits(3);
Best regards
Aneesh A.V

Powershell / Scientific Notation Woes / Formatting Output to Live Excel Sheet

I have a WMI query in a script that dumps machine information to a live excel sheet.
I find when I query the model # of the machine using (this line of code from the script):
$Sheet.Cells.Item($count,4) = (Get-WmiObject win32_computersystem -ComputerName $computer).Model
The output almost always changes into Scientific Notation, because this is a typical model number : "3500-E52"
Is there a way to modify the formatting of the:
$Sheet.Cells.Item($count,4)
so that Excel uses "text" formatting for that cell? I know you can change the fonts etc... but have not been lucky in finding a powershell > excel reference
that explains how to change a cell or column's formatting beyond the basics.
I have seen recommendations to others to dump the results queries to a CSV first, and then import into Excel (which would allow a manual change of that column's format). I'm just
hoping to bypass the extra "hands on" and format more directly to a sheet in Excel.
If .csv is the best way to go, I'll muddle through it and change the code.
Any help is greatly appreciated.
Ben

$sheet.Cells(1,1).NumberFormat
= "@"
¯\_(ツ)_/¯

How do I get System.out.format to print out doubles with the same precision

Using the System.out.format, how do I print out the value of a double such that it looks exactly like it does if it were print from a System.out.println.
For example, take the following code:
double d = 12.48564734342343;
System.out.format("d as format: %f\n", d);
System.out.println("d as sout: " + d);Running the code, I get:

d as format: 12.485647
d as sout: 12.48564734342343

The precision of d has been lost.
I could bump up the precision as follows:
double d = 12.48564734342343;
System.out.format("d as format: %.14f\n", d);
System.out.println("d as sout: " + d);That appears to work, I get:

d as format: 12.48564734342343
d as sout: 12.48564734342343

However, that solution fails if d has a different precision, say 12.48. In that case I get:

d as format: 12.48000000000000
d as sout: 12.48

So how do I get System.out.format to print out doubles with the same precision as System.out.println?
Thanks..

YoungWinston wrote:
Schmoe wrote:
Interesting, but this is not what I am looking for...Your original question was "how do I print out the value of a double such that it looks exactly like it does if it were print from a System.out.println", and you've been told how to do that (although the pattern given by sabre may be a bit excessive - you should only need 15 '#'s).The initial phrase from my question was "Using the System.out.format, how do I..".
It's worth remembering that, unlike the Format hierarchy, 'format()' is NOT native to Java. It's a convenience implementation of the 'printf()' and 'sprintf()' methods provided in C, and first appeared in Java 1.5. Those methods were designed to produced fixed-format output; 'println()' was not.Perhaps it is the case that this can't be done.
Furthermore, Double.toString(), which is what is used by println() does not produce the same format in all cases; format("%.14f\n", d) does. TrySystem.out.println(1.8236473845783d);
System.out.println(1823647384.5783d);and you'll see what I mean.I am fine with that. It still displays all the precision.
I am simply looking for a way to quickly print out multiple variables on a sysout while debugging. I want it as syntactically sweet as possible. System.out.println can be a pain when outputting multiple variables like the following:
"System.out.println("a: " + a + "; b:" + b + "; c: " + c);"
For some reason, my fingers always typo the plus key.
I was hoping that System.out.format would be easier,along the lines of:
"System.out.format("a: %f, b: %f, c: %f\n", a, b, c);"
From a syntactical sweetness point of view, it is easier. However, the %f on doubles truncates the precision. I figured there must be a way to get the full precision.
DecimalFormat is syntactically sour for this purpose, as you need to instantiate the DecimalFormat.
fwiw I have enjoyed reading the suggestions in this thread...

Formatting Doubles with Scientific Notation Depending on Exponent Size

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