FRM-40602: Cannot insert into or update data in a view

Hi all!
I have a form based on a view and I want to get rid off this message.
I set the properties blocks query only but it still doesn't work.
Does someone met with this situation?
Many thanks!

Hello
I've just been messing about with a similar problem. Basically, I have a view that involves a join across two tables, I have a data block in my form that's based on the view, and I've written an INSTEAD OF trigger to insert/update/delete from the two tables.
I was getting the error message 'Cannot insert or update data in a view', and it turned out that the error was happening because the join column between the two tables was the primary key on one of the tables, but the corresponding column on the join table had no unique key on it. This meant that Oracle couldn't establish a one-to-one relationship between rows in the view and rows in the underlying tables. The column on the join table was in fact unique on that table, and adding a unique constraint on that column in the database cured the problem.
Hope that's of use.
regards
Andrew
UK

Similar Messages

Cannot find symbl method update Date(int,java.util.Date)

I get following error
cannot find symbl method update Date(int,java.util.Date) on compling class called GuestDataBean at line ( rowSet.updateDate( 4, guest.getDate() ); ).
GustBean.java. I need help on why I get it.
// JavaBean to store data for a guest in the guest book.
package com.deitel.jhtp6.jsp.beans;
import java.util.*;
public class GuestBean
   private String firstName;
   private String lastName;
   private String email;
   private Date date;
   private String message;
   //Constructors
   public GuestBean(){
        public GuestBean(String firstname, String lastname, String email,Date date,String message){
             this.firstName=firstname;
             this.lastName=lastName;
             this.email=email;
             this.date=date;
             this.message=message;
   // set the guest's first name
   public void setFirstName( String name )
      firstName = name;
   } // end method setFirstName
   // get the guest's first name
   public String getFirstName()
      return firstName;
   } // end method getFirstName
   // set the guest's last name
   public void setLastName( String name )
      lastName = name;
   } // end method setLastName
   // get the guest's last name
   public String getLastName()
      return lastName;
   } // end method getLastName
   // set the guest's email address
   public void setEmail( String address )
      email = address;
   } // end method setEmail
   // get the guest's email address
   public String getEmail()
      return email;
   } // end method getEmail
   public void setMessage( String mess)
      message = mess;
   } // end method setEmail
   // get the guest's email address
   public String getMessage()
      return message;
   } // end method getEmail
   public void setDate( Date dat )
      date = dat;
   } // end method setEmail
   // get the guest's email address
   public Date getDate()
      return date;
   } // end method getEmail
} // end class GuestBean
GuestDataBean.java/**
* @(#)GuestDataBean.java
* @author
* @version 1.00 2008/7/18
// Class GuestDataBean makes a database connection and supports
// inserting and retrieving data from the database.
package com.deitel.jhtp6.jsp.beans;
import java.sql.SQLException;
import javax.sql.rowset.CachedRowSet;
import java.util.ArrayList;
import com.sun.rowset.CachedRowSetImpl; // CachedRowSet implementation
import java.sql.*;
public class GuestDataBean
   private CachedRowSet rowSet;
   // construct TitlesBean object
   public GuestDataBean() throws Exception
      // load the MySQL driver
      Class.forName( "org.gjt.mm.mysql.Driver" );
      // specify properties of CachedRowSet
      rowSet = new CachedRowSetImpl();
      rowSet.setUrl( "jdbc:mysql://localhost:3306/virsarmedia" );
      rowSet.setUsername( "root" );
      rowSet.setPassword( "" );
       // obtain list of titles
      rowSet.setCommand(
         "SELECT firstName, lastName, email,date,message FROM guest" );
      rowSet.execute();
   } // end GuestDataBean constructor
   // return an ArrayList of GuestBeans
   public ArrayList< GuestBean > getGuestList() throws SQLException
      ArrayList< GuestBean > guestList = new ArrayList< GuestBean >();
      rowSet.beforeFirst(); // move cursor before the first row
      // get row data
      while ( rowSet.next() )
         GuestBean guest = new GuestBean();
         guest.setFirstName( rowSet.getString( 1 ) );
         guest.setLastName( rowSet.getString( 2 ) );
         guest.setEmail( rowSet.getString( 3 ) );
         guest.setDate( rowSet.getDate( 4 ) );
         guest.setMessage( rowSet.getString( 5 ) );
         guestList.add( guest );
      } // end while
      return guestList;
   } // end method getGuestList
   // insert a guest in guestbook database
   public void addGuest( GuestBean guest ) throws SQLException
      rowSet.moveToInsertRow(); // move cursor to the insert row
      // update the three columns of the insert row
      rowSet.updateString( 1, guest.getFirstName() );
      rowSet.updateString( 2, guest.getLastName() );
      rowSet.updateString( 3, guest.getEmail() );
      rowSet.updateDate( 4, guest.getDate() );
      rowSet.updateString( 5, guest.getMessage() );
      rowSet.insertRow(); // insert row to rowSet
      rowSet.moveToCurrentRow(); // move cursor to the current row
      rowSet.commit(); // propagate changes to database
   } // end method addGuest
} // end class GuestDataBean

This isn't a JSP question, it better belongs in the JavaProgramming, or JDBC forums.
But the problem is because the updateDate method uses a java.sql.Date object and you are giving it a java.util.Date object. You have to convert from java.util.Date to java.sql.Date. See: [the api for java.sql.Date|http://java.sun.com/javase/6/docs/api/java/sql/Date.html] .
Edited by: stevejluke on Jul 21, 2008 5:43 PM

A trigger that changes an insert into an update?

This is probably a quite unusual question, but is it possible to create a trigger that changes an insert into an update?
So, if someone tries to do something like this:
INSERT INTO SOME_TABLE (column1, column2, column3) VALUES (value1, value2, value3);
...the trigger is able to change it into:
UPDATE SOME_TABLE column1=value1, column2=value2, column3=value3 WHERE ID=1;
Can it be done?

Hi,
You can do things like that in an INSTEAD OF INSERT trigger.
See the PL/SQL manual for details:
http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28370/create_trigger.htm#sthref2864
INSTEAD of triggers only work on views. Of course, you can create a view as "SELECT * FROM some_table" just so you can use an INSTEAD OF trigger.

Update data from a view

Hi,
trying to update data from a view with:
- Company (table)
- Products (table)
In a form, the user wants to update
e.g: both products.product_name and Company.company_name.
Is there a way to update a view records built on 2 tables ?
Any idea will be really appreciated
Thks

An other question on INSTEAD OF Trigger:
Base Tables:
1.
SQL> desc pcs_companies;
Name Null? Type
COMPANY_ID NOT NULL NUMBER(12)
COUNTRY VARCHAR2(350)
COMPANY_NAME VARCHAR2(320)
COMPANY_PHONE VARCHAR2 (320)
COMPANY_FAX VARCHAR2(320)
COMPANY_URL VARCHAR2(150)
UPDATED_DATE DATE
2.
SQL> desc pcs_individuals;
Name Null? Type
INDIVIDUAL_ID NOT NULL NUMBER(12)
COMPANY_ID NUMBER(12)
FIRST_NAME VARCHAR2(320)
LAST_NAME VARCHAR2(320)
LOB VARCHAR2(300)
JOB_ROLE VARCHAR2(300)
TITLE VARCHAR2(300)
GENDER VARCHAR2(3)
EMAIL VARCHAR2(720)
FAX VARCHAR2(720)
PHONE_NO VARCHAR2(720)
UPDATED_DATE DATE
COUNTRY VARCHAR2(150)
ADDRESS_1 VARCHAR2(720)
ADDRESS_2 VARCHAR2(720)
ADDRESS_3 VARCHAR2(720)
CITY VARCHAR2(720)
3. pcs_individuals.COMPANY_ID = FK, ref pcs_companies.
4.
SQL> CREATE VIEW V_PCS_COMPANY_IND
AS
SELECT
   i.INDIVIDUAL_ID,
   c.company_id,
   c.country,
   c.Company_name,
   c.company_phone,
   i.Company_id indiv_company_id,
   i.gender,
   i.first_name,
   i.last_name,
   i.lob,
   i.job_role,
   i.title,
   i.email_address,
   i.fax,
   i.phone_no ,
   i.address_1,
   i.address_2,
   i.address_3,
   i.city
FROM
  pcs_individuals i,
  pcs_companies c
WHERE
  i.company_id = c.company_id
5.
CREATE OR REPLACE TRIGGER PCS_ADMIN.PCS_COMP_IND_UPDATE_TR
INSTEAD OF UPDATE ON PCMS_ADMIN.V_PCS_COMPANY_IND
FOR EACH ROW
begin
update PCS_COMPANIES
set
     Company_name = nvl(:new.company_name,company_name),
     company_phone = nvl(:new.company_phone,company_phone)
where company_id = :new.company_id;
update PCS_INDIVIDUALS
set
     gender = nvl(:new.gender,gender),
first_name = nvl(:new.first_name,first_name),
     last_name = nvl(:new.last_name,last_name),
     lob = nvl(:new.lob,lob),
     title = nvl(:new.title,title),
     email_address = nvl(:new.email_address,email_address),
phone_no = nvl(:new.phone_no,phone_no),
     fax = nvl(:new.fax,fax),
     country = nvl(:new.country,country),
     address_1 = nvl(:new.address_1,address_1),
     address_2 = nvl(:new.address_2,address_2),
     address_3 = nvl(:new.address_3,address_3),
     city = nvl(:new.city,city)
where company_id = :new.company_id;
end PCMS_COMP_IND_UPDATE_TR;
6.
CREATE OR REPLACE TRIGGER PCS_ADMIN.NEW_COMPANY_ID_INSERT
INSTEAD OF INSERT ON PCS_ADMIN.V_PCS_COMPANY_IND
DECLARE
ID number;
BEGIN
INSERT INTO pcs_companies (org_id)
select v_pcs_comp_id_seq.nextval
into ID
from dual;
:new.company_id = ID;
INSERT INTO pcs_individuals (company_id)
select v_pcs_comp_id_seq.nextval
into ID
from dual;
:new.company_id = ID;
end;
My question
On point 6:
Assumption:
- Company_id is PK of pcs.Company and FK in pcs.individuals
- It should be feed by sequence (v_pcs_comp_id_seq)
Now how can i insert the same value for company_id (current.v_pcs_comp_id_seq) in both pcs_companies and pcs_individuals ? I've tested it in the above INSTEAD OF Trigger.It failed.
Thks for any advice,
lamine

HT1399 I have an ipod shuffle 4, my playlist is in alphabetical order on my itunes, when I go to add it to my ipod it puts it into order of "date added", under "View" i can change it, but when I sync it, it immediately reverts back?!!

I have an ipod shuffle 4, my playlist is in alphabetical order on my itunes, when I go to add it to my ipod it puts it into order of "date added", under "View" i can change it, but when I sync it, it immediately reverts back?!!

Yeah - not really. Sorry - but you will need to get it fixed so you can back it up. You are going to want to Restore your new iPhone from that backup when you get it, so it will really be worth it.
As soon as you get your new iPhone, set up automatic iCloud backups, or if you don't have Wifi, then it is really important to get into the habit of backing your device up weekly to iTunes.
Best of luck!
GB

Cannot insert into database

Can any body help plzzzzzzzzzzzzzzzz,
I establish a connection using connection pooling as given in netbeans
helps.With that ican retrieve data from database but cant insert into it.While inserting only null values ere entered into database.why?
please somebody help

My Jsp page userRegistration.jsp
<%@page contentType="text/html"%>
<%@page pageEncoding="UTF-8"%>
<%@ taglib uri="/WEB-INF/struts-html.tld" prefix="html"%>
<%@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean"%>
<%@taglib prefix="c"uri="http://java.sun.com/jsp/jstl/core"%>
<%@taglib prefix="sql" uri="http://java.sun.com/jsp/jstl/sql"%>
<%@ page import="java.sql.*" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
   "http://www.w3.org/TR/html4/loose.dtd">
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>JSP Page</title>
        </head>
    <body>
<html:errors/>
    <table>
<html:form action="reg.do"method="post" >
<tr>
<td>
firstname<html:text property="firstName" />
</td>
</tr>
<tr>
<td>
lastname<html:text property="lastName" />
</td>
</tr>
<tr>
<td>
username<html:text property="userName" />
</td>
</tr>
<tr><td>
email<html:text property="email" />
</td>
</tr>
<tr>
<td>
phone<html:text property="phone" />
</td>
</tr>
<tr>
<td>
fax<html:text property="fax" />
</td>
</tr>
<tr>
<td>
password<html:password property="password" />
</td>
</tr>
<tr><td>
passwordcheck<html:password property="passwordCheck" />
</td>
</tr>
<tr>
<td>
<html:submit />
</td>
<td>
<html:cancel />
</td>
</tr>
</table>
</html:form>
</body>
</html>
my struts action
package action;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.ActionForward;
import javax.servlet.http.HttpSession;
public class reg extends Action {
     private String firstName;
    private String lastName;
    private String userName;
           private String email;
           private String phone;
           private String fax;
           private String password;
           private String passwordCheck;
    /* forward name="success" path="" */
    private final static String SUCCESS = "success";
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            HttpServletRequest request, HttpServletResponse response)
            throws Exception {
        response.sendRedirect("complete.jsp");
        return mapping.findForward(getSUCCESS());
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        return firstName;
    public void setFirstName(String firstName) {
        this.firstName = firstName;
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        return lastName;
    public void setLastName(String lastName) {
        this.lastName = lastName;
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        return userName;
    public void setUserName(String userName) {
        this.userName = userName;
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        return email;
    public void setEmail(String email) {
        this.email = email;
    public String getPhone() {
        return phone;
    public void setPhone(String phone) {
        this.phone = phone;
    public String getFax() {
        return fax;
    public void setFax(String fax) {
        this.fax = fax;
    public String getPassword() {
        return password;
    public void setPassword(String password) {
        this.password = password;
    public String getPasswordCheck() {
        return passwordCheck;
    public void setPasswordCheck(String passwordCheck) {
        this.passwordCheck = passwordCheck;
    public static String getSUCCESS() {
        return SUCCESS;
    private javax.sql.DataSource getHima() throws javax.naming.NamingException {
        javax.naming.Context c = new javax.naming.InitialContext();
        return (javax.sql.DataSource) c.lookup("java:comp/env/jdbc/hima");
my complete.jsp where insertion happens
<%@page contentType="text/html"%>
<%@page pageEncoding="UTF-8"%>
<%@ taglib uri="/WEB-INF/struts-html.tld" prefix="html"%>
<%@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean"%>
<%@taglib prefix="c"uri="http://java.sun.com/jsp/jstl/core"%>
<%@taglib prefix="sql" uri="http://java.sun.com/jsp/jstl/sql"%>
<%@ page import="java.sql.*" %>
String firstName=("firstName");
String lastName = getInitParameter("lastName");
String userName = getInitParameter("userName");
String email= getInitParameter("email");
String phone = getInitParameter("phone");
String fax = getInitParameter("fax");
String password = getInitParameter("password");
String passwordCheck = getInitParameter("passwordCheck");
<%
       String firstName=(String)request.getAttribute("firstName");
       request.getSession().setAttribute("firstName",firstName);
%>
<sql:query var="queryresults" dataSource="jdbc/hima">
        select phone from user
        </sql:query>
<sql:update var="resultset" dataSource="jdbc/hima">
            INSERT INTO user1 (firstName,lastName,userName,email,phone,fax,password,passwordCheck)
            VALUES(firstName,lastName,userName,email,phone,fax,password,passwordCheck)
        </sql:update>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
   "http://www.w3.org/TR/html4/loose.dtd">
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    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>JSP Page</title>
    </head>
    <body>
<form action="comp"></form>
    <h1>JSP Page</h1>
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    <tr>
    <th>first</th>
    </tr>
    <c:forEach var="row" items="${queryresults.rows}">
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        <td><c:out value="${row.phone}"/></td>
        </tr>
    </c:forEach>
</table>
    </body>
</html>

Can select, but cannot insert into oracle tables using php.

I am having trouble inserting data into a tables in oracle using PHP. I can insert into the tables using baninst1, but nothing else. I can't even insert using the tables' owner. Every time I try I get the ORA-00492 error of table or view does not exist. However, I can run a select statement just fine. So far, baninst1 is the only user that can actually do inserts. I've triple checked all the table grants and everything is fine. Also, I can copy/paste the exact insert statement into SQL*Plus and it works with the correct user. It doesn't have to be baninst1. I've tried everything I can think of. I've tried putting the table name in quotes, adding the schema name to the table, checking public synonyms, but everything appears to be ok. I would greatly appreciate any suggestions others may have.
I'm using PHP 5.2.3 with an oracle 9i DB.

Here is the code that doesn't work. It works only with baninst1, no other username will work and all I do is change the my_username/my_password to something different. This is one example function where I try to do an insert, but it doesn't work on any of the tables I try.
Thanks for looking.
class Oracle {
     private $oracleUser = "my_username";
     private $oraclePassword = "my_password";
     private $oracleDB = "MY_DB";
     private $c = null;
     function Connect() {
          if ( !($this->c = ocilogon( $this->oracleUser, $this->oraclePassword, $this->oracleDB ) ) )
               return false;
          return true;
     function AddNewTest($testName, $course, $section, $term, $maxAttempts, $length, $startDate, $startTime, $endDate, $endTime)
          $result = "";
          if( $this->c == null )
               $this->Connect();
          $splitIndex = strpos($course, " ");
          $subjectCode = substr($course, 0, $splitIndex);
          $courseNumber = substr($course, $splitIndex + 1);
          $insertStatment = "insert into szbtestinfo(szbtestinfo_test_name,
                                                            szbtestinfo_course_numb,
                                                       szbtestinfo_section,
                                                            szbtestinfo_max_attempts,
                                                            szbtestinfo_length_minutes,
                                                            szbtestinfo_start,
                                                            szbtestinfo_end,
                                                            szbtestinfo_id,
                                                            szbtestinfo_subj_code,
                                                            szbtestinfo_eff_term)
                                                            values( '" . $testName .
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               "', '" . $section .
               "', " . $maxAttempts .
               ", " . $length .
               ", to_date('" . $startDate . " " . $startTime . "', 'MM/DD/YYYY HH24:MI')" .
               ", to_date('" . $endDate . " " . $endTime . "', 'MM/DD/YYYY HH24:MI')" .
               ", szsnexttest.nextval" .
               ", '" . $subjectCode .
               "', '" . $term . "')";
          //return $insertStatment;
          $s = OCIParse($this->c, $insertStatment);
          try
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          catch(exception $e)
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JSP cannot Insert into MYSQL

hi, i have a jsp code which can successfully return results from MySQL database. But once i change the SQL statement from a select statement to a insert statement, it does not add in a new row in the database. It has no error while compiling but it also appear nothing on the screen when being run. Has the problem got to do with the user privilages of MySQL? thanks.
//jsp file which parameter posted from another html file. Parameter has been successfully passed.
<%@ page import="java.sql.*"%>
<body>
<%
     String file = request.getParameter("file");
     String pic = request.getParameter("pic");
     ResultSet rs = null;
     ResultSet rs2 = null;
     String timestamp = "CURRENT_TIMESTAMP()";
     String q2 = "Select * from fileReqAce";
     String q1 = "INSERT INTO fileReqAce(PIC,FileName,DateReq) VALUES('"+pic+"','"+file+"',CURRENT_Timestamp())";
try{
     Class.forName("com.mysql.jdbc.Driver").newInstance();
     Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/wendy?user=user;password=password");
Statement state = con.createStatement();
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     rs = state.executeQuery(q1);
     //Statement state2 = con.createStatement();
     /**rs2 = state2.executeQuery(q2);
     %><br>
     <table border="1"><%
     while(rs2.next()){
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     <tr>
     <td>Request by : <%=rs2.getString("PIC")%></td><td>File Reference : <%=rs2.getString("FileName")%></td><td>Time Requested : <%=rs2.getTimestamp("DateReq")%></td>
     </tr>
     <%
     %></table>
<%**/
     rs.close();
//     rs2.close();
     con.close();
     catch(Exception e)
     System.err.println("Unable to load driver");
     e.printStackTrace();
%>
</body>

That all might be good and well but I think the very important thing to note here is what the first reply stated.
If you are going to run an Insert sql statement you need to use the executeUpdate() method. You also use this function for Updates and Delete SQL statements.
Only Select statements that return a recordset use the executeQuery() method. The executeUpdate() method returns an interger that reflects the number of rows affected by the SQL statement.
Like when you insert 1 row the return value of the executeUpdate method will be one. You can accordingly check this returned value to see if the operation ran successfully. A return value of 0 means that now rows where inserted.
That is my 2c worth. I hope it helped some.

Urgent : Performance Issue DELETE , INSERT INTO SELECT, UPDATE

Hi,
NEED ASSISTANCE TO OPTIMIZE THE INSERT STATEMENT (insert into select):
=================================================
We have a report.
As per current design following steps are used to populate the custom table whcih is used for reporting purpose:
1) DELETE all the recods from the custom table XXX_TEMP_REP.
2) INSERT records in custom table XXX_TEMP_REP (Assume all the records related to type A)
using
INSERT..... INTO..... SELECT.....
statement.
3) Update records in XXX_TEMP_REP
using some custom logic for the records populated .
4) INSERT records in custom table XXX_TEMP_REP (Records related to type B)
using
INSERT..... INTO..... SELECT.....
statement.
Stats gathered related to Insert statement are:
Event Wait Information
SID 460 is waiting on event : db file sequential read
P1 Text : file#
P1 Value : 20
P2 Text : block#
P2 Value : 435039
P3 Text : blocks
P3 Value : 1
Session Statistics
redo size : 293.84 M
parse count (hard) : 34
parse count (total) : 1217
user commits : 3
Transaction and Rollback Information
Rollback Used : 35.1796875 M
Rollback Records : 355886
Rollback Segment Number : 12
Rollback Segment Name : _SYSSMU12$
Logical IOs : 1627182
Physical IOs : 136409
RBS Startng Extent ID : 14
Transaction Start Time : 09/29/10 04:22:11
Transaction_Status : ACTIVE
Please suggest how this can be optimized.
Regards,
Narender

Hello,
Is there any relation with the Oracle Forms tool ?
Francois

Want to update data in a view based on multiple tables

Hi
I am facing a problem i want to update data in tables using a view. As that view is based on multiple tables so i am unable to update data. i came to know we can update table from view only if view is based on single table. so if anyone knows any alternative please let me know.
Thanx
Devinder

Devinder,
The table can be updated through a view based on multiple tables, if and only if the table is a "key preserved" table. Rather than explaining myself, i avoided the burden of typing by finding the material in Oracle Docs and pasting it for you :-)
If you want a join view to be updatable, all of the following conditions must be
true:
1. The DML statement must affect only one table underlying the join.
2. For an INSERT statement, the view must not be created WITH CHECK
OPTION, and all columns into which values are inserted must come from a
key-preserved table. A key-preserved table in one for which every primary
key or unique key value in the base table is also unique in the join view.
3. For an UPDATE statement, all columns updated must be extracted from a
key-preserved table. If the view was created WITH CHECK OPTION, join
columns and columns taken from tables that are referenced more than once
in the view must be shielded from UPDATE.
4. For a DELETE statement, the join can have one and only one key-preserved
table. That table can appear more than once in the join, unless the view was
created WITH CHECK OPTION.
HTH
Naveen

Updating data throug a view in forms

Hi,
How is it possible to update data through a updateable view, when there is no rowids in a view? Can i define primary key some how to the form instead of rowid?
Regards Tarja

yes, you can choose one (or more) item then set the PRIMARY KEY property to yes.
Francois

Cannot log into CC updater

I keep getting a message that I've been signed out of my account but when I try to sign-in, the same message appears. I tried to delete the database as instructed by your help directions, but I cannot do that either - keeps saying it is being used by another program even though nothing is open. How can I update my apps if I cannot get my updater to open?
Debra Pearlman
<********> deleted email address.

Hi Kungfuontoast,
Rename the opm.db file.
Close the Creative Cloud application if it's running.
Navigate to the OOBE folder.
Windows: [System drive]:\Users\[username]\AppData\Local\Adobe\OOBE
Mac OS: /User/<username>/Library/Application Support/Adobe/OOBE folder
Rename the opm.db file to opm_old.db
Launch Creative Cloud
Make sure that you unhide the hidden files of your computer or else you will not fir "AppData" folder.
Do let me knew if it worked or not.
Regards,
Ratandeep Arora

Can not update data in table view

When i open a table from a connection in the connection navigator i can not alter the data in it... I can only add new rows. Is there a setting so i can alter the data?
My user has update rights because when i write my own update statement and execute it, it works fine.

I found the issue... You can do it in 10g but you have to define a PK on the table, otherwhise he does not know what row to update. When i added a PK i could edit the data in Jdev in data view.

Frm-40602

Hi,
I am using views to create forms in 9i. When my form is a single block form then using on lock trigger
LOCK TABLE abc
IN ROW SHARE MODE;
lets me do an insert update or delete on the view
but when i am using a detail block based on another view cde (which is based on table rtf).
rtf being a detail of xyz that is the table on which abc is based on
it wont let me do any insert update or delete i have required permissions on both the tables and corresponding views. Iam writing on lock triggers for both the tables
LOCK TABLE abc
IN ROW SHARE MODE;
LOCK TABLE rtf
IN ROW SHARE MODE;
How to resolve.
Regards,
Sumiat

It would be nice is you would give us the text corresponding to the error number:
FRM-40602: Cannot insert into or update data in a view.
Somehow, I don't think the lock_table has anything to do with this message or updating a view.

FRM 40602 and Patch Set 9

We have a long (and potentially very boring) history of not being able to install patch sets for Developer Forms on our systems because of various bugs.
The last one to cause a problem was FRM 40602 Cannot insert or update data in a view which was first found in patch set 7. (Bug number was 1996710). This was still there in 8 and meant to be fixed in 9.
Support are looking at the problem but initial indications are that the bug has not been fixed - still waiting for confirmation.
My question is whether anyone else has sen this in PS9 - there has been a forum on Metalink stating this but I have not seen anything else.

We're using XP and have successfully been running Forms and Reports Runtime 6.0.17.1 and 6.0.17.0 for the past 3 or 4 months. However, just yesterday we came across this error only 1 system out of 40+ machines that run an application that uses both Forms & Reports R/T. I have spent around 8 hours today attempting to repair the problem without success. Yet when I go to another machine with the identical install and build, I can run the app without any problems under the same user id as on the machine that does not work. Our exact error that pops up is:
FRM-40602 Cannot insert into or update data in a view. field: LM_XREF.XREF_ENTITY_TYPE
After reading the message I am making this statement to, I never new there was a bug. I did a test with version 6.0.11.x before applying the patch and got it to work, but there is another bug in there that is repaired in version 6.0.13.x and re-appears in ver 6.0.17.1, so I want to apply the patches, but I don't, if you know what I mean. I'm wondering if anyone else has come across this problem? If so, I could use the help and hopefully others can benefit from this as well.
I have rebuilt the image and used various Oracle R/T, Net 8, ODBC, and SQL Net configurations but this one stumps me! $0+ machines working perfectly good and 1 does not, all the same build, with all the same Oracle middleware... I'm almost starting to think a wierd hardware problem.
Cheers,

FRM-40602: Cannot insert into or update data in a view

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