Function Module to find the Difference between two times.

Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayana

check this .
data : p_timel like sy-uzeit,
       p_timeh like sy-uzeit,
       diff like sy-uzeit,
       di(8) type c .
       p_timel = '200000'.
       p_timeh = '060000'.
       diff = p_timeh - p_timel.
       concatenate diff+0(2) ':' diff+2(2) into di.
       write:/ di.
also check for this.
       p_timel = '060000'.
       p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay

Similar Messages

Function Module to get the difference between two times.

Hi All,
I want to know if there is any function module that gives me the difference between two specified times.
For Ex: Time 1: 12/01/2007 00:01 A.M
            Time 2: Time 1 - 180 Seconds. This changes the time, also may even change the Date. (As in above situation, the Time 2 will be 11/30/2007 11:58 P.M)
Could some one please suggest if there is any function module for this case.
Thanks in Advance.

Hi, You can use the following function module to calculate the diffrence between to dates in the unit that you want.
COPF_DETERMINE_DURATION calculates the difference between two dates and time in minutes and hours.
Parameters:
EXPORTING
     I_START_DATE "The start date of the time interval
     I_START_TIME "The start time of the time interval
     I_END_DATE   "The end date of the time interval
     I_END_TIME   "The end time of the time interval
     I_UNIT_OF_DURATION "Time unit of the duration if not to be calculated in days.
     Value     =====     Meaning
     ' '     =====     Day (default)
     D     =====     Days
     H     =====     Hours
     MIN     =====     Minutes
     MON     =====     Months
     S     =====     Seconds
     WK     =====     Weeks
     YR     =====     Years
     I_FACTORY_CALENDER     "A factory calender if not using the Gregorian calender
IMPORTING
     E_DURATION      "Time difference in unit specified.
Message was edited by:
        Rajesh Soman

Function Module to find the Diff bt Two Times : O/p : Hours:Minutes only

Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes:Seconds) Time2 ( Hours:Minutes:Seconds)
Need Output in Hours:Minutes only . ( No seconds Needed )
Thanks,
N.L.Narayana

Hi
Please use FM
<b>SD_DATETIME_DIFFERENCE</b>

Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.

X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
            Dim myDate As String = myDateTime.ToString("dd/MM/yy")
            Dim myTime As String = myDateTime.ToString("hh:mm tt")
            Dim myDateTime1 As DateTime = Now
            Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
            Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
    ' This replicates the Excel MOD function
    XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.

Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future....

Help I need to subtract times to find the difference between two times?

Hello there, I really need help.
I'm trying to make this attendance tracking system so that when a user enters his or her ID the system wll remember his/her check in time. However I also need to find out either how late the person is or how early to store their over time and late.
So I get the time by using a timestamp, so I'm left with a timestamp that I store into the db. But the problem comes when trying to compute for the late or over time. To do that I have to get the normal login/checkin time from the employee schedules table in the db and either subtract that time from the checkInTime to compute for how late or subtract the checkIn time from it to find early.
The thing is, the schedule is stored in datetime format in the db since the db is sql. Also I have no idea on how to subtract the two dates via java. The month, date and year stored in the sql db are just fillers, all I need computed is the time difference of the hours and minutes between the checkInTime and the schedule.
I've tried to use datediff: SELECT e.employeeNumber, datediff('hh', startTime, checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
But it keeps on giving out various errors: You have an error in your sql syntax check your manual that corresponds to your sql server version. for the right syntax to use near , checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
My sql server is My SQL 5.0.5
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?

NewtonsApple_2 wrote:
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?it may help...
GregorianCalendar

How to do find the difference between two time stamps

Hi all,
i have a table with 2 columns called GMT time and Local time . so i need to find difference between these two time stamps.
i tried like this
select to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') from date_table
the result is coming as follows ..
0.291666666667
i did not under stand the out put.
In my table GMT_TIME= 2011-06-26 00:00:00 and LOCAL_TIME=2011-06-25 17:00:00 ..
please help me how to get exact hours between two dates ..
Thanks
Sreedhar

Hi Sreedhar,
Your output (0.2916666) has the unit day.
You should multiply with 24 to get the unit hour.
select ( to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') ) * 24 from date_table;Rgds,
Tycho

Need to find the Difference between two table

Hello ,
I have stucked in program as below scenario:-
I have two tables of huge data of same structure in a same schema.I need to find the difference exact values in tables.
By using MINUS we can find the difference between two table ,i need to find the what exact difference in the there values with colunm and value at that column.
Example TableA
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
80 DEF 6005 YY 446 YY8
TableB
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
81 DEF 6005 Yu 447 YY8
I need to the out put like this :-
The Diffence between two table is
TableA.COL1=80 TableB.Col1=81, Different
TableA.Col4=YY TableB.col4=Yu,Different
TableA.Col5=446TableB.col5=447,Different
Please suggest me to write the pl/sql program for the same
thanx in advance
KK

Thanx friends for all your efforts
I have a sample code for the same,this will compare the two tables for single row in each table .
what r the modification needed for the multiple rows of values in the two tables??
Please suggest!!
CREATE OR REPLACE PROCEDURE test_compare
IS
TYPE t_col
IS
TABLE OF VARCHAR2 (30)
INDEX BY PLS_INTEGER;
l_col t_col;
j NUMBER := 0;
l_sql VARCHAR2 (2000);
col1 VARCHAR2 (30);
col2 VARCHAR2 (30);
val1 NUMBER;
val2 NUMBER;
status VARCHAR2 (30);
CURSOR c1
IS
SELECT column_id, column_name
FROM all_tab_columns
WHERE table_name = 'TEST1';
BEGIN
FOR i IN c1
LOOP
j := j + 1;
l_col (j) := i.column_name;
END LOOP;
FOR k IN 1 .. j
LOOP
l_sql :=
'SELECT '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST2.'
|| l_col (k)
|| ', '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST1.'
|| l_col (k )
|| ', '
|| 'DECODE(TEST2.'
|| l_col (k)
|| ' -TEST1.'
|| l_col (k)
|| ', 0, ''NO CHANGE'', ''CHANGED'') FROM TEST2, TEST1';
EXECUTE IMMEDIATE l_sql INTO col1, val1,col2, val2, status;
IF status = 'CHANGED'
THEN
DBMS_OUTPUT.put_line( 'TEST2.'
|| col1
|| '='
|| val1
|| ', TEST1.'
|| col2
|| '='
|| val2
|| ', '
|| status);
END IF;
END LOOP;
EXCEPTION
WHEN OTHERS
THEN
DBMS_OUTPUT.put_line ('Error:- ' || SQLERRM);
END;
/

Find the difference between two columns in an ssrs matrix ? MSCRM

Hi All,
I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
I am trying to create report using fetch xml based. Below is the snap what we required the result.
Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
Revenue.
https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
Thanks,
Mohammad Sharique

Hi Bro,
I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage.
Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
Below expression using to showing Plan Revenue in Percentage for year.
=
Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
- Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
/IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
,1)
)*100))
Result issue is as below in snap with highlighted in red colour.
Kindly help me on this issue also :)

How to find the difference between 2 time values in Java

hi all,
i have 2 time values
String time1="6:20";
String time2="21:30"
How to find the difference between 2 times in Java?
pls help
thanx in advance....

Calculating Java dates: Take the time to learn how to create and use dates
Working in Java time: Learn the basics of calculating elapsed time in Java
Formatting a Date Using a Custom Format
Parsing a Date Using a Custom Format

Find the difference between two internal table

how can i see the difference between two interal tables?
The requirement is as follows
1. We have a transparent table, which stores the employee data with EMP ID as key.
2. We load the transp table data into a interal table (B).
3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
We want to do followign things
I = A - B
D = B - A
Both A and B will have around 40k records. Hence we are trying to avoid the looping.
Please suggest the best option for us.
Thank you in advance.
Raghavendra

>
RAGHAV URAL wrote:
> how can i see the difference between two interal tables?
> The requirement is as follows
>
> 1. We have a transparent table, which stores the employee data with EMP ID as key.
> 2. We load the transp table data into a interal table (B).
> 3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
>
> Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
>
> We want to do followign things
> I = A - B
> D = B - A
>
> Both A and B will have around 40k records. Hence we are trying to avoid the looping.
>
> Please suggest the best option for us.
>
> Thank you in advance.
> Raghavendra
Hi Raghavendra,
Currently as of my knowledge, these operations are only possible through LOOPs. But LOOPign can be really fast here if you properly utilize the SORTING, READ with BINARY SEARCH and FIELD-SYMBOLS usage. I would say:-
Steps for Insert:-
SORT: A, B.
LOOP AT A ASSIGNING <WA_A>.
READ TABLE B WITH TABLE KEY key = <WA_A>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_A> TO I.
ENDIF.
ENDLOOP.
Steps for Delete:-
SORT: A, B.
LOOP AT B ASSIGNING <WA_B>.
READ TABLE A WITH TABLE KEY key = <WA_B>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_B> TO D.
ENDIF.
ENDLOOP.
Regards,
Ravi.

FormCalc Formula to tell the difference between two time fields if they are populated - Help please

Hi,
I have a cell (TotalTime1) that references two other time formatted cells (Start1 and Finish 1).
The below formula is intended to tell the difference between the Start and Finish time if they are populated.
I had it working without the HasValue condition but the formula was calculating when there was no value in Start1 and Finish1 (due to time format).
This is the code I do have, it says there is an error near the last line; I am sorry if I post this in the wrong manner, I have not posted on this forum before but here goes:
if (HasValue (Finish1) and HasValue (Start1)) then if (Time2Num(Start1.formattedValue, "HH:MM") < Time2Num (Finish1.formattedValue, "HH:MM")) then Abs (Time2Num(Start1.formattedValue, "HH:MM") - Time2Num(Finish1.formattedValue, "HH:MM")) / (60 * 60 * 1000) else 24 - Abs (Time2Num(Finish1.formattedValue, "HH:MM") - Time2Num(Start1.formattedValue, "HH:MM")) / (60 * 60 * 1000) endif
Any help would be appreciated.
Regards Fetachini

Thanks whyisthisme,
Your speedy response is greatly appreciated, your support has resolved my issue.
Many thanks.
Regards
Fetachini

Find the difference between two dates for the specific month and year

Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?

I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

How to find the difference between two date?

Hi,
I currently writing a date comparision program. Below is the idea analogy,
Currently i need to find how many day differences between 30 July 2003 and 22 June 2004. How can i use java to code it?
Thanks.

there doesn't seem to be a direct way but try this:int daysBetween = 0;
Calendar c = new GregorianCalendar(2004, Calendar.JULY, 30);
Calendar d = new GregorianCalendar(2003, Calendar.JUNE, 22);
while (c.get(Calendar.YEAR) != d.get(Calendar.YEAR)) {
daysBetween += 360;
d.add(Calendar.DAY_OF_YEAR, 360);
daysBetween += c.get(Calendar.DAY_OF_YEAR) - d.get(Calendar.DAY_OF_YEAR);This gives the correct result of 404 (= 8 days from June 22 to June 30 + 366 days between July 1 of 2003 and 2004 + 30 days from July 1 to July 30)

How do I calculate the difference between two times?

I am so embarrassed by the fact that I can't figure this out.
Cell B2- 8:00 am
Cell C2- 10:50 am
Cell D2- (How do I get this cell to calculate the difference and say 2:50?)
I know this is probably one of the most basic operations, but for the life of me I can't figure it out. Cells B2 & C2 are formatted for 24 hour clock. But if I tell the system to just subtract the two, I get "0.118". Everything I find on the forum search goes beyond what I need. Can anyone help me?
Thank you.

KOENIG Yvan wrote:
Numbers states clearly in the Help and the PDF Users Guide that it doesn't know a "duration" object but a time one which is restricted to the range 00:00:0 to 23:59:59.
When I search the U.S. language Numbers User Guide for the word "duration," it is not found.
What may be more clear: _duration is not available but time is_?
Once again your response resemble to a rant againt the Help and the User Guide.
In the Help:
+date-time Any Numbers date/time value. _While you can choose to display only date or time in a cell, all Numbers date or time values contain both the date and time._+
Which wording would be more clear and precise?
TIMEVALUE
+The TIMEVALUE function converts a date, a time, or a text string to _a decimal fraction of a 24-hour day._+
Which wording would be more clear and precise?
TIME
+The TIME function converts hours, minutes, and seconds into a time format.+
+TIME(hours, minutes, seconds)+
+hours: The number of hours _(using a 24-hour clock)._+
+minutes: The number of minutes.+
+seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59, respectively. _If the hours, minutes, and seconds add up to more than 24 hours, Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
Which wording would be more clear and precise?
In the User Guide:
page 190
+date-time Any Numbers date/time value. _While you can choose to display_+
+_only date or time in a cell, all Numbers date or time values contain_+
+_both the date and time._+
+TIME (page 277) Converts a time to a decimal fraction of a 24-hour day.+
+TIMEVALUE (page 278) Converts a time in a string to a decimal fraction of a 24-hour day.+
TIME
+The TIME function converts the specified time to a decimal fraction of a 24-hour day.+
+TIME(hours, minutes, seconds)+
+• hours: The number of hours _(using a 24-hour clock)_.+
+• minutes: The number of minutes.+
+• seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59,+
+respectively. _If the hours, minutes, and seconds add up to more than 24 hours,_+
+_Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
+You can also specify fractional values for hours, minutes, or seconds.+
TIMEVALUE
+The TIMEVALUE function converts a time in a string to a decimal fraction of a 24-hour+
day.
TIMEVALUE(date-time)
+• date-time: A date, a time, or a string in any of the Numbers date and time formats.+
As you may check, the infos are exactly the same in the Help and in the Guide.
And I really don't understand how you may find them unclear.
Yvan KOENIG (from FRANCE lundi 4 août 2008 14:57:36)

How to find the difference between two timestamp column

Dear All,
please Solve my issue,
I have Table name Record which has the following columns,
Empid in number column, dat in timestamp
which has the following values
Expand|Select|Wrap|Line Numbers
empid dat
====== ====
101 4/9/2012 9:48:54 AM
101 4/9/2012 9:36:28 AM
101 4/9/2012 6:16:28 PM
101 4/10/2012 9:33:48 AM
101 4/10/2012 12:36:28 PM
101 4/10/2012 8:36:12 PM
101 4/11/2012 9:36:28 AM
101 4/11/2012 4:36:22 PM
Here I need to display the following columns,
empid,min(dat) as start,max(dat) as end and difference(max(dat)-min(dat) for each day,
for eg,
Empid Strart end difference
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
like this.
Here 3 different days are exists so It should return 3 records with the above mentioned columns,
Please Help me to get this.
Thank you,
Regards,
Gurujothi
Edited by: Gurujothi on Apr 25, 2012 4:45 AM

>
101 4/9/2012 9:48:54 AM 4/9/2012 6:16:28 PM 8.28
>
why 4/9/2012 9:48:54?
why not 4/9/2012 9:36:28 AM ?
SQL>
SQL> with t as
2 (select 101 empid, to_timestamp('4/9/2012 9:48:54 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
3 select 101, to_timestamp('4/9/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
4 select 101, to_timestamp('4/9/2012 6:16:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
5 select 101, to_timestamp('4/10/2012 9:33:48 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
6 select 101, to_timestamp('4/10/2012 12:36:28 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
7 select 101, to_timestamp('4/10/2012 8:36:12 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual union all
8 select 101, to_timestamp('4/11/2012 9:36:28 AM', 'dd/mm/yyyy hh:mi:ss AM') dat from dual union all
9 select 101, to_timestamp('4/11/2012 4:36:22 PM', 'dd/mm/yyyy hh:mi:ss PM') dat from dual
10 )
11 select empid, min(dat) as start_dat
12 , max(dat) as end_dat
13 , max(dat)-min(dat) diff
14 from t
15 group by empid, trunc(dat)
16 /
     EMPID START_DAT                                         END_DAT                                           DIFF
       101 04.09.12 09:36:28,000000000                       04.09.12 18:16:28,000000000                       +000000000 08:40:00
       101 04.11.12 09:36:28,000000000                       04.11.12 16:36:22,000000000                       +000000000 06:59:54
       101 04.10.12 09:33:48,000000000                       04.10.12 20:36:12,000000000                       +000000000 11:02:24
SQL>

Function Module to find the Difference between two times.

Similar Messages

Maybe you are looking for