Function to calculate diference between 2 times?

Hi All,
Does anybody knows a functions, that calculates the diference in hours of to times, having in acount also the date?
For example: The diference between 23h00 of 17.01.2007 and 04h00 of 18.01.2007. Result 5 hours.
Thanks in advanced.
Marcelo Moreira

Hi,
Please check this FM.
CCU_TIMESTAMP_DIFFERENCE.
SD_DATETIME_DIFFERENCE
Regards,
Ferry Lianto

Similar Messages

How to calculate period between date/time?

All,
I have not been able to find any function module that does this.
I have a create date/time from a table (VBAK).
I need to calculate the difference in days/hours/minutes (seconds not needed) between the date in this table and the current date/time.
Then based on the result - e.g. difference is say 2 days 3 hours and 50 minutes - I will compare to a comfigured period users input to determine record selection.
I can get date difference - SAP handles that - but the hours and minutes are a different story.
Thanks.
Scott

No Matters if problem solved by own. Surely Posting a solution would help others needed person in future .

Using analytical function to calculate concurrency between date range

Folks,
I'm trying to use analytical functions to come up with a query that gives me the
concurrency of jobs executing between a date range.
For example:
JOB100 - started at 9AM - stopped at 11AM
JOB200 - started at 10AM - stopped at 3PM
JOB300 - started at 12PM - stopped at 2PM
The query would tell me that JOB1 ran with a concurrency of 2 because JOB1 and JOB2
were running started and finished within the same time. JOB2 ran with the concurrency
of 3 because all jobs ran within its start and stop time. The output would look like this.
JOB START STOP CONCURRENCY
=== ==== ==== =========
100 9AM 11AM 2
200 10AM 3PM 3
300 12PM 2PM 2
I've been looking at this post, and this one if very similar...
Analytic functions using window date range
Here is the sample data..
CREATE TABLE TEST_JOB
( jobid NUMBER,
created_time DATE,
start_time DATE,
stop_time DATE
insert into TEST_JOB values (100, sysdate -1, to_date('05/04/08 09:00:00','MM/DD/YY hh24:mi:ss'), to_date('05/04/08 11:00:00','MM/DD/YY hh24:mi:ss'));
insert into TEST_JOB values (200, sysdate -1, to_date('05/04/08 10:00:00','MM/DD/YY hh24:mi:ss'), to_date('05/04/08 13:00:00','MM/DD/YY hh24:mi:ss'));
insert into TEST_JOB values (300, sysdate -1, to_date('05/04/08 12:00:00','MM/DD/YY hh24:mi:ss'), to_date('05/04/08 14:00:00','MM/DD/YY hh24:mi:ss'));
select * from test_job;
JOBID|CREATED_TIME |START_TIME |STOP_TIME
----------|--------------|--------------|--------------
100|05/04/08 09:28|05/04/08 09:00|05/04/08 11:00
200|05/04/08 09:28|05/04/08 10:00|05/04/08 13:00
300|05/04/08 09:28|05/04/08 12:00|05/04/08 14:00
Any help with this query would be greatly appreciated.
thanks.
-peter

after some checking the model rule wasn't working exactly as expected.
I believe it's working right now. I'm posting a self-contained example for completeness sake.I use 2 functions to convert back and forth between epoch unix timestamps, so
I'll post them here as well.
Like I said I think this works okay, but any feedback is always appreciated.
-peter
CREATE OR REPLACE FUNCTION date_to_epoch(p_dateval IN DATE)
RETURN NUMBER
AS
BEGIN
return (p_dateval - to_date('01/01/1970','MM/DD/YYYY')) * (24 * 3600);
END;
CREATE OR REPLACE FUNCTION epoch_to_date (p_epochval IN NUMBER DEFAULT 0)
RETURN DATE
AS
BEGIN
return to_date('01/01/1970','MM/DD/YYYY') + (( p_epochval) / (24 * 3600));
END;
DROP TABLE TEST_MODEL3 purge;
CREATE TABLE TEST_MODEL3
( jobid NUMBER,
start_time NUMBER,
end_time NUMBER);
insert into TEST_MODEL3
VALUES (300,date_to_epoch(to_date('05/07/2008 10:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 19:00','MM/DD/YYYY hh24:mi')));
insert into TEST_MODEL3
VALUES (200,date_to_epoch(to_date('05/07/2008 09:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 12:00','MM/DD/YYYY hh24:mi')));
insert into TEST_MODEL3
VALUES (400,date_to_epoch(to_date('05/07/2008 10:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 14:00','MM/DD/YYYY hh24:mi')));
insert into TEST_MODEL3
VALUES (500,date_to_epoch(to_date('05/07/2008 11:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 16:00','MM/DD/YYYY hh24:mi')));
insert into TEST_MODEL3
VALUES (600,date_to_epoch(to_date('05/07/2008 15:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 22:00','MM/DD/YYYY hh24:mi')));
insert into TEST_MODEL3
VALUES (100,date_to_epoch(to_date('05/07/2008 09:00','MM/DD/YYYY hh24:mi')),
date_to_epoch(to_date('05/07/2008 23:00','MM/DD/YYYY hh24:mi')));
commit;
SELECT jobid,
epoch_to_date(start_time)start_time,
epoch_to_date(end_time)end_time,
n concurrency
FROM TEST_MODEL3
MODEL
DIMENSION BY (start_time,end_time)
MEASURES (jobid,0 n)
(n[any,any]=
count(*)[start_time<= cv(start_time),end_time>=cv(start_time)]+
count(*)[start_time > cv(start_time) and start_time <= cv(end_time), end_time >= cv(start_time)]
ORDER BY start_time;
The results look like this:
JOBID|START_TIME|END_TIME |CONCURRENCY
----------|---------------|--------------|-------------------
100|05/07/08 09:00|05/07/08 23:00| 6
200|05/07/08 09:00|05/07/08 12:00| 5
300|05/07/08 10:00|05/07/08 19:00| 6
400|05/07/08 10:00|05/07/08 14:00| 5
500|05/07/08 11:00|05/07/08 16:00| 6
600|05/07/08 15:00|05/07/08 22:00| 4

Query designer - calc diference between lines

Dear coleagues,
i need to calculate diference between actual line and last line like this example::
Material Month Value        Diference with Last Month
A0001   01        100,00
A0001   02        150,00      50,00
A0001   03        250,00      100,00
How can i do this on Query Designer ??
Thanks in advance.
Fabrício

HI ,
Just a try ,
Create a calculated KF1 with value --> with first value in exception aggregation tab --> with reference characteristic as Month
Create a calculated KF2 with value --> with Last value in exception aggregation tab --> with reference characteristic as Month
KF3 = KF2 - KF1
Regards,
Sathya

How to use case when function to calculate time ?

Dear All,
May i know how to use case when function to calculate the time ?
for the example , if the First_EP_scan_time is 12.30, then must minus 30 min.
CASE WHEN FIRSTSCAN.EP_SHIFT <> 'R1' AND FIRSTSCAN.EP_SHIFT <> 'R2'
THEN ROUND(CAST((DATEDIFF(MINUTE,CAST(STUFF(STUFF((CASE WHEN SHIFTCAL.EP_SHIFT = 'N1'
THEN CONVERT(VARCHAR(8),DATEADD(DAY,+1,LEFT(FIRSTSCAN.EP_SCAN_DATE ,8)),112) + ' ' + REPLACE(CONVERT(VARCHAR(8),DATEADD(HOUR,+0,SHIFTDESC.EP_SHIFT_TIMETO + ':00'),108),':','')
ELSE LEFT(FIRSTSCAN.EP_SCAN_DATE ,8) + ' ' + REPLACE(CONVERT(VARCHAR(8),DATEADD(HOUR,+0,SHIFTDESC.EP_SHIFT_TIMETO + ':00'),108),':','') END),12,0,':'),15,0,':') AS DATETIME),CAST(STUFF(STUFF(LASTSCAN.EP_SCAN_DATE,12,0,':'),15,0,':') AS DATETIME)) / 60.0 - 0.25) AS FLOAT),2)
ELSE ROUND(CAST((DATEDIFF(MINUTE,CAST(STUFF(STUFF(FIRSTSCAN.EP_SCAN_DATE,12,0,':'),15,0,':') AS DATETIME),CAST(STUFF(STUFF(LASTSCAN.EP_SCAN_DATE,12,0,':'),15,0,':') AS DATETIME)) / 60.0) AS FLOAT),2) END AS OTWORK_HOUR

Do not use computations in a declarative language. This is SQL and not COBOL.
Use a table of time slots set to one more decimal second of precision than your data. You can now use temporal math to add it to a DATE to TIME(1) get a full DATETIME2(0). Here is the basic skeleton.
CREATE TABLE Timeslots
(slot_start_time TIME(1) NOT NULL PRIMARY KEY,
slot_end_time TIME(1) NOT NULL,
CHECK (start_time < end_time));
INSERT INTO Timeslots --15 min intervals
VALUES ('00:00:00.0', '00:14:59.9'),
('00:15:00.0', '00:29:59.9'),
('00:30:00.0', '00:44:59.9'),
('00:45:00.0', '01:00:59.9'),
('23:45:00.0', '23:59:59.9');
Here is the basic query for rounding down to a time slot.
SELECT CAST (@in_timestamp AS DATE), T.start_time
FROM Timeslots AS T
WHERE CAST (@in_timestamp AS TIME)
BETWEEN T.slot_start_time
AND T.slot_end_time;
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL

Calculate difference between two dates/times

Hi all,
Is there any function module to calculate difference between two dates/times which are in TIMESTAMPL format.
I need to know how many millisconde(second,minutes, hours... )there is between these two times.
Please, It is urgent
Thank you all.
Karim

hi,
try the following function
CALL FUNCTION 'CCU_TIMESTAMP_DIFFERENCE'
      EXPORTING
           timestamp1 = timestamp1
           timestamp2 = timestamp2
      IMPORTING
           difference = diff
      EXCEPTIONS
           OTHERS     = 1.
the above function gives the difference in seconds...
try the following code to set the resolution to milliseconds..
SET RUN TIME CLOCK RESOLUTION LOW
check the thread for details:
SET RUN TIME CLOCK RESOLUTION?
all the best!!!
Regards,
Aparna

Function Module to find the Difference between two times.

Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
       06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayana

check this .
data : p_timel like sy-uzeit,
       p_timeh like sy-uzeit,
       diff like sy-uzeit,
       di(8) type c .
       p_timel = '200000'.
       p_timeh = '060000'.
       diff = p_timeh - p_timel.
       concatenate diff+0(2) ':' diff+2(2) into di.
       write:/ di.
also check for this.
       p_timel = '060000'.
       p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay

How to read time stamps from a spreadsheet and calculate the difference between consecutive time stamps?

Hi,
I am new to Labview. This question might be a joke to some of you here, but any help would be greatly appreciated. I have a spreadsheet with time stamps and power outputs from a generator. I am supposed to calculate the difference between consecutive time stamps, which will act as a delay for the next power output update that needs to be sent. For example, lets say that I have to following data:
Time Stamp                    Power Output
11:00:00 AM                       3kW
11:00:02 AM                       2.9kW
11:00:04 AM                       3.2kW
11:00:06 AM                       3.1kW
The above data doesn't make any sense, but it is just for the purpose of this question.
So, I have to read 11:00:00 AM and 3kW initially - 3kW is the initial request that is sent. Then I have to

Repeated forum post
Please view http://forums.ni.com/ni/board/message?board.id=170&message.id=294435
Regards,
Juan Galindo
Applications Engineer
National Instruments

Need Help to calculate difference between times

Hello everyone,
I have two fields which just stores the time in 24 hour format ex: 08:00 and 20:00 now I want to calculate difference between the two times
Kindle help me
Thanks for your help
Thanks
Ravi

Are your fields of varchar2 datatype or...?
Is 08:00 the start time or 20:00?
Date arithmetic is pretty simple in Oracle if you use the right datatype.
See:
http://asktom.oracle.com/pls/asktom/ASKTOM.download_file?p_file=6551242712657900129
Assuming you are storing strings:
SQL> -- generating sample data:
SQL> with t as (
2 select '08:00' btime, '20:00' etime from dual
3 )
4 --
5 -- actual query:
6 --
7 select numtodsinterval(to_date(etime, 'hh24:mi') - to_date(btime, 'hh24:mi'), 'day') nti
8 ,      (to_date(etime, 'hh24:mi') - to_date(btime, 'hh24:mi'))*24 dt
9 from   t;
NTI                                                                                 DT
+000000000 12:00:00.000000000                                                       12
1 row selected.
SQL>

Function to calculate time elapsed needed

Hi all,
I need a function which will give me total time elapse if I provide 2 dates with timings.
ie Date1 : "23-Feb-2005 21:00:00"
Date2 : "21-Feb-2005 22:00:00"
output should be somewhat like
1 day ,23 hrs ,00 mins and 00 secs( i.e total time elapsed).
Regards

Hi,
You have the solution in Metalink note
1035465.6: How to Display Date Difference Values in Years, Months, Days
Nicolas

Numbers function IF greater than using date & time

I am trying to produce a number sheet that will allow me calculate a working rota for staff.
The problem i am having is when i try and use a IF function to remove 1hr (for lunch) if the person works 8 hours or more.
If that person works between 6 and 8 they require a 30 mins lunch.
I have already setup the sheet to calculate the total shift time by subtracting the starting time from the finishing time. i.e. 18:00 - 08:00 = 10hrs
Now i need it to subtract 1hr for lunch.
It should read something like IF 10 >8 then -1 from 10.
I just don't know how to not cause an error.
ideally i would like it to be able to handle 2 IF's in the one cell. if its 6-8hrs - 30mins or if its greater than 7 -1 hr.
I currently have all the cells set at time and date.
Any help would be greatly appreciated.
Richard

this works a little but it seems to subtract 0.5 and then 1 removing to much time.
I have attached a link which i hope will explain this better.
https://onedrive.live.com/redir?resid=82B56CEF9A61CDE9!8770&authkey=!ALJn-lja2b2 q1iw&ithint=file%2cnumbers
Thank you for your help

Calculate duration between start date and end date

Hi everyone,
I'm facing with problem when calculating duration between start & end with this function below . This fuction is working well, but i want to change working time from 8:00 am to 17:30 pm instead of 17:00 , and lunch time from 12:00 to 13:30 instead
of 13:00 as present . Problem is , i changed data type of start hour and end hour from INT to decimal . But it is still wrong .
Pls help me . It's very urgent bcoz i need it for monthly report .
Many thanks .
Here is function which im using :
ALTER Function [dbo].[GetWorkingMin](@pStartDate DateTime, @pEndDate DateTime) Returns Int
AS
Begin
 Declare @StartDate DateTime = @pStartDate
 Declare @EndDate DateTime = @pEndDate
 Declare @WorkMin int = 0 -- Initialize counter
 Declare @Reverse bit -- Flag to hold if direction is reverse
 Declare @StartWorkingHour int = 8 -- Start of business hours (can be supplied as an argument if needed)
 Declare @EndWorkingHour int = 17 -- End of business hours (can be supplied as an argument if needed)
 Declare @Holidays Table (HDate DateTime) -- Table variable to hold holidayes
 Declare @LunchHour int = 12
 Declare @StartHour int = DatePart(HH, @StartDate)
 Declare @EndHour int = DatePart(HH, @EndDate)
 -- If dates are in reverse order, switch them and set flag
 If @StartDate>@EndDate
 Begin
 Declare @TempDate DateTime=@StartDate
 Set @StartDate=@EndDate
 Set @EndDate=@TempDate
 Set @Reverse=1
 End
 Else Set @Reverse = 0
 -- Get country holidays from table based on the country code
 Insert Into @Holidays (HDate) Select HDate from HOLIDAY Where HDATE>=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)
 If DatePart(HH, @StartDate)<@StartWorkingHour
 begin
 Set @StartDate = DateAdd(hour, @StartWorkingHour, DateDiff(DAY, 0, @StartDate))
 -- If Start time is less than start hour, set it to start hour
 Set @StartHour = DatePart(HH, @StartDate)
 end
 If DatePart(HH, @StartDate)>=@EndWorkingHour
 begin
 Set @StartDate = DateAdd(hour, @StartWorkingHour+24, DateDiff(DAY, 0, @StartDate))
 -- If Start time is after end hour, set it to start hour of next day
 Set @StartHour = DatePart(HH, @StartDate)
 --return DatePart(day, @StartDate)
 end
 If DatePart(HH, @EndDate)>=@EndWorkingHour
 begin
 Set @EndDate = DateAdd(hour, @EndWorkingHour, DateDiff(DAY, 0, @EndDate))
 -- If End time is after end hour, set it to end hour
 Set @EndHour = DatePart(HH, @EndDate)
 end
 If DatePart(HH, @EndDate)<@StartWorkingHour
 begin
 Set @EndDate = DateAdd(hour, @EndWorkingHour-24, DateDiff(DAY, 0, @EndDate))
 -- If End time is before start hour, set it to end hour of previous day
 Set @EndHour = DatePart(HH, @EndDate)
 end
 If (@StartHour>=@LunchHour and @StartHour < (@LunchHour +1))
 Begin
 Set @StartDate = DateAdd(hour, @LunchHour + 1, DateDiff(DAY, 0, @StartDate))
 -- If Start time is in lunch time, set it to 12
 Set @StartHour = @LunchHour + 1
 End
 If (@StartHour>=@LunchHour and DatePart(DW, @StartDate) = 7)
 Begin
 Set @StartDate = DateAdd(hour, @StartWorkingHour + 24, DateDiff(DAY, 0, @StartDate))
 Set @StartHour = DatePart(HH, @StartDate)
 End
 If (@EndHour>=@LunchHour and @EndHour < (@LunchHour +1))
 Begin
 Set @EndDate = DateAdd(hour, @LunchHour +1, DateDiff(DAY, 0, @EndDate))
 -- If End time is in lunch time, set it to 13
 Set @EndHour = @LunchHour + 1
 End
 If (DatePart(DW, @EndDate) = 7 and DatePart(HH, @EndDate) >= @LunchHour) Set @EndDate = DateAdd(hour, @LunchHour, DateDiff(DAY, 0, @EndDate)) -- If End day is Saturday and End time is after end hour, set it to end hour of saturday
 If @StartDate>@EndDate Return 0
 -- If Start and End is on same day
 If DateDiff(Day,@StartDate,@EndDate) <= 0
 Begin
 If (Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7)
 -- If day is between sunday and saturday
 If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0
 -- If day is not a holiday
 If @EndDate<@StartDate Return 0 Else
 Begin
 Set @WorkMin=DATEDIFF(MI, @StartDate, @EndDate)
 -- Calculate difference
 If (@StartHour <= @LunchHour and @EndHour >= @LunchHour + 1)
 Set @WorkMin = @WorkMin - 60;
 End
 Else Return 0
 Else Begin
 if (DATEPART(dw,@StartDate)=7) set @WorkMin = @WorkMin + DATEDIFF(MI, @StartDate, @EndDate);
 Return @WorkMin
 End
 End
 Else Begin
 Declare @Partial int=1
 -- Set partial day flag
 While DateDiff(Day,@StartDate,@EndDate) > 0
 -- While start and end days are different
 Begin
 If Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7 -- If this is a weekday
 Begin
 If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0 -- If this is not a holiday
 Begin
 If @Partial=1
 -- If this is the first iteration, calculate partial time
 Begin
 Set @WorkMin=@WorkMin + DATEDIFF(MI, @StartDate, DateAdd(hour, @EndWorkingHour, DateDiff(DAY, 0, @StartDate)))
 If (@StartHour <= @LunchHour) Set @WorkMin = @WorkMin - 60;
 Set @StartDate=DateAdd(hour, @StartWorkingHour+24, DateDiff(DAY, 0, @StartDate))
 Set @Partial=0
 End
 Else Begin
 -- If this is a full day, add full minutes
 Set @WorkMin=@WorkMin + (@EndWorkingHour-@StartWorkingHour - 1)*60
 Set @StartDate = DATEADD(DD,1,@StartDate)
 End
 End
 Else Set @StartDate = DATEADD(DD,1,@StartDate)
 End
 Else Begin
 If (DATEPART(dw,@StartDate)=7)
 Begin
 Set @WorkMin = @WorkMin + DATEDIFF(MI, @StartDate, DateAdd(hour, @LunchHour, DateDiff(DAY,
0, @StartDate)));
 End
 --Set @StartDate = DATEADD(DD,1,@StartDate)
 Set @StartDate = DateAdd(hour, @StartWorkingHour + 24, DateDiff(DAY, 0, @StartDate))
 Set @StartHour = DatePart(HH, @StartDate)
 End
 End
 If Datepart(dw,@StartDate)>1 And DATEPART(dw,@StartDate)<7
 -- If last day is a weekday
 If (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@StartDate), 0)) = 0
 -- And it is not a holiday
 Begin
 If @Partial=0 Set @WorkMin=@WorkMin + DATEDIFF(MI, @StartDate, @EndDate) Else
Set @WorkMin=@WorkMin + DATEDIFF(MI, DateAdd(hour, @StartWorkingHour, DateDiff(DAY, 0, @StartDate)), @EndDate)
 If (@EndHour >= (@LunchHour + 1)) Set @WorkMin = @WorkMin - 60;
 End
 If (DATEPART(dw,@EndDate)=7)
 Begin
 Set @WorkMin = @WorkMin + DATEDIFF(MI, DateAdd(hour, @StartWorkingHour, DateDiff(DAY, 0, @EndDate)),@EndDate);
 End
 End
 If @Reverse=1 Set @WorkMin=-@WorkMin
 Return @WorkMin
End

The problem is you cannot specify partial hours.
I think your best bet would be to alter the function sufficiently so it will accept times instead of hours, and where you're making comparisons to the hour, use dates/date functions instead.
Then, just set the variable as a full time (or datetime, if you need).

Time between to time

Hi, experts
Can i get a method that give the time between two time.
I have two times 'oEditHEmb' and 'oEditHDeb' which are in two columns. I want to calculate the time between these two times.
Pls help.

hello freind try this function
hear yu can use dtmStart and dtmEnd for yur 1 colum and second colum
Function TimeDiffString(ByVal dtmStart As String, ByVal dtmEnd As String) As Decimal
 Dim intHrs1, intMins1, intSecs1 As Decimal
 Dim intHrs2, intMins2, intSecs2 As Decimal
 Dim hrs, min As Decimal
 'Dim strHrsString, strMinsString, strSecsString As String
 'Dim dtmEnd1 As Date
 'dtmEnd1 = DateTime.ParseExact(dtmEnd, "HHmm", Nothing)
 If (dtmStart.Length < 4) Then
 dtmStart = "0" & dtmStart
 End If
 If (dtmEnd.Length < 4) Then
 dtmEnd = "0" & dtmEnd
 End If
 intHrs1 = Convert.ToDecimal(dtmStart.Substring(0, 2))
 intMins1 = Convert.ToDecimal(dtmStart.Substring(2, 2))
 intHrs2 = Convert.ToDecimal(dtmEnd.Substring(0, 2))
 intMins2 = Convert.ToDecimal(dtmEnd.Substring(2, 2))
 hrs = intHrs2 - intHrs1
 min = intMins2 - intMins1
 If (hrs < 0) Then
 Return (-1)
 ElseIf (hrs = 0) And (min < 0) Then
 Return (-1)
 ElseIf (hrs = 0) And (min = 0) Then
 Return (0)
 ElseIf (hrs = 0) And (min > 0) Then
 Return (1)
 ElseIf (hrs > 0) Then
 Return (1)
 End If
 End Function

What is the diference between apple tv and airport express?

I can see tv online in my tv whitout airport express??
What is the diference between apple tv and new apple tv2?

Airport is a router, Apple TV is a set-top box.
http://www.apple.com/airportexpress/
http://www.apple.com/appletv/
Original Apple TV had a hard-drive, and has been discontinued for quite some time.
ATV2 is a streaming only device, smaller, and use less power. It is also now discontinued
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Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.

X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
            Dim myDate As String = myDateTime.ToString("dd/MM/yy")
            Dim myTime As String = myDateTime.ToString("hh:mm tt")
            Dim myDateTime1 As DateTime = Now
            Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
            Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
    ' This replicates the Excel MOD function
    XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.

Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future....

Function to calculate diference between 2 times?

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