Function to replace nth occurrence of a character

Hi,
Is there a function already to replace the nth occurrence of a character ?
For example: 'ORACLE IS THE INFORMATION COMPANY'
Replace 3rd 'O' from left with 0 (Zero):
'ORACLE IS THE INFORMATI0N COMPANY'
Thanks !
Regrads,
Pat

SQL> var a varchar2(100);
SQL> var occ number;
SQL> exec :a := 'ORACLE IS THE INFORMATION COMPANY';
PL/SQL procedure successfully completed.
SQL> exec :occ := 3;
PL/SQL procedure successfully completed.
SQL> select SUBSTR(:A,1, instr(:A,'O',1,:occ)-1)||'0'||SUBSTR(:A,instr(:A,'O',1,:occ)+1) from dual
2 /
SUBSTR(:A,1,INSTR(:A,'O',1,:OCC)-1)||'0'||SUBSTR(:A,INSTR(:A,'O',1,:OCC)+1)
ORACLE IS THE INFORMATI0N COMPANYKarthick.

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Function to replace nth occurrence of a character

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