Generate calender date in column wise

Question

Hi,
I need to get a report based on Year and Month as a input, calender date must get populate.
if user inputs values are JAN AND 2011 as the input it must generate the report as
1 2 3 4 5 .... 30
based on the number of days it has it must populate the date. Each date must be a separate column. Please suggest me
Thanks
Sudhir

Answer 1

Hi,
This does what you requested:
WITH     got_dt     AS
     SELECT     TO_DATE ( 'JAN 2011'
               , 'MON YYYY'
               , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If needed
               )     AS dt
     FROM    dual
SELECT     TO_CHAR (dt, 'MON YYYY')     as mon_year
,     MIN (CASE WHEN LEVEL =  1 THEN LEVEL END)     AS d1
,     MIN (CASE WHEN LEVEL =  2 THEN LEVEL END)     AS d2
,     MIN (CASE WHEN LEVEL = 31 THEN LEVEL END)     AS d31
FROM     got_dt
CONNECT BY     LEVEL     <= EXTRACT (     DAY
                       FROM     LAST_DAY (dt)
;The query you were copying had one row per week, which is hy it used the aGROUP BY clause like it did. You only want one row altogether, so you won't need a GROUP BY clause.
The query you were copying had 7 poivoted columns, each fgenerated by a line of code such as
max(decode(to_char(dt,'d'),'1',lpad(to_char(dt,'fmdd'),2))) "Su",that was specifically looking for one of the 7 possible days of the week. You want 31 columns, for the 31 possible values for the day of the month.
The sub-query isn't really necessary for the problem as you gave it, but it could be very useful for related problems. Gor example, if you wanted output that had DATEs in each column instead of NUMBERs:
d1          d2          d3          ...
01-Jan-2011     02-Jan-2011     03-Jan-2011     ...