Generate XML Urgent !!!!!

Question

Hi all,
i have just problem with generating XML through database.
my code is
DECLARE
XML_DATA XMLTYPE;
BEGIN
FOR v_cur IN (SELECT * FROM EMPLOYEES)
LOOP
SELECT dbms_xmlgen.getxmltype('SELECT * FROM EMPLOYEES WHERE EMP_ID=' || v_cur.EMP_ID)
INTO XML_DATA
FROM DUAL;
INSERT INTO TEST_DATA VALUES (XML_DATA);
END LOOP;
END;
NOW i am getting out put like
<Rowset>
<Row>
<emp_id>101<emp_id>
<emp_name>King</emp_name>
<add1>160-2</add1>
<add2>Apex Appartment</add2>
<dept_id>10</dept_id>
<city>NJ</city>
</Row>
</Rowset>
But i want out put in following format :
<Rowset>
<Row>
<emp_id>101<emp_id>
<emp_name>King</emp_name>
<Address>
<add1>160-2</add1>
<add2>Apex Appartment</add2>
</Address>
<dept_id>10</dept_id>
<city>NJ</city>
</Row>
</Rowset>
also tell me if column has NULL value the only node disply like <add2></add2>( this is not mandatory)
please help me out
Thanks in advance

Answer 1

Here is a way to do it:
declare
XML_DATA XMLTYPE;
BEGIN
FOR v_cur IN (SELECT * FROM emp)
LOOP
SELECT dbms_xmlgen.getxmltype('select empno, ename, xmlforest (job, mgr) as ADDRESS from emp WHERE empno=' || v_cur.empno)
INTO XML_DATA
FROM DUAL;
INSERT INTO TEST_DATA VALUES (XML_DATA);
END LOOP;
END;
/change the emp to employees, and list out all the columns you want to include in xml.
in xmlforest (job, mgr), replace job, mgr columns to the columns you want to include in address segment.
Thanks
Edited by: PhoenixBai on Aug 23, 2010 11:16 PM