Generic Sync: How to register 2 Outbound Methods

Question

Hello,
i am developing a generic sync application.
I have registered a method for inbound+outbound.
It works well.Now i have a second method in the same application. I made the mapping in BWAFMAPP,but when i try to create a outbound container for the method,i get the exeption method is not registerd.
Coding:  outfactory.createOutboundContainer(VisibilityType.USER_SHARED,2_METHOD,outboundContainer.TYPE_REQUEST);
I think i have to do something in doInitialize() for the second container ,but i don't know exactly what.
Can anyone help me?
Regards

Answer 1

Hi,
go create a new class like this one:
import com.sap.ip.me.api.sync.InboundContainer;
import com.sap.ip.me.api.sync.InboundProcessor;
public class MyProc implements InboundProcessor {
     public String getMethodName() {
          return "R3_2_METHOD";
     public void process(InboundContainer inboundContainer) {
          System.out.println("Container for " + getMethodName() + " came in...");
then, register it at the Registry like this:
InboundProcessor i = new MyProc();
InboundProcessorRegistry.getInstance().register(i);
Cheers, Stefan