Get back ids based on ids having all one status

Question

I have a table
CREATE TABLE [dbo].[myTable](
[p_id] [varchar](3) NOT NULL,
[s_id] [varchar](9) NOT NULL,
[d_name] [varchar](9) NOT NULL,
[status] [varchar](1) NOT NULL)
And it has the following data.
1 1 X1 N
1 1 X2 E
1 1 X3 E
1 2 Y1 E
1 2 Y2 E
1 2 Y3 E
1 3 Z1 N
1 3 Z2 N
I would like to get the p_id and s_id where all the records for a given p_id and s_id contain status = 'N'.  That is I'm look to get back p_id = 1 and s_id = 3 because all the records contain an 'N'.
lg

Answer 1

SELECT *
FROM
SELECT *,SUM(CASE WHEN status ='N' THEN 0 ELSE 1 END) OVER (PARTITION BY p_id,s_id) AS Cnt
FROM Table
)t
WHERE Cnt = 0
Use logic like above
if you want just distinct p_id and s_id value tweak it as below
SELECT DISTINCT p_id,s_id
FROM
SELECT *,SUM(CASE WHEN status ='N' THEN 0 ELSE 1 END) OVER (PARTITION BY p_id,s_id) AS Cnt
FROM Table
)t
WHERE Cnt = 0
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