Get Excel File Name

I have an Excel Source and would like to use file name as a input column.
I noticed that I can use For Each Loop Container to get file name pass to the Excel Source, I just wanted to know does it work like flat file to get file name using advance edit?
Your help and information is great appreciated,
Regards,
Souris,

Are you looping through Excel files?
If so you already parametrized the name of the file and then use
Click on Excel Connection Manager --> go to Properties window --> Select Expression and set
ExcelFilePath with package variable User::CurrentFileName from the loop as shown below:
Reference: http://sql-bi-dev.blogspot.ca/2010/08/dynamic-ssis-package-to-import-excel.html
PS: The Excel connection does not expose the filename property that the FFC does.
Arthur My Blog

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How to capture the excel file name

Hi friends,
when i execute my program one excel sheet is getting generated.for this i have used a fm 'SAP_CONVERT_TO_XLS_FORMAT'.i want to capture that excel file name and i want to pass it to next function module as input.bcz i should not do any hard coding like passing the filename directly into the function module.
anybody have any suggestion for this.

Hi,
Here is the piece of code ....
I hope this will add some help to u...
FORM convert_xls_itab.
break devuser.
CALL FUNCTION 'TEXT_CONVERT_XLS_TO_SAP'
    EXPORTING
      i_field_seperator    = 'X'
      i_line_header        = 'X'
      i_tab_raw_data       = wa_tab
      i_filename           = p_file
    TABLES
      i_tab_converted_data = it_data
    EXCEPTIONS
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      OTHERS               = 2.
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
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ENDIF.
CALL FUNCTION 'ALSM_EXCEL_TO_INTERNAL_TABLE'
EXPORTING
FILENAME = P_FILE
I_BEGIN_COL = P_BEGCOL
I_BEGIN_ROW = P_BEGROW
I_END_COL = P_ENDCOL
I_END_ROW = P_ENDROW
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IF SY-SUBRC <> 0.
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Thanks & Regards
Ashu Singh

How do I get the file names on a customized proof sheet?

How do I get the file names on a customized proof sheet?

Actually, I really don't know what you say.
But when you see the properties of a file in Windows, you can see there are two file size. One is called "SIze" and the other one is called "Size on disk".
Therefore, I would like to know the size on disk but not just the size.

How is it posible to get the File name, size and type from a File out the H

How is it posible to get the File name, size and type from a File out the HttpServletRequest. I want to upload a File from a client and save it on a server with the client name. I want to conrole before saving the name, type and size of the file.How is it posible to get the File name, size and type from a File out the HttpServletRequest.
form JSP
<form name="form" method="post" action="procesuploading.jsp" ENCTYPE="multipart/form-data">
File: <input type="file" name="filename"/
Path: <input type="text" readonly="" name="path" value="c:"/
Saveas: <input type="text" name="saveas"/>
<input name="submit" type="submit" value="Upload" />
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proces JSP
<%@ page language="java" %>
<%@ page import="java.util.*" %>
<%@ page import="FileUploadBean" %>
<jsp:useBean id="TheBean" scope="page" class="FileUploadBean" />
<%
TheBean.doUpload(request);
%>
BEAN
import java.io.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletInputStream;
public class FileUploadBean {
public void doUpload(HttpServletRequest request) throws IOException
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Thanks it works great.
Here an excample from my code
import org.apache.commons.fileupload.*;
public class FileUploadBean extends Object implements java.io.Serializable{
String foutmelding = "geen";
String path;
String filename;
public boolean doUpload(HttpServletRequest request) throws IOException
     try
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     FileUpload upload = new FileUpload();
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     upload.setSizeThreshold(100000000);
     upload.setRepositoryPath("/");
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     List items = upload.parseRequest(request);
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     Iterator iter = items.iterator();
     while (iter.hasNext())
     FileItem item = (FileItem) iter.next();
          if (item.isFormField())
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          String filename = "";
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               filename = item.getName().substring(temp,item.getName().length());
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     catch(Exception e)
          System.out.println("er is een foutontstaan bij het opslaan de een bestand "+e);
          foutmelding = "Bestand opsturen is fout gegaan";
     return true;
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File Upload, how to get full file name

Hi Experts,
I have to get the complete file path when I use fileupload UI Element. but I am not able to achive this.
I used a File Upload UI, with filename property mapped to string variable filename and Data mapped to a binary variable filedata.
I tried to get the file name in below ways
1. wdContext.nodefile().currentfileelement.getfilename();
and
2. through modifiablebinary type also.
but in both cases I am getting only the file name, but not the complete path.
Is there any way that I can get the file path.
If I uplod a file in D drive (example.txt),
I am getting the file name as example.txt but I want to get it as D://example.txt
Please help me,
Regards,
Srinivas

Hi
What Stream are you using for read a file ?
InputStream inputStream = resource.read(false);
File filePath = new File(inputStream.toString());
wdComponentAPI.getMessageManager().reportWarning(filePath .getAbsolutePath());
Best Regards
Satish Kumar

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Hi,
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Which Function can process it ?

Hi Zheng,
FYI link which will guide you through FTP process
http://wiki.sdn.sap.com/wiki/display/Snippets/ABAPsolutiontoimplementFTP+transactions
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Hi,
I need to get the file name into odi variable like ..A/ETC/file.txt
For eg.the filename file.txt should get store in a variable.
Then i want to compare the file name stored in the variable with some other value.
Please suggest.
Thanks.

in package,
declare the variable, then evaluate it with another variable, generally using # syntax
if the variable is date type, suggest to use : syntax, because # will treat the variable value as text value
in loadplan
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Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
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Hi Experts,
i have one requirement with file name in xml file.
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treat this as Very Urgent.

Hi Bheem,
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>>i need to get the file name of file in one of the node in xml content of that file.
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<SUPPL_DETAIL>oracle.tip.esb.server.common.exceptions.BusinessEventRejectionException: Error occured while handling monitor message dequeued from monitor topic. Message text is "<activityMessages><activityMessage order='10' type='6'><flowId>cRfy7g6a-8HDUKqyf4GsKw==</flowId><subFlowId>1245307693657</subFlowId><timestamp>1245307703862</timestamp><operationGUID>2F1C13905B3F11DE8F0BD923A1148BB1</operationGUID><operationQName>ESBTest.InvokeESB</operationQName><errorMessage><![CDATA[An unhandled exception has been thrown in the ESB system. The exception reported is: "org.collaxa.thirdparty.apache.wsif.WSIFException: exception on JaxRpc invoke: serialization error: java.lang.IllegalArgumentException: getSerializer requires a Java type and/or an XML type
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        at com.collaxa.cube.ws.wsif.providers.oc4j.jaxrpc.WSIFOperation_JaxRpc.invokeRequestResponseOperation(WSIFOperation_JaxRpc.java:1460)
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        at oracle.tip.esb.server.dispatch.InitialEventDispatcher.processSubscriptions(InitialEventDispatcher.java:529)
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        at oracle.tip.esb.server.dispatch.BusinessEvent.raise(BusinessEvent.java:1467)
        at oracle.tip.esb.utils.EventUtils.raiseBusinessEvent(EventUtils.java:119)
        at oracle.tip.esb.utils.EventUtils.raiseBusinessEvent(EventUtils.java:65)
        at oracle.tip.esb.server.service.impl.inadapter.ESBListenerImpl.processMessage(ESBListenerImpl.java:722)
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        at oracle.tip.adapter.file.inbound.ProcessWork.publishMessage(ProcessWork.java:1173)
        at oracle.tip.adapter.file.inbound.ProcessWork.doTranslation(ProcessWork.java:882)
        at oracle.tip.adapter.file.inbound.ProcessWork.processMessages(ProcessWork.java:342)
        at oracle.tip.adapter.file.inbound.ProcessWork.run(ProcessWork.java:224)
        at oracle.j2ee.connector.work.WorkWrapper.runTargetWork(WorkWrapper.java:242)
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        at EDU.oswego.cs.dl.util.concurrent.PooledExecutor$Worker.run(PooledExecutor.java:825)
        at java.lang.Thread.run(Thread.java:595)
        at oracle.tip.esb.server.common.wsif.WSIFInvoker.executeOperation(WSIFInvoker.java:1020)
        at oracle.tip.esb.server.common.wsif.WSIFInvoker.nextService(WSIFInvoker.java:810)
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        at oracle.tip.esb.server.service.impl.outadapte]]></exception><retryable>false</retryable></activityMessage></activityMessages>"
at oracle.tip.esb.monitor.manager.ActivityMessageReceiver.handleMessage(ActivityMessageReceiver.java:96)
at oracle.tip.esb.server.dispatch.agent.ESBWork.process(ESBWork.java:178)
at oracle.tip.esb.server.dispatch.agent.ESBWork.run(ESBWork.java:132)
at oracle.j2ee.connector.work.WorkWrapper.runTargetWork(WorkWrapper.java:242)
at oracle.j2ee.connector.work.WorkWrapper.doWork(WorkWrapper.java:215)
at oracle.j2ee.connector.work.WorkWrapper.run(WorkWrapper.java:190)
at EDU.oswego.cs.dl.util.concurrent.PooledExecutor$Worker.run(PooledExecutor.java:825)
at java.lang.Thread.run(Thread.java:595)
Caused by: oracle.tip.esb.monitor.MonitorException: Due to the error "", the activity message could not be stored.
at oracle.tip.esb.monitor.manager.database.AbstractFaultPersister.persist(AbstractFaultPersister.java:107)
at oracle.tip.esb.monitor.manager.database.DBActivityMessageStore.persistMessage(DBActivityMessageStore.java:340)
at oracle.tip.esb.monitor.manager.database.DBActivityMessageStore.store(DBActivityMessageStore.java:131)
at oracle.tip.esb.monitor.manager.ActivityMessageReceiver.handleMessage(ActivityMessageReceiver.java:83)
... 7 more
Caused by: java.lang.NullPointerException
at oracle.tip.esb.monitor.manager.database.oracle.OracleFaultPersister.persist(OracleFaultPersister.java:102)
at oracle.tip.esb.monitor.manager.database.AbstractFaultPersister.persist(AbstractFaultPersister.java:105)
... 10 more
</SUPPL_DETAIL>
When I use the same function getRequestHeader for FileAdapter, it is working fine. Do anyone know why this issue occurs? Is this an issue with environment?

As far as I can see the problem is the invoke of the SOAP service. This could be because of an empty filename but maybe there are other issues. First, make sure that the filename is read correctly by looking it up in the BPEL runtime process. Maybe the content is different than you expected it so that the read action for the properties give wrong result. Are you sure that ehdr is the correct prefix for the ftpheader?

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How to get the File name reived through the FTP Adpater. I have created a variable with the Message type from ftpAdapterinboundheader.wsdl. from there I mapped the filename attribute to a local string variable.
But I did not receive the file name. The output in the Audit trail is as follows:
<?xml version="1.0" encoding="UTF-8" ?>
- <Invoke_File_Process_FileProcess_InputVariable>
- <part xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="InputParameters">
- <InputParameters xmlns="http://xmlns.oracle.com/pcbpel/adapter/db/PIERS/SP_FILE_PROCESS_UPDATE/">
<AS_DIR xmlns="">I</AS_DIR>
<AS_FILE_NAME xmlns="" />
</InputParameters>
</part>
</Invoke_File_Process_FileProcess_InputVariable>
Can any one let me know how to get the recevied file name from FTP adapter.
Thanks

you have to define variable of type InboundHeader_msg. Then in receive activity click on Adapter tab and for header variable chose your newly created variable (InboundHeader_msg). Once you receive message from FTP you should see in this variable fileName.

File adapter polling and getting the file name 11g Jdeveloper

I am using JDeveloper 11g. My process is something like;
A file adapter reads a XML file
This triggers the BPM process, file content is sent to start activity as message
I have to get the file name that is read by file adapter.
How to do that? Any help is appreciated.
I have seen couple of answers like bellow in forum but did not help me much
This is a very simple task in JDeveloper 11g, file adapters are linked to the receive activity, here there is a tab called Properties which you can use to extract the file name. Please follow the steps below:
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2. Open the Receive activity in your bpel project.
3. Scroll down to jca.file.FileName and double click on the value column, click on the browse button (...), select Variable, then click the search icon
4. Locate your recently created variable
5. Now when your project runs it will assign the file name to this variable, you can use this same approach also to pull the directory, file size, etc.
*************************/

hi,
Like you said.. steps are simple and clearly mentioned in guide.
1. create a variable of type string
2. after configuring the file adapter , go to corresponding receive activity , go to properties tab
3. search for a property with name as jca.file.FileName . This basically keeps track of file name
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HTH,
Ketan

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Hi
How to get the file Name at receiver side using XSLT mapping.
Could any one please help me
Regards
sowmya

Sowmya
If you will use Grpahical Mesage Mapping then this can be achieved using Adapter-Specific Attribute u201CFileNameu201D
http://help.sap.com/saphelp_nw04/helpdata/en/43/03612cdecc6e76e10000000a422035/content.htm
Code Snippet -->
DynamicConfiguration conf = (DynamicConfiguration) container
.getTransformationParameters()
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DynamicConfigurationKey key = DynamicConfigurationKey.create(
u201Chttp://sap.com/xi/XI/System/Fileu201D,
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File adapter polling and getting the file name

I have a requirement where I have to poll a file and dump the data into the DB. But while polling a file for a particular file name, I also need to get the name of the file to do some operations on the file. The file name should be passed from the adapter in order to do some operations based on the file name. Is it possible to get the file name by any chance?

Hi,
its easy to get the file name..by creating the variable for the fileAdapterInboundHeader.wsdl
just follow the below link.
http://abhishek-soablog.blogspot.com/2008/06/bpel-getting-file-name-from-file.html
Edited by: Oraacler on Mar 19, 2010 2:59 AM

Can you get the file name of the current executing TSQL script?

Can you get the file name of the current executing TSQL script? I wrote entries to a generic log file and would like to include the script name.

Okay, So What you can do is
1. Read get the version from your database and redirect it to a text file(SQLCMD outout can be directed to text file using -o option or windows redirection operator >)
2. Now you can read this value from the text file either inside a batch file or a powershell script and decide what operations you can do.
Satheesh
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Get Excel File Name

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