Get file name

Question

Hello world,
Am writing a small server application that can accept files and save them locally. Now, the server is working, but am finding it very hard to get the name of the file that's been sent so that I can save the file with that name and its extension.
e.g. I want if I sent a hello.java file, then, the server will save it as hello.java. But at the moment, its not saving it like that because there is no way can get the name of the file from the client.
Here is my code:
import java.io.*;
import java.net.*;
class Server {
    static final String ToSave = "C:\\";
    static final int PORT               = 2391;
    public static void main(String args[]) {
        while ( true ) {
            try {
                ServerSocket socketServer = new ServerSocket(PORT);
                Socket socket = socketServer.accept();
                //Assuming we have a file name (FILENAME)from client
                FileOutputStream fos = new FileOutputStream(ToSave + FILENAME);//<--HERE IS WERE i WANT THE FILENAME
                BufferedOutputStream out = new BufferedOutputStream(fos);
                BufferedInputStream in = new BufferedInputStream( socket.getInputStream() );
                int i;
                while ((i = in.read()) != -1) {
                    out.write(i);  
                out.flush();
                in.close();
                out.close();
                socket.close();
                socketServer.close();
                System.out.println("Transfer complete.");
            catch(Exception e) {
                System.out.print(  e  );
            try {
                Thread.sleep(1000);
            } catch (InterruptedException ie) {
                System.err.println("Interrupted");
}

Answer 1

You have to define a protocol which enables the
client to tell the server the file name.
BTW creating server sockets inside a loop is not a
good idea.
Thank you very much :)
I've got the idea on how to implement it now. All I have to do is:
first connect to the server and send a message containing the name of the file and then, at the server end, I will receive the name and use it to save to incoming file.
Thanks again.