Get Percentage Difference between 2 rows.

Hello. I'm trying to add a field to a report that shows the difference between 2 rows. Example.
Month Total
%diff
Aug 1000
11%
July 900
The math behind is (1000-900)/900 or 11%. I tried this:
SUM(Fields!Total.value - PREVIOUS(Fields!Total.value))/PREVIOUS(Fields!Total.value)
This would work great if I could actually use PREVIOUS w/out errors. Any ideas?
Thank you.

Hi EonHale,
According to your description, you want to calculate the growth percentage for each month. Right?
In this scenario, we just need to use current value minus previous value (use Previous function), then divide by previous value. Since it doesn't have previous value for the first records, so we can use IIF function and add condition in expression
to return a null value. We have tested in our local environment with sample data. Please try the expression below:
=IIF(Previous(Fields!Amt.Value) is nothing,nothing,(Fields!Amt.Value-previous(Fields!Amt.Value))/previous(Fields!Amt.Value))
If you have any question, please feel free to ask.
Best Regards,
Simon Hou

Similar Messages

How to get percentage difference between two matrices?

Good day everyone, I just want to ask how to get the percentage difference between two binary matrices. This is for comparing two images converted to matrices in LabView. Thank you.
Solved!
Go to Solution.

pinkman wrote:
Good day everyone, I just want to ask how to get the percentage difference between two binary matrices. This is for comparing two images converted to matrices in LabView. Thank you.
You probably converted it to a 2D array (A matrix in LabVIEW has a special meaning).
"Binary" is not very well defined (unless you are looking for the number of bits that are different). What is the datatype? Was it a color image or a greyscale image? Are both arrays the same size?
How do you define "percentage difference"? Which one of the two is the 100% reference?
Do you want a new 2D array where each element is the difference of the second array compared to the first (or vice versa), expressed in percentages?
Do you want to know what percentage of array elements are different between the two arrays?
Do you want to know the average difference between all array elements?
All possible interpretations can be easily solved with very little code, but you need to explain in more detail what you actually want?
Here is a simple solution for case #2, for example (assuming the array have the same size, and we only want a rought estimate, rounded down to the nearest integer percent):
LabVIEW Champion . Do more with less code and in less time .
Attachments:
PCT-Difference.png ‏16 KB

How to get difference between two rows for a column field?

hi, all,
Could anyone show me what query statement is to get the difference betweem two rows for two column fields?
The tables and its records are like this:
id,      begin,      end
p1         21          30
p2          45          60
p3          120          150
I would like to have the query result like this
id,    diff
p1     15    --- which is 45 minus 30
p2     60    --- which is 120 minus 60
and so on...
thank you in advance.
Raffy

You can use the LAG function to access values from previous rows:
with q as (select 'p1' id, 21 v_start, 30 v_end from dual
union all
select 'p2', 45, 60 from dual
union all
select 'p3', 120, 150 from dual)
select id, v_start, v_end, v_start - lag (v_end, 1, 0)
over (order by id) v_diff from q
ID,V_START,V_END,V_DIFF
p1,21,30,21
p2,45,60,15
p3,120,150,60
See the SQL Language doc
http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions075.htm

Difference between current row and previous row in a table

Hi All,
I am having a problem with the query. Can some of please help me?
I need to get difference between current row and previous row in a table. I have a table, which have data like bellow.
TABLEX
================
Name Date Items
AAA 01-SEP-09 100
BBB 02-SEP-09 101
CCC 03-SEP-09 200
DDD 04-SEP-09 200
EEE 05-SEP-09 400
Now I need to get output like bellow...
Name Date Items Diff-Items
AAA 01-SEP-09 100 0
BBB 02-SEP-09 101 1
CCC 03-SEP-09 200 99
DDD 04-SEP-09 200 0
EEE 05-SEP-09 400 200
Can some one help me to write a query to get above results?
Please let me know if you need more information.
Thanks a lot in advance.
We are using Oracle10G(10.2.0.1.0).
Thanks
Asif

     , nvl (items - lag (items) over (order by dt), 0)like in
SQL> with test as
2 (
3 select 'AAA' name, to_date('01-SEP-09', 'dd-MON-rr') dt, 100 items from dual union all
4 select 'BBB' name, to_date('02-SEP-09', 'dd-MON-rr') dt, 101 items from dual union all
5 select 'CCC' name, to_date('03-SEP-09', 'dd-MON-rr') dt, 200 items from dual union all
6 select 'DDD' name, to_date('04-SEP-09', 'dd-MON-rr') dt, 200 items from dual union all
7 select 'EEE' name, to_date('05-SEP-09', 'dd-MON-rr') dt, 400 items from dual
8 )
9 select name
10       , dt
11       , items
12       , nvl (items - lag (items) over (order by dt), 0)
13    from test
14 ;
NAM DT             ITEMS NVL(ITEMS-LAG(ITEMS)OVER(ORDERBYDT),0)
AAA 01-SEP-09        100                                      0
BBB 02-SEP-09        101                                      1
CCC 03-SEP-09        200                                     99
DDD 04-SEP-09        200                                      0
EEE 05-SEP-09        400                                    200
SQL>

How to get the difference between two columns in a column group

Hi All,
My first time here and really new to programming. I would like to get the difference between 2 columns that are inside
a column group.
Here is my sample table below: The Column Group is PeriodNumber and can only choose 2. like 1 and 2.. I would like to have a third row which will simply calculate the difference between the amounts in PeriodNumber 1 and 2.
PeriodNumber
Account 1 2
1) Cash 10,000 15,000
2) Receivables 12,000 11,500
3) Equipment 5,000 5,500
Total Assets 27,000 32,000

Hi yabgestopa,
From your description, you want to get the difference between two columns in a column group. After testing it in my environment, we can use custom code to achieve your requirement. For more details, you can refer to the following steps:
Copy the custom code below and paste it to your report. (Right-click report>Report Properties>Code)
Dim Shared Num1 As Integer
Dim shared Num2 As Integer
Public Function GetAmount(Amount as Integer, Type as String)
If Type = "1" Then
Num1=Amount
Else
Num2=Amount
End If
Return Amount
End Function
Public Function GetDif()
Return Num1-Num2
End function
Right-click the second column to insert a third column with Outside Group-Right.
Then use the expressions below in the matrix.
=Code.GetAmount(Fields!Amount.Value,Fields!PeriodNumber.Value)
=code.GetAmount(Sum(Fields!Amount.Value),Fields!PeriodNumber.Value)
=Code.GetDif()
The report looks like below.
If you have any questions, please feel free to ask.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Query to get the difference between 2 totals from 2 different queries

I wanted to know if it is possible to get the difference between 2 totals from 2 different queries. I would explain with an example:
1st query - Select sum(homepass) from table 1
2nd query – select sum(homepass) from table2
Is it possible to display the difference like-
Select sum(homepass) from table 1 - sum(homepass) from table2
I know the above query would gives syntax error but is there a better way or a trick to get the above task accomplished from a single query.
I hope, my question is clear.
Please revert with the reply to my query.
Regards

tomernitin wrote:
Try this one also:
WITH adtn1
AS
SELECT 110 val1 FROM dual UNION ALL
SELECT 100 FROM dual UNION ALL
SELECT 90 FROM dual UNION ALL
SELECT 10 FROM dual
adtn2
AS
SELECT 10 val2 FROM dual UNION ALL
SELECT 20 FROM dual UNION ALL
SELECT 30 FROM dual UNION ALL
SELECT 100 FROM dual
SELECT(Sum(a1.val1)-Sum(a2.val2)) Diff FROM adtn1 a1,adtn2 a2;
let me know if you still have any doubt.
Um.... I don't think so. Not with the cartesian join between a1 and 2.

Get Date Difference between 2 date values as days

Hi,
How to get the difference between 2 dates in number of days format. Say if i need the difference between 2012-08-23 and 2012-08-20 as 3
Please help..

Hi,
You can do it in XSLT since the dates are in ISO 8601 format...
http://www.w3.org/TR/NOTE-datetime
Here is a sample XSLT...
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:template match="/">
<xsl:variable name="date1" select="xs:dateTime(/root/date1)"/>
<xsl:variable name="date2" select="xs:dateTime(/root/date2)"/>
<xsl:value-of select="fn:days-from-duration($date2 - $date1)"/>
</xsl:template>
</xsl:stylesheet>The above XSLT will result *4* for the following input...
<root>
<date1>2012-01-11T00:00:00.000-05:00</date1>
<date2>2012-01-15T00:00:00.000-05:00</date2>
</root>You can test this example here...
http://xslttest.appspot.com/
Hope this helps...
Cheers,
Vlad
It is considered good etiquette to reward answerers with points (as "helpful" - 5 pts - or "correct" - 10pts)
https://forums.oracle.com/forums/ann.jspa?annID=893

Why there is a huge difference between a row size on a disk based table and a row size in memoptimized table of SQL 2014?

Hi All,
I have two table with similar structure and data, one is on disk and the other is in memory. I somehow calculated the difference between a row size of on disk and in memory table and found that the row size of in memory is 700 Bytes more than the disk based
tables.
aa

As others mentioned, memory optimized tables and disk based tables have different structures in SQL Server 2014.
For memory optimized tables, the number of indexes on table also contribute to the size. You can calculate the exact size of rows and thus the table size using the formula given in the below articles
Table and Row Size in Memory-Optimized Tables
Estimate the Size of a Table
Krishnakumar S

Do we have a way to get the differences between xtext model before and after partial parse?

Do we have a way to get the differences between xtext model before and after partial parse?
As an example i have file contains 4 lines, xtext parsed this file and generated its model, then i made small modification in line number 3, so xtext partially parsed the file and generated another model.
The question is could we get the nodes that has been deleted from the model?
could we get the new nodes added to the model?
could we get the differences between the two models?

Workflow {
bean = StandaloneSetup {
scanClassPath = true
platformUri = "${runtimeProject}/.."
// The following two lines can be removed, if Xbase is not used.
registerGeneratedEPackage = "org.eclipse.xtext.xbase.XbasePackage"
registerGenModelFile = "platform:/resource/org.eclipse.xtext.xbase/model/Xbase.genmodel"
component = ParseXextModel{
//Load the xtext model and keep the reference of the inmem model
component = DirectoryCleaner {
directory = "${runtimeProject}/src-gen"
component = DirectoryCleaner {
directory = "${runtimeProject}/model/generated"
component = DirectoryCleaner {
directory = "${runtimeProject}.ui/src-gen"
component = DirectoryCleaner {
directory = "${runtimeProject}.tests/src-gen"
component = Generator {
pathRtProject = runtimeProject
pathUiProject = "${runtimeProject}.ui"
pathTestProject = "${runtimeProject}.tests"
projectNameRt = projectName
projectNameUi = "${projectName}.ui"
encoding = encoding
language = auto-inject {
uri = grammarURI
// Java API to access grammar elements (required by several other fragments)
fragment = grammarAccess.GrammarAccessFragment auto-inject {}
// provides a compare view
fragment = compare.CompareFragment auto-inject {}
component = ParseXextModel{
//Load the xtext model again and keep the reference of the inmem model
component = CompareModel {
//Implement this using EMF Comapre to see the differnces between 2 models
}

Getting the difference between 2 dates

Hi,
I am creating a Date object (using today;s day, month and year. hours and minutes come from a config file) and getting the difference between this date and the current date and time.
My code is as follows:
I am passing 07:30 into the method as the parameter aSstart_time.
Calendar newCalendar = Calendar.getInstance(Locale.UK);
    SimpleDateFormat dtformat = new SimpleDateFormat("dd-MM-yy HH:mm");
    int lIYear = newCalendar.get(newCalendar.YEAR);
    int lIMonth = newCalendar.get(newCalendar.MONTH);
    int lIDay = newCalendar.get(newCalendar.DAY_OF_MONTH);
    String lSstartHrs = aSstart_time.substring(0,aSstart_time.indexOf(":"));
    //System.out.println(">>>>>>>>> THE HOURS IS: " + lSstartHrs);
    String lSstartMins = aSstart_time.substring(aSstart_time.indexOf(":")+1,aSstart_time.length());
    //System.out.println(">>>>>>>>> THE MINS IS: " + lSstartMins);
    java.util.Date ldStartTime = new java.util.Date(lIYear,lIMonth,lIDay, Integer.parseInt(lSstartHrs),Integer.parseInt(lSstartMins));
    System.out.println("Year: " + lIYear);
    System.out.println("Month: " + lIMonth);
    System.out.println("Day: " + lIDay);
    System.out.println("Hour: " + Integer.parseInt(lSstartHrs));
    System.out.println("Min: " + Integer.parseInt(lSstartMins));
    System.out.println("The number of milliseconds for current time is: " + newCalendar.getTime().getTime());
    System.out.println("The number of milliseconds for 07:30 is: " + ldStartTime.getTime());
    System.out.println("calendar time: " + dtformat.format(newCalendar.getTime()).toString());
    System.out.println("created time: " + dtformat.format(ldStartTime).toString());
    if(newCalendar.getTime().getTime() < ldStartTime.getTime()){
      System.out.println("The current time is less than the config time (07:30)");
    else{
      System.out.println("The time is greater than 07:30");
    }When I run this program at 10:06am I get the following output:
Year: 2006
Month: 1
Day: 15
Hour: 7
Min: 30
The number of milliseconds for current time is: 1139997962321
The number of milliseconds for 07:30 is: 61098132600000
calendar time: 15-02-06 10:06
created time: 15-02-06 07:30
The current time is less than the config time (07:30)
The Date.gettime() method should measure the number of milliseconds after 01-01-1970 so the number of milliseconds for the current time (10:06am) should be greater than the number of milliseconds for 07:30. A you can see in the above output this is not the case.
Anybody have any idea why this is happening. Am I using the .gettime() method for the correct purpose.
Any ideas or suggestions would be greatly appreciated.
Thanks

It is beacause Calendar use fully defined year as parameter, so Calendar.set(year + 1900, month, date, hrs, min) is (almost) equivalent to new Date(year, month, date, hrs, min)Example:    int year = 85; // old way of specifying a year in a Date
    int month = 3;
    int date = 12;
    int hrs = 12;
    int min = 0;
    Calendar cal = Calendar.getInstance();
    cal.set(year + 1900, month, date, hrs, min);
    Date d = new Date(year, month, date, hrs, min);
    System.out.println(d);
    System.out.println(cal.getTime());You will obtain the same date (except seconds and miliseconds in this case, as they probably won't be zero with Calendar.getInstance(); )

Trying to Get the "Difference" Between Two Tracks

What I am trying to accomplish is this: I have an audio track of a voiceover with a music bed beneath it. I also have the bed music by itsself, without the voiceover. I want only the voice portion. Is there a way that I can "cancel out" the music portion or get the difference between the two tracks (just the voice portion)? It seems that there should be some means of doing this, but for the life of me I cannot figure out how to do it!
Any advice?

If it's exactly the same music track, then as long as you line it up sample-accurate and the levels co-incide, you can do a simple subtractive process. You need both files available, trimmed to length. Open them both in Edit View, and copy one of them to the clipboard. Open the other, and select Mix-paste, and use the 'invert' option. That will effectively subtract one from the other, with the difference being your vocal.
Have to tell you though that the chances of getting this spot on are amazingly low... any errors at all leave you with bleed-through, about which you can do nothing.

How to get the difference between these two dates

Hello Friends,
I need to get the difference between these two fields which store dates but with varchar2 data types
SELECT pac.segment1, pac.segment2 emp_no, pac.segment3 NAME,
pac.segment4 POSITION, pac.segment5 start_date, pac.segment6,
pac.segment7
FROM per_analysis_criteria pac, fnd_id_flex_structures_vl ffs
WHERE ffs.id_flex_structure_code = 'Employee Rejoin'
AND ffs.id_flex_num = pac.id_flex_num
AND TO_CHAR (TO_DATE (pac.segment7, 'YYYY/MM/DD HH24:MI:SS'))
- TO_CHAR (TO_DATE (pac.segment6, 'YYYY/MM/DD HH24:MI:SS')) > 1;
my query is something like this...
am trying to find the difference between the last two columns but with not much luck..
can some one suggest me a solution please

SELECT pac.segment1, pac.segment2 person_id, pac.segment3 NAME,
papf.employee_number, paaf.supervisor_id, pac.segment4 POSITION,
pac.segment5 start_date, pac.segment6, pac.segment7,
papf2.email_address,
( TO_DATE (TO_CHAR (pac.segment7), 'DD-MON-YYYY HH:MI:SS AM')
- TO_DATE (pac.segment6, 'DD-MON-YYYY HH:MI:SS AM')
+ 1
) difference,
POST.email_address
FROM per_analysis_criteria pac,
apps.fnd_id_flex_structures_vl ffs,
per_all_people_f papf,
per_all_assignments_f paaf,
per_all_people_f papf2,
(SELECT email_address, person_id
FROM per_all_people_f
WHERE person_id IN (
SELECT person_id
FROM per_all_assignments_f
WHERE position_id IN (SELECT position_id
FROM per_positions
WHERE NAME LIKE 'HR Manager.704.')
AND TRUNC (SYSDATE) BETWEEN effective_start_date
AND effective_end_date)
AND TRUNC (SYSDATE) BETWEEN effective_start_date AND effective_end_date
AND business_group_id = fnd_profile.VALUE ('PER_BUSINESS_GROUP_ID')) POST
WHERE ffs.id_flex_structure_code = 'Employee Rejoin'
AND TO_CHAR (papf.person_id) = pac.segment2
AND ffs.id_flex_num = pac.id_flex_num
AND TRUNC (SYSDATE) BETWEEN papf.effective_start_date
AND papf.effective_end_date
AND papf.current_employee_flag = 'Y'
AND papf.person_id = paaf.person_id
AND TRUNC (SYSDATE) BETWEEN paaf.effective_start_date
AND paaf.effective_end_date
AND papf.person_id = paaf.person_id
AND papf2.person_id = paaf.supervisor_id
AND paaf.primary_flag = 'Y'
AND TRUNC (SYSDATE) BETWEEN papf2.effective_start_date
AND papf2.effective_end_date
AND papf2.current_employee_flag = 'Y'
and ( TO_DATE(to_char(pac.segment7), 'DD-MON-YYYY HH:MI:SS AM')-TO_DATE (pac.segment6, 'DD-MON-YYYY HH:MI:SS AM')+1) >1
last line is giving me the error pls suggest a solution

Java code to get the difference between two dates in days

Hi ppl,
I need to write a user defined function to get the difference between two date nodes, in days.Please help me out
regards,
Prashanth

Hi,
have a look at those two:
(How do I calculate the difference between two dates?)
http://joda-time.sourceforge.net/faq.html
Calculating the Difference Between Two Datetime Stamps
http://www.xmission.com/~goodhill/dates/deltaDates.html
Get difference in days
http://javaalmanac.com/egs/java.util/CompDates.html
Regards,
michal

How to get the difference between two HashMaps

i have two HashMaps
HashMap first = new HashMap<Integer,Object>();
HashMap second = new HashMap<Integer,Object>();
How to get the difference between one and two and put the result in the third
HashMap third = new HashMap<Integer,Object>();

My bad, difference of course means removeAll():Map<Integer,Object> first = new HashMap<Integer,Object>();
Map<Integer,Object> second = new HashMap<Integer,Object>();
Map<Integer,Object> third = new HashMap<Integer, Object>(first);
third.keySet().removeAll(second.keySet());No loops needed.

How to get the difference between two date

Hello,
I want to know how to write a code the tell me the difference between two date, I am using
oracle.jbo.domain.Date
i have a rent date and return date so my code is
Date rent=(Date)nr.getAttrbute("RentDate"),ret=(Date)nr.getAttrbute("ReturnDate");
is there a way to know the difference in days between those two dates ?
Thanks

hi,
try this.....
DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
Date date = (Date)formatter.parse(dateStr); //// dateStr <- from date value (that is string value)
Date dateto = (Date)formatter.parse(datetostr); //// datetostr <- to date value (to date getting from as a string)
Calendar cal = Calendar.getInstance();
cal.setTime(date);
Calendar calto = Calendar.getInstance();
calto.setTime(dateto);
fromDate = cal.get(Calendar.DATE) + "/" + (cal.get(Calendar.MONTH) + 1) + "/" + cal.get(Calendar.YEAR);
toDate = calto.get(Calendar.DATE) + "/" + (calto.get(Calendar.MONTH) + 1) + "/" + calto.get(Calendar.YEAR);
// System.out.println("from Date : " + fromDate);
if ((fromDate != null && toDate != null) && (date.compareTo(dateto) > -1) ) {
fc.addMessage("VacationQueryComponent", new FacesMessage(FacesMessage.SEVERITY_ERROR, "From Date cannot be lower than To Date", "From Date cannot be lower than To Date"));
fc.renderResponse();
thks.

Get Percentage Difference between 2 rows.

Similar Messages

Maybe you are looking for