Getting an error while selecting from table having CLOB column.
Hi All,
I have below table created in My oracle database version Oracle Database 11g Enterprise Edition Release 11.2.0.1.0.
CREATE TABLE my_clob -- Dummy table created
(DataBody CLOB);
Current Database Character set - WE8MSWIN1250.
On the front end of my application, I have one form through which I can save/edit data in the above table. If I'm creating one new entry in the above table then it first check with existing record to avoid the duplicate entry and the this point application create the below select statement on the above table and return the error "ORA-00932: inconsistent data types: expected - got CLOB".
I can not change the sql statement.
SELECT * FROM my_clob WHERE databody IS NULL OR databody ='';
Even when I run the same statement on my DB server I’m getting the same error. Shown below
SQL> SELECT * FROM my_clob WHERE databody IS NULL OR databody ='';
SELECT * FROM my_clob WHERE databody IS NULL OR databody =''
ERROR at line 1:
ORA-00932: inconsistent datatypes: expected - got CLOB
SQL>
Is there anything with OraOLEDB which causing this error? Please help me out to get rid of this error.
Thanks,
Santosh
You cannot compare directly a CLOB column with a VARCHAR2 column. In your case you don't need to do such comparison because Oracle consider zero length strings as null values:
SQL> create table my_clob(data int, databody clob);
Table created.
SQL> insert into my_clob values(1, null);
1 row created.
SQL> insert into my_clob values(2, '');
1 row created.
SQL> commit;
Commit complete.
SQL> select * from my_clob where databody is null;
DATA
DATABODY
1
2About null values in Oracle, please read http://docs.oracle.com/cd/E11882_01/server.112/e26088/sql_elements005.htm#SQLRF30037.
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SQL> create type string_table is table of varchar(100);
2 /
Type created.
declare
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v_names.EXTEND(3);
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v_names(2) := 'name2';
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But, I don't think INTO Clause is mandatory here.
Please check your modified code (w/o INTO) and the output :
DECLARE
TYPE string_table IS TABLE OF VARCHAR (100);
v_names string_table := string_table ();
v_test string_table := string_table ();
BEGIN
v_names.EXTEND (3);
v_names (1) := 'name1';
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DBMS_OUTPUT.put_line (CHR(10));
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Old collection - name3
Old collection - 3
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In FOR Loop --- name2
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Edited by: ranit B on Dec 26, 2012 2:29 PM
-- code modified
Edited by: ranit B on Dec 26, 2012 2:45 PM
-- code 'again' updated -- FOR LOOP added -
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Can someone explain why the error near the bottom of the code below is occuring? If USER1 grants SELECT on the external table to USER2, then USER2 can select from the view without any problems; however, I want to avoid giving USER2 access to all of the columns in the external table. (I only want to give USER2 access to two of the four columns.)
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FIELDS TERMINATED BY ','
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{code}user503699 wrote:
user1983440 wrote:
Can someone explain why the error near the bottom of the code below is occuring? If USER1 grants SELECT on the external table to USER2, then USER2 can select from the view without any problems; however, I want to avoid giving USER2 access to all of the columns in the external table. (I only want to give USER2 access to two of the four columns.)As you have demonstrated, I guess the view approach only works for database tables. External tables are actually files on the file system. Even through OS, it is not possible to grant READ/WRITE access to only part of the file. The access is for entire file. An "External Table" is just a "wrapper" provided by oracle (using data cartridge) to allow user to be able to access the file as a "table". So it can definitely not do something that underlying OS can not do.
p.s. In fact, oracle does not even allow to edit data in external tables using SQL.Why not just make a second external table (only including the 2 columns you need) and grant select directly on that to the user. I know you say "views only" but there's an exception to every rule ... just because it's called a table doesn't make it so. You could argue an external table is nothing more than a fancy view.
Worst case, make a view on top of the second external table.
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last_name VARCHAR2(30)
ORGANIZATION EXTERNAL
TYPE ORACLE_LOADER
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OPTIONALLY ENCLOSED BY '"'
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229|1|506460|SIGROUP |4890|100|0|0|10:31:01|2007/12/17|M009|20191395001|L|B|12|CLIENT|INE547A01012|10:31:00|
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SQL> CREATE TABLE TEMP_SAUDA
2 (S_A VARCHAR2(20),
3 S_TYPE VARCHAR2(20),
4 S_CO VARCHAR2(20),
5 S_CONAME VARCHAR2(40),
6 S_RATE NUMBER,
7 S_QTY NUMBER,
8 S_G NUMBER,
9 S_H NUMBER,
10 S_TIME TIMESTAMP WITH TIME ZONE,
11 S_DATE DATE,
12 S_PCODE VARCHAR2(20),
13 S_SETNO VARCHAR2(20),
14 S_M VARCHAR2(20),
15 S_N VARCHAR2(20),
16 S_O VARCHAR2(20),
17 S_CLIENTOWN VARCHAR2(10),
18 S_ISIN VARCHAR2(12),
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21 ORGANIZATION EXTERNAL
22 (TYPE oracle_loader
23 DEFAULT DIRECTORY BSE17122007
24 ACCESS PARAMETERS
25 (RECORDS DELIMITED BY NEWLINE
26 FIELDS
27 (
28 S_A CHAR(20),
29 S_TYPE CHAR(20),
30 S_CO CHAR(20),
31 S_CONAME CHAR(20),
32 S_RATE CHAR(20),
33 S_QTY CHAR(20),
34 S_G CHAR(20),
35 S_H CHAR(20),
36 S_TIME CHAR(35) date_format TIMESTAMP WITH TIMEZONE mask "DD-MON-RR HH.MI.SSXFF AM TZH:TZM
37 S_DATE CHAR(22) date_format DATE mask "mm/dd/yyyy hh:mi:ss ",
38 S_PCODE CHAR(20),
39 S_SETNO CHAR(20),
40 S_M CHAR(20),
41 S_N CHAR(20),
42 S_O CHAR(20),
43 S_CLIENTOWN CHAR(20),
44 S_ISIN CHAR(20),
45 S_ORDER_TIME date_format TIMESTAMP WITH TIMEZONE mask "DD-MON-RR HH.MI.SSXFF AM TZH:TZM"
46 )
47 )
48 location (BSE17122007:'BR171207.DAT')
49 )
50 ;
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SELECT * FROM TEMP_SAUDA
ERROR at line 1:
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binary_float, comma, char, date, defaultif, decimal, double, float, integer, (,
nullif, oracle_date, oracle_number, position, raw, recnum, ), unsigned,
varrawc, varchar, varraw, varcharc, zoned"
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Is there any mistake in this table creation.
what i have to declare to the time format if the format in the file id hh:mm:ss
Thank u...!
RaviThe output you posted is completely wrong, I could not even create the table without errors.
Try with this.
CREATE TABLE TEMP_SAUDA
(S_A VARCHAR2(20),
S_TYPE VARCHAR2(20),
S_CO VARCHAR2(20),
S_CONAME VARCHAR2(40),
S_RATE NUMBER,
S_QTY NUMBER,
S_G NUMBER,
S_H NUMBER,
S_TIME TIMESTAMP WITH TIME ZONE,
S_DATE DATE,
S_PCODE VARCHAR2(20),
S_SETNO VARCHAR2(20),
S_M VARCHAR2(20),
S_N VARCHAR2(20),
S_O VARCHAR2(20),
S_CLIENTOWN VARCHAR2(10),
S_ISIN VARCHAR2(12),
S_ORDER_TIME TIMESTAMP WITH TIME ZONE
ORGANIZATION EXTERNAL
(TYPE oracle_loader
DEFAULT DIRECTORY BSE17122007
ACCESS PARAMETERS
(RECORDS DELIMITED BY NEWLINE
FIELDS terminated by "|"
S_A CHAR(20),
S_TYPE CHAR(20),
S_CO CHAR(20),
S_CONAME CHAR(20),
S_RATE CHAR(20),
S_QTY CHAR(20),
S_G CHAR(20),
S_H CHAR(20),
S_TIME CHAR(8) date_format TIMESTAMP WITH TIMEZONE mask "HH.MI.SSXFF AM TZH:TZM",
S_DATE CHAR(10) date_format DATE mask "yyyy/mm/dd",
S_PCODE CHAR(20),
S_SETNO CHAR(20),
S_M CHAR(20),
S_N CHAR(20),
S_O CHAR(20),
S_CLIENTOWN CHAR(20),
S_ISIN CHAR(20),
S_ORDER_TIME char(8) date_format TIMESTAMP WITH TIMEZONE mask "HH.MI.SSXFF AM TZH:TZM"
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;With this you get:
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01-JAN-08 10.31.01.000000 AM +00:00 17.DEC.2007 00:00:00 01-JAN-08 10.31.00.000000 AM +00:00
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TNS for 32-bit Windows: Version 11.2.0.3.0 - Production
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data lt_rkrp like hashed table of wa_rkrp
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Regards,
MuinulHi
Have you ever been able to deploy into SDM. What is the password that you type. Try typing SDM and see. If that doesnt work then you will have to change the password of your SDM. Your password either has been corrupted or changed
Anyway follow these steps
1. Start the Config Tool.
(Execute <SAPj2eeEngine_install_dir> \configtool\configtool.bat.)
1. Select the secure store node.
The configuration for the secure storage in the file system appears.
1. Select the admin/password/<SID> entry.
2. Enter the administrator user's new password in the "Value" field and choose "Add".
3. Choose "File" --> "Apply" to save the data.
Note: Contrary to the message that appears, you do not need to restart the server or cluster for this change to take effect.
4. Finally restart SDM server.
Hope that helps. Let me know if you require more information
regards
Ravi -
Error while filling setup tables for 2lis_13_vahdr
Dear friends,
I am getting below Error while filling setup tables for 2lis_13_vahdr.
More faulty documents found than the tolerated 0000000000
Message no. M2222
Can any one guide me how to address this issue.
Thanks and Regards
NithyaHello Nithya,
It seems the No of tolerated faulty documents that you have given is 0. So when you initialize try to these.
While executing OLI*BW including a value in the maintain "No. tolerated faulty documents" - 5000 or 10000.
Then execute the program in background.
Once the job is completed check the background job log if any errors.
Thanks
Chandran
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