Getting Column names (header) of a table dynamically
Dear Experts,
Greetings.
I have a requirement in which I need to get the column name (header) of a table when the user clicks on a column.
Kindly suggest me the possible ways.
Thanks in advance.
Regards
Sathya
Hi,
use one of the following based on your requirement
Bind the header text to a context attribute and access this attribute from code when clicked on the column.
Or use parameter mapping.
Regards
Ayyapparaj
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Can any one suggests me a way to get column names from a particular table of a database from the java.sql.Connection object. ?
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DatabaseMetaData metadata = connection.getMetaData();
String[] names = {"TABLE"};
ResultSet tables = metadata.getTables(null,"%", "%", names);
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Error 4101 Description:
Execute SQL - The connection, statement, or query handle you provided is not valid.
I don't just used the toolkit in a while,now, I am developing a irrigation system. For the table field names defined by users,column names must be known before any select operations. Do you have any other good idea about drawing out the columnname parameters?
As you know, a valid DSN and table have been also available. The database I used is Access. The bad thing to me is that there is no any text information gotten. And I think, it may be some problems in connection way which I don't find out.
Really appreciated by your reply.
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There is a requirement to set the Header of a column group in a Advanced table dynamically by fetching the values from a view attribute.
Code :
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Analysis:
the same piece of code works for
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Hi,
Could someone help me how to get column names in EJB3.0.
I am having reference to folloiwng ejb.
@Entity
@Table(name = "users")
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@SequenceGenerator(name = "users", sequenceName = "users")
public class User {
private Long userId;
private String username;
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@GeneratedValue(strategy = GenerationType.AUTO, generator = "users_seq")
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public void setUserId(Long userId) {
this.userId = userId;
@NotNull
@Column(name = "username")
public String getUsername() {
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You need to know the object, the schema, and how to map one to the other.
So you should look at the SQL table "users" and map this object to it.
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Hi,
I have MS Access intalled in my desktop.I am using aveConnect jdbc driver to connect to MS Access database.
I am trying to retrieve all the table name and column names of respective tables .
But when i get column name as empty string when i try to retrieve the column name of a table.
here is the sample code i use.
I am getting the column count of a particular table and type of the column.
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sheebaYou're here in a JDBC forum, not a SQL forum. I suggest you to start learning SQL and come back once you have JDBC issues.
Here is a list of links to all SQL tutorials available on the Internet.
http://www.google.com/search?q=sql+tutorial -
Getting column names from cursor
Hi all
I have procedure which produces list of applied for jobs web page(using htp. package)
I got result in cursor, but have to provide dinamic sort, based on colimn pressed
procedure my_application_list
(pi_resume_num in varchar2 default null
,pi_sort_col in varchar2 default null
,pi_page_no in varchar2 default null
,pi_action in varchar2 default null
,pi_msg in varchar2 default null
is
CURSOR cur_job IS
SELECT jtl.JOB_TITLE
,jtl.COMPANY_NAME
,a.APPLY_DATE
,a.lang
,a.job_id
FROM job_tl jtl, applied_for_job a, gateway gt
WHERE a.job_seeker_id=app.job_Seeker
AND a.job_id=jtl.job_id
AND a.lang=jtl.lang
AND a.gateway=gt.gateway
AND jtl.lang=(SELECT substr(MIN(lt.order_list||jtl0.lang),2) lang
FROM job_tl jtl0
,language_tl lt
WHERE jtl0.job_id = a.job_id
AND jtl0.lang=lt.lang
AND lt.gui_lang=app.language)
ORDER BY pi_sort_col
rest of code
The columns displayed in web page are Job_title, Company_name and Applied_date
This page is displyed well, bu without column nmes at the top. I am trying to get column names from cursor in order to have ORDER BY <pi_sort_col>
can someone help how i can get those column names:Job_title, Company_name and Applied_date
User will be able to click on column and sort
Thank in advance .I appreciate any helpHi Francisco
Here is my code
CREATE OR REPLACE PACKAGE BODY cc_web_application_list
IS
TYPE COL_NAME_LIST IS TABLE OF VARCHAR2(100)
INDEX BY BINARY_INTEGER;
TYPE COL_ORDER_LIST IS TABLE OF VARCHAR2(30)
INDEX BY BINARY_INTEGER;
col_name_t col_name_list;
col_order_t col_order_list;
procedure my_application_list
(pi_resume_num in varchar2 default null
,pi_sort_col in varchar2 default null
,pi_page_no in varchar2 default null
,pi_action in varchar2 default null
,pi_msg in varchar2 default null
is
l_my_page_no PLS_INTEGER := TO_NUMBER(nvl(pi_page_no,1));
l_js_name gam_user.username%TYPE;
l_js_first_name gam_user.first_name%TYPE;
l_cnt PLS_INTEGER := 0;
l_scr_lines PLS_INTEGER := 0;
l_curline PLS_INTEGER;
l_jobs_applied PLS_INTEGER;
l_total_rec PLS_INTEGER;
l_total_pages PLS_INTEGER;
l_pos PLS_INTEGER;
l_first PLS_INTEGER :=0;
last PLS_INTEGER :=0;
l_lines PLS_INTEGER := 10;
col_name VARCHAR2(100) := col_name_t(3) ;
col_order VARCHAR2(30) := 'DESC';
str VARCHAR2(2000);
TYPE display_rec IS TABLE OF VARCHAR2(500) INDEX BY BINARY_INTEGER;
display display_rec;
TYPE page_table_type IS TABLE OF PLS_INTEGER INDEX BY BINARY_INTEGER;
page_number page_table_type;
CURSOR cur_job IS
SELECT jtl.JOB_TITLE job_title
,jtl.COMPANY_NAME company_name
,a.APPLY_DATE apply_date
,a.lang
,a.job_id
FROM job_tl jtl, applied_for_job a, gateway gt
WHERE a.job_seeker_id=app.job_Seeker
AND a.job_id=jtl.job_id
AND a.lang=jtl.lang
AND a.gateway=gt.gateway
ORDER BY a.apply_date;
This decode is a problem
decode(col_order,'ASC'
,decode(col_name
,col_name_t(1), jtl.job_title
,col_name_t(2), jtl.company_name
,col_name_t(3), TO_CHAR(a.apply_date, 'YYYYMMDDhh24miss')
,a.apply_date)
) ASC
,decode(col_order,'DESC'
,decode(col_name
,col_name_t(1), jtl.job_title
,col_name_t(2), jtl.company_name
,col_name_t(3), TO_CHAR(a.apply_date, 'YYYYMMDDhh24miss')
,a.apply_date)
) DESC
,a.apply_date
TYPE rec_one IS TABLE OF cur_job%ROWTYPE INDEX BY BINARY_INTEGER;
r rec_one;
BEGIN
BEGIN
SELECT username,first_name
INTO l_js_name,l_js_first_name
FROM gam_user
WHERE user_id = App.job_seeker;
EXCEPTION
WHEN OTHERS THEN NULL;
END;
Cc_Pkg_Elements.p_page_top_job_seeker(
'Personal Job List'
,REPLACE(Txt_Proc_My_Joblist.title_job_list
,'##first_name##',l_js_first_name),'N' ,TRUE ,'Pxx');
----- get numer of records returned by query
SELECT COUNT(1)
INTO l_total_rec
FROM job_tl jtl,applied_for_job a
,gateway gt
WHERE a.job_id = jtl.job_id
AND a.job_seeker_id = App.job_seeker
AND a.gateway = gt.gateway ;
------get number of pages
l_total_pages:=CEIL (l_total_rec/l_lines);
l_jobs_applied := 0;
col_name := pi_sort_col;
col_order := pi_sort_col;
--get first positions
l_first := (nvl(l_my_page_no,1) - 1) * l_lines + 1;
FOR rec IN cur_job LOOP
l_cnt := l_cnt + 1;
EXIT WHEN l_cnt > l_first + l_lines - 1;
IF l_cnt >= l_first THEN
l_scr_lines := l_scr_lines + 1;
r(l_scr_lines) := rec; --assign counter from loop to r index
IF rec.apply_date IS NOT NULL THEN
l_jobs_applied := l_jobs_applied + 1;
END IF;
END IF;
END LOOP;
htp.p('<FORM ACTION="'||App.gateway||'8.my_application_list" METHOD="post">');
htp.p('<table align="center">');
htp.p('<tr><td>');
IF r.COUNT = 0 THEN
Web_Pkg_Elements.doc_msg(Txt_Proc_My_Joblist.no_jobs);
END IF;
htp.p('</td></tr>');
htp.p('</table>');
--table_heading(col_name ,col_order );
htp.p('<table align=center>');
htp.p('<tr align="center"><td>');
FOR i IN 1..l_total_pages LOOP
page_number(i) := i;
IF page_number(i) = l_total_pages THEN
htp.p('');
||'');
Web_Pkg_Elements.doc_val_small(page_number(i)||'</A>');
ELSE
htp.p('');
|'||'');
Web_Pkg_Elements.doc_val_small(page_number(i)||' |'||'</A>');
END IF;
END LOOP;
htp.p('</td></tr>');
htp.p('</table>');
htp.p('<table align=center>');
FOR l_curline IN 1..l_scr_lines LOOP
display(1) := NVL(r(l_curline).job_title, '<br>');
display(2) := NVL(r(l_curline).company_name, '<br>');
display(3) := NVL(Cc_Pkg_Nls.date2char(r(l_curline).apply_date, App.date_format), '<br>');
IF MOD(l_curline, 2) = 0 THEN
Cc_Pkg_Elements.tr_even;
ELSE
Cc_Pkg_Elements.tr_odd;
END IF;
htp.p('<td>');
htp.p('');
Web_Pkg_Elements.doc_val(display(1)||'');
htp.p('</td>');
htp.p('<td>');
Web_Pkg_Elements.doc_val(display(2));
htp.p('</td>');
htp.p(' <td>');
Web_Pkg_Elements.doc_val(display(3));
htp.p(' </td>');
htp.p('</tr>');
END LOOP;
htp.p('</TABLE>');
htp.p('<TABLE width="88%" BORDER="0" CELLPADDING="0" CELLSPACING="0"
align="center">');
htp.p('<tr valign=bottom>');
htp.p('<TD colspan=2 align=right>');
IF l_my_page_no > 1 THEN
htp.p('<P>'||'<IMG SRC="'||App.image||'prev.gif" ALT="'
||Txt_Proc_My_Joblist.prev
||'"' ||' HEIGHT=20 BORDER=0 ALIGN=bottom '
||'hspace=2>');
END IF;
IF l_my_page_no < CEIL (l_total_rec/l_lines) THEN
htp.p(' <a href="'||
web_pkg_elements.link$$(App.gateway||'8.my_application_list?'
||'pi_sort_col='||Web_Pkg_Elements.replace_in_url(pi_sort_col)
||'&pi_msg=&pi_page_no='||TO_CHAR(l_my_page_no + 1)
||">'||'<IMG SRC="'||App.image||'next.gif" ALT="'
||Txt_Proc_My_Joblist.NEXT
||'"' ||' HEIGHT=20 BORDER=0 ALIGN=bottom '
||'hspace=2></a>');
END IF;
htp.p('</TD>');
htp.p('</TR>');
htp.p(' </TABLE>');
htp.formHidden('pi_sort_col', pi_sort_col);
htp.formHidden('pi_page_no', pi_page_no);
htp.p('</FORM>');
END my_application_list;
END ; --cc_pkg_application_list -
I have done extensive programming with the SQL Toolkit with LabVIEW versions through 6.1. My customer now wants to upgrade to Windows 7, so I am trying to upgrade to LabVIEW 2009 (my latest purchased version) using the Database Connectivity Toolkit, and the SQL Toolkit Compatibility vis. Everything seemed to be going okay with the higher level SQL operations, but I ran into trouble with the Get Column Name.vi.
The pictures below show the problem. The original SQL Toolkit connected the Prepare SQL.vi with the Get Column Name.vi with a cluster of two references, one for connection, and one for sql. The new compatibility vis have a class conflict in the wire because the Prepare SQL.vi contains a cluster with connection, and command references, but the Get Column Name.vi expects a cluster with connection and recordset references.
How do I resolve this conflict?
Thank You.
DanI've never worked with the old version of the toolkit, so I don't know how it did things, but looking inside the SQL prep VI, it only generates a command, and the the column name VI wants a recordset. I'm not super familiar with all the internals of ADO, but my understanding is that is standard - you only have the columns after you execute the command and get the recordset back. What you can apparently do here is insert the Execute Prepared SQL VI in the middle and that will return what you need.
I'm not sure why it worked before. Maybe the execute was hidden inside the prep VI or maybe you can get the column names out of the command object before execution. In general, I would recommend considering switching to the newer VIs.
Try to take over the world! -
How to get column names for a specific view in the scheme?
how to get column names for a specific view in the scheme?
TIA
Don't have DD on the wall anymore....or this?
SQL> select text from ALL_VIEWS
2 where VIEW_NAME
3 ='EMP_VIEW';
TEXT
SELECT empno,ename FROM EMP
WHERE empno=10 -
Jakata POI excel: get column name
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Is there a way I can get column name where a particular cell is: (In excel spreadsheet)
Ex: If I have column number 2: I should get "C" ( given col numbers are 0 based).
Please let me know.
Thanks
bibIt's not as easy as it might seem, since the letter sequence system is not compatible with common numeric sequence system.
See here:
[Java, POI - Converting number to Excel columns letter names|http://ondra.zizka.cz/stranky/programovani/java/converting_number_to_excel_column_letters_name.texy] -
Get column names into a VB program, for an SQL query that joins tables
use [mydatabase]
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left join _btblInvoiceLines ilin
on inum.autoindex = ilin.iinvoiceid
left join stkitem s
on ilin.istockcodeid = s.stocklink where InvNumber = 'IVQ0834' or InvNumber = 'IVQ0835'
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I want to use something like:
select column_name from information_schema.columns where TABLE_NAME = ....
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Dim reader As SqlDataReader = command.ExecuteReader()
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Console.WriteLine(reader.GetName(x))
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Dan Guzman, SQL Server MVP, http://www.dbdelta.com -
How to get column names in table maintenance dialog?
I created a new Z table and created a maintanance dialog so that I can maintain the table through sm30. i don't see columns names on maintenance screen, just a "+" sign for each column! Could someone please tell me how to display column name?
Thanks.
MithunHello Mithun
The column texts are taken from the field descriptions of the data elements used in your z-table. A "+" sign usually indicates that none of the field descriptions of the data element has been maintained.
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How to get column names as value in the target table ?
Hello All,
I want your help to solve my problem. Any suggestions are welcomed.
Problem - I have source data in Microsoft Excel in following format,
Ids q12 q13 q14
10001 1 1 2
10002 2 4 1
In my target table , which is in Oracle i want data in following format,
IDs Question Answer
10001 q12 1
10001 q13 1
10001 q14 2
10002 q12 2
10002 q13 4
10002 q14 1
In table i have q12, q13, q14 as column names, Now i want to fill q12, q13,
q14 as values of one of the column ( Question ) in my target table.
Note - I don't want to hard code the values ... is there any way i achieve this?
Thanks in Advance.
AC1. Create a staging table with 4 columns. Ids,q12,q13 and q14
2. Create a main table in the format you want ie., Ids, question and answer
3. Load the Excel after converting into CSV using SQLLDR into the staging table.
4. Then move the data from staging to main as below
insert into main(ids,question,answer)
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union all
select ids,'q13',q13 from table1
union all
select ids,'q14',q14 from table1)There might be someother easier way to achieve this. But i dont think you can use SQLLDR to load the data denormalized like you have mentioned. But you can write a procedure which reads the file using UTL_FILE and insert into the table.
Message was edited by:
Mohana Kumari -
Using Column Name in a Second Table
I have two tables in a sheet, Data and Report. Data contains a column named Hours. How can I write a sum function in the Report table that sums the values in the Hours column in Data? I'd like to use a named reference instead of a row/column letter/number range for when the Hours column gets longer.
David Benman1 wrote:
Thanks. I tried what you said, but initially it didn't work. I realized I needed to make the top row a header row, but that leads to a new question. All my columns now can be reference by name except the first column. Is there anything special I need to do to the first column? If the first column is "Hours", then when I type in "Hours" in my formula, the spreadsheet doesn't recognize it as a column name.
Yes, you must read the User Guide which explains :
Yvan KOENIG (VALLAURIS, France) 2 septembre 2010 12:06:03
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