Getting count of days

I have a query...
SELECT
to_char(t.traffichour, 'Day') as theDay,
to_char(t.traffichour, 'D') as day,
to_char(t.traffichour, 'hh24') as hour,
Round(100*SafeDivide(sum(t.traffic) over ( PARTITION BY to_char(t.traffichour, 'D'), to_char(t.traffichour, 'hh24') ),sum(t.traffic) over ( PARTITION BY to_char(t.traffichour, 'D') ))) as pct, traffic
FROM
traffic.traffic_stage t,
store_info b
WHERE t.store_id = b.unitynbr
AND b.pslocation = 2838
AND trunc(t.TRAFFICHOUR) > sysdate - 180
that returns the day name, number, hour of day, a traffic number and percentage over the past 180 days..
How can I get the count of the days also.. for example how many mondays, tuesdays, wednesdays, etc have there been in the past 180 days?
I tried
count(to_char(t.traffichour, 'D') over (partition by trunc(t.traffichour)) as dayCount,
but to_char in count(to_char(t.traffichour,'D') gets hightlighted and I get 'window function not allowed here'..
Thanks guys!

Hi,
Try this:
SQL> l
1 select count(to_char(date#,'d')) as NumDay, to_char(date#,'DAY') day#
2     from (select sysdate-delay+level as date#
3           from (select &delay+1 as delay from dual)
4           connect by level <= delay)
5 group by to_char(date#,'DAY'),to_char(date#,'d')
6* order by to_char(date#,'d')
SQL> /
Enter value for delay: 180
old   3:          from (select &delay+1 as delay from dual)
new   3:          from (select 180+1 as delay from dual)
    NUMDAY DAY#
        26 MONDAY
        26 TUESDAY
        26 WEDNESDAY
        26 THURSDAY
        25 FRIDAY
        26 SATURDAY
        26 SUNDAY
7 rows selected.
SQL> /
Enter value for delay: 7
old   3:          from (select &delay+1 as delay from dual)
new   3:          from (select 7+1 as delay from dual)
    NUMDAY DAY#
         1 MONDAY
         1 TUESDAY
         1 WEDNESDAY
         2 THURSDAY <-- Today and today-7 (29 dec. 05)
         1 FRIDAY
         1 SATURDAY
         1 SUNDAY
7 rows selected.
SQL> Nicolas.
Message was edited by:
N. Gasparotto

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