Getting first row in a group by order by sql

Question

Hi all,
I'm having problems with the query below. What I want is to get a count of hotelid and group it then take the top result. My problem is that the version of oracle that I'm using is giving me errors because of the nested group by, order by. Is there any way around this?
SELECT *
FROM (SELECT agentid, hotelid, COUNT(hotelid) AS COUNT
FROM akorders a, akworklist_summary b
WHERE a.agentid = 1408946 AND
a.akorderid = b.akorderid
GROUP BY agentid, hotelid
ORDER BY COUNT DESC)
WHERE ROWNUM < 2
TIA!
Brian

Answer 1

SELECT agentid, hotelid, COUNT(hotelid) AS COUNT
FROM akorders a, akworklist_summary b
WHERE a.agentid = 1408946 AND
a.akorderid = b.akorderid
GROUP BY agentid, hotelid
HAVING COUNT(*) = (SELECT MAX(icount)
                   FROM (SELECT agentid, hotelid, COUNT(hotelid) AS icount
                         FROM akorders a, akworklist_summary b
                         WHERE a.agentid = 1408946 AND
                               a.akorderid = b.akorderid
                               GROUP BY agentid, hotelid ))