Getting jar file name with wrapper

Question

Hi,
I'm using [java service wrapper|http://wrapper.tanukisoftware.org/] to launch my project,
with the command
File jarFile = new File(main.class.getProtectionDomain().getCodeSource()
          .getLocation().toString());witch opens the jar file name, this command returns the following
file:C:/wrapper/../lib/project.jar
this string raises the exception java.lang.IllegalArgumentException: URI is not hierarchical
Is there any other why to get the application jar name ?, thanks

Answer 1

Hi, the is the answer of my previous question
     public static String getJarNameURI () {
         String pathrojar = main.class.getProtectionDomain().getCodeSource()
                 .getLocation().toString();
         if (pathrojar.charAt(5) != '/')
            pathrojar = pathrojar.replace(":", ":/");
         return URI.create(pathrojar).normalize().toString();
File jarFile = new File(getJarNameURI ());