Getting the shortest match using regex

Hi,
I'm wondering how I can get the shortest match when I use the Matcher.find() method. For example, lets say my string is "AAAAB" and my pattern is "A+". after I call Matcher.find() i get "AAAA" when I call Matcher.group(). I want to get "A", then call it again and get "A", and so on.
What I'm trying to do is read a string and tokenize into pieces that match the regular expresion that I have.
Any help is appreciated. Thanks,
ranko

ok, to answer my own question it seems that using nongreedy matching works. adding a questionmark after a quantifier accomplishes this. so in my case I would use A+?.

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Getting the shortest match using regex

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