Getting user name from sopa header

How should get user name from soap header in my udf...?i searched in sdn,but not get exact solution...

I din't get this with SRemoteUser
1. i've enabled " Do Not Use SOAP Envolope"
2.Enabled ASMA
3.Variable Transport Binding .
used the following code as well:
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey user = DynamicConfigurationKey.create( "http://sap.com/xi/XI/System/SOAP", "SRemoteUser");
conf.get(user);
But not value in it.. Correct me if iam wrong..

Similar Messages

Get user name from ID

is there a way to get a user's name from their ID? This arises from sending an email from a workflow for activities. You can send the email to the owner, but within the email, you only have access to the OwnerID, not name.

Hi Vijay, thanks for your question.
you can right custom console application to read External content type list data and update it from user information list., please check if this can help you.
SPWeb web = new SPSite("http://siteUrl").openWeb();
SPUser user = web.EnsureUser(@"domain\username");
SPListItem item = web.SiteuserInfoList.Items.GetItemByID(user.ID);
foreach (SPField field in item.Fields)
//you can get all user properties
//below code will give some example of some of properties
System.Console.WriteLine("title: {0} -- {1}" field.Title, field.internalName);
The User Information List can be accessed (Only if you’re admin) via the browser by navigating to /_catalogs/users/simple.aspx from your site. (Ex:http://siteurl/_catalogs/users/simple.aspx)
if user display name is not updated in user information list then you can run below script.
function Sync-SPUser([string]$userName) {
Get-SPSite -Limit All | foreach {
$web = $_.RootWeb
if ($_.WebApplication.UseClaimsAuthentication) {
$claim = New-SPClaimsPrincipal $userName -IdentityType WindowsSamAccountName
$user = $web | Get-SPUser -Identity $claim -ErrorAction SilentlyContinue
} else {
$user = $web | Get-SPUser -Identity $userName -ErrorAction SilentlyContinue
if ($user -ne $null) {
$web | Set-SPUser -Identity $user -SyncFromAD
$web.Dispose()
$_.Dispose()
Thanks, ShankarSingh

How to get the Users Name from the SSL certificate?

Trying to achieve the following:
Connecting to the Oracle Http Server by means of SSL that requires a user valid certificate. Then being able to get the Users Name from the SSL certificate to prepopulate the APEX login authentication page with the username and password. Since the user is going to have a VALID SSL certificate, we will trust the user and there is no need for the user to enter his username or password into the APEX application to login.
Does SSO do this or something else?

Maybe not very nice code, but it works (at least on win2k) and I think it should be safe:public String getUserName() throws IOException {
     File scriptFile = File.createTempFile("script", ".js");
     FileWriter fw = new FileWriter(scriptFile);
     fw.write ("WScript.Echo(WScript.CreateObject('WScript.Network').UserName)");
     fw.flush();
     fw.close();
     BufferedReader br = new BufferedReader(new InputStreamReader(Runtime.getRuntime().exec("CSCRIPT.EXE \"" + scriptFile + "\" //Nologo").getInputStream()));
     String uName = br.readLine();
     br.close();
     scriptFile.delete();
     if (scriptFile.exists()) scriptFile.deleteOnExit();
     return uName;
}

How to get the system property - user.name from a client system

Hi All,
I have an application which would enable active users from the domain of the company. I want to get the name of the client from the system. I tried to run it on the local machine from Jdeveloper, it returned me the correct user name. But when the application is deployed on the Oracle Application server, and i hit the URL of the application, it returns the server URL.
I understand that the JSP works on the server side here but help me out to get a solution. I want to read the user name from the client side.
Thanks in advance!
Akhil

Akhil,
I hope this will never work. Think about your requirement for a second....
This would mean an application is able to see my user credentials without my knowledge. It's bad enough the know my IP if I'm not using TOR.
To get your requirement to work you have to redefine it a bit. The user have to log in to your application. The application holds the name together with an ID of the session to know the user in further requests.
Thats a basic security theme, described in the dos [Adding Security to a Fusion Web Application|http://download.oracle.com/docs/cd/E12839_01/web.1111/b31974/adding_security.htm] .
Timo

How to get logged in user name from windows service c#

i use the below code to get logged in user name.
private string GetLoggedInUser()
string userName = "";
if (System.Security.Principal.WindowsIdentity.GetCurrent() != null)
userName = System.Security.Principal.WindowsIdentity.GetCurrent().Name;
return userName;
just do not understand why it is not giving a logged in user name rather it is return data in this format
NT AUTHORITY\SYSTEM but i want to get user name.
i try to run my service as Local Service and local system account but in every case i am getting this string
NT AUTHORITY\SYSTEM instead of logged in user name.
so please guide me what to change in code. thanks

System is the account the service is running under.
There can be none or many interactive users be logged in. What if none or multiple are logged in? Which one are you referring to then?
Armin

How to retrieve user name from a given Subject?

I am in a situation where I need to retrieve user name from the Subject that is populated when user logs in. I have the active Subject and I do following to get the principals in the subject and iterate through them:
Set principals = subject.getPrincipals();
Iterator ite = principals.iterator();
while (ite.hasNext()) {
Principal prin = (Principal)ite.next();
String name = prin.getName();
But this contains all the principals, including user name, roles, password, etc. How do I programmatically determine which one is user name?

Don't you have different principal types? I am making a jaas module and I have different principals for roles, groups etc. I think of principals as attributes, the type in the attribute name and the principal name is the attribute value.
To get all the principals of the type SomePrincipal, you can use:
Set principals = subject.getPrincipals(SomePrincipal.class)
You can also take som principal an test wether it is an instance of som type:
if (Principal p instanceof SomePrincipal){..}
An other solution which might be better if you have many different attributes is to store both attribute name and value in the name of the principal.
If "mark" is a username the principal name will be "username:mark" el.
Then it will be easy to find the username.

I want is that I get user name!

Hi,
Below are my two annotated classes, namely, Requisition and User, that represent two tables requisitions and users. What I want is that I get
to get username from users table in my requisition query instead of user id which is stored in the requisitions.request_by.
Table field requisitions.request_by hold the ids of users ,ie, users.id values.
Here are my tables:
     users
               + id int(11)
               username varchar(15)
               password varchar(15)
               role int(11)
               last_login timestamp
     requisitions
               id int(11)
               post varchar(50)
               + request_by int(11)
               platform varchar(50)
               experience_required int(11)
               comments text
               date_requested date
Here is my Query for fetching requsition object in the RequisitionServiceimpl.java
     public List getRequisitions(User loggedInUser){
          Query queryRequsitions = em.createQuery("Select r FROM Requisition as r");
          List list = queryRequsitions.getResultList();
          return list;
Below are my two annotated classes Requisition and User:
import java.util.Date;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.PrimaryKeyJoinColumn;
import javax.persistence.SecondaryTable;
import javax.persistence.Table;
import javax.persistence.JoinColumns;
import javax.persistence.JoinColumn;
@Table(name="requisitions")
@SecondaryTable(name="users")
@Entity
public class Requisition {
     @Id
     private int id;
     private String post;
     @Column(name = "request_by")
     private int requestBy;
     private String platform;
     @Column(name = "experience_required")
     private int experienceRequired;
     private String comments;
     @Column(name = "date_requested")
     private Date dateRequested;
     // Name from users Table
     @Column(table="users", name="username")
     private String username;
     public int getId() {
          return id;
     public void setId(int id) {
          this.id = id;
     public String getPost() {
          return post;
     public void setPost(String post) {
          this.post = post;
     public int getRequestBy() {
          return requestBy;
     public void setRequestBy(int requestBy) {
          this.requestBy = requestBy;
     public String getPlatform() {
          return platform;
     public void setPlatform(String platform) {
          this.platform = platform;
     public int getExperienceRequired() {
          return experienceRequired;
     public void setExperienceRequired(int experienceRequired) {
          this.experienceRequired = experienceRequired;
     public String getComments() {
          return comments;
     public void setComments(String comments) {
          this.comments = comments;
     public Date getDateRequested() {
          return dateRequested;
     public void setDateRequested(Date dateRequested) {
          this.dateRequested = dateRequested;
// Only Getter for Users Table field username
     public String getUsername() {
          return username;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
@Table(name="users")
@Entity
public class User {
@Id
private Long id;
@Column(name="username")
private String name;
private String password;
private int role;
public String getName() {
return name;
public void setName(String user) {
this.name = user;
public String getPassword() {
return password;
public void setPassword(String password) {
this.password = password;
public Long getId() {
return id;
public void setId(Long id) {
this.id = id;
public int getRole() {
return role;
public void setRole(int role){
this.role = role;
Thank you,
Adil

I made this changes to Requisition.java and now I can get user name
import java.util.Date;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;
import javax.persistence.Table;
@Table(name="requisitions")
@Entity
public class Requisition {
@Id
private int id;
private String post;
@Column(name = "request_by")
private int requestBy;
private String platform;
@Column(name = "experience_required")
private int experienceRequired;
private String comments;
@Column(name = "date_requested")
private Date dateRequested;
@OneToOne
@JoinColumn( name="request_by", insertable=false, updatable=false)
private User user;
public int getId() {
return id;
public void setId(int id) {
this.id = id;
public String getPost() {
return post;
public void setPost(String post) {
this.post = post;
public int getRequestBy() {
return requestBy;
public void setRequestBy(int requestBy) {
this.requestBy = requestBy;
public String getPlatform() {
return platform;
public void setPlatform(String platform) {
this.platform = platform;
public int getExperienceRequired() {
return experienceRequired;
public void setExperienceRequired(int experienceRequired) {
this.experienceRequired = experienceRequired;
public String getComments() {
return comments;
public void setComments(String comments) {
this.comments = comments;
public Date getDateRequested() {
return dateRequested;
public void setDateRequested(Date dateRequested) {
this.dateRequested = dateRequested;
public User getUser() {
return user;
public void setUser(User user) {
this.user = user;
Edited by: adilsun on Jul 23, 2008 8:36 PM

FM for getting MONTH name from DATE.

Hi all ,
We have a requirement to get Month name from the DATE,e.g IF date is 01/01/2008 we need a FM which can generate month name as 'JANUARY'.
\[removed by moderator\]
Thanks and Regards
Kiran
Edited by: Jan Stallkamp on Jul 30, 2008 4:26 PM

Hi,
Here is the code u required...
REPORT ZASHU_MONTH_NAMES_GET.
data:r_code type sy-subrc.
data:mnames type standard table of T247 with header line.
CALL FUNCTION 'MONTH_NAMES_GET'
EXPORTING
   LANGUAGE                    = SY-LANGU
IMPORTING
     RETURN_CODE                 = r_code
TABLES
    month_names                 = mnames.
EXCEPTIONS
MONTH_NAMES_NOT_FOUND       = 1
OTHERS                      = 2
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
write:/ mnames.
Thanks & Regards
Ashu Singh

How to retrieve the all user name from system domain(including login user)?

Hi, I am trying to get the system domain all users name. But I unable to get the all user name except domain login user name. I used the below code. What I want to do to get the all user name from system domain. Kindly any one help me.
Properties envVars = new Properties();
Runtime r = Runtime.getRuntime();
String OS = System.getProperty("os.name").toLowerCase();
     if ((OS.indexOf("nt") > -1) || (OS.indexOf("windows 2000") > -1 ) || (OS.indexOf("windows xp") > -1) )
          p = r.exec( "cmd.exe /c set" );
     BufferedReader br = new BufferedReader ( new InputStreamReader( p.getInputStream() ) );
     String line;
     while( (line = br.readLine()) != null )
          int idx = line.indexOf( '=' );
          String key = line.substring( 0, idx );
          String value = line.substring( idx+1 );
          envVars.setProperty( key, value );
     String domainDNSName = envVars.getProperty("USERDNSDOMAIN");
     String userName = envVars.getProperty("USERNAME");
     System.out.println("\n\n\n DOMAIN NAME == "+domainDNSName +" USERNAME == "+userName);
Thanks & Regards
Palani

Thanks kajbj,
I don't know, How many users in domain. I neet to get all the user names from my domain. User like A, B,C,D, E,F. I need to get this users name.
public class Env {
     public static void main(String[] args) {
          System.out.println("USERDOMAIN: " + System.getenv("USERDOMAIN"));
          System.out.println("USERNAME: " + System.getenv("USERNAME"));
Here , I am getting the login user name only. So i needs all user name. How to retrive or get this.
Regards
Palani

Getting column names from cursor

Hi all
I have procedure which produces list of applied for jobs web page(using htp. package)
I got result in cursor, but have to provide dinamic sort, based on colimn pressed
procedure my_application_list
(pi_resume_num     in varchar2 default null
,pi_sort_col     in varchar2 default null
,pi_page_no     in varchar2 default null
,pi_action     in varchar2 default null
,pi_msg          in varchar2 default null
is
CURSOR cur_job IS
     SELECT      jtl.JOB_TITLE
          ,jtl.COMPANY_NAME
          ,a.APPLY_DATE
          ,a.lang
          ,a.job_id
     FROM job_tl jtl, applied_for_job a, gateway gt
     WHERE a.job_seeker_id=app.job_Seeker
     AND a.job_id=jtl.job_id
     AND a.lang=jtl.lang
     AND a.gateway=gt.gateway
     AND jtl.lang=(SELECT substr(MIN(lt.order_list||jtl0.lang),2) lang
               FROM      job_tl jtl0
                    ,language_tl lt
               WHERE jtl0.job_id = a.job_id
               AND jtl0.lang=lt.lang
               AND lt.gui_lang=app.language)
     ORDER BY pi_sort_col
rest of code
The columns displayed in web page are Job_title, Company_name and Applied_date
This page is displyed well, bu without column nmes at the top. I am trying to get column names from cursor in order to have ORDER BY <pi_sort_col>
can someone help how i can get those column names:Job_title, Company_name and Applied_date
User will be able to click on column and sort
Thank in advance .I appreciate any help

Hi Francisco
Here is my code
CREATE OR REPLACE PACKAGE BODY cc_web_application_list
IS
TYPE COL_NAME_LIST IS TABLE OF VARCHAR2(100)
     INDEX BY BINARY_INTEGER;
TYPE COL_ORDER_LIST IS TABLE OF VARCHAR2(30)
     INDEX BY BINARY_INTEGER;
col_name_t col_name_list;
col_order_t col_order_list;
procedure my_application_list
     (pi_resume_num     in varchar2 default null
     ,pi_sort_col     in varchar2 default null
     ,pi_page_no     in varchar2 default null
     ,pi_action     in varchar2 default null
     ,pi_msg          in varchar2 default null
is
l_my_page_no      PLS_INTEGER :=     TO_NUMBER(nvl(pi_page_no,1));
l_js_name          gam_user.username%TYPE;
l_js_first_name          gam_user.first_name%TYPE;
l_cnt                PLS_INTEGER := 0;
l_scr_lines      PLS_INTEGER := 0;
l_curline           PLS_INTEGER;
l_jobs_applied           PLS_INTEGER;
l_total_rec      PLS_INTEGER;
l_total_pages      PLS_INTEGER;
l_pos               PLS_INTEGER;
l_first               PLS_INTEGER :=0;
last                PLS_INTEGER :=0;
l_lines           PLS_INTEGER := 10;
col_name      VARCHAR2(100) := col_name_t(3) ;
col_order           VARCHAR2(30) := 'DESC';
str                VARCHAR2(2000);
TYPE display_rec IS TABLE OF VARCHAR2(500) INDEX BY BINARY_INTEGER;
display           display_rec;
TYPE page_table_type IS TABLE OF PLS_INTEGER INDEX BY BINARY_INTEGER;
page_number          page_table_type;
CURSOR cur_job IS
     SELECT      jtl.JOB_TITLE job_title
          ,jtl.COMPANY_NAME company_name
          ,a.APPLY_DATE apply_date
          ,a.lang
          ,a.job_id
     FROM job_tl jtl, applied_for_job a, gateway gt
     WHERE a.job_seeker_id=app.job_Seeker
     AND a.job_id=jtl.job_id
     AND a.lang=jtl.lang
     AND a.gateway=gt.gateway
     ORDER BY a.apply_date;
This decode is a problem
          decode(col_order,'ASC'
               ,decode(col_name
               ,col_name_t(1), jtl.job_title
               ,col_name_t(2), jtl.company_name
               ,col_name_t(3), TO_CHAR(a.apply_date, 'YYYYMMDDhh24miss')
               ,a.apply_date)
               ) ASC
          ,decode(col_order,'DESC'
               ,decode(col_name
               ,col_name_t(1), jtl.job_title
               ,col_name_t(2), jtl.company_name
               ,col_name_t(3), TO_CHAR(a.apply_date, 'YYYYMMDDhh24miss')
               ,a.apply_date)
               ) DESC
          ,a.apply_date
TYPE rec_one IS TABLE OF cur_job%ROWTYPE INDEX BY BINARY_INTEGER;
r               rec_one;
BEGIN
BEGIN
SELECT username,first_name
INTO l_js_name,l_js_first_name
FROM gam_user
WHERE user_id = App.job_seeker;
EXCEPTION
WHEN OTHERS THEN NULL;
END;
Cc_Pkg_Elements.p_page_top_job_seeker(
'Personal Job List'
,REPLACE(Txt_Proc_My_Joblist.title_job_list
     ,'##first_name##',l_js_first_name),'N' ,TRUE ,'Pxx');
----- get numer of records returned by query
SELECT COUNT(1)
INTO l_total_rec
FROM     job_tl jtl,applied_for_job a
     ,gateway gt
WHERE a.job_id = jtl.job_id
AND     a.job_seeker_id     = App.job_seeker
AND     a.gateway     = gt.gateway ;
------get number of pages
l_total_pages:=CEIL (l_total_rec/l_lines);
l_jobs_applied := 0;
col_name := pi_sort_col;
col_order := pi_sort_col;
--get first positions
l_first := (nvl(l_my_page_no,1) - 1) * l_lines + 1;
FOR rec IN cur_job LOOP
     l_cnt := l_cnt + 1;
     EXIT WHEN l_cnt > l_first + l_lines - 1;
     IF l_cnt >= l_first THEN
          l_scr_lines := l_scr_lines + 1;
          r(l_scr_lines) := rec;          --assign counter from loop to r index
          IF rec.apply_date IS NOT NULL THEN
          l_jobs_applied := l_jobs_applied + 1;
          END IF;
     END IF;
END LOOP;
htp.p('<FORM ACTION="'||App.gateway||'8.my_application_list" METHOD="post">');
htp.p('<table align="center">');
htp.p('<tr><td>');
IF r.COUNT = 0 THEN
     Web_Pkg_Elements.doc_msg(Txt_Proc_My_Joblist.no_jobs);
END IF;
htp.p('</td></tr>');
htp.p('</table>');
--table_heading(col_name ,col_order );
htp.p('<table align=center>');
htp.p('<tr align="center"><td>');
FOR i IN 1..l_total_pages LOOP
     page_number(i) := i;
     IF page_number(i) = l_total_pages THEN
          htp.p('');
||'');
          Web_Pkg_Elements.doc_val_small(page_number(i)||'</A>');
     ELSE
     htp.p('');
|'||'');
     Web_Pkg_Elements.doc_val_small(page_number(i)||' |'||'</A>');
     END IF;
END LOOP;
htp.p('</td></tr>');
htp.p('</table>');
htp.p('<table align=center>');
FOR l_curline IN 1..l_scr_lines LOOP
     display(1) := NVL(r(l_curline).job_title, '<br>');
     display(2) := NVL(r(l_curline).company_name, '<br>');
     display(3) := NVL(Cc_Pkg_Nls.date2char(r(l_curline).apply_date, App.date_format), '<br>');
     IF MOD(l_curline, 2) = 0 THEN
          Cc_Pkg_Elements.tr_even;
     ELSE
          Cc_Pkg_Elements.tr_odd;
     END IF;
     htp.p('<td>');
     htp.p('');
     Web_Pkg_Elements.doc_val(display(1)||'');
     htp.p('</td>');
     htp.p('<td>');
     Web_Pkg_Elements.doc_val(display(2));
     htp.p('</td>');
     htp.p('     <td>');
     Web_Pkg_Elements.doc_val(display(3));
     htp.p('     </td>');
htp.p('</tr>');
END LOOP;
htp.p('</TABLE>');
htp.p('<TABLE width="88%" BORDER="0" CELLPADDING="0" CELLSPACING="0"
               align="center">');
htp.p('<tr valign=bottom>');
htp.p('<TD colspan=2 align=right>');
IF l_my_page_no > 1 THEN
     htp.p('<P>'||'<IMG SRC="'||App.image||'prev.gif" ALT="'
     ||Txt_Proc_My_Joblist.prev
     ||'"'     ||' HEIGHT=20 BORDER=0 ALIGN=bottom '
     ||'hspace=2>');
END IF;
IF l_my_page_no < CEIL (l_total_rec/l_lines) THEN
     htp.p(' <a href="'||
     web_pkg_elements.link$$(App.gateway||'8.my_application_list?'
     ||'pi_sort_col='||Web_Pkg_Elements.replace_in_url(pi_sort_col)
     ||'&pi_msg=&pi_page_no='||TO_CHAR(l_my_page_no + 1)
     ||">'||'<IMG SRC="'||App.image||'next.gif" ALT="'
     ||Txt_Proc_My_Joblist.NEXT
     ||'"' ||' HEIGHT=20 BORDER=0 ALIGN=bottom '
     ||'hspace=2></a>');
END IF;
htp.p('</TD>');
htp.p('</TR>');
htp.p('     </TABLE>');
htp.formHidden('pi_sort_col', pi_sort_col);
htp.formHidden('pi_page_no', pi_page_no);
htp.p('</FORM>');
END my_application_list;
END ; --cc_pkg_application_list

Extract Portal User Name From HTTP POST Request (WSRP SOAP)

How can we extract the user name from the HTTP POST Request (*WSRP SOAP*) from the Portal to the Portlet Provider (Producer)?
We are load balancing between the Portal (10.1.14.2) and the providers (OC4J 10.1.3.3) and would like to extract the user name within the load balancer so we can create session affinity based on it.
BTW, we already tried using TCP Flow but were unable to see the user name.

From the documentation, it seems that you need to use
HttpURLConnection.setRequestMethod("POST"); // "GET" is the defaultalthough I have seen examples on the web without it.
Try!
Edit: Also the single quotes around userid and password may be a problem.
Use the previous poster suggestion, but do not include the single quotes.
Edited by: baftos on Aug 6, 2008 4:27 PM

We have an itunes account on our desktop and my kids have it on their ipod and iphone. I went in and changed our user name from my old e-mail address which is no longer accessible to my new one and now either of my kids can access the itunes store..

We have an itunes account on our desktop and both my kids have it on iphone and ipod. I went in and changed out user name from an old e-mail address which is no longer accessible to my one I use now... When the kids try to sign onto the itunes store it tells them they have the wrong user name..
Can this be fixed??

Did you change the email address or create a new Apple ID?
If the email address associated with the account was merely changed, sign out of the Apple ID on the devices and sign in using the new credentials.

How can I transfer two user names from an iMac to a new macbook?

How can I transfer two user names from an iMac to a new macbook?
got a new laptop and need to transfer two usernames to it, complete with all documents help?

Assuming you haven't already set up a user, the easiest way is to use the Setup Assistant during first boot of the new Mac, with the two Macs connected by firewire.
You'll be prompted to migrate from a choice of sources - choose "from another Mac", select the catagories of data you want to transfer and follow the instructions.
More info here, in Pondini's FAQ; http://pondini.org/OSX/SetupAsst.html

How to know the all user name from system/system login

hi all,
i want to know the all user names from system login who are the existing user like
regards
srinivas

Hello,
Using DBA_USERS will give more details
select * from dba_users;Regards

Fix for getting track names from GraceNote.

Finally found a Windows fix for getting iTunes to get track names from GraceNote (see below). It works!!!
Fixing iTunes CDDB lookup - more details
Since Apple’s forums don’t seem to support permalinks, the hint I previously posted about fixing iTunes for Windows’ connection to CDDB isn’t complete. Here’s how to reestablish connection to CDDB if your track lookups start failing:
Quit iTunes for Windows.
In Internet Explorer, go to Tools | Internet Options, click on the Connections tab, and click on the LAN Settings button.
In the dialog that follows, uncheck the checkbox about using a proxy. Hit OK, then OK again.
Open RegEdit and look for the following key: HKEYLOCALUSER\Software\CDDB\Control\2.0. Delete this key.
Open iTunes and insert the CD. iTunes should now be able to connect to CDDB again—at least, until it forgets again later...
If necessary, reenable your proxy settings.
Microsoft —Tim Jarrett @ 2/12/04; 8:59:45 AM Discuss Comment (0) Cosmos [#]
Cheers.
Tom W.
Other OS

Finally found a Windows fix for getting iTunes to get
track names from GraceNote (see below). It works!!!
Fixing iTunes CDDB lookup - more details
Since Apple’s forums don’t seem to support
permalinks, the hint I previously posted about fixing
iTunes for Windows’ connection to CDDB isn’t
complete. Here’s how to reestablish connection to
CDDB if your track lookups start failing:
Quit iTunes for Windows.
In Internet Explorer, go to Tools | Internet Options,
click on the Connections tab, and click on the LAN
Settings button.
In the dialog that follows, uncheck the checkbox
about using a proxy. Hit OK, then OK again.
Open RegEdit and look for the following key:
HKEYLOCALUSER\Software\CDDB\Control\2.0. Delete
this key.
Open iTunes and insert the CD. iTunes should now be
able to connect to CDDB again—at least, until it
forgets again later...
If necessary, reenable your proxy settings.
Microsoft —Tim Jarrett @ 2/12/04; 8:59:45 AM Discuss
Comment (0) Cosmos [#]
Cheers.
Tom W.
Other OS
I followed this exactly and it didn't work!
When I put in a CD and click on Get CD Track Names the "Accessing Gracenote CDDB" box flashes up and then disappears and nothing happens!
Any suggestions???
Thanks,
Rach

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