GROUP BY grouping sets
Hello everybody,
I have this query
SELECT ALL
M_PAGAMENTO||' '||D_TIPO MPAGA,
grouping(F.KIND_F),
DECODE (grouping(F.KIND_F), 0 , 'Totali IVA',F.KIND_F) a1,
case
when grouping(F.KIND_F) = 1 then F.KIND_F
when grouping(F.KIND_F) = 0 then 'Totali IVA'
end TIPOF,
F.KIND_F TIPOF,
COUNT(*) NFATTURE,
sum(F.TOT_FT) TFATTURA, sum(F.BOLLO) TBOLLO,
K_IVA, SUM(FA.IPBFA) TIMP, SUM(FA.IPSFA) TIPS
FROM A_FATTURE F,A_PAZIENTI A,TIPOLOGIA_PAGAMENTI p ,A_FATTURE_ALIQUOTE FA
where (F.TIPORD = A.TIPORD AND F.K_CODE = A.K_CODE AND F.ANNO = A.ANNO)
AND (FA.TIPORD = F.TIPORD AND FA.K_CODE = F.K_CODE AND FA.ANNO = F.ANNO AND FA.N_FATT_D = F.N_FATT_D)
and p.ID_TIPO = f.M_PAGAMENTO
&MYWHERE
GROUP BY grouping sets (M_PAGAMENTO||' '||D_TIPO,F.KIND_F),K_IVA
ORDER by 1
Why I get this result(A1, tipof) = NULL but they would be = 'D' (F.KIND_F ='D'
MPAGA GROUPING(F.KIND_F) A1 TIPOF TIPOF NFATTURE TFATTURA TBOLL K_IVA TIMP TIPS
01 Contante 1 5 3183,24 7,24 20 250 50
01 Contante 1 3 2342,43 5,43 FC 5,43 0
01 Contante 1 50 7024,61 9,91 ES 24458,91 0
02 Assegno 1 1 780,81 1,81 FC 1,81 0
02 Assegno 1 2 816,96 1,81 ES 755,15 0
02 Assegno 1 1 780,81 1,81 20 50 10
04 Carta di credito 1 1 780,81 1,81 FC 1,81 0
04 Carta di credito 1 1 780,81 1,81 20 50 10
04 Carta di credito 1 1 780,81 1,81 ES 719 0
0 Totali IVA Totali IVA D 53 8622,37 23,53 ES 25933,06 0
0 Totali IVA Totali IVA D 5 3904,05 9,05 FC 9,05 0
0 Totali IVA Totali IVA D 7 4744,86 10,86 20 350 70where I am wrong?
thanks for any help
Rosario,
Those rows where grouping(f.kind_f) = 1 are superaggregate rows where you are grouping by M_PAGAMENTO||' '||D_TIPO,K_IVA. So f.kind_f doesn't come into play for these rows, and it shows a null value.
You can of course hard code a 'D' value in there, but values of the f.kind_f column are always null at this grouping level.
See this example:
SQL> select deptno
2 , job
3 , extract(year from hiredate)
4 , sum(sal)
5 , grouping(job)
6 from emp
7 group by deptno
8 , grouping sets (job,extract(year from hiredate))
9 /
DEPTNO JOB EXTRACT(YEARFROMHIREDATE) SUM(SAL) GROUPING(JOB)
10 CLERK 1300 0
10 MANAGER 2450 0
10 PRESIDENT 5000 0
20 CLERK 1900 0
20 ANALYST 6000 0
20 MANAGER 2975 0
30 CLERK 950 0
30 MANAGER 2850 0
30 SALESMAN 5600 0
10 1981 7450 1
10 1982 1300 1
20 1980 800 1
20 1981 5975 1
20 1982 3000 1
20 1983 1100 1
30 1981 9400 1
16 rijen zijn geselecteerd.
SQL> select deptno
2 , job
3 , extract(year from hiredate)
4 , sum(sal)
5 , grouping(job)
6 , decode(grouping(job),1,job)
7 from emp
8 group by deptno
9 , grouping sets (job,extract(year from hiredate))
10 /
DEPTNO JOB EXTRACT(YEARFROMHIREDATE) SUM(SAL) GROUPING(JOB) DECODE(GR
10 CLERK 1300 0
10 MANAGER 2450 0
10 PRESIDENT 5000 0
20 CLERK 1900 0
20 ANALYST 6000 0
20 MANAGER 2975 0
30 CLERK 950 0
30 MANAGER 2850 0
30 SALESMAN 5600 0
10 1981 7450 1
10 1982 1300 1
20 1980 800 1
20 1981 5975 1
20 1982 3000 1
20 1983 1100 1
30 1981 9400 1
16 rijen zijn geselecteerd.Regards,
Rob.
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SQL 11 100
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NULL 11 100
NULL 20 500
NULL NULL 700
Oracle NULL 500
SQL NULL 200*/
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3000
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1250
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1500
1600
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SQL> create table orig_data as
2 select distinct job, deptno
3 from scott.emp e
4 /
Table created.
SQL> select job
2 , deptno
3 from orig_data
4 order by
5 job
6 , deptno
7 /
JOB DEPTNO
ANALYST 20
CLERK 10
CLERK 20
CLERK 30
MANAGER 10
MANAGER 20
MANAGER 30
PRESIDENT 10
SALESMAN 30
9 rows selected.The real-world data is about 5 million rows.
First I group by job (I use xmlagg here because I am on version 11.1 and therefore no listagg ;-) ):
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2 , rtrim(xmlagg(xmlelement(d,od.deptno,',').extract('//text()') order by od.deptno),',') deptnos
3 from orig_data od
4 group by od.job
5 /
JOB DEPTNOS
ANALYST 20
CLERK 10,20,30
MANAGER 10,20,30
PRESIDENT 10
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3 from (
4 select od.job
5 , rtrim(xmlagg(xmlelement(d,od.deptno,',').extract('//text()') order by od.deptno),',') deptnos
6 from orig_data od
7 group by od.job
8 ) s2
9 group by s2.deptnos
10 /
DEPTNOS JOBS
10 PRESIDENT
10,20,30 CLERK,MANAGER
20 ANALYST
30 SALESMANMy requirement is to identify all such unique groups of deptnos in my orig_data table, give each such group a surrogate key in a parent table, and then populate two child tables with the deptnos of each group and the jobs that have that group of deptnos:
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2 groupkey number primary key
3 )
4 /
Table created.
SQL> create table groups_depts (
2 groupkey number references groups (groupkey)
3 , deptno number(2)
4 )
5 /
Table created.
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2 groupkey number references groups (groupkey)
3 , job varchar2(9)
4 )
5 /
Table created.For the surrogate groupkey I can just use a rownumber on my group by deptnos query:
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2 , s2.deptnos
3 , rtrim(xmlagg(xmlelement(j,s2.job,',').extract('//text()') order by s2.job),',') jobs
4 from (
5 select od.job
6 , rtrim(xmlagg(xmlelement(d,od.deptno,',').extract('//text()') order by od.deptno),',') deptnos
7 from orig_data od
8 group by od.job
9 ) s2
10 group by s2.deptnos
11 /
GROUPKEY DEPTNOS JOBS
1 10 PRESIDENT
2 10,20,30 CLERK,MANAGER
3 20 ANALYST
4 30 SALESMANThat query I can use for a (slow) insert into my three tables in this simple manner:
SQL> begin
2 for g in (
3 select row_number() over (order by s2.deptnos) groupkey
4 , s2.deptnos
5 , rtrim(xmlagg(xmlelement(j,s2.job,',').extract('//text()') order by s2.job),',') jobs
6 from (
7 select od.job
8 , rtrim(xmlagg(xmlelement(d,od.deptno,',').extract('//text()') order by od.deptno),',') deptnos
9 from orig_data od
10 group by od.job
11 ) s2
12 group by s2.deptnos
13 ) loop
14 insert into groups values (g.groupkey);
15
16 insert into groups_depts
17 select g.groupkey
18 , to_number(regexp_substr(str, '[^,]+', 1, level)) deptno
19 from (
20 select rownum id
21 , g.deptnos str
22 from dual
23 )
24 connect by instr(str, ',', 1, level-1) > 0
25 and id = prior id
26 and prior dbms_random.value is not null;
27
28 insert into groups_jobs
29 select g.groupkey
30 , regexp_substr(str, '[^,]+', 1, level) job
31 from (
32 select rownum id
33 , g.jobs str
34 from dual
35 )
36 connect by instr(str, ',', 1, level-1) > 0
37 and id = prior id
38 and prior dbms_random.value is not null;
39
40 end loop;
41 end;
42 /
PL/SQL procedure successfully completed.The tables now contain this data:
SQL> select *
2 from groups
3 order by groupkey
4 /
GROUPKEY
1
2
3
4
SQL> select *
2 from groups_depts
3 order by groupkey, deptno
4 /
GROUPKEY DEPTNO
1 10
2 10
2 20
2 30
3 20
4 30
6 rows selected.
SQL> select *
2 from groups_jobs
3 order by groupkey, job
4 /
GROUPKEY JOB
1 PRESIDENT
2 CLERK
2 MANAGER
3 ANALYST
4 SALESMANI can now from these data get the same result as before (just to test I have created the desired data):
SQL> select g.groupkey
2 , d.deptnos
3 , j.jobs
4 from groups g
5 join (
6 select groupkey
7 , rtrim(xmlagg(xmlelement(d,deptno,',').extract('//text()') order by deptno),',') deptnos
8 from groups_depts
9 group by groupkey
10 ) d
11 on d.groupkey = g.groupkey
12 join (
13 select groupkey
14 , rtrim(xmlagg(xmlelement(j,job,',').extract('//text()') order by job),',') jobs
15 from groups_jobs
16 group by groupkey
17 ) j
18 on j.groupkey = g.groupkey
19 /
GROUPKEY DEPTNOS JOBS
1 10 PRESIDENT
2 10,20,30 CLERK,MANAGER
3 20 ANALYST
4 30 SALESMANSo far so good. This all works pretty much as desired - except for a couple of things:
The very simple loop insert code will be slow. OK, it is a one-time conversion job (in theory, but very few times at least) so that could probably be acceptable (except for my professional pride ;-) .)
But worse is, that I have groups where the string aggregation won't work - the string would have to be about varchar2(10000) which won't work in SQL in the group by :-( .
So I have tried an attempt using collections. First a collection of deptnos:
SQL> create type deptno_tab_type as table of number(2)
2 /
Type created.
SQL> select od.job
2 , cast(collect(od.deptno order by od.deptno) as deptno_tab_type) deptnos
3 from orig_data od
4 group by od.job
5 /
JOB DEPTNOS
ANALYST DEPTNO_TAB_TYPE(20)
CLERK DEPTNO_TAB_TYPE(10, 20, 30)
MANAGER DEPTNO_TAB_TYPE(10, 20, 30)
PRESIDENT DEPTNO_TAB_TYPE(10)
SALESMAN DEPTNO_TAB_TYPE(30)All very good - no problems here. But then a collection of jobs:
SQL> create type job_tab_type as table of varchar2(9)
2 /
Type created.
SQL> select s2.deptnos
2 , cast(collect(s2.job order by s2.job) as job_tab_type) jobs
3 from (
4 select od.job
5 , cast(collect(od.deptno order by od.deptno) as deptno_tab_type) deptnos
6 from orig_data od
7 group by od.job
8 ) s2
9 group by s2.deptnos
10 /
group by s2.deptnos
ERROR at line 9:
ORA-00932: inkonsistente datatyper: forventede -, fik XAL_SUPERVISOR.DEPTNO_TAB_TYPENow it fails - I cannot group by a collection datatype...
I am not asking anyone to write my code, but I know there are sharper brains out there on the forums ;-) .
Would anyone have an idea of something I might try that will allow me to create these "groups of groups" even for larger groups than string aggregation techniques can handle?
Thanks for any help, hints or tips ;-)The "group-by-collection" issue can be solved by creating a container object on which we define an ORDER method :
SQL> create type deptno_container as object (
2 nt deptno_tab_type
3 , order member function match (o deptno_container) return integer
4 );
5 /
Type created
SQL> create or replace type body deptno_container as
2 order member function match (o deptno_container) return integer is
3 begin
4 return case when nt = o.nt then 0 else 1 end;
5 end;
6 end;
7 /
Type body created
Then a multitable INSERT can do the job, after unnesting the collections :
SQL> insert all
2 when rn0 = 1 then into groups (groupkey) values (gid)
3 when rn1 = 1 then into groups_jobs (groupkey, job) values(gid, job)
4 when rn2 = 1 then into groups_depts (groupkey, deptno) values(gid, deptno)
5 with all_groups as (
6 select s2.deptnos
7 , cast(collect(s2.job order by s2.job) as job_tab_type) jobs
8 , row_number() over(order by null) gid
9 from (
10 select od.job
11 , deptno_container(
12 cast(collect(od.deptno order by od.deptno) as deptno_tab_type)
13 ) deptnos
14 from orig_data od
15 group by od.job
16 ) s2
17 group by s2.deptnos
18 )
19 select gid
20 , value(j) job
21 , value(d) deptno
22 , row_number() over(partition by gid order by null) rn0
23 , row_number() over(partition by gid, value(j) order by null) rn1
24 , row_number() over(partition by gid, value(d) order by null) rn2
25 from all_groups t
26 , table(t.jobs) j
27 , table(t.deptnos.nt) d
28 ;
15 rows inserted
SQL> select * from groups;
GROUPKEY
1
2
3
4
SQL> select * from groups_jobs;
GROUPKEY JOB
1 SALESMAN
2 PRESIDENT
3 CLERK
3 MANAGER
4 ANALYST
SQL> select * from groups_depts;
GROUPKEY DEPTNO
1 30
2 10
3 10
3 30
3 20
4 20
6 rows selected
Works great on the sample data but how this approach scales on a much (much) larger dataset is another story :) -
Anyconnect tunnel-group and group-policy from LDAP
Recently we've changed from LOCAL to LDAP authentication and added additional group-policies for different users to increase security.
To prevent users from selecting an incorrect group-policy, the LDAP server provides a IETF-Radius-Class value which matches the different group-policy names.
It is my understanding that the authentication method is provided by the tunnel-group.
tunnel-group DefaultWEBVPNGroup general-attributes
authentication-server-group LDAP_AD
This all works, but for _one_ of the group policies i'd like to enable (external) two factor authentication. Two enable two factor auth a 'secondary-authentication-server-group' needs to be set in the tunnel-group.
Creating a tunnel-group which maches the name of the group-policy doesn't seem to have any effect. When listing the connected users via "show vpn-sessiondb anyconnect", it always states the correct Group Policy but also always DefaultWEBVPNGroup.
When enabling the listing of tunnel-groups for webvpn, thus allowing users to select their own tunnel-group, the two factor auth does work.
To summarize, is it possible to let LDAP decide which tunnel-group is used or is there another way to have different group policies without users being able to choose ?Fabian,
Your connection lands on a tunnel group and picks a group policy.
A typical way to overcome the problem you're indicating is by using group-url.
a URL is bound to a specific tunnel-group and allows you to land directly on the one you desire.
vide:
http://www.cisco.com/c/en/us/support/docs/security/asa-5500-x-series-next-generation-firewalls/98580-enable-group-dropdown.html
M.
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