Help..encryption causes block to double!

Question

this is my code
class key
     public static byte[] toBytes(long n)
          byte[] b = new byte[16];
          for (int i=15;i>=8;i--)
               b=0;
     b[7] = (byte) (n);
     n >>>= 8;
     b[6] = (byte) (n);
     n >>>= 8;
     b[5] = (byte) (n);
     n >>>= 8;
     b[4] = (byte) (n);
     n >>>= 8;
     b[3] = (byte) (n);
     n >>>= 8;
     b[2] = (byte) (n);
     n >>>= 8;
     b[1] = (byte) (n);
     n >>>= 8;
     b[0] = (byte) (n);
     return b;
Heres the encryption code
long k=10000;
Cipher aesCipher;
byte totry[]=key.toBytes(k);
SecretKeySpec skeySpec = new SecretKeySpec(totry,"AES");
aesCipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
aesCipher.init(Cipher.ENCRYPT_MODE, skeySpec);           
byte[] cleartext = toencrypt.getBytes();
System.out.println(aesCipher.getBlockSize());
emessage = aesCipher.doFinal(cleartext);
System.out.println(emessage.length+" "+cleartext.length);
The output is 32,16!!!
Can someone help
Thanks

Answer 1

But my block size is 16 and my byte array size is
16.Padding shouldnt cause it to double..shud it?Please spend some time reading about PKCS5 padding.
In essence, PKCS5 pads your data with bytes up to the next block length with a byte value which is the number of bytes you have used for padding. If you already have an integral number of blocks then this policy will add a full block length of bytes each havaing the block length as value.
For example, if your block size is 16 and you have data as 16 bytes then the padding will give you
x x x x x x x x x x x x x x x x 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16
Of course, if you know you always have an integral number blocks then you can specify NoPadding .