Help get the array number fo a element

Question

Hi
1. This program does the following: Ask for three numbers, print them in a row and show the largest number of the three.
2. I also would like the program to: Print out the position of the array, whre the largest number is. Please give me a hint where to begin.
import java.util.*;
public class Ovning5 {
     public static void main (String [] arg) {
          Scanner scan = new Scanner (System.in);
          int [] numbers = new int [3]; // New array
          int x; // Numbers in array
          int largestNumber; // Largest number in the array
          // Ask for numbers
          System.out.print("Put in (three) numbers");
          for (x=0; x<numbers.length; x++) {
               numbers[x]=scan.nextInt ();
          // Print numbers in a row     
          for (x=0; x<numbers.length; x++) {
               System.out.print (numbers[x]+ " ");
          // Put a new line before next function
          System.out.println (); {     
               // Find the largest number     
               largestNumber = 0; // Set the highest number to 0
               for (x=0; x<numbers.length; x++) { // Use the first number in the array.
                    if (x == 0) {
                         largestNumber = numbers[0];
                    // if the current number we're
                    // looking at in the array is bigger than the highest number,
                    // set the highest number to this current number
                    if (numbers[x] > largestNumber) {
                         largestNumber = numbers[x];
               }     // Close new line function
            // Print out the largest number
               System.out.println("The biggest number is " + largestNumber);
}

Answer 1

"As you iterate over the array, looking for the largest element, keep track of the index of the largest element as well as it's value. Whenever you set the largest to array[n], also store n."
It took a while to figure out, but it is something like this you meen :)
// Find the largest number and the position in the array     
               largestNumber = 0; // Set the highest number to 0
               for (x=0; x<numbers.length; x++) { // Use the first number in the array.
                    if (x == 0) {
                         largestNumber = numbers[0];
                    // if the current number we're
                    // looking at in the array is bigger than the highest number,
                    // set the highest number to this current number
                    if (numbers[x] > largestNumber) {
                         largestNumber = numbers[x];
                         y=x; // Since we look at all the numbers in the loop
                         // and we started from zero, y is going to be compared to xDo you think my comments make sense?