Help in sorting the data using Rank

Question

Hello Experts
I am having trouble in selecting the record which is one less than the maximum rank  Please see the desired results part.
I am trying using the Rank or Dense_rank but I could not.
Please help in solving this issue.
The Oracle version I am working on is
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
Thanks
RB
with t as
SELECT 29951 SOURCE_ID,'03/4/2013' CREATE_DATE, 'AAAA' NAME FROM DUAL UNION ALL
SELECT 29951 SOURCE_ID,'03/11/2013' CREATE_DATE, 'BBBB' NAME FROM DUAL UNION ALL
SELECT 29951 SOURCE_ID,'03/21/2013' CREATE_DATE, 'CCCC' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/14/2013' CREATE_DATE, 'SSSS' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/4/2013' CREATE_DATE, 'TTTT' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/24/2013' CREATE_DATE, 'PPPP' NAME FROM DUAL UNION ALL
SELECT 29953 SOURCE_ID,'03/01/2013' CREATE_DATE, 'MMMM' NAME FROM DUAL UNION ALL
SELECT 29953 SOURCE_ID,'03/11/2013' CREATE_DATE, 'RRRR' NAME FROM DUAL UNION ALL
SELECT 29954 SOURCE_ID,'03/24/2013' CREATE_DATE, 'WWWW' NAME FROM DUAL
SELECT row_number() over (PARTITION BY source_id ORDER BY SOURCE_ID,create_date  ) rank, source_id,create_date
  FROM t
SOURCE_ID          CREATE_DATE            NAME
29951                    03/11/2013                   BBBB
29952                    03/14/2013                   SSSS
29953                    03/1/2013                     MMMM
29954                    03/24/2013                   WWWW

Answer 1

select  source_id,create_date,name
from (
SELECT row_number() over (PARTITION BY source_id ORDER BY create_date  ) rank, source_id,create_date,name
  FROM t
where rank = 1
Perhaps you want to handle the dates as dates.
Do you want the first or the second rank?
Could there be equal create_dates in one partition?
What do you expect as second for source_id=29954?
select  source_id,create_date,name
from (
SELECT row_number() over (PARTITION BY source_id ORDER BY to_date(create_date,'MM/DD/YYYY')  ) rank, source_id,create_date,name
FROM t
where rank = 2
SOURCE_ID
CREATE_DATE
NAME
29951
03/11/2013
BBBB
29952
03/14/2013
SSSS
29953
03/11/2013
RRRR
Ah, now i see, you want descending order
select  source_id,create_date,name
from (
SELECT row_number() over (PARTITION BY source_id ORDER BY to_date(create_date,'MM/DD/YYYY') desc ) rank, source_id,create_date,name
FROM t
where rank = 2
Finally i might have understood
with t as
SELECT 29951 SOURCE_ID,'03/4/2013' CREATE_DATE, 'AAAA' NAME FROM DUAL UNION ALL
SELECT 29951 SOURCE_ID,'03/11/2013' CREATE_DATE, 'BBBB' NAME FROM DUAL UNION ALL
SELECT 29951 SOURCE_ID,'03/21/2013' CREATE_DATE, 'CCCC' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/14/2013' CREATE_DATE, 'SSSS' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/4/2013' CREATE_DATE, 'TTTT' NAME FROM DUAL UNION ALL
SELECT 29952 SOURCE_ID,'03/24/2013' CREATE_DATE, 'PPPP' NAME FROM DUAL UNION ALL
SELECT 29953 SOURCE_ID,'03/01/2013' CREATE_DATE, 'MMMM' NAME FROM DUAL UNION ALL
SELECT 29953 SOURCE_ID,'03/11/2013' CREATE_DATE, 'RRRR' NAME FROM DUAL UNION ALL
SELECT 29954 SOURCE_ID,'03/24/2013' CREATE_DATE, 'WWWW' NAME FROM DUAL
, ranks as (
SELECT
row_number() over (PARTITION BY source_id ORDER BY to_date(create_date,'MM/DD/YYYY') desc ) rank
,source_id
,create_date
,name
FROM t
select
source_id
,create_date
,name
from ranks r
where rank =
case
when (select count(*) from ranks where source_id = r.source_id) = 1
then 1 else 2
end
SOURCE_ID
CREATE_DATE
NAME
29951
03/11/2013
BBBB
29952
03/14/2013
SSSS
29953
03/01/2013
MMMM
29954
03/24/2013
WWWW
Message was edited by: chris227 extended