Help Inserting a record

I have a access db and need to insert a record from a formmy
query isn't working, Can some one help?
Here is my query;
<form method=Post Action=doform.cfm>
<table border=0 cellspacing=5>
<tr>
<td valign="top"><span
class="t15">Issue:</span></td>
<td><textarea name="Issue" cols="60"
rows="5"></textarea></td>
</tr>
</table>
</form>
<CFQUERY NAME="InsertRecord"
DATASOURCE="AdminServerIssues">
Insert Into Issue (Issue)
Values ('#form.Issue#')
</CFQUERY>

tracjerian,
1. Add a "submit" button to the form
2. If you're using a self-posting form (ie the code is all in
one page named "doform.cfm"), the FORM.Issue variable only exists
after the form is submitted. Use IsDefined() to detect if
the form field exists and if it does, run the insert query.

Similar Messages

Help needed regarding insert a record

Hi,
I have designed a page to insert employee records.
After pressing the "Apply" button is giving the following error :
The requested page contains stale data. This error could have been caused through the use of the browser's navigation buttons (the browser Back button, for example). If the browser's navigation buttons were not used, this error could have been caused by coding mistakes in application code. Please check Supporting the Browser Back Button developer guide - View Object Primary Key Comparison section to review the primary causes of this error and correct the coding mistakes.
Cause:
The view object CreateAM.EMP_Create_VO1 contained no record. The displayed records may have been deleted, or the current record for the view object may not have been properly initialized.
Please help me in resolving this error.
Thanks,
Swaroop

Hi shiv,
I have created a EO attached it to EMP table. Created VO, atteched to that EO.
and My controller code is :
|
package oracle.apps.OPI.setup.webui;
import oracle.apps.fnd.common.VersionInfo;
import oracle.apps.fnd.framework.OAApplicationModule;
import oracle.apps.fnd.framework.webui.OAControllerImpl;
import oracle.apps.fnd.framework.webui.OAPageContext;
import oracle.apps.fnd.framework.webui.OAWebBeanConstants;
import oracle.apps.fnd.framework.webui.beans.OAWebBean;
import oracle.apps.fnd.framework.OAApplicationModule;
import oracle.apps.fnd.framework.webui.OADialogPage;
import oracle.apps.fnd.framework.webui.TransactionUnitHelper;
import oracle.apps.fnd.framework.webui.OADialogPage;
import oracle.apps.fnd.framework.webui.TransactionUnitHelper;
import oracle.jbo.domain.Number;
import oracle.apps.fnd.common.MessageToken;
import oracle.apps.fnd.framework.OAException;
import oracle.apps.fnd.framework.OAViewObject;
import oracle.apps.fnd.framework.webui.OAWebBeanConstants;
* Controller for ...
public class CreateCO extends OAControllerImpl
public static final String RCS_ID="$Header$";
public static final boolean RCS_ID_RECORDED =
VersionInfo.recordClassVersion(RCS_ID, "%packagename%");
* Layout and page setup logic for a region.
* @param pageContext the current OA page context
* @param webBean the web bean corresponding to the region
public void processRequest(OAPageContext pageContext, OAWebBean webBean)
// Always call this first.
super.processRequest(pageContext, webBean);
// If isBackNavigationFired = false, we're here after a valid navigation
// (the user selected the Create Empoyee button) and we should proceed
// normally and initialize a new employee.
if (!pageContext.isBackNavigationFired(false))
// We indicate that we are starting the create transaction (this
// is used to ensure correct Back button behavior).
TransactionUnitHelper.startTransactionUnit(pageContext, "empCreateTxn");
// This test ensures that we don't try to create a new employee if
// we had a JVM failover, or if a recyled application module
// is activated after passivation. If these things happen, BC4J will
// be able to find the row that you created so the user can resume
// work.
if (!pageContext.isFormSubmission())
OAApplicationModule am = pageContext.getApplicationModule(webBean);
am.invokeMethod("createEmployee", null);
else
if (!TransactionUnitHelper.isTransactionUnitInProgress(pageContext, "empCreateTxn", true))
// We got here through some use of the browser "Back" button, so we
// want to display a stale data error and disallow access to the page.
// If this were a real application, we would probably display a more
// context-specific message telling the user she can't use the browser
// "Back" button and the "Create" page. Instead, we wanted to illustrate
// how to display the Applications standard NAVIGATION ERROR message.
OADialogPage dialogPage = new OADialogPage(NAVIGATION_ERROR);
pageContext.redirectToDialogPage(dialogPage);
} // end processRequest()
* Procedure to handle form submissions for form elements in
* a region.
* @param pageContext the current OA page context
* @param webBean the web bean corresponding to the region
public void processFormRequest(OAPageContext pageContext, OAWebBean webBean)
super.processFormRequest(pageContext, webBean);
OAApplicationModule am = pageContext.getApplicationModule(webBean);
if (pageContext.getParameter("Apply") != null)
am.invokeMethod("apply");
pageContext.forwardImmediately("OA.jsp?page=/oracle/apps/OPI/setup/webui/DisplayPG",
null,
OAWebBeanConstants.KEEP_MENU_CONTEXT,
null,
null,
true, // retain AM
OAWebBeanConstants.ADD_BREAD_CRUMB_NO);
else if (pageContext.getParameter("Cancel") != null)
am.invokeMethod("rollbackEmployee");
pageContext.forwardImmediately("OA.jsp?page=/oracle/apps/OPI/setup/webui/CreatePG",
null,
OAWebBeanConstants.KEEP_MENU_CONTEXT,
null,
null,
true, // retain AM
OAWebBeanConstants.ADD_BREAD_CRUMB_NO);
My AM code is:
package oracle.apps.OPI.setup.server;
import oracle.apps.fnd.framework.server.OAApplicationModuleImpl;
import oracle.jbo.Row;
import oracle.apps.fnd.framework.OAViewObject;
import oracle.jbo.Transaction;
// --- File generated by Oracle ADF Business Components Design Time.
// --- Custom code may be added to this class.
// --- Warning: Do not modify method signatures of generated methods.
public class CreateAMImpl extends OAApplicationModuleImpl {
/**This is the default constructor (do not remove)
public CreateAMImpl() {
/**Container's getter for CreateVO1
public CreateVOImpl getCreateVO1() {
return (CreateVOImpl)findViewObject("CreateVO1");
/**Sample exportable method.
public void sampleCreateAMImplExportable() {
/**Sample exportable method.
public void sampleCreateAMImplExportable2(String testParam1) {
/**Sample main for debugging Business Components code using the tester.
public static void main(String[] args) {
launchTester("oracle.apps.OPI.setup.server", /* package name */
"CreateAMLocal" /* Configuration Name */);
* Creates a new employee.
public void createEmployee()
OAViewObject vo = (OAViewObject) getEMP_Create_VO1();
if (!vo.isPreparedForExecution())
vo.executeQuery();
Row row = vo.createRow();
vo.insertRow(row);
// Required per OA Framework Model Coding Standard M69
row.setNewRowState(Row.STATUS_INITIALIZED);
} // end createEmployee()
* Executes a rollback including the database and the middle tier.
public void rollbackEmployee()
Transaction txn = getTransaction();
// This small optimization ensures that we don't perform a rollback
// if we don't have to.
if (txn.isDirty())
txn.rollback();
} // end rollbackEmployee()
public void apply()
getDBTransaction().commit();
/**Container's getter for EMP_Create_VO1
public EMP_Create_VOImpl getEMP_Create_VO1() {
return (EMP_Create_VOImpl)findViewObject("EMP_Create_VO1");
}

Urgent help : how when insert new record navigation off

hi master
Sir
when i insert new record by mistake press down key and curser move to next record and my need is
When I insert new record or change any record that time my form navigation musht be off and no move to next record how I restrict to navigation please give me idea which event and what code I use
Thanking you
aamir

If u want the cursor not to move ahead from a particular field when the records are inserted or updated on that field then u can just write null to the
key-next-item trigger of that particular item.
ie IN key-next-item
null;
Hope this is what you wanted.

Error inserting XML records 4000 bytes through Pro*C

Hi,
I am seeing the following error while trying to insert XML records > 4000 bytes (Records < 4000 bytes get inserted without any issues). Any help in resolving the issue would be highly appreciated.
ORA return text: ORA-01461: can bind a LONG value only for insert into a LONG column.
I am also able to insert records > 4000 bytes using the following query, But, I want to insert the records through a C application (using Pro*C) that is not running on the database server.
INSERT INTO MY_XML_TABLE
VALUES (XMLType(bfilename('XML_DIR', 'MY_FILE.XML'),
nls_charset_id('AL32UTF8')));
Oracle Version
===============
SQL> select * from v$version;
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
PL/SQL Release 11.2.0.2.0 - Production
CORE 11.2.0.2.0 Production
TNS for Solaris: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production
Pro*C/C++ version:
====================
Pro*C/C++ RELEASE 11.2.0.0.0 - PRODUCTION
Schema registration:
====================
begin
DBMS_XMLSCHEMA.registerSchema (
SCHEMAURL => 'MY_XML_SCHEMA.xsd',
SCHEMADOC => bfilename ('ENG_REPORTS', 'MY_XML_SCHEMA.xsd'),
GENTYPES => FALSE,
OPTIONS => DBMS_XMLSCHEMA.REGISTER_BINARYXML,
CSID =>nls_charset_id ('AL32UTF8'));
end;
Table creation
===============
CREATE TABLE MY_XML_TABLE (
MY_XML_RECORD XmlType )
XMLTYPE MY_XML_RECORD STORE AS BINARY XML
XMLSCHEMA "MY_XML_SCHEMA.xsd" ELEMENT "MYXMLTAG" ;
Record Insertion (Pro*C generated code):
=========================================
/* EXEC SQL FOR :l_sizeof_array_togo
insert INTO MY_XML_TABLE
(MY_XML_RECORD )
VALUES( XMLTYPE(:l_XML_ptr INDICATOR :l_XML_indicators )); */
struct sqlexd sqlstm;
sqlstm.sqlvsn = 12;
sqlstm.arrsiz = 1;
sqlstm.sqladtp = &sqladt;
sqlstm.sqltdsp = &sqltds;
sqlstm.stmt = "insert into MY_XML_TABLE (MY_XML_RECORD) values (XMLTYPE(:s1\
:s2 ))";
sqlstm.iters = (unsigned int )l_sizeof_array_togo;
sqlstm.offset = (unsigned int )20;
sqlstm.cud = sqlcud0;
sqlstm.sqlest = (unsigned char *)&sqlca;
sqlstm.sqlety = (unsigned short)4352;
sqlstm.occurs = (unsigned int )0;
sqlstm.sqhstv[0] = (unsigned char *)&l_XML_ptr->xml_record;
sqlstm.sqhstl[0] = (unsigned long )8002;
sqlstm.sqhsts[0] = ( int )sizeof(struct xml_rec_definition);
sqlstm.sqindv[0] = ( short *)&l_XML_indicators->XML_record_ind;
sqlstm.sqinds[0] = ( int )sizeof(struct XML_indicator);
sqlstm.sqharm[0] = (unsigned long )0;
sqlstm.sqadto[0] = (unsigned short )0;
sqlstm.sqtdso[0] = (unsigned short )0;
sqlstm.sqphsv = sqlstm.sqhstv;
sqlstm.sqphsl = sqlstm.sqhstl;
sqlstm.sqphss = sqlstm.sqhsts;
sqlstm.sqpind = sqlstm.sqindv;
sqlstm.sqpins = sqlstm.sqinds;
sqlstm.sqparm = sqlstm.sqharm;
sqlstm.sqparc = sqlstm.sqharc;
sqlstm.sqpadto = sqlstm.sqadto;
sqlstm.sqptdso = sqlstm.sqtdso;
sqlcxt((void **)0, &sqlctx, &sqlstm, &sqlfpn);
}

After selecting data from xmltab table I just received first line of xmldata file. i.e
<?xml version="1.0" encoding="WINDOWS-12 52"?> <BAROutboundXM L xmlns="http://BARO
That must be a display issue.
What client tool are you using, and what version?
If SQL*Plus, you won't see the whole content unless you set some options :
{code}
SET LONG <value>
SET LONGCHUNKSIZE <value>
{code}
Could you try the following?
{code}
SET LONG 10000
SELECT t.object_value.getclobval() FROM xmltab t;
-- to force pretty-printing :
SELECT extract(t.object_value, '/*').getclobval() FROM xmltab t;
{code}
Edited by: odie_63 on 16 févr. 2011 08:58

Error in inserting a record in to table

hi..
i created a trigger....when i am trying to insert new record in to table i am getting the fallowing error...plz kindly help me out from this...
SQL> create or replace trigger secure_emp
2 before insert on employees begin
3 if(to_char('sysdate','DY') in ('SAT','SUN')) or
4 (to_char('sysdate','HH24:MI') not between '8:00' and '18:00') then
5 raise_application_error(-20500,'error');
6 end if;
7 end;
8 /
Trigger created.
SQL> insert into employees(employee_id,last_name,first_name,email,hire_date,job_id,salary,department
_id)
2 values (300,'smith','jack','SJACK',sysdate,'IT_PROG',4500,60);
insert into employees(employee_id,last_name,first_name,email,hire_date,job_id,salary,department_id)
ERROR at line 1:
ORA-06502: PL/SQL: numeric or value error: character to number conversion error
ORA-06512: at "SCOTT.SECURE_EMP", line 2
ORA-04088: error during execution of trigger 'SCOTT.SECURE_EMP'

Yeah. Whenever Oracle sees TO_CHAR('string_literal1', 'string_literal2), it implicitly converts it to TO_CHAR(TO_NUMBER('string_literal1'), 'string_literal2). That's why an error in trigger occurs.
SQL> explain plan for
2 select null
3    from dual
4   where dummy = to_char('A', 'DY');
Explained
SQL> @utlxpls
Cannot SET MARKUP
PLAN_TABLE_OUTPUT
Plan hash value: 397561404
| Id | Operation         | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT |      |     1 |     2 |     2   (0)| 00:00:01 |
|* 1 | TABLE ACCESS FULL| DUAL |     1 |     2 |     2   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   1 - filter("DUMMY"=TO_CHAR(TO_NUMBER('A'),'DY'))
13 rows selected

Error when inserting a Record Form

Hi,
I'm very green with web development and am just trying my hand at PHP. I've set up a database with Mysql and phpmyadmin those are working fine.
I had inserted a record form using the record insertion form wizard and it worked just fine. I deleted it because I wanted some different information and
now every time I try to insert a new form this error message comes up.
While executing onClick in ServerObject-InsRecPHP.htm, the following JavaScript error(s) occurred:
At line 5694 of file 'C:\Program Files (x86)Adobe\Adobe Dreamweaver CS5\Configuration\Shared\Common\Scripts\dwscriptsExtData.js':this.node has no
properties.
I've gone to look at the file but I'm not sure how to tell if the properties are working or not. I've also googled this problem but haven't found someone with exactly my dilemma. Any help will be greatly appreciated!
Thank you for your time

Troubleshooting JavaScript errors in Dreamweaver
http://kb2.adobe.com/cps/405/kb405604.html
Try #4 and #12 first.

Problem while inserting a record to infotype 416

Iam facing a problem while inserting a record to the infotype 416 for a personnel no using the FM 'HR_INFOTYPE_OPERATION'.I have created a FM to insert a record to the infotype 416.In that FM iam using the FM 'HR_INFOTYPE_OPERATION' to create a record for infotype 416.while executing my FM the FM 'HR_INFOTYPE_OPERATION' is returning the return value 0.But when i check in PA30 for the infotype 416,there is no record created for that personnel no.Also in the table PA0416 the record is not get created.SO what might be the problem.can anyone please provide me help on this.
I have attached the code of my FM for ur reference.
FUNCTION Y_ESS_FL_ENCASH.
DATA: G_COMPENSATION_AMOUNT LIKE PA0416-AMONT,
      G_RETURN TYPE BAPIRETURN1.
DATA T_PA0416 LIKE P0416 OCCURS 0 WITH HEADER LINE.
CALL FUNCTION 'HR_READ_INFOTYPE'
    EXPORTING
       TCLAS                 = 'A'
       PERNR                 = '00000014'
       INFTY                 = '0416'
     BEGDA                 = sy-datum
     ENDDA                 = sy-datum
       BYPASS_BUFFER         = 'X'
     LEGACY_MODE           = ' '
IMPORTING
     SUBRC                 =
      TABLES
        INFTY_TAB             = T_PA0416
EXCEPTIONS
INFTY_NOT_FOUND       = 1
OTHERS                = 2
    LOOP AT T_PA0416
    WHERE SUBTY = '1002'.
    ENDLOOP.
    IF SY-SUBRC <> 0.
      CALL FUNCTION 'BAPI_EMPLOYEE_ENQUEUE'
        EXPORTING
           NUMBER = '00000014'
        IMPORTING
           RETURN = G_RETURN.
      IF SY-SUBRC <> 0.
         MESSAGE I016(RP) WITH ' RECORD IS ALREADY LOCKED'.
      ENDIF.
      T_PA0416-PERNR = '00000014'.
      T_PA0416-SUBTY = '1002'.
      T_PA0416-INFTY = '0416'.
      T_PA0416-OBJPS = ''.
      T_PA0416-SPRPS = ''.
      T_PA0416-SEQNR = ''.
      T_PA0416-AEDTM = SY-DATUM.
      T_PA0416-UNAME = SY-UNAME.
      T_PA0416-ENDDA = SY-DATUM.
      T_PA0416-BEGDA = SY-DATUM.
      T_PA0416-NUMBR = '10'.
      T_PA0416-WGTYP = '1530'.
      T_PA0416-AMONT = '15000'.
      T_PA0416-WAERS = 'INR'.
      T_PA0416-QUONR = '1'.
      APPEND T_PA0416.
      CALL FUNCTION 'HR_INFOTYPE_OPERATION'
        EXPORTING
          INFTY                  = '0416'
          NUMBER                 = '00000014'
          SUBTYPE                = '1002'
OBJECTID               =
LOCKINDICATOR          =
         VALIDITYEND            = '31129999'
         VALIDITYBEGIN          = SY-DATUM
        RECORDNUMBER           = ''
          RECORD                 = T_PA0416
          OPERATION              = 'INS'
          TCLAS                  = 'A'
DIALOG_MODE            = '0'
        NOCOMMIT               = 'X'
VIEW_IDENTIFIER        =
SECONDARY_RECORD       =
        IMPORTING
          RETURN                 = G_RETURN.
KEY                    =
      IF G_RETURN+0(1) EQ 'E'.
              MESSAGE I086(ZHR) WITH 'Record is not inserted in IT416'.
      ELSE.
          COMMIT WORK.
      ENDIF.
      CALL FUNCTION 'BAPI_EMPLOYEE_DEQUEUE'
        EXPORTING
          NUMBER = '00000014'
        IMPORTING
          RETURN = G_RETURN.
    ENDIF.
ENDFUNCTION.

Hi Murthy
With a first glance, I think you have given a wrong parameter value to "validityend". It should be '99991231' not '31129999' .
If your problem still persists, try inserting the data online from PA30. If your input causes no errors, then please state what the return parameter contains.
Regards
*--Serdar <a href="https://www.sdn.sap.com:443http://www.sdn.sap.comhttp://www.sdn.sap.com/irj/servlet/prt/portal/prtroot/com.sap.sdn.businesscard.sdnbusinesscard?u=qbk%2bsag%2bjiw%3d">[ BC ]</a>

Problem with inserting new records in Oracle Forms

Hi Friends,
I am a new user to Oracle Forms and I need a help from you people. The problem is as follows:
I have a data block in which I can display a number of records. In this data block the user will be able to edit the fields if no child records are found in another table. I have used when-new-record-instance to attain this scenario. All are text items. One item licensee_id which is made invisible by setting the property in property palette and required=no ( as this is the primary key of the table). Also the audit columns are made invisible.
The code for it is as follows:
DECLARE
     v_alert_button NUMBER;
     v_cnt                          NUMBER;
BEGIN
     SELECT COUNT (*)
INTO v_cnt
FROM id_rev_contracts
WHERE licensee_id = :ID_REV_LICENSEES.licensee_id;
IF v_cnt > 0 THEN
set_item_property('ID_REV_LICENSEES.LICENSEE_NAME', UPDATE_ALLOWED, PROPERTY_FALSE);
ELSE
     set_item_property('ID_REV_LICENSEES.LICENSEE_NAME', UPDATE_ALLOWED, PROPERTY_TRUE);
     -- set_item_property('ID_REV_LICENSEES.LICENSEE_NAME', INSERT_ALLOWED, PROPERTY_TRUE);
END IF;
END;
Now in this data block I should also be able to insert new records and for the same I have used PRE-INSERT trigger and the code for it is as follows:
DECLARE
     v_alert_button NUMBER;
CURSOR v_licensee_id IS SELECT id_rev_licensees_s.NEXTVAL FROM dual;
BEGIN
OPEN v_licensee_id;
FETCH v_licensee_id INTO :id_rev_licensees.licensee_id;
CLOSE v_licensee_id;
IF :id_rev_licensees.licensee_id IS NULL THEN
Message('Error Generating Next v_licensee_id');
RAISE Form_Trigger_Failure;
END IF;
:ID_REV_LICENSEES.created_by := :GLOBAL.g_login_name;
:ID_REV_LICENSEES.last_updated_by := :GLOBAL.g_login_name;
:ID_REV_LICENSEES.create_date := SYSDATE;
:ID_REV_LICENSEES.last_update_date := SYSDATE;
EXCEPTION
WHEN form_trigger_failure
THEN
RAISE form_trigger_failure;
WHEN OTHERS
THEN
v_alert_button :=
msgbox ('ERROR in Pre-Insert - ' || SQLERRM, 'STOP', 'Contact IST');
RAISE form_trigger_failure;
END;
Every thing is compiling fine but at the run time when I am trying to insert a new record I am receiving the following error:
FRM-40508:ORACLE error:unable to insert record
I also think the pre-insert record is not firing at the time of inserting a new record and saving it. So I request you to please delve into this problem and suggest me how to overcome this problem. Code snippets would do more help for me. If you need any other things from me please let me know. I will see if I could be of any help in that concern because I may not be able to send the entire form as it is.
Thanks and regards,
Vamsi K Gummadi.

first of all
pre-insert fires after the implicit/explicit commit/commit_form is issued and before the real insert is submitted to the db.
i would suggest to remove the error handling part for the moment
because i believe you might be getting "ora-xxxx cannot insert null"
and also make visible the primary column to check if the pre-insert is executed.
it would be better to make visible for a while the not null columns of the table/block
i suppose that the block is insert allowed and you are using table as the source of the block and not any procedures or something...

Inserting a record in backend using syncbo

Hi,
I have a header table and item table like,
EmpHdr-- fields 1) empno
2)ename
EmpItem--fields 1) empno
2)designation
how can I insert a record in the tables using syncbo.Can any body provide me the detail code.I am new to MI.Please help me.
MerepMeta.xml
<?xml version="1.0" encoding="utf-8"?><MeRepApplication schemaVersion="1.1" id="ZNEWEMPMCD" version="1.0"><Property name="CLIENT.BUILDNUMBER"></Property><Property name="C_APPLRESOLVE"></Property><Property name="DATA_VISIBLE_SHARED">X</Property><Property name="E_APPLRESOLVE"></Property><Property name="HOMEPAGE.INVISIBLE"></Property><Property name="INITVALUE"></Property><Property name="RUNTIME">JSP</Property><Property name="TYPE">APPLICATION</Property>
<SyncBO id="ZNEWEMP" version="3" type="twoWay" allowCreate="true" allowModify="true" allowDelete="true" reqDirectSync="true" downloadOrder="1">
<TopStructure name="TOP">
<Field name="SYNC_KEY" type="N" length="10" decimalLength="0" signed="false" isKey="true" isIndex="true"><Input type="create">false</Input><Input type="modify">false</Input></Field>
<Field name="ZEMPID" type="C" length="10" decimalLength="0" signed="false" isKey="false" isIndex="false"/>
<Field name="ZEMPNAME" type="C" length="20" decimalLength="0" signed="false" isKey="false" isIndex="false"/>
<ChildStructure name="010">
<Field name="SYNC_KEY" type="N" length="10" decimalLength="0" signed="false" isKey="true" isIndex="true"><Input type="create">false</Input><Input type="modify">false</Input></Field>
<Field name="ZEMPID" type="C" length="10" decimalLength="0" signed="false" isKey="false" isIndex="false"/>
<Field name="ZDESIG" type="C" length="15" decimalLength="0" signed="false" isKey="false" isIndex="false"/>
</ChildStructure>
</TopStructure></SyncBO></MeRepApplication>
Regards,
Srikanth Reddy.T
Edited by: Srikanth Thatipally on Oct 21, 2008 8:22 AM

Hello,
Please refer to the API:
https://admin.sdn.sap.com/irj/sdn/go/portal/prtroot/com.sap.km.cm.docs/library/mobile/mobile-infrastructure/mobile%20development%20kit%202.5/content/javadoc/overview-summary.html
Look into the smartcyn package. You will want to create an instance f your sync bo and add rows into it. The API is pretty straightforward.
You can also use mCAF that is shipped with MAM/MAU/DSD/etc that hides the technicalities from you.
Thank you,
Julien.
http://www.msc-mobile.com

Inserting a record in database using Java

Hello All,
i have connected a Java Application to the SAP BO Database using DI API and would like to insert a record in the demo database without using an SQL Query "Insert into table1...." but using the following snippet though i dont know if am using the right classes :
                                ICompany company = conn.getCompany();
                                 IItems items = SBOCOMUtil.newItems(company);
                    items.setItemCode("124");
                    items.setItemName("VXC");
                    items.setItemsGroupCode(1);
                    items.setItemType(0);
                    items.add();
What i am trying to do here is insert a new record but i dont know where i should mention the table name for e.g. there is table called OITM in the demo database from BO where i would like to create a new Item.
Could anyone help me here.
Regards,
Amit Hingher

Hi Amit,
You don't need to reference the destination tables as there is a class for each data object in the DI API and the data tables associated with the object are hardcoded in the class.
The Items class is the correct one for adding item master data (ie data in OITM, OITW etc).
I'm not very familiar with these Java objects but I think the add method should return an integer value (as it does with the COM objects used by .NET). If the return value is zero then the add was successful. If the add failed then you'll get a non-zero value which is the SBO error code.
Kind Regards,
Owen

Insert Multiple records using Database adapter with Stored procedure func

Hi All,
I want to insert multiple records on a database using a stored procedure. I wanted to insert those records using a Database Adapter and the Database adapter should be invoked by a Mediator.
Can somebody suggest me with ideas whether it can be acheived with OOB capabtilities in SOA suite or not?
Thanks for your help in advance.
Thanks,
Shiv

The use case you want to achieve is feature supported by the DBAdapter and it is possible to invoke the same from mediator.
Please have a look at the oracle documentation and you should be able to get the necessary information.
The below links should help you as well:
http://download.oracle.com/docs/cd/E15523_01/integration.1111/e10231/adptr_db.htm
http://blogs.oracle.com/ajaysharma/2011/03/using_file_adapter_database_adapter_and_mediator_component_in_soa_11g.html
There are some video tutorials as well :)
http://www.youtube.com/watch?v=dFldS-fDx70 This should also help
Thanks,
Patrick

Inserting a record in an internal table - Urgent

Hi Friends,
I have a requirement where in I have 2 internal tables say itab1 and itab2.Itab1 has 10 records and itab2 has one record initially.
Now I have to move the records of itab1 into itab2.
My question is if some conditions satisfy,then I need to append the records of itab1 after the single record in itab2.In some other cases I need to insert the records of itab1 before
the single record in itab2.
What is the syntax to attach the records before the record as append statement always attaches the record after the existing record.
Your help is highly appreciated.
Regards,
Vishnu.

You can use insert itab index idx .
Alternative 2
... itab INDEX idx
Effect
This variant can only be used for standard tables and sorted tables. Each line line_spec to be inserted into the line before the table index idx and the table index of the following lines is increased by one. A data object of the type i is expected for idx.
If idx contains a value equal to the number of the existing table lines plus one, the new line is appended as the last line in the internal table. If idx contains a greater value, no line is inserted and sy-subrc is set to 4.
An exception that cannot be handled is raised when:
idx contains a value less than or equal to 0
A line to be inserted would cause a duplicate entry in tables with a unique table key
A line to be inserted would disrupt the sort order of sorted tables
Within a LOOP loop, you can omit the addition INDEX. Each line to be inserted is inserted before the current table line of the LOOP loop. However, if the current line is deleted in the same loop pass, the response is undefined.
read help on this .
reward if helpful

Insertion a record in a table having columns of different charsets using OLEDB

My development environment -
Database -> Microsoft SQL Server
2008 R2
OS -> Windows Server
2008 R2
Database Charset -> Chinese_PRC_CI_AS (Windows
936)
Operating System Charset -> Chinese
Below table is having varchar fields with different charsets.
create
table dbo.tcolcs1 (
    c1 int
not
null
primary
key,
    c2 varchar(30)
collate SQL_Latin1_General_Cp1_CI_AS ,
    c3 varchar(30)
collate Chinese_PRC_CI_AS
I want to insert below record using OLEDB APIs provided by Microsoft. Just for information, character '0x00C4' does not
belong to Windows 936 codepage.
insert
into dbo.tcolcs1
values (10,
NCHAR(0x00C4), NCHAR(0x4EBC))
Code snippet -
DBPARAMBINDINFO bind_info
memset(&bind_info,
0, sizeof(DBPARAMBINDINFO));
bind_info.pwszDataSourceType = L"DBTYPE_VARCHAR";
bind_info.wType = DBTYPE_STR;
I have bound the varchar field with DBTYPE_STR. I can see that my code is not inserting Latin1 character (0x00C4) correctly
into the table. The code always inserts a blank character into Latin1 column (c2) and 0x4EBC into Chinese column (c3).
Later, I changed the binding from DBTYPE_STR to DBTYPE_BYTES as below -
bind_info.pwszDataSourceType = L"DBTYPE_BINARY";
bind_info.ulParamSize =
0;
bind_info.wType = DBTYPE_BYTES;
With the above change, I observed that OLEDB is converting hex value to string. It is inserting 0x00C4 as 'C4' and 0x4EBC
as '4EBC'. I also tried with adding 'AutoTranslate=no' in driver connection string, but it did not help. How can I insert above record with OLEDB in the above table ?
Thanks in advance.

Did you try making fields as unicode?
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Visakh
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How to insert multiple records?

I have dynamically checkboxes, which get the data from database. I have used a FOR loop to store each value of the checkbox to session variables, i.e.
session.setAttribute("Slangs"+a,request.getParameter("langsID"+a)); (p/s: a is a counter, I also set a hidden variable to store the number of record in DB)
Now, I wanna insert these records to the table called CusLangs which has CusID(PK) and Langs(PK). I wanna construct a insert.jsp, so that those checkboxes that I selected can be written into table CusLangs.
Anyone know how to do that?
Thanks.
From
jeff

You have a checkboxes with the same name in your html/jsp.When you post to a servlet/jsp, use request.getParameterValues("checkboxname ) to get String [], ie.
<html>
<input type="checkbox" name="sampleCheck" value="1">
<input type="checkbox" name="sampleCheck" value="2">
</html>
Servlet/ JSP
String check[] = request.getParameterValues("sampleCheck");
query = "Insert into CusLangs (CusID) values (?') ";
stmt = connection.prepareStatement(query);
for(int i=0, i < check.length, i++) {
stmt.setString(1, check[0]);
int x = stmt.executeUpdate();
Hope this will help.

How to insert 20 records only in one table

hi to all,
i want insert 20 records only in a table,but suppose i want to enter 21th record it will not inserted .
suppose delete one record then insert, it will insert.
but always count(*) is not greater than 20.
is there any solution for that,
pls help me

Yes there is a solution for that using a materialied view:
SQL> select * from v$version;
BANNER
Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
PL/SQL Release 10.2.0.1.0 - Production
CORE 10.2.0.1.0 Production
TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
SQL> drop table t purge;
Table dropped.
SQL> drop materialized view t_mv;
Materialized view dropped.
SQL> create table t (
2 x integer,
3 y varchar2(30)
4 );
Table created.
SQL> CREATE MATERIALIZED VIEW LOG on t
2 WITH ROWID (x, y)
3 including new values;
Materialized view log created.
SQL> CREATE MATERIALIZED VIEW t_mv
2 REFRESH FAST ON COMMIT AS
3 SELECT count(*) cnt
4 FROM t;
Materialized view created.
SQL> alter table t_mv ADD CONSTRAINT chk check(cnt<=20);
Table altered.
SQL> insert into t select object_id, object_name from all_objects where rownum <
21;
20 rows created.
SQL> commit;
Commit complete.
SQL> insert into t values(21,'KO');
1 row created.
SQL> commit;
commit
ERROR at line 1:
ORA-12008: error in materialized view refresh path
ORA-02290: check constraint (TEST.CHK) violated
SQL>
SQL> select count(*) from t;
COUNT(*)
20
SQL>Not sure that trigger based solution works due to multi versioning read consistency.

Help Inserting a record

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