Help needed- lost

hey ppl,
i've got a Zen touch 20GB MP3 player, but i installed the CD on my old computer, now the old computer has broken down an i cant find the cd to install it on my new computer. So i cant upload songs on my zen no more, i've got the manual but not the cd.
Does any one know of any downloads or anythin that could help me out ...plzzz help!!!
thanx in advance.
kayzee

kayzee,
You can get the downloads you need through Support> Downloads. You'll need to download drivers and an application to use the player (like MediaSource). If you install MediaSource, you'll need the right plug-in for the application aswell.
There is a section in the FAQ aswell that refers to "if you lost your CD", it should cover the information you need.
Cat

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mimico kid,
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Slymm71 wrote:
just had similar problem got email from find my phone saying initiating full phone wipe this cannot be stopped ***? i own the phone from new and registerred in m name but wiped whilst i was using it !!!
See your other post...
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My iPhone 3Gs (3.1) has been running fine, until several hours ago today, when I plugged it to my MacBook, the iPhone is no longer detected - it doesn't show up in iTunes, nor it is charged. I tried opening iPhoto, and it wasn't there too. Not with Image Capture too. I tried charging it using the out-of-box wall charger using the same out-of-box USB cable I use for MacBook, and it can be charged without any problem. Then I put it into Recovery mode, and there iTunes can see it. I don't want to restore it before I figure out exactly what went wrong, as I don't want the restore process somehow gets stuck in the middle that the connection is lost again.
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Help needed with java

Hello everyone
I'm a Student and new to java and I have been given a question which I have to go through. I have come across a problem with one of the questions and am stuck, so I was wondering if you guys could help me out.
here is my code so far:
A Class that maintains Information about a book
This might form part of a larger application such
as a library system, for example.
@author (your name)
*@version (a version number or a date)*
public class Book
// instance variables or fields
private String author;
private String title;
Set the author and title when the book object is constructed
public Book(String bookAuthor, String bookTitle)
author = bookAuthor;
title = bookTitle;
Return The name of the author.
public String getAuthor()
return author;
Return The name of the title.
public String getTitle()
return title;
and below are the questions that I need to complete. they just want me to add codes to my current one, but the problem is I don't know where to put them and how I should word them, if that makes sense.
Add a further instance variable/field pages to the Book class to store the number of pages in the book.
This should be of type int and should be set to 0 in the Constructor.
Add a second Constructor with signature
public Book(String bookAuthor, String bookTitle, int noPages) so it has a third parameter passed to it as well as the author and title;
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Add a method printDetails() to your Book class. This should print out the Author title and number of pages to the Terminal Window. It is your choice as to how the data is formatted, perhaps all on one line, perhaps on three, and with or without explanatory text. For instance you could print out in the format:
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Add a further instance variable/field refNumber() to your Book class. This stores the Library's reference number. It should be of type String and be initialised to the empty String "" in the constructor, as its initial value is not passed in as a parameter. Instead a public mutator method with the signature:
public void setRefNumber(String ref) should be created. The body of this method should assign the value of the method parameter ref to the refNumber.
Add a corresponding getRefNumber() accessor method to your class so you can check that the mutator works correctly
Modify your printDetails() method to include printing the reference number of the book.
However the method should print the reference number only if it has been set - that is the refNumber has a non-zero length.
If it has not been set, print "ZZZ" instead.
Hint Use a conditional statement whose test calls the length() method of the refNumber String and gives a result like:
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Add a further integer variable/field borrowed to the Book class, to keep a count of the number of times a book has been borrowed. It should (obviously??) be set to 0 in the constructor.
Add a mutator method borrow() to the class. This should increment (add 1 to) the value of borrowed each time it is called.
Include an accessor method getBorrowed() that returns the value of borrowed
Modify Print Details so that it includes the value of the borrowed field along with some explanatory text
PS. sorry it looks so messey

1. In the future, please use a more meaningful subject. "Help needed with java" contains no information. The very fact that you're posting here tells us you need help with Java. The point of the subject is to give the forum an idea of what kind of problem you're having, so that individuals can decide if they're interested and qualified to help.
2. You need to ask a specific question. If you have no idea where to start, then start here: [http://home.earthlink.net/~patricia_shanahan/beginner.html]
3. When you post code, use code tags. Copy the code from the original source in your editor (NOT from an earlier post here, where it will already have lost all formatting), paste it in here, highlight it, and click the CODE button.

New Nokia E7 just bought in Italy * help needed to...

I just bought a new E7
Very nice and light but I let my old E90 and I need some help to solve some problems
How can I
*If I want to check mail manually there is nowhere a function or option or button "check mail" !!
*In my address book of E90 I could add some details on the descriptions. I can't there ! If for an example I wanted to make difference etween more mobiles number on a name I could put on E90 mobile perso or mobile night or mobile urgency
There I can't add any detail on the voices on the phone !
And when I transferred from E90 all those details are now lost and I have the name with 5 mobiles numbers without any tag or note !
*Other very big problem, when you send mails (not sms) there is no folder "sent mails" anywhere !!! You can't keep you sent mails !!!
in italian
* Nei vari indirizzi mail come faccio a fare il controllo mail manualmente ? Non esiste nelle opzioni o da nessuna parte il tasto check mail o similare
* Nella rubrica a differenza sempre del mio ultimo E90 se voglio mettere un dettaglio su le varie voci non posso. Per esempio Mario Rossi ha tre numeri cellulari dove prima mettevo numero celliulare giorno, numero urgenze o numero riservato e adesso non posso. Oltre ad avermi nel trasferimento dei dati dall e90 a e7 perso tutti i "dettagli" della rubrica qui sopra spiegati. Mi ha trasferito i numeri ma senza i dettagli che avevo aggiunto
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no news from Nokia...
Re: New Nokia E7 just bought in Italy * help needed to solve problems
03-May-2011 05:15 PM
Please help answering few functions missing !!
1 Any news from Nokia for the SENT MAIL patch release ???
    Still got empty sent mails and even NO possibility to make automatically a copy in personal   mail of what we send !
2      Other patch ALARM SETTINGS CANT PUT AN alarm for tomorrow for example and can t suspend a daily weekly alarm but can oly cancel and after need to reinsert it
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Help! lost some of my contacts after the new update

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Troubleshooting help needed: My iMac keeps crashing and restarting with a notice: "Spinlock application timed out" What can I do?

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Help needed for writing query

help needed for writing query
i have the following tables(with data) as mentioned below
FK*-foregin key (SUBJECTS)
FK**-foregin key (COMBINATION)
1)SUBJECTS(table name)
SUB_ID(NUMBER) SUB_CODE(VARCHAR2) SUB_NAME (VARCHAR2)
2           02           Computer Science
3           03           Physics
4           04           Chemistry
5           05           Mathematics
7           07           Commerce
8           08           Computer Applications
9           09           Biology
2)COMBINATION
COMB_ID(NUMBER) COMB_NAME(VARCHAR2) SUB_ID1(NUMBER(FK*)) SUB_ID2(NUMBER(FK*)) SUB_ID3(NUMBER(FK*)) SUBJ_ID4(NUMBER(FK*))
383           S1      9           4           2           3
384           S2      4           2           5           3
---------I actually designed the ABOVE table also like this
3) a)COMBINATION
COMB_ID(NUMBER) COMB_NAME(VARCHAR2)
383           S1
384           S2
b)COMBINATION_DET
COMBDET_ID(NUMBER) COMB_ID(FK**) SUB_ID(FK*)
1               383          9
2               383          4
3               383          2
4               383          3
5               384          4
6               384          2
7               384          5
8               384          3
Business rule: a combination consists of a maximum of 4 subjects (must contain)
and the user is less relevant to a COMB_NAME(name of combinations) but user need
the subjects contained in combinations
i need the following output
COMB_ID COMB_NAME SUBJECT1 SUBJECT2      SUBJECT3      SUBJECT4
383     S1     Biology Chemistry      Computer Science Physics
384     S2     Chemistry Computer Science Mathematics Physics
or even this is enough(what i actually needed)
COMB_ID     subjects
383           Biology,Chemistry,Computer Science,Physics
384           Chemistry,Computer Science,Mathematics,Physics
you can use any of the COMBINATION table(either (2) or (3))
and i want to know
1)which design is good in this case
(i think SUB_ID1,SUB_ID2,SUB_ID3,SUB_ID4 is not a
good method to link with same table but if 4 subjects only(and must) comes
detail table is not neccessary )
now i am achieving the result by program-coding in C# after getting the rows from oracle
i am using oracle 9i (also ODP.NET)
i want to know how can i get the result in the stored procedure itsef.
2)how it could be designed in any other way.
any help/suggestion is welcome
thanks for your time --Pradeesh

Well I forgot the table-alias, here now with:
SELECT C.COMB_ID
, C.COMB_NAME
, (SELECT SUB_NAME
FROM SUBJECTS
WHERE SUB_ID = C.SUB_ID1) AS SUBJECT_NAME1
, (SELECT SUB_NAME
FROM SUBJECTS
WHERE SUB_ID = C.SUB_ID2) AS SUBJECT_NAME2
, (SELECT SUB_NAME
FROM SUBJECTS
WHERE SUB_ID = C.SUB_ID3) AS SUBJECT_NAME3
, (SELECT SUB_NAME
FROM SUBJECTS
WHERE SUB_ID = C.SUB_ID4) AS SUBJECT_NAME4
FROM COMBINATION C;
As you need exactly 4 subjects, the columns-solution is just fine I would say.

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