Help required for ---- Java Client  -- XI -- R/3

Hello,
*My Java Client is on Server A. My XI is on server B. I had wsdl (webservice) with me .*
How to call wsdl (webservice) from Java Client that is on Server A to XI that is on server B.
Pls help
Regards

Good Morning Prateek,
I have tested with Altoval XML spy . It is working fine.
Altoval XML spy (on my local machine) -- XI -- R/3.
Now instead of xml spy I want java client  -- XI -- R/3 with scanerio that javal client is on server A and XI on server B.
2. For that request parameter (O/B Interface) I have made wsdl (webservice) through XI .
After making wsdl it ask to save that wsdl.I have saved that wsdl currently
in my local machine.
3.How to call this wsdl (webservice) from Java Client that is on Server A to XI that is on server B.
Pls explain me the all the steps in detail and also send me links/docs for it.
Regards

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    }//end class
    I am sorry for all this junk code but I only understand it this way. Your urgent help is required. Looking forward to your reply.
    Thanks in advance.
    Koonda
    //

    Hi,
    Thanks for your help but I really don't understand the table lookup algorithm. Could you please send me some code to implement that.
    I will send you the formatted code as well
    Thanks for your help.
    looking forward to your reply.
    Koonda
    Hi all,
    I am a student and I have a project due 20th of this month, I mean May 20, 2007 after 8 days. The project is about creating a Connect Four Game. I have found some code examples on the internet which helped me little bit. But there are lot of problems I am facing developing the whole game. I have drawn the Board and the two players can play. The players numbers can fill the board, but I have problem implementing the winner for the game. I need to implement the hasWon() method for Horizontal win, Vertical win and Diagonal win. I also found some code examples on the net but I was unable to make it working. I have 5 classes and one interface which I m implementing. The main problem is how to implement the hasWon() method in the PlayGame class below with Horizontal, vertical and diagonal moves.
    Sorry there is so much code.
    This the interface I must implement, but now I am only implementing the int move() of this interface. I will implement the rest later after solving the winner problem with your help.
    Interface code..............
    interface Player {
    void init (Boolean color);
    String name ();
    int move ();
    void inform (int i);
    Player1 class......................
    import java.util.*;
    import java.io.*;
    import javax.swing.*;
    public class Player1 implements Player
    public Player1()
    public int move()
    Scanner scan = new Scanner(System.in);
    // BufferedReader stdin = new BufferedReader (new InputStreamReader(System.in));
    int player1;
    System.out.println ("What is your Number, player 1?");
    player1 = scan.nextInt();
    System.out.println ("Hey number"+player1+" are you prepared to CONNECT FOUR");
    System.out.println();
    return player1;
    //Player.move();
    //return player1;
    }//end move method
    public void init (Boolean color)
    public void inform (int i)
    public String name()
    return "Koonda";
    }//end player1 class
    Player2 class...........................
    import java.util.*;
    import java.io.*;
    import javax.swing.*;
    public class Player2 implements Player
    public int move()
    //int cup0,cup1,cup2,cup3,cup4,cup5,cup6;
    // cup0=5;cup1=5;cup2=5;cup3=5;cup4=5;cup5=5;cup6=5;
    //int num1, num2;
    Scanner scan = new Scanner(System.in);
    // BufferedReader stdin = new BufferedReader (new InputStreamReader(System.in));
    int player2;
    System.out.println ("What is your Number, player 2?");
    player2 = scan.nextInt();
    System.out.println ("Hey "+player2+" are you prepared to CONNECT FOUR");
    System.out.println();
    //return player1;
    return player2;
    }//end move method
    public void init (Boolean color)
    public void inform (int i)
    public String name()
    return "malook";
    }//end player1 class
    PlayGame class which contains all the functionality.........................................................
    import java.util.*;
    import java.io.*;
    import javax.swing.*;
    public class PlayGame
    //Player player1;
    //Player player2;
    int [][]ConnectFourArray;
    boolean status;
    int winner;
    int player1;
    int player2;
    public PlayGame()
    //this.player1 = player1;
    //this.player2 = player2;
    public void StartGame()
    try{
    // int X = 0, Y = 0;
    //int value;
    int cup0,cup1,cup2,cup3,cup4,cup5,cup6;
    cup0=5;cup1=5;cup2=5;cup3=5;cup4=5;cup5=5;cup6=5;
    int[][] ConnectFourArray = new int[6][7];
    int num1, num2;
    for(int limit=21;limit!=0;limit--)
    BufferedReader selecter = new BufferedReader (new InputStreamReader(System.in));
    String column1;
    System.out.println();
    for ( int row=0; row < ConnectFourArray.length; row++ ){
    System.out.print("Row " + row + ": ");
    for ( int col=0; col < ConnectFourArray[row].length; col++ )
    System.out.print( ConnectFourArray[row][col] + " ");
    System.out.println();
    System.out.println();
    System.out.println ("Please Select a column of 0 through 6 ");
    column1 = selecter.readLine();
    num1= Integer.parseInt(column1);
    System.out.println();
    if (num1==0){
    ConnectFourArray[cup0][0]=1;
    cup0=cup0-1;
    else if (num1==1){
    ConnectFourArray[cup1][1]=1;
    cup1=cup1-1;
    else if (num1==2){
    ConnectFourArray[cup2][2]=1;
    cup2=cup2-1;
    else if (num1==3){
    ConnectFourArray[cup3][3]=1;
    cup3=cup3-1;
    else if (num1==4){
    ConnectFourArray[cup4][4]=1;
    cup4=cup4-1;
    else if (num1==5){
    ConnectFourArray[cup5][5]=1;
    cup5=cup5-1;
    else if (num1==6){
    ConnectFourArray[cup6][6]=1;
    cup6=cup6-1;
    System.out.println();
    BufferedReader selecter2 = new BufferedReader (new InputStreamReader(System.in));
    String column2;
    System.out.println();
    for ( int row=0; row < ConnectFourArray.length; row++ ){
    System.out.print("Row " + row + ": ");
    for ( int col=0; col < ConnectFourArray[row].length; col++ )
    System.out.print( ConnectFourArray[row][col] + " ");
    System.out.println();
    System.out.println();
    System.out.println ("Please Select a column of 0 through 6 ");
    column1 = selecter.readLine();
    num1= Integer.parseInt(column1);
    System.out.println();
    if (num1==0){
    ConnectFourArray[cup0][0]=2;
    cup0=cup0-1;
    else if (num1==1){
    ConnectFourArray[cup1][1]=2;
    cup1=cup1-1;
    else if (num1==2){
    ConnectFourArray[cup2][2]=2;
    cup2=cup2-1;
    else if (num1==3){
    ConnectFourArray[cup3][3]=2;
    cup3=cup3-1;
    else if (num1==4){
    ConnectFourArray[cup4][4]=2;
    cup4=cup4-1;
    else if (num1==5){
    ConnectFourArray[cup5][5]=2;
    cup5=cup5-1;
    else if (num1==6){
    ConnectFourArray[cup6][6]=2;
    cup6=cup6-1;
    System.out.println();
    System.out.println();
    catch (Exception E){
    System.out.println("Error with input");
    System.out.println("Would you like to play again");
    try{
    String value;
    BufferedReader reader = new BufferedReader (new InputStreamReader(System.in));
    // Scanner scan = new Scanner(System.in);
    System.out.println("Enter yes to play or no to quit");
    // value = scan.nextLine();
    // String value2;
    value = reader.readLine();
    //value2 = reader.readLine();
    if (value.equals("yes"))
    System.out.println("Start again");
    StartGame(); // calling the StartGame method to play a game once more
    else if (value.equals("no"))
    System.out.println("No more games to play");
    // System.exit(0);
    else
    System.exit(0);
    System.out.println();
    catch (Exception e){
    System.out.println("Error with input");
    finally
    System.out.println(" playing done");
    //StartGame();
    //check for horizontal win
    public int hasWon()
    int status = 0;
    for (int row=0; row<6; row++)
    for (int col=0; col<4; col++)
    if (ConnectFourArray[col][row] != 0 &&
    ConnectFourArray[col][row] == ConnectFourArray[col+1][row] &&
    ConnectFourArray[col][row] == ConnectFourArray[col+2][row] &&
    ConnectFourArray[col][row] == ConnectFourArray[col+3][row])
    //status = true;//int winner;
    if(status == player1)
    System.out.println("Player 1 is the winner");
    else if(status == player2)
    System.out.println("Player 2 is the winner" );
    }//end inner for loop
    }// end outer for loop
    } // end method Winner
    return status;
    }//end class
    ClassConnectFour which designs the board........................
    import java.util.*;
    import java.io.*;
    import javax.swing.*;
    public class ClassConnectFour
    //Player player1;
    //Player player2;
    public ClassConnectFour()
    //this.player1 = player1;
    public void DrawBoard()
    int[][] ConnectFourArray = new int[6][7] ;
    for ( int row=0; row < ConnectFourArray.length; row++ ){
    System.out.print("Row " + row + ": ");
    for ( int col=0; col < ConnectFourArray[row].length; col++ )
    System.out.print( ConnectFourArray[row][col] + " ");
    System.out.println();
    System.out.println();
    }//end class
    TestConnetFour class which uses most of the above class..................
    import java.util.*;
    import java.io.*;
    import javax.swing.*;
    public class TestConnectFour
    public static void main(String[] args)
    ClassConnectFour cf = new ClassConnectFour();
    cf.DrawBoard();
    Player1 player1 = new Player1();
    Player2 player2 = new Player2();
    player1.move();
    player2.move();
    System.out.println("Number 1 belongs to player " + player1.name());
    System.out.println("Number 2 belongs to player " + player2.name());
    PlayGame pg = new PlayGame();
    pg.StartGame();
    pg.hasWon();
    //pg.Play();
    //System.out.println(player.name());
    //System.out.println(player2.name());
    }// end main
    }//end classI am sorry for all this junk code but I only understand it this way. Your urgent help is required. Looking forward to your reply.
    Thanks in advance.
    Koonda

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