Help retreiving count as multiple columns

Question

I have a table 'decision_makers' with columns
'made_by' - decision maker name
and
'decision_code' - code for decision 'A' -accepted 'R' -rejected 'P' -pending
Assuming the data below in the table
user1 'A'
user2 'A'
user3 'P'
user1 'A'
user2 'R'
user3 'A'
user1 - A
I would like to see the out put in the following format
user A R P
user1 2 0 0
user2 1 1 0
user3 1 0 1
total 4 1 1
I am trying like
select "made_by",count("decision_code") from "decision_makers"
where "decision_code"='A' group by "made_by"
But how can I write this 3 times to get desired result.
Would it be possible by a single query? or do I need to write a sql procedure or 'view'
I am new to Oracle and the above requirement looks complex to me.
Anybody can push me in the right direction?
Thanks
R,
Edited by: user10974770 on Apr 23, 2010 3:35 AM

Answer 1

Welcome to the forums!
It looks like you need a PIVOT with ROLLUP to achieve the results you want:
SQL> WITH decision_makers AS
  2  (
  3          SELECT 'user1' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
  4          SELECT 'user2' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
  5          SELECT 'user3' AS MADE_BY, 'P' AS DECISION_CODE FROM DUAL UNION ALL
  6          SELECT 'user1' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
  7          SELECT 'user2' AS MADE_BY, 'R' AS DECISION_CODE FROM DUAL UNION ALL
  8          SELECT 'user3' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL
  9  )
10  SELECT  DECODE(GROUPING(MADE_BY),1,'total',MADE_BY) AS MADE_BY
11  ,       COUNT(CASE WHEN DECISION_CODE='A' THEN 1 END) AS A
12  ,       COUNT(CASE WHEN DECISION_CODE='R' THEN 1 END) AS R
13  ,       COUNT(CASE WHEN DECISION_CODE='P' THEN 1 END) AS P
14  FROM    DECISION_MAKERS
15  GROUP BY ROLLUP(MADE_BY)
16  /
MADE_BY                            A                    R                    P
user1                              2                    0                    0
user2                              1                    1                    0
user3                              1                    0                    1
total                              4                    1                    1Edited by: Centinul on Apr 23, 2010 6:49 AM
Simpler solution