Distinct count on multiple columns

Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Prod
PL/SQL Release 10.2.0.1.0 - Production
"CORE     10.2.0.1.0     Production"
TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
select  distinct USERID,REG_DATE,COUNT(*) CNT from REGISTRATION where TRUNC(REG_DATE)>TO_DATE('01-NOVEMBER-2012','DD-MONTH-YYYY')
and REG_ID not in (select REG_ID from REG_SEG_CAT) group by USERID,REG_DATE  
41     27-NOV-12     1
43     27-NOV-12     1
43     27-NOV-12     1any idea how to show count=2 for userid 43
Edited by: 946207 on Dec 4, 2012 2:11 PM

Hi,
How could we know if you don't show us your input data?
Please read SQL and PL/SQL FAQ
Additionally when you put some code please enclose it between two lines starting with {noformat}{noformat}
i.e.:
{noformat}{noformat}
SELECT ...
{noformat}{noformat}
Regards.
Al                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               

Similar Messages

  • How to get a distinct count of multiple columns

    I've done this before and I'll be darned why I can't recall this.
    Table with 3 columns with the primary key defined in column a.
    Row a b c
    num.
    1 020 how abc
    2 030 why def
    3 010 not ghi
    4 040 how abc
    5 050 yes def
    6 060 why def
    So what I want is a count of the unique values for columns b and c as if b and c were actually one field.
    So the result of the query would be:
    Count = 4 unique rows.
    Hopefully I'm making some sort of sense. It's a bit much to ask about the number of occurrences of each duplicate value, I'm sure just getting count of the unique rows of the non-indexed rows will be sufficient. Since the query is meant to be universal for multiple columns of numeric and alphanumeric data and can be expanded for multiple columns, I am simply trying to get a basic skeleton that works for an "on the fly" analysis.

    Thanks to all of you. I had the idea and just couldn't nail it down. You did it.
    All of you understood what I poorly communicated. My apologies for the lack of prep with a table, I was running patches on the system and couldn't dare interrupt it on my laptop and starting Oracle 11 while Micro$lop was patching all sorts of evil code. This is something I'm setting up on my own time so it's a work I'm going to try to be proud of. So there will be plenty of instrumentation and debugging code for timing.
    I'd thought of concatenating columns and was worried it wouldn't backport to older Oracle versions (work goes back to 8.1.7) with nulls and other goofy things like long raw fields or lob/clobs plus the other DBs that are at various sites. What I'm trying to do is improve on a crappy data analysis tool SAP provides to use with reporting unique columns. (Basis people could recognize this as DB05). I tried dragging out the SQL that their ABAP/4 language generates from an SQL trace but it was unusable and often dies on internal storage which on most sites is about 4GB per process. Needless to say, the program is wasteful and I'm trying to keep the work on the DB where it belongs and discourage cowboys from doing this in the DB on the fly and at the same time make it simpler for junior members to use while having a semblance of an audit trail.
    What I'm trying to do is work out a tool that checks all the crappy secondary indexes that were created by folks who seem to think in ways that are from an alien species not yet speculated about even with the strongest psychedelics. One of them actually decreases performance by a minimum factor of 5. It's not much when it's 5 seconds but when the response time averages about 3 hours beforehand, you can imagine what it was like afterward. In this particular case, the "logic" was that the index needed to be defined by the order of the fields of the select clause. Some myths never die. So it's not easy to work out which ones haven't been used in a long time, so it's down to finding which of the custom ones are actually bad in terms of selectivity. Some of these may have made a little bit of sense when the system was started up, now that some of these have millions of rows instead of a few thousand, thaw tend to expose the flaws in design.
    I'm also trying to make this work on multiple DBs such as DB2, MaxDB and (sob) SQL Squealer. The idea is to write this in ABAP code as a utility without the overhead of internal tables in ABAP as some of these tables are many millions of rows and I have to account for the size in memory. (ABAP field sizes in internal memory are generally much larger than the actual DB lengths. so every bit helps!) So I'm trying to create actual SQL on the fly and use it internally without going through the SAP DB interface which limits the type of SQL functions used and all the overhead. It's intended to grab a secondary index and if there are more than 2 fields defined, work it backwards to show unique values for all columns, all columns - 1, all columns - 2 and so on back to the initial column in the index.
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    I'm testing null values next (which worked!) but these suggestions all seem to follow the same idea which won't work in ABAP without some serious memory issues. So I'm down to this type of coding:
    exec sql.
    <dynamically generated true SQL>
    end-exec.
    rather than using ABAP with their concept of "open SQL" and the DB interface with all the overhead.
    RB's suggestion of the UNION ALL wasn't quite what I was looking for BUT it made me think that this would be a nice enhancement for evaluations!
    So the candidates that seem to work for what I wanted are as follows:
    SQL> SELECT COUNT (MIN (0)) AS distinct_col3_col4_cnt
    2 from rb group by b, c;
    DISTINCT_COL3_COL4_CNT
    7
    select count(distinct(b || c)) num_rows from rb;
    So thanks also to Frank, APNL and Nimesh for their examples. Now the fun starts as I spec out the processing.

  • How do you count the multiple columns of a field in a table

    How do you count the multiple columns of a field in a table

    Hi,
    4396bf34-e890-4202-a6b0-4e08c9ff0e89 wrote:
    How do you count the multiple columns of a field in a table
    Whenever you have a problem, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables involved, and also post the results you want from that data.
    Explain, using specific examples, how you get those results from that data.
    Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
    See the forum FAQ: https://forums.oracle.com/message/9362002
    "Field" isn't a standard database term.  Some people say "field" when they mean "column", but I don't think that's what you mean ("How do you count the multiple columns of a column ..").  Do you want to know how many times a column is used (as opposed to NULL), or the number of different values in a column?  You really need to show what you want.

  • Distinct count for multiple fact tables in the same cube

    I'm fairly new to working with SSAS, but have been working with DW environments for many years.
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    Thanks for the help,
    Andy

    Hi Andy,
    Each distinct count measure cause an ORDER BY clause in the SELECT sent to the relational data source during processing. In SSAS 2005 or later, it creates a new measure group for each distinct count measure(it's a technique strategy for improving perormance).
    Besides, please take a look at the following distinct count optimization techniques:
    Create Customized Aggregations
    Define a Processing Plan
    Create Partitions of Equal Size
    Use Partitions Comprised of a Distinct Range of Integers
    Distribute the Hash of Your UserIDs
    Modulo Function
    Hash Function
    Choose a Partitioning Strategy
    For more detail information, please refer to the article below:
    Analysis Services Distinct Count Optimization:
    http://www.microsoft.com/en-us/download/details.aspx?id=891
    In addition, here is a good article about SSAS Best Practices for your reference:
    http://technet.microsoft.com/en-us/library/cc966525.aspx
    If you have any feedback on our support, please click
    here.
    Hope this helps.
    Elvis Long
    TechNet Community Support

  • Calculating distinct counts of dimension columns

    Hi, OBIEE Gurus.  Here's today's question on the quiz show "Can this be done?".
    Month
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    Sales
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    # Regions
    Jan-2013
    East
    1000
    2
    3
    Jan-2013
    Central
    2000
    2
    3
    Jan-2013
    West
    3500
    2
    3
    Feb-2013
    East
    1250
    2
    3
    Feb-2013
    Central
    1925
    2
    3
    Feb-2013
    West
    3450
    2
    3
    The # Months and # Regions columns are the goal today.  There are two months in this analysis (Jan-2013, Feb-2013), out of a total population of 96 months.  There are three regions in this analysis (East, Central, West) out of a total population of 7 regions.  I want those values (2 and 3, respectively) reflected in the # Months and # Regions columns.
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    I found one potential (but somewhat flawed) solution for # Months:
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    If you have anything more elegant, bring it on.

  • Help retreiving count as multiple columns

    I have a table 'decision_makers' with columns
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    and
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    user1 'A'
    user2 'A'
    user3 'P'
    user1 'A'
    user2 'R'
    user3 'A'
    user1 - A
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    user A R P
    user1 2 0 0
    user2 1 1 0
    user3 1 0 1
    total 4 1 1
    I am trying like
    select "made_by",count("decision_code") from "decision_makers"
    where "decision_code"='A' group by "made_by"
    But how can I write this 3 times to get desired result.
    Would it be possible by a single query? or do I need to write a sql procedure or 'view'
    I am new to Oracle and the above requirement looks complex to me.
    Anybody can push me in the right direction?
    Thanks
    R,
    Edited by: user10974770 on Apr 23, 2010 3:35 AM

    Welcome to the forums!
    It looks like you need a PIVOT with ROLLUP to achieve the results you want:
    SQL> WITH decision_makers AS
      2  (
      3          SELECT 'user1' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
      4          SELECT 'user2' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
      5          SELECT 'user3' AS MADE_BY, 'P' AS DECISION_CODE FROM DUAL UNION ALL
      6          SELECT 'user1' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL UNION ALL
      7          SELECT 'user2' AS MADE_BY, 'R' AS DECISION_CODE FROM DUAL UNION ALL
      8          SELECT 'user3' AS MADE_BY, 'A' AS DECISION_CODE FROM DUAL
      9  )
    10  SELECT  DECODE(GROUPING(MADE_BY),1,'total',MADE_BY) AS MADE_BY
    11  ,       COUNT(CASE WHEN DECISION_CODE='A' THEN 1 END) AS A
    12  ,       COUNT(CASE WHEN DECISION_CODE='R' THEN 1 END) AS R
    13  ,       COUNT(CASE WHEN DECISION_CODE='P' THEN 1 END) AS P
    14  FROM    DECISION_MAKERS
    15  GROUP BY ROLLUP(MADE_BY)
    16  /
    MADE_BY                            A                    R                    P
    user1                              2                    0                    0
    user2                              1                    1                    0
    user3                              1                    0                    1
    total                              4                    1                    1Edited by: Centinul on Apr 23, 2010 6:49 AM
    Simpler solution

  • Distinct count of values which are displayed in two columns in SSAS

    Hi,
    How is it possible to get distinct count of two columns in fact table, meaning how many different appearances are in both columns.
    Please note I DO NOT mean distinct count on the concatenated fields.
    I’ll demonstrate with example:
    Fact table- deals with CustomerID and SupplierID and deals data.
    I need distinct count of companies which are either customer/ supplier in the fact table.
    (making a concatenated field and distinct count on that would not give what I need).
    Ex: fact :
    Deal1, Customer X, Supplier Y …
    Deal2, Customer X, Supplier Z …
    Distinct count of companies in the above should be 3.
    How can this be done?
    Thanks
    Namnami
    Anyone?? There must be a way to do this?!

    Are you trying to do this using the SSAS model, or just off the data using SQL?  If you were to just use SQL I would create two sub queries and union them to remove duplicates.
    ie.
    SELECT DISTINCT customer FROM table_1
    UNION
    SELECT DISTINCT supplier FROM table_1
    This will give you one unique master list.

  • DAX query to calculate distinct count respect to a column after a Filter function - SSAS 2012 Tabular

    Hi,
    I'm trying to build the dax query to determine the distinct count for a column returned by the application of a Filter function.
    evaluate(
    row("counter",
    countrows(
    filter(order_summary,
    year(order_summary[change_date]) = 2013) )
    I need to count the distinct values for an id returned by the Filter function.
    Any helps, please? Thanks

    Hi pscorca,
    According to your description, you want to calculate the distinct values for records where change_date is 2013. Right?
    In this scenario, we can use the DISTINCT() function within COUNTROWS(). Please try the expression below:
    =calculate(
    countrows(distinct(order_summary[column])),
    Filter('order_summary', year(order_summary[change_date])=2013)
    Reference:
    Distinct Count Measure in PowerPivot using DAX
    Related Distinct Count
    Best Regards,
    Simon Hou
    TechNet Community Support

  • Getting DISTINCT count from two different columns

    Hi all,
    I have following query which gives currency code from two different tables. I would like to get the distinct count of currency codes from these two different columns.
    SELECT eb.person_seq_id, eb.bonus_amount, eb.currency_cd, ed.currency_cd_host
    FROM fr_emp_bonuses eb, fr_emp_details ed, fr_periods p
    WHERE eb.person_seq_id = ed.person_seq_id AND ed.period_seq_id = eb.period_seq_id
    AND ed.period_seq_id = p.period_seq_id AND p.period_status = 'CURRENT'
    AND eb.bonus_amount >= 0 AND eb.person_seq_id = 3525125;
    This query gives following result
    3525125     240000     USD     INR
    3525125     0      USD     INR
    3525125     60000      USD     INR
    3525125     50000      USD     INR
    There are two distinct currency codes (USD, INR) and total amount is 350000. So I am looking for a query to give me the following result
    3525125     350000 2
    Thanks in advance

    Hi,
    Here's one way:
    WITH     original_query     AS
         SELECT  eb.person_seq_id
         ,     eb.bonus_amount
         ,     eb.currency_cd
         ,     ed.currency_cd_host
         FROM     fr_emp_bonuses         eb
         ,     fr_emp_details          ed
         ,     fr_periods          p
         WHERE      eb.person_seq_id    = ed.person_seq_id
         AND      ed.period_seq_id    = eb.period_seq_id
         AND      ed.period_seq_id    = p.period_seq_id
         AND      p.period_status         = 'CURRENT'
         AND      eb.bonus_amount     >= 0
         AND     eb.person_seq_id    = 3525125
    ,     unpivoted_data     AS
         SELECT     person_seq_id
         ,     bonus_amount
         ,     currency_cd
         FROM     original_query
        UNION ALL
            SELECT  person_seq_id
         ,     0               AS bonus_amount
         ,     currency_cd_host     AS currency_cd
         FROM     original_query
    SELECT       person_seq_id
    ,       SUM (bonus_amount)          AS total_bonus_amount
    ,       COUNT (DISTINCT currency_cd)     AS distinct_currency_cds
    FROM       unpivoted_data
    GROUP BY  person_seq_id
    ;There may be a shorter, more efficient way to get the same results, but without knowing more about your tables, I can't tell.
    The tricky thing is getting two columns (currency_cd and currencuy_cd_host in this case) counted together. You can't simply say
    COUNT (DISTINCT eb.currency_cd) +
    COUNT (DISTINCT ed.currency_code_host)That happens to get the correct result with the sample data you posted, but what if you had data like thEe following?
    currency_cd     currency_cd_host
    INR          USD
    USD          INRHere, the count of distinct currency_cds is 2, and the count of distinct currency_cd_hsots is also 2. Does that mean the grand total is 2 + 2 = 4? No, the 2 codes in one column arte the same 2 codes as in the other column. We need to get both currency_cd and currency_cd_hsot into the same column, and then do COUNT (DISTINCT ...) on that combined column. A UNION, as shown above, will certainly do that, starting with your query as you posted it. The query you posted isn't necessarily the best frist step towards this result, however, so there may be a much better approach, depending on your tables.
    Edited by: Frank Kulash on Feb 1, 2012 6:21 PM
    Here's a slightly shorter, and probably more efficient way to get the same results:
    WITH     cntr     AS
         SELECT     LEVEL     AS n
         FROM     dual
         CONNECT BY     LEVEL     <= 2
    SELECT       eb.person_seq_id
    ,       SUM (eb.bonus_amount)          AS total-amount
    ,       COUNT ( DISTINCT CASE
                        WHEN  c.n = 1
                        THEN  eb.currency_cd
                        ELSE  ed.currency_cd_host
                      END
              )               AS distinct_currency_cds
    FROM       fr_emp_bonuses    eb
    ,       fr_emp_details    ed
    ,       fr_periods          p
    ,       cntr              c
    WHERE        eb.person_seq_id  = ed.person_seq_id
    AND        ed.period_seq_id  = eb.period_seq_id
    AND        ed.period_seq_id  = p.period_seq_id
    AND        p.period_status   = 'CURRENT'
    AND        eb.bonus_amount   >= 0
    AND       eb.person_seq_i   = 3525125
    --       NOTE: no join condition involving c; we really do want a cross-join
    GROUP BY  eb.person_seq_id
    ;

  • Count Distinct based on another column in the same table

    Hello,
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    Is there an easy way to achieve this on the DWH level or should it be done with MDX in the cube?
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    Hi,
    Below a solution to use the view by adding a column with window functioning, maybe this will help.
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    ('BBB','1'),
    ('BBB','1'),
    ('BBB','1'),
    ('CCC','1'),
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    ('CCC','3');
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    AS
    SELECT PERSON
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    FROM #TMP
    SELECT PERSON, MAX(RN) AS RN
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    Reshma
    Please Vote as Helpful if an answer is helpful and/or Please mark Proposed as Answer or Mark As Answer when question is answered

  • Counting Occurences over multiple columns

    I have searched the forums and found how to calculate the number of occurrences of a word in a single column.
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    I need to find out how many times a specific agent represents both buyers and sellers.
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    I have very large tables with multiple categories for each sale.
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    Please help.
    All the best,
    Will

    Will,
    Jerry has given you a good solution in general terms but there are some ambiguities in your question.
    For example, your question suggests there is transaction amount column, as one might expect, but did not specify if these amounts are listed in separate buyer/seller columns. The solution below assumes they are in a single column.
    An auxiliary column (hidden) was added to the Data Table to determine whether or not an agent represented both buyer and seller. The agent's name appears in this column if he/she did, and the formula is:
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    pw

  • Distinct count using lookup table

    How can I get a distinct count of column values using a different table?
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    What I want is to find counts for all companies that have a value of "california" in the "state" column of the "lookup" Table. I want the output to look like:
    Sears 17
    Pennys 22
    Marshalls 6
    Macys 9
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    M

    Mark,
    In the future you might consider creating test cases for us to work with. Something similar to the following where sample data is created for each table as the union all of multiple select statementsselect 'INIT_ASSESS' lookup_type
         , 1 lookup_value
         , 'Initial Assessment' lookup_value_desc
      from dual union all
    select 'JOB_REF', 2, 'Job Reference' from dual union all
    select 'SPEC_STA', 3, 'SPEC STA' from dual;
    select 'INIT_ASSESS' rfs_category
         , 1 val
      from dual union all
    select 'JOB_REF', 1 from dual union all
    select 'JOB_REF', 1 from dual union all
    select 'SPEC_STA', null from dual;Then we can either take your select statements and make them the source of a CTAS (create table as) statementcreate table lookup as
    select 'INIT_ASSESS' lookup_type
         , 1 lookup_value
         , 'Initial Assessment' lookup_value_desc
      from dual union all
    select 'JOB_REF', 2, 'Job Reference' from dual union all
    select 'SPEC_STA', 3, 'SPEC STA' from dual;, or include them as subfactored queries by using the with statement:with lookup as (
    select 'INIT_ASSESS' lookup_type
         , 1 lookup_value
         , 'Initial Assessment' lookup_value_desc
      from dual union all
    select 'JOB_REF', 2, 'Job Reference' from dual union all
    select 'SPEC_STA', 3, 'SPEC STA' from dual
    ), RFS as (
    select 'INIT_ASSESS' rfs_category
         , 1 val
      from dual union all
    select 'JOB_REF', 1 from dual union all
    select 'JOB_REF', 1 from dual union all
    select 'SPEC_STA', null from dual
    select lookup_value_desc, count_all, count_val, dist_val
      from lookup
      join (select rfs_category
                 , count(*) count_all
                 , count(val) count_val
                 , count(distinct val) dist_val
              from RFS group by rfs_category)
        on rfs_category = lookup_type;Edited by: Sentinel on Nov 17, 2008 3:38 PM

  • Groups into Multiple Columns

    Post Author: Donamese
    CA Forum: General
    I am trying to create a report that is split between 3 companies and all states using a distinct count of individuals (as there are duplicates in the data pool).  I would like the report to look like:
    State             Company 1                Company 2                 Company 3
    AL                       0                                 16                           5
    AR                      3                                  9                             4
    AZ                       5                                 0                              7
    Currently I can only get it to list vertical like:
    Company 1
    AL       0
    AR      3
    AZ       5
    Company 2
    AL     16
    etc....
    I am unable to get the formating of multiple columns with the grouping.  Is it possible?  And if

    Post Author: rookie10
    CA Forum: General
    Try inserting a Cross Tab in the Report or page header. Its pretty much like a pivot table.
    Use State as the Row, Company as the Column, Individuals as Summarized field using Distinct Count as the summary type.
    In customized style part of the cross tab you can hide some of the totals and such to get pretty close to the report above - supress subtotals and such.
    Hope this works for you. I was pretty excited when I found this feature in Crystal.
    Rookie10

  • SELECT in SELECT returning multiple columns ?

    10.2.0.3 version.
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