Help with expression for business days

Question

Dear Frends,
I need help with business days expression.
The report is for call center operation. Whenever a user calls in and opens an issue it is recorded as a case. And each case is associated with create time and valueofone(which is always one).
My report contains 'case type' as the first column, and rest of the columns are age buckets(col1: 0-5 days, col2: 6-10 days). By saying agebuckets I mean number of days between create date and current date. All the cases that are less than 5 days older will go to first column and similarly all the cases that are 6-10 days old will go to the second column and so on.
In a normal case I use the following case statement: case when daysbetween(current_date, create_date) between x1 and x2 then count(valueofone) else null end
But I need to calculate only the business days as age, so I need an expression look something like this: case when (_days_between(current_date, create_date)-no of holidays) between x1 and x2 then count(valueofone) else null end
Note: My calendar table has a column 'Business Day' which assigns 'Y' to Business day and 'N' to holiday.
Any help with this expression or any suitable way.
Regards
Chilla

Answer 1

If you have a calendar table, wouldn't your function be just
CREATE FUNCTION business_days_between( p_day1 IN DATE, p_day2 IN DATE )
  RETURN NUMBER
IS
  l_cnt NUMBER;
BEGIN
  SELECT COUNT(*)
    INTO l_cnt
    FROM calendar_table ct
   WHERE ct.business_day = 'Y'
     AND ct.<<date column>> >= trunc(p_day1)
     AND ct.<<date column>> < trunc(p_day2);
  RETURN l_cnt;
END;Basially, count the number of rows in your calendar table that are business days between the two dates.
Justin