Help with Order creation

I have a Workflow....
There I have component Siebel Operation
(BC is Order Entry - Orders
Operation is Insert)
It's work successfully BUT I need to create Order and when I'm creating
fill some fields with my data...Now it's creating without filling fields
How to do this using input arguments of siebel operation???

If "Argument Fields for an Input Argument"
http://download.oracle.com/docs/cd/B40099_02/books/BPFWorkflow/BPFWorkflow_Reference26.html#wp1168244
doesn't help, then you need to tell us more exactly what you do and what you can't get to work.
Axel

Similar Messages

I had to put my computer by together without migration or time machine I NEED help with order of the files?

I had to put my computer by together without migration or time machine I NEED help with order of the files?

Hi, where are these other files exactly?

Help with ordering prints

Can anyone help with ordering prints for Shutterfly? I keep getting to step 4 (payment type) and then it just goes to blank page and nothing happens.

Thanks for your help, I am new to all of this. I think it was my edited pics that were the problem, they were to big of files, I had to go and save them as a new file as a jpeg and then went to shutterfly and downloaded from there. I never could get it to work from Photoshop Elem.
Date: Thu, 9 May 2013 00:51:58 -0700
From: [email protected]
To: [email protected]
Subject: Help with ordering prints
    Re: Help with ordering prints
    created by vsh07 in Photoshop Elements - View the full discussion
Looks like some problem! Just try the following steps. They worked for me: 1. Go to shutterfly website (www.shutterfly.com) and log into your account.2. In My Account Section> Billing Information, add your Credit Card details and Save.3. Logout from your account and open Photoshop Elements application to order prints.4. Now,on step4 (payment type),your Credit Card details will appear magically Let me know if this solution works for you. It can be of some help to other members too.
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Need help with order by

Test Data:
CREATE TABLE "TEST_GMU"
   ( "PZINSKEY" VARCHAR2(255) NOT NULL ENABLE,
"PXCREATEDATETIME" DATE,
"PXURGENCYASSIGN" NUMBER(18,0),
"WORK_PXURGENCYWORK" NUMBER(18,0),
"MASTERACCNTFIRMCUSTID" VARCHAR2(255 CHAR)
   ) SEGMENT CREATION IMMEDIATE
PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255 NOCOMPRESS LOGGING
STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE DEFAULT)
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12858!AMADVISORSERVICESFLOW','16-JUL-13 15.55.57.000000 PM',0,40,'2531215');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12859!AMADVISORSERVICESFLOW','16-JUL-13 15.01.22.000000 PM',0,40,'742254777');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12860!AMADVISORSERVICESFLOW','16-JUL-13 15.01.23.000000 PM',0,40,'2531215');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12861!AMADVISORSERVICESFLOW','16-JUL-13 15.03.55.000000 PM',0,40,'2568091');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12862!AMADVISORSERVICESFLOW','16-JUL-13 15.03.56.000000 PM',0,40,'742254777');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12863!AMADVISORSERVICESFLOW','16-JUL-13 15.03.57.000000 PM',0,40,'2568091');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12864!AMADVISORSERVICESFLOW','16-JUL-13 15.06.29.000000 PM',0,40,'742254777');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12865!AMADVISORSERVICESFLOW','16-JUL-13 15.06.31.000000 PM',0,40,'2568091');
insert into test_gmu values ('ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12866!AMADVISORSERVICESFLOW','16-JUL-13 15.06.32.000000 PM',0,40,'742254777');
The output required is like below
1.       AM-12859 BXYZAB CO. 742254777 07/16/2013 15:01:21
2.       AM-12862 BXYZAB CO. 742254777 07/16/2013 15:03:56
3.       AM-12864 BXYZAB CO. 742254777 07/16/2013 15:06:27
4.       AM-12866 BXYZAB CO. 742254777 07/16/2013 15:06:31
5.       AM-12858 WHIJKL CO. 2531215 07/16/2013 15:01:16       The values of this timestamp is actually '16-JUL-13 15.55.57 in datbase
6.       AM-12860 WHIJKL CO. 2531215 07/16/2013 15:01:22
7.       AM-12861 SIJKLM CO. 2568091 07/16/2013 15:03:54
8.       AM-12863 SIJKLM CO. 2568091 07/16/2013 15:03:56
9.       AM-12865 SIJKLM CO. 2568091 07/16/2013 15:06:30
I could work this out till below:
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12859!AMADVISORSERVICESFLOW 7/16/2013 3:01:22 PM 0 40 742254777
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12862!AMADVISORSERVICESFLOW 7/16/2013 3:03:56 PM 0 40 742254777
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12864!AMADVISORSERVICESFLOW 7/16/2013 3:06:29 PM 0 40 742254777
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12866!AMADVISORSERVICESFLOW 7/16/2013 3:06:32 PM 0 40 742254777
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12861!AMADVISORSERVICESFLOW 7/16/2013 3:03:55 PM 0 40 2568091
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12863!AMADVISORSERVICESFLOW 7/16/2013 3:03:57 PM 0 40 2568091
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12865!AMADVISORSERVICESFLOW 7/16/2013 3:06:31 PM 0 40 2568091
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12860!AMADVISORSERVICESFLOW 7/16/2013 3:01:23 PM 0 40 2531215
ASSIGN-WORKBASKET SCHWAB-ACE-SERVICEREQUEST-WORK-ACCTMAINT AM-12858!AMADVISORSERVICESFLOW 7/16/2013 3:55:57 PM 0 40 2531215
with order by masteraccntfirmcustid desc ,pxcreatedatetime
But one of the developer told me masteraccntfirmcustid should be asc
This resultset is supposed to be ordered by
order by masteraccntfirmcustid ,pxurgencyassign desc NULLS LAST ,work_pxurgencywork desc NULLS LAST,pxcreatedatetime
in the test data I have been given pxurgencyassign and work_pxurgencywork is same for all the records
Could you please help?
Thanks,
swapnil

the results of the query are not matching the data in the table. like ....
1.      BXYZAB CO.
2.      BXYZAB CO.
3.      BXYZAB CO.

Need help with order booking tutorial

Hi
I am new to OracleFusion.
Started Learning By practising OrderBooking tutorial for 10g.
I am practising parellel branching in the tutorial .
I ve invoked Rapid distributors service in branch 1 of the flow activity.
and
i ve invoked Select manufacturing service in branch 2 of flow activity.
I ve deployed order booking service,rapid distributed service,select manufacturing service in the server.
Select manufacturing service is an asynchronous service .for this service to be complete it requires user to manually set price for the item ordered.
So I accesed SelectManufacturinUI in browser as instructed in book.The problem is tht it is directing me to login page where User id and password should be submitted.
In the tutorial no info is given regarding login details fot this page.Hence i am not able to set price for order.
So the Select manufacturing service is not completed ..hence i am not able to move further in the tutorial..
Kindly help with this..if any one has faced same prblm
thanks

Hi
I got the answer. Just posting it so that it helps someone
User id i tried : jcooper
password : Bpel console startup password

Help with order by

I want to select the same column name from 2 tables, combine them, and give them a certain order but I am getting:
ORA-01785: ORDER BY item must be the number of a SELECT-list expression
select a from table1 where a = 'TYY000007'
union all
select a from table2 where a = 'TXXXXXXXX'
order by TRANSLATE(a, 'ABCDEFGHIJKMNOPQRSUVWXYTL0123456789','0123456789ABCDEFGHIJKMNOPQRSUVWXYTL') DESC;
I know the TRANSLATE works because it will work with just 1 table query and I've used it in other queries.
Please help.

Hi,
Noramally, you can ORDER BY something that is not in the SELECT clause.
In a UNION query, you can't.
if you want to ORDER BY d046d (or something derived from it), then you have to include d046d in the SELECT clause. To avoid displaying it, you can do the UNION in a sub-query, like this:
WITH     union_results     AS
     select a, d046d from table1 where a = 'TYY000007'     -- This is easy to do without a UNION,
     union all                                              -- but that's not the point
     select a, d046d from table2 where a = 'TXXXXXXXX'
SELECT       a
FROM       union_results
ORDER BY TRANSLATE ( d046d
                      , 'ABCDEFGHIJKMNOPQRSUVWXYTL0123456789'
              , '0123456789ABCDEFGHIJKMNOPQRSUVWXYTL'
              )          DESC
;

Need help with ORDER BY clause

Hey,
I have a table:
Name: Year:
Eagle 2000
Tiger 2001
Eagle 2002
Lion 2006
Lion 1999
Fox 1991
Lion 1995
I need a query which will return in such order:
Name: Year: Position:
Eagle 2000 1
Eagle 2002 2
Fox 1991 1
Lion 1995 1
Lion 1999 2
Lion 2006 3
Tiger 2001 1
So, of course to get Name and Year in this order is quite easy:
select Name, Year from Animals order by Name, Year;
but how about Position, is there a way to count it with SQL?
any help is welcome,
Silvestras

SQL> with rt as
2 (select 'Eagle' nm, 2000 yr from dual union all
3 select 'Tiger', 2001 from dual union all
4 select 'eagle', 2002 from dual union all
5 select 'Lion', 2006 from dual union all
6 select 'Lion', 1999 from dual union all
7 select 'Fox', 1991 from dual union all
8 select 'Lion', 1995 from dual)
9 select nm,yr,row_number() over(partition by (nm) order by nm,yr) position from rt;
NM            YR   POSITION
Eagle       2000          1
Fox         1991          1
Lion        1995          1
Lion        1999          2
Lion        2006          3
Tiger       2001          1
eagle 2002 1
7 rows selected.
SQL> with rt as
2 (select 'Eagle' nm, 2000 yr from dual union all
3 select 'Tiger', 2001 from dual union all
4 select 'eagle', 2002 from dual union all
5 select 'Lion', 2006 from dual union all
6 select 'Lion', 1999 from dual union all
7 select 'Fox', 1991 from dual union all
8 select 'Lion', 1995 from dual)
9 select nm,yr,row_number() over(partition by lower(nm) order by nm,yr) position from rt;
NM            YR   POSITION
Eagle       2000          1
eagle 2002 2
Fox         1991          1
Lion        1995          1
Lion        1999          2
Lion        2006          3
Tiger       2001          1
7 rows selected.
SQL>

Need help with Order by statement

I have a report which has an order by statement to order a varchar2 field in ascending order.
The report sorts the records correctly but if I rerun the report, the records with the same values in the column that I order by, do not maintain the same order as was in the report's 1st run.
The records will still be sorted in ascending order but those records that have the same values interchange positions each time I run the report.
Is this ok or is there a way of making records with same values maintain the same order in all the report runs? Please assist. Thanks.

user8655468 wrote:
but those records that have the same values interchange positions each time I run the report.
Is this ok or is there a way of making records with same values maintain the same order in all the report runs? Please assist. Thanks.Hello,
It's normal those are same values may interchange at each run. you can add another column in order by clause. That
Order by column1,column2 may add another column3 -- this will maintain always same but column 1,2,3 have same value , it will may interchange.
Hope this helps
Hamid

HELP WITH ORDERING A BOOK

I've been using iPhoto successfully for a while, and like making and ordering books.
My MacBook had a problem and the IT Manager sorted it - but everything was re-installed.
All is fine, but I'm trying to order a book, and when I click on the BUY button, nothing happens.
I've checked Preferences, registered on my account etc. I have no idea how to connect my book to the ordering facility. My internet connection is working.
Any ideas?

Welcome to the Apple Discussions.
registered on my account etc.
Does that mean you went online and re-entered all of your Apple account information?
First try deleting the iPhoto preference file, com.apple.iPhoto.plist, that resides in your User/Library/Preferences folder, launch iPhoto, reset its preferences and try again.
If that doesn't help, log into another account on your MBP, create a test library if there is no library there, create a quick test book and try the Buy button. You can abort the purchase process if the Buy button is working.
If the Buy button doesn't work in the other account a reinstall of iPhoto is warranted. To do so you'll have to delete the current iPhoto application and all files with "iPhoto" in the file name that reside in the HD/Library/Receipts folder. Now reinstall iPhoto from the disk it came on, apply the latest updater and try again.
TIP: For insurance against the iPhoto database corruption that many users have experienced I recommend making a backup copy of the Library6.iPhoto (iPhoto.Library for iPhoto 5 and earlier versions) database file and keep it current. If problems crop up where iPhoto suddenly can't see any photos or thinks there are no photos in the library, replacing the working Library6.iPhoto file with the backup will often get the library back. By keeping it current I mean backup after each import and/or any serious editing or work on books, slideshows, calendars, cards, etc. That insures that if a problem pops up and you do need to replace the database file, you'll retain all those efforts. It doesn't take long to make the backup and it's good insurance.
I've created an Automator workflow application (requires Tiger or later), iPhoto dB File Backup, that will copy the selected Library6.iPhoto file from your iPhoto Library folder to the Pictures folder, replacing any previous version of it. There are versions that are compatible with iPhoto 5, 6, 7 and 8 libraries and Tiger and Leopard. Just put the application in the Dock and click on it whenever you want to backup the dB file. iPhoto does not have to be closed to run the application, just idle. You can download it at Toad's Cellar. Be sure to read the Read Me pdf file.
NOTE: The new rebuild option in iPhoto 09 (v. 8.0.2), Rebuild the iPhoto Library Database from automatic backup" makes this tip obsolete.

Urgent: Help with Order Entry Verification Requirement

Hi,
I have a requirement that must be completed in a few hours. It is as folllow's:
During order entry the program must verify what material groups the customer is allowed to purchase based on license type. If the material belongs to group that the customer is not allowed to buy then the system will need to provide an error and do not create the line in the order.
This is a license type check
This is supposed to be done through the use of a user-exit.
Does anyone have any idea what USER-EXIT this refers to and what data is needed in order for the requirement to be completed?
Responses will be rewarded and greatly appreciated.
Additional Information:
Material groups (MARA-MATKL)
     0001 Beer
     0002 - Still wine
     0003 Sparkling wine/champ
     0004 Fortified wine
     0005 Spirits
There are other material groups but they are non-alcoholic, so no license is required.
Customer license type (table KNVV, fields: PRAT1, PRAT2, PRAT3, PRAT4). License type is specified in:
Customer master creation
Sales Area Data
Sales Tab
Product attributes
Product Attributes
-     PRAT1 - No Spirit License
-     PRAT2 - No fortified wine license
-     PRAT3 - No wine license
-     PRAT4 - No beer license
Although there are 10 product attributes only the first 4 require a license to be able to purchase them.

@Lasers_Edge just to avoid confusion: it is not necessary to 'create' variables for TEB's, they are created and assigned by default. I don't like the name of that generic variable because it is identical to the TEB's name but they exist. Good practice to me is to replace those variables by custom user variables, and for that purpose the X button is also available next to the variable name (same button as in the Format accordion for a text container, that allows you to insert a variable)
@choi.M Another approach is to print the content of those associated variables by a JavaScript that you assign to a Print button. If you prefer the approach to insert the variables in a text container, you could try the Print widget included with Captivate as well.

Noob needs help with site creation -- interactive?

I want to make a site where people can post and/or reply to other posts.
I've used iWeb for a couple years so I'm good with "static" sites but how can I make one where people can post to the site themselves?
For example, I write ::"what is your favorite rum when making a hurricane":: and a list of users/responses follows?
Is that even possible?
I'm using iWeb '09.
Thanks,
Jay

Jay ~ Welcome to the discussions. You could link to a free forum you've set up here:
http://www.lefora.com
And to link to an external forum from iWeb's navigation bar:
Link it to a blank internal page titled "Forum" (actually you can name the page whatever you want.) Then in that Forum page add an HTML Snippet with the following code:
<script type="text/javascript">
parent.window.location = "http://www.yourforumname.lefora.com"; // change this to your own URL
</script>
...Once published, clicking on the Forum page in the navbar will immediately redirect to your external Forum page. (Thanks to Cyclosaurus for the code).
Ning, the free "social networking" site, includes a forum:
Add a rich single or multi-threaded discussion forum with categories, photos and attachments to your Ning Network. Limit forum topic creation to you or open it up to all of your members.
http://about.ning.com/product.php

Help with dynamic creation of class object names

Hi all
Wonder if you can help. I have a class player.java. I want to be able to create objects from this class depending on a int counter variable.
So, for example,
int counter = 1;
Player p+counter = new Player ("Sam","Smith");the counter increments by 1 each time the method this sits within is called. The syntax for Player name creation is incorrect. What I am looking to create is Player p1, Player p2, Player p3.... depending on value of i.
Basically I think this is just a question of syntax, but I can't quite get there.
Please help if you can.
Thanks.
Sam

here is the method:
//add member
public void addMember() {
    String output,firstName,secondName,address1,address2,phoneNumberAsString;
    long phoneNumber;
    boolean isMember=true;
    this.memberCounter++;
    Player temp;
    //create HashMap
    HashMap memberList = new HashMap();
    output="Squash Court Booking System \n";
    output=output+"Enter Details \n\n";
    firstName=askUser("Enter First Name: ");
    secondName=askUser("Enter Second Name: ");
    address1=askUser("Enter Street Name and Number: ");
    address2=askUser("Enter Town: ");
    phoneNumberAsString=askUser("Enter Phone Number: ");
    phoneNumber=Long.parseLong(phoneNumberAsString);
    Player p = new Player(firstName,secondName,address1,address2,phoneNumber,isMember);
    //place member into HashMap
    memberList.put(new Integer(memberCounter),p);
    //JOptionPane.showMessageDialog(null,"Membercounter="+memberCounter,"Test",JOptionPane.INFORMATION_MESSAGE);
    //create iterator
    Iterator members = memberList.values().iterator();
    //create output
    output="";
    while(members.hasNext()) {
      temp = (Player)members.next();
      output=output + temp.getFirstName() + " ";
      output=output + temp.getSecondName() + "\n";
      output=output + temp.getAddress1() + "\n";
      output=output + temp.getAddress2() + "\n";
      output= output + temp.getPhoneNumber() + "\n";
      output= output + temp.getIsMember();
    //display message
    JOptionPane.showMessageDialog(null,output,"Member Listings",JOptionPane.INFORMATION_MESSAGE);
}//end addMemberOn running this, no matter how many details are input, the HashMap only gives me the first one back....
Any ideas?
Sam

[10g] Need help with order by clause in hierarchical query

I have the following sample data:
CREATE TABLE     bill_test1
(     parent_part     CHAR(25)
,     child_part     CHAR(25)
,     line_nbr     NUMBER(5)
,     qty_per          NUMBER(9,5)
INSERT INTO bill_test1 VALUES ('ABC-1','ABC-10',100,1);
INSERT INTO bill_test1 VALUES ('ABC-1','ABC-20',200,2);
INSERT INTO bill_test1 VALUES ('ABC-1','ABC-30',300,3);
INSERT INTO bill_test1 VALUES ('ABC-1','HARDWARE-1',401,10);
INSERT INTO bill_test1 VALUES ('ABC-1','HARDWARE-2',402,5);
INSERT INTO bill_test1 VALUES ('ABC-10','ABC-155',100,2);
INSERT INTO bill_test1 VALUES ('ABC-10','HARDWARE-1',200,1);
INSERT INTO bill_test1 VALUES ('ABC-155','RAW-2',100,4.8);
INSERT INTO bill_test1 VALUES ('ABC-155','HARDWARE-3',200,3);
INSERT INTO bill_test1 VALUES ('ABC-20','RAW-1',100,10.2);
INSERT INTO bill_test1 VALUES ('ABC-30','RAW-3',100,3);And the query below gives me exactly what I want, in the order I want it. However, I am wondering if there is a way to get this order without creating the SEQ column, since I don't need it in my results
SELECT     part_nbr
,     parent_part
,     child_part
FROM     (
     SELECT     CONNECT_BY_ROOT b.parent_part                         AS part_nbr
     ,     b.parent_part
     ,     b.child_part
     ,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
     FROM     bill_test1 b
     ,     dual
     CONNECT BY     parent_part     = PRIOR child_part
WHERE          part_nbr     = 'ABC-1'
ORDER BY     seq
Results of above query, except with SEQ included in SELECT (just to show what I'm sorting off of):
PART_NBR                     PARENT_PART                  CHILD_PART                   SEQ
ABC-1                        ABC-1                        ABC-10                        100
ABC-1                        ABC-10                       ABC-155                       100 100
ABC-1                        ABC-155                      RAW-2                         100 100 100
ABC-1                        ABC-155                      HARDWARE-3                    100 100 200
ABC-1                        ABC-10                       HARDWARE-1                    100 200
ABC-1                        ABC-1                        ABC-20                        200
ABC-1                        ABC-20                       RAW-1                         200 100
ABC-1                        ABC-1                        ABC-30                        300
ABC-1                        ABC-30                       RAW-3                         300 100
ABC-1                        ABC-1                        HARDWARE-1                    401
ABC-1                        ABC-1                        HARDWARE-2                    402

Hi,
As long as there's only one root, you can say ORDER SIBLINGS BY, but you can't do that in a sub-query (well, you can, but usually there's no point in doing it in a sub-query). If the CONNECT BY is being done in a sub-query, there is no guarantee that the main query will preserve the hierarchical order that the sub-query provides.
The query you posted doesn't require a suib-query, so you can say:
SELECT     CONNECT_BY_ROOT b.parent_part                         AS part_nbr
,     b.parent_part
,     b.child_part
--,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
FROM     bill_test1 b
WHERE          CONNECT_BY_ROOT b.parent_part     = 'ABC-1'
CONNECT BY     parent_part     = PRIOR child_part
ORDER SIBLINGS BY     b.line_nbr
;I said the query you posted doesn't require a sub-query. It also doesn't require dual, so I suspect what you posted is a simplification of what you're really doing, and that may need a sub-query. In particular, if you intend to GROUP BY part_nbr, then you need the sub-query. We can repeat the CONNECT_BY_ROOT expression in the WHERE clause (or, now that I think about it, use a START WITH clause instead of WHERE), but, for some reason, we can't use CONNECT_BY_ROOT in a GROUP BY clause; we need to compute CONNECT_BY_ROOT in a sub-query, give it a name (like part_nbr), and GROUP BY that column in a super-query.
This assumes that there is only one root node. ORDER SIBLINGS BY means just that: children of a common parent will appear in order, but the root nodes, who have no parents, will not necessarily be in order.
Here's what I meant by using START WITH instead of WHERE:
SELECT     CONNECT_BY_ROOT b.parent_part                         AS part_nbr
,     b.parent_part
,     b.child_part
--,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
FROM     bill_test1 b
START WITH     b.parent_part     = 'ABC-1'
CONNECT BY     parent_part     = PRIOR child_part
ORDER SIBLINGS BY     b.line_nbr
;This should be much more efficient, because it narrows down the results before you waste time getting their descendants.
Using a START WITH clause here is analagous to me sending you an e-mail, saying "Come to a meeting a my office at 3:00."
Using a WHERE clause here is analagous to me sending an e-mail to everyone in the company, saying "Come to a meeting a my office at 3:00", and then, as people get here, telling everyone except you that they can go back.
ORDER SIBLINGS BY was introduced in Oracle 9.
Edited by: Frank Kulash on Dec 9, 2010 2:39 PM
Added version with START WITH clause

Help with gallery creation

I’ve been creating galleries by using Commands/create
web photo album for ages now without a problem but suddenly the
files are being placed on the thumbnail page out of order. The
files are numeric and used to appear from 1 to whatever just fine;
now they are automatically placed randomly and I have no idea why.
Can anyone help or advise?
Thanks
James

Meant to say: I am using Dreamweaver 8 and Fireworks 5

Help with ordering a query

Hi,
I have written the following query:
select customer.cust_id as "Customer ID"
     ,customer.cust_area_code as "Customer Area Code"
     ,customer.cust_number as "Customer Number"
     ,sum(calls.elapsed_minutes) as "Total Call Length (Mins)"
     ,sum(calls.elapsed_minutes*calls.rate) as "Total Cost Of Calls £"
from
     (select cust_id
          ,floor((end_date_time-start_date_time)*1440) as elapsed_minutes
          ,chrg_per_minute as rate
     from phonecall
     ) calls
     ,customer
where customer.cust_id = calls.cust_id
group by customer.cust_id, customer.cust_area_code, customer.cust_number, calls.cust_id
order by customer.cust_id asc
However on the last line instead of ordering it by customer.cust_id i would like to order it by "total cost of calls" however when ever i try and order it by this i get an error.
Do i need to assign it to another var before i use it in an order clause?
Thanks

I wrote about [url http://forums.oracle.com/forums/click.jspa?searchID=5648765&messageID=1739843]the order of evaluating on select statement recently.
On the logical, select statement is evaluated in th following order.
[1-1] from
[1-2] on (joining)
[2-1] where (joining)
[2-2] start with, connect by
[2-3] where (excluding joining)
[3] group by
[4] having
[5] select
[6] union, union all, minus, intersect
[7] order by
The alias can be referred predefined in this order, but cannot be referred same level or post-defined. In subquery, this principle is affected as same also.
The table alias and/or the column alias on [1-1] 'from' can be referred all level excluding [1-1], but cannot be referred in inline view (subquery) on [1-1] 'from'.
select xxx from tab1 a1,(select xxx2 from tab2 a2 where a2.xxx=a1.xxx) -- No Good (This is same level)
select a1,a2 from (select xxx a1, xxx2 a2 from tab1) -- Good
select * from (select xxx a1, xxx2 a2 from tab1) -- Good, * explode to a1,a2
The column alias on [5] 'select' only can be referred on [7] 'order by'.
select xxx a1, xxx2 a2,count(*) from tab1 group by a2 -- No Good (post defined)
select xxx a1, xxx2 a2,count(*) from tab1 order by a2 -- Good
The naming rule of alias must accord with [url http://download-west.oracle.com/docs/cd/B19306_01/server.102/b14200/sql_elements008.htm#i27561]Schema Object Names and Qualifiers.
So, the alias enclosed by double quotation mark becomes case sensitive.
In additional, in order-by-clause, we can specified column number on select-clause.
select empno,ename,sal from scott.emp order by 3; -- this means order by sal

Help with Order creation

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