Help with this prefix method
I need help with this method. The program runs but i still hava problem for example i enter +56 and return 11 but when i tried to enter -+567 return 25 instead of 23 also when i tried to enter +45-3 it return 9 so after 5 the program stop it just return the addition of 4+5
public static int prefixEvaluation(String s){
int result=0 ;
int i=1;
char ch = s.charAt(0);
s=s.substring(i , s.length());// I want to be able to read all the character of the string every time i call the recursive method
if (ch>='0'&& ch<='9'){
result=((int)ch-48);
System.out.println(result);
return result;
else if (ch=='+'|| ch=='-'|| ch=='*'|| ch=='/'){
char op=ch;
System.out.println(ch);
int operand1= prefixEvaluation(s);
s = s.substring(i++);
int operand2= prefixEvaluation(s);
double post!
http://forum.java.sun.com/thread.jspa?threadID=781431&messageID=4444181#4444181
Similar Messages
-
I need help with this recursion method
public boolean findTheExit(int row, int col) {
char[][] array = this.getArray();
boolean escaped = false;
System.out.println("row" + " " + row + " " + "col" + " " + col);
System.out.println(array[row][col]);
System.out.println("escaped" + " " + escaped);
if (possible(row, col)){
System.out.println("possible:" + " " + possible(row,col));
array[row][col] = '.';
if (checkBorder(row, col)){
System.out.println("check border:" + " " + checkBorder(row,col));
escaped = true;
else {
System.out.println();
escaped = findTheExit(row+1, col);
if (escaped == false)
escaped = findTheExit(row, col+1);
else if (escaped == false)
escaped = findTheExit(row-1, col);
else if (escaped == false)
escaped = findTheExit(row, col-1);
if (escaped == true)
array[row][col] = 'O';
return escaped;
}I am having difficulties with this recursion method. What I wanted here is that when :
if escaped = findTheExit(row+1, col); I am having trouble with the following statement:
A base case has been reached, escaped(false) is returned to RP1. The algorithm backtracks to the call where row = 2 and col = 1 and assigns false to escaped.
How do I fix this code?
I know what's wrong with my code now, even though that if
if (possible(row, col))
[/code[
returns false then it will go to if (escaped == false)
escaped = findTheExit(row, col+1);
how do I do this?Okay I think I got the problem here because I already consult with the instructor, he said that by my code now I am not updating my current array if I change one of the values in a specific row and column into '.' . How do I change this so that I can get an update array. He said to me to erase char[][] array = getArray and replace it with the array instance variable in my class. But I don't have an array instance variable in my class. Below is my full code:
public class ObstacleCourse implements ObstacleCourseInterface {
private String file = "";
public ObstacleCourse(String filename) {
file = filename;
public boolean findTheExit(int row, int col) {
boolean escaped = false;
//System.out.println("row" + " " + row + " " + "col" + " " + col);
//System.out.println(array[row][col]);
//System.out.println("escaped" + " " + escaped);
if (possible(row, col)){
//System.out.println("possible:" + " " + possible(row,col) + "\n");
array[row][col] = '.';
if (checkBorder(row, col)){
escaped = true;
else {
escaped = findTheExit(row+1, col);
if (escaped == false)
escaped = findTheExit(row, col+1);
else if (escaped == false)
escaped = findTheExit(row-1, col);
else if (escaped == false)
escaped = findTheExit(row, col-1);
if (escaped == true)
array[row][col] = 'O';
return escaped;
public char[][] getArray() {
char[][] result = null;
try {
Scanner s = new Scanner(new File(file));
int row = 0;
int col = 0;
row = s.nextInt();
col = s.nextInt();
String x = "";
result = new char[row][col];
s.nextLine();
for (int i = 0; i < result.length; i++) {
x = s.nextLine();
for (int j = 0; j < result.length; j++) {
result[i][j] = x.charAt(j);
} catch (Exception e) {
return result;
public int getStartColumn() {
char[][] result = this.getArray();
int columns = -1;
for (int i = 0; i < result.length; i++) {
for (int j = 0; j < result[i].length; j++) {
if (result[i][j] == 'S')
columns = j;
return columns;
public int getStartRow() {
char[][] result = this.getArray();
int row = -1;
for (int i = 0; i < result.length; i++) {
for (int j = 0; j < result[i].length; j++) {
if (result[i][j] == 'S')
row = i;
return row;
public boolean possible(int row, int col) {
boolean result = false;
char[][] array = this.getArray();
if (array[row][col] != '+' && array[row][col] != '.')
result = true;
return result;
public String toString() {
String result = "";
try {
Scanner s = new Scanner(new File(file));
s.nextLine();
while (s.hasNextLine())
result += s.nextLine() + "\n";
} catch (Exception e) {
return result;
public boolean checkBorder(int row, int col) {
char[][] array = this.getArray();
boolean result = false;
int checkRow = 0;
int checkColumns = 0;
try {
Scanner s = new Scanner(new File(file));
checkRow = s.nextInt();
checkColumns = s.nextInt();
} catch (Exception e) {
if ((row + 1 == checkRow || col + 1 == checkColumns) && array[row][col] != '+')
result = true;
return result;
I thought that my problem would be not to read the file using the try and catch everytime in the method. How do I do this?? Do I have to create an array instance variable in my class? -
Can someone help with this getPos method of aList class ?
public class AList<T> implements ListInterface<T>
private T[] entries; // array of list entries
private int length; // current number of entries in list
private static final int MAX_SIZE = 50; // max length of list
public AList()
this(MAX_SIZE); // call next constructor
} // end default constructor
public AList(int maxSize)
length = 0;
entries = (T[]) new Object[maxSize]; // necessary cast to generic type
} // end constructor
public boolean add(T newEntry)
boolean isSuccessful = true;
if (!isFull())
// Assertion: Length of list < length of array
assert length < entries.length;
// position of new entry will be after last entry in list,
// that is, at position length+1; corresponding array index is
// 1 less than this position, so index is length
entries[length] = newEntry;
length++;
else
isSuccessful = false;
return isSuccessful;
} // end add
public boolean add(int newPosition, T newEntry)
boolean isSuccessful = true;
if (!isFull() && (newPosition >= 1) && (newPosition <= length + 1))
makeRoom(newPosition);
entries[newPosition - 1] = newEntry;
length++;
else
isSuccessful = false;
return isSuccessful;
} // end add
public T remove(int givenPosition)
T result = null; // return value
if ((givenPosition >= 1) && (givenPosition <= length))
assert !isEmpty();
result = entries[givenPosition - 1]; // get entry to be removed
// move subsequent entries toward entry to be removed,
// unless it is last in list
if (givenPosition < length)
removeGap(givenPosition);
length--;
} // end if
return result; // return reference to removed entry, or
// null if either list is empty or givenPosition
// is invalid
} // end remove
public T getEntry(int givenPosition)
T result = null; // result to return
if ((givenPosition >= 1) && (givenPosition <= length))
assert !isEmpty();
result = entries[givenPosition - 1];
} // end if
return result;
} // end getEntry
public int getPos(T anItem)
}I would recommend using a for loop to compare anItem to each member of the array. If you get a match, return the index.
-
Need some help with this project (methods)
Ok. in this project it states the following:
Write an application that rolls a die and displays the reuslt. Let the user pick the number of sides on the die. Use the Die Class to represent the die in your program.
This is what i have so far, but im confused on how to utilize the Die class because it keeps giving me errors:
P4_3.java:
Code:
import cs1.Keyboard;
import java.util.Random;
// extends the Die class...
public class P4_3 extends Die
public static void main (String[] args)
{ // asks the user how many sides of the die there is.
int userSides;
System.out.println("How many sides of the die do you want?");
userSides = Keyboard.readInt();
System.out.println ("You rolled "+Die.die);
}Die.java:
Code:
// the die class
import cs1.Keyboard;
import java.util.Random;
public class Die extends P4_3
public static void Die()
// rolls the dice
Random generator = new Random();
int die;
die = generator.nextInt(P4_3.userSides) +1;
}It keeps giving me:
cannot resolve symbol
symbol : variable die
location: class Die
System.out.println ("You rolled "+Die.die);
^
cannot resolve symbol
symbol : variable userSides
location: class P4_3
die = generator.nextInt(P4_3.userSides) +1;Can somebody point me in the right direction?
Thanks, ps2cho
(PS: Please keep it as simple as possible, dont give me some crazy wacky tough code because i wont understand a word of it, no matter how hard you try to explain it. Simple simple simple!)
Thanksssimport java.io.*;
import java.util.Random;
public class DieTest
public static void main(String[] args)
boolean more = true;
BufferedReader br = null;
try
br = new BufferedReader(
new InputStreamReader(System.in));
while(more)
System.out.println("enter number for die sides, \"q\" to quit");
String line = br.readLine();
if(line.equalsIgnoreCase("q"))
break;
int sides = Integer.parseInt(line);
Die die = new Die(sides);
for(int j = 0; j < 5; j++)
System.out.println("die roll " + (j+1) + " = " + die.roll());
br.close();
catch(IOException ioe)
System.err.println("read error " + ioe.getMessage());
more = false;
class Die
int sides;
Random seed;
public Die(int n)
this.sides = n;
seed = new Random();
public int roll()
// 0 <= seed.nextInt(sides) <= sides-1
// 1 <= return value <= sides
return 1 + seed.nextInt(sides);
} -
Need Help with a getText method
Gday all,
I need help with a getText method, i need to extract text from a JTextField. Although this text then needs to converted to a double so that i can multiply a number that i have already specified. As you may of guessed that the text i need to extract already will be in a double format.e.g 0.1 or 0.0000004 etc
Thanks for your help
ps heres what i have already done its not very good though
ToBeConverted.getText();
( need help here)
double amount = (and here)
total = (amount*.621371192);
Converted.setText("= " + total);Double.parseDouble( textField.getText() );
-
powerpoint presentation I have stored in icloud until recently were syncing to Keynote on my iPad with no problem. Now when I open Keynote on my iPad there is nothing. I could use some help with this problem.
Morning AndreD86,
Thanks for using Apple Support Communities.
These articles explain exactly what is backed up by using their method.
iTunes: About iOS backups
http://support.apple.com/kb/ht4946
and
iCloud: Backup and restore overview
http://support.apple.com/kb/ht4859
Also we want to double-click the Home button and swipe the Task Bar to the right.
Then make sure the button on the far left of Task Bar is not muted.
Best of luck,
Mario -
I need help with this code error "unreachable statement"
the error_
F:\Java\Projects\Tools.java:51: unreachable statement <-----------------------------------------------------------------------------------------------------------------THIS
int index;
^
F:\Java\Projects\Tools.java:71: missing return statement
}//end delete method
^
F:\Java\Projects\Tools.java:86: missing return statement
}//end getrecod
^
3 errors
import java.util.*;
import javax.swing.*;
import java.awt.*;
public class Tools//tool class
private int numberOfToolItems;
private ToolItems[] toolArray = new ToolItems[10];
public Tools()//array of tool
numberOfToolItems = 0;
for(int i = 0; i < toolArray.length; i++)//for loop to create the array tools
toolArray[i] = new ToolItems();
}//end for loop
}//end of array of tools
public int search(int id)//search mehtod
int index = 0;
while (index < numberOfToolItems)//while and if loop search
if(toolArray[index].getID() == id)
return index;
else
index ++;
}//en while and if loop
return -1;
}//end search method
public int insert(int id, int numberInStock, int quality, double basePrice, String nm)//insert method
if(numberOfToolItems >= toolArray.length)
return 0;
int index;
index = search(id); <-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------HERE
if (index == -1)
toolArray[index].assign(id,numberInStock, quality, basePrice,nm);
numberInStock ++;
return 1;
}//end if index
}//end if toolitem array
return -1;
}//end insert method
public int delete(/*int id*/)//delete method
}//end delete method
public void display()//display method
for(int i = 0; i < numberOfToolItems; i++)
//toolArray.display(g,y,x);
}//end display method
public String getRecord(int i)//get record method
// return toolArray[i].getName()+ "ID: "+toolArray[i].getID()
}//end getrecod
}//end class
Edited by: ladsoftware on Oct 9, 2009 6:08 AM
Edited by: ladsoftware on Oct 9, 2009 6:09 AM
Edited by: ladsoftware on Oct 9, 2009 6:10 AM
Edited by: ladsoftware on Oct 9, 2009 6:11 AMladsoftware wrote:
Subject: Re: I need help with this code error "unreachable statement"
F:\Java\Projects\Tools.java:51: unreachable statement <-----------------------------------------------------------------------------------------------------------------THIS
int index;
^
F:\Java\Projects\Tools.java:71: missing return statement
}//end delete method
^
F:\Java\Projects\Tools.java:86: missing return statement
}//end getrecod
^
3 errorsThe compiler is telling you exactly what the problems are:
public int insert(int id, int numberInStock, int quality, double basePrice, String nm)//insert method
if(numberOfToolItems >= toolArray.length)
return 0; // <<== HERE you return, so everyting in the if block after this is unreachable
int index;
index = search(id); //< -----------------------------------------------------------------------------------------------------------------HERE
if (index == -1)
toolArray[index].assign(id,numberInStock, quality, basePrice,nm);
numberInStock ++;
return 1;
}//end if index
}//end if toolitem array
return -1;
}//end insert method
public int delete(/*int id*/)//delete method
// <<== HERE where is the return statement?
}//end delete method
public String getRecord(int i)//get record method
// return toolArray.getName()+ "ID: "+toolArray[i].getID() <<== HERE you commented out the return statement
}//end getrecod
}//end class -
Hi,
I need a help to resolve my problem.Actually i have a JSP page with a list box. When i select some value in the list box, appropriate values must list out according to the selected value.And i have a submit button to process that jsp page.
I wrote a validation as all the fields must be entered to submit a page.
But when i tried with the following code,it's just moving to processing page when i select a values from the list box.This is happening when i cheked the validation.
Pls help with this code.This is very urgent.
Code is as follows
"Example1.jsp"
<%
String str1 = request.getParameter("Modem");
%>
<html>
<head>
<script language = "JavaScript">
function Validate()
if(document.UpdateFiosAccounts.Modem.value == "Select One")
alert("Please select the value")
document.UpdateFiosAccounts.Modem.focus()
return false
if(document.UpdateFiosAccounts.text1.value == "")
alert("Please type some text")
document.UpdateFiosAccounts.text1.focus()
return false
return true
</script>
</head>
<body>
<form name = "UpdateFiosAccounts" action="./Example1.jsp" method ="post" onSubmit= "return Validate()">
Pls select One:<select name="Modem" size="1" onChange="document.UpdateFiosAccounts.submit()">
<%
if(str1 == null)
%>
<option value="Select One">Select One</option>
<option value="One">One</option>
<option value="Two">Two</option>
<option value="Three">Three</option>
<option value="Four">Four</option>
<%
else
%>
<option value="<%=str1%>"><%=str1%></option>
<%
%>
</select><br>
Pls type something: <input type ="text" name="text1">
<input type ="submit" value="submit" onClick="document.UpdateFiosAccounts.action='./Accounts.jsp'">
</form>
</body>
</html>Hi! The reason is that in the onChange property you are doing the submit, so, when you select something, it goes automatically and never pases through your validation function. So, remove that onChange. Next, the button is a submit buton, so, no matter what your validation does, the page will go. You need to change the submit type of the button to just button (<input type="button" onclick="function to validate">) and then you will get what you want. By the way, this is NOT a Java question, is more JavaScript question.
Hope this helps. -
Anybody can help with this SQL?
The table is simple, only 2 columns:
create table personpay(
id integer primary key,
pay number(8,2) not null);
So the original talbe looks like this:
ID PAY
1 800
2 400
3 1200
4 500
5 600
6 1900
The requirement is to use one single query(no pl/sql) to show something lile the following, in other words, for each ID, the pay is the sum of all before itself and itself. So the query result looks like this:
ID PAY
1 800
2 1200
3 2400
4 2900
5 3500
6 5400
Again, just use one sql. No pl/sql. Anybody can help with this? I really appreciate that.
thanks,Eh, people are so "analytically minded" that can't even notice a simple join?
Counting Ordered Rows
Let’s start with a basic counting problem. Suppose we are given a list of integers, for example:
x
2
3
4
6
9
and want to enumerate all of them sequentially like this:
x #
2 1
3 2
4 3
6 4
9 5
Enumerating rows in the increasing order is the same as counting how many rows precede a given row.
SQL enjoys success unparalleled by any rival query language. Not the last reason for such popularity might be credited to its proximity to English . Let examine the informal idea
Enumerating rows in increasing order is counting how many rows precede a given row.
carefully. Perhaps the most important is that we referred to the rows in the source table twice: first, to a given row, second, to a preceding row. Therefore, we need to join our number list with itself (fig 1.1).
Cartesian Product
Surprisingly, not many basic SQL tutorials, which are so abundant on the web today, mention Cartesian product. Cartesian product is a join operator with no join condition
select A.*, B.* from A, B
Figure 1.1: Cartesian product of the set A = {2,3,4,6,9} by itself. Counting all the elements x that are no greater than y produces the sequence number of y in the set A.
Carrying over this idea into formal SQL query is straightforward. As it is our first query in this book, let’s do it step by step. The Cartesian product itself is
select t.x x, tt.x y
from T t, T tt
Next, the triangle area below the main diagonal is
select t.x x, tt.x y
from T t, T tt
where tt.x <= t.x
Finally, we need only one column – t.x – which we group the previous result by and count
select t.x, count(*) seqNum
from T t, T tt
where tt.x <= t.x
group by t.x
What if we modify the problem slightly and ask for a list of pairs where each number is coupled with its predecessor?
x predecessor
2
3 2
4 3
6 4
9 6
Let me provide a typical mathematician’s answer, first -- it is remarkable in a certain way. Given that we already know how to number list elements successively, it might be tempted to reduce the current problem to the previous one:
Enumerate all the numbers in the increasing order and match each sequence number seq# with predecessor seq#-1. Next!
This attitude is, undoubtedly, the most economical way of thinking, although not necessarily producing the most efficient SQL. Therefore, let’s revisit our original approach, as illustrated on fig 1.2.
Figure 1.2: Cartesian product of the set A = {2,3,4,6,9} by itself. The predecessor of y is the maximal number in a set of x that are less than y. There is no predecessor for y = 2.
This translates into the following SQL query
select t.x, max(tt.x) predecessor
from T t, T tt
where tt.x < t.x
group by t.x
Both solutions are expressed in standard SQL leveraging join and grouping with aggregation. Alternatively, instead of joining and grouping why don’t we calculate the count or max just in place as a correlated scalar subquery:
select t.x,
(select count(*) from T tt where tt.x <= t.x) seq#
from T t
group by t.x
The subquery always returns a single value; this is why it is called scalar. The tt.x <= t.x predicate connects it to the outer query; this is why it is called correlated. Arguably, leveraging correlated scalar subqueries is one the most intuitive techniques to write SQL queries.
How about counting rows that are not necessarily distinct? This is where our method breaks. It is challenging to distinguish duplicate rows by purely logical means, so that various less “pure” counting methods were devised. They all, however, require extending the SQL syntactically, which was the beginning of slipping along the ever increasing language complexity slope.
Here is how analytic SQL extension counts rows
select x, rank() over(order by x) seq# from T; -- first problem
select x, lag() over(order by x) seq# from T; -- second problem
Many people suggest that it’s not only more efficient, but more intuitive. The idea that “analytics rocks” can be challenged in many ways. The syntactic clarity has its cost: SQL programmer has to remember (or, at least, lookup) the list of analytic functions. The performance argument is not evident, since non-analytical queries are simpler construction from optimizer perspective. A shorter list of physical execution operators implies fewer query transformation rules, and less dramatic combinatorial explosion of the optimizer search space.
It might even be argued that the syntax could be better. The partition by and order by clauses have similar functionality to the group by and order by clauses in the main query block. Yet one name was reused, and the other had been chosen to have a new name. Unlike other scalar expressions, which can be placed anywhere in SQL query where scalar values are accepted, the analytics clause lives in the scope of the select clause only. I have never been able to suppress an impression that analytic extension could be designed in more natural way. -
If only it were that simple. Many of us have no "none" available.
Since the guy on the other discussion clearly had no desire to help anyone, I thought I'd ask here instead... can anyone help with this?Open iTunes and navigate to the app store. Select a free app to download. A simple way to do this is to scroll down to the top free apps box on the right hand side, hover your mouse over the first item and click on the free button that appears when you hover over it.
A pop up will open asking you to sign in with your Apple ID click "create new account", click continue to create your account. Check the box to accept the store terms and conditions and click continue.
Enter your email address, password, security question, and date of birth, click continue. Now, you will be asked to provide a payment method. Note now that the last option says "none". -
Help with this acoustic guitar sound.
Hi guys,
Having a break from recording vox for a bit. So now on to recording acoustic guitars
I need some help with this acoustic guitar i recored today, it sound ok? but needs help. I'v messed about with EQ but still not happy .
I'v put the recording up as a quicktime movie so you can see mic positions. Processing so far is a bit of compression and a dab of EQ cutting 500 Hz and reverb. Mic is a SE-Z5600.
The performance is far from perfect as this was a once through take for sound tests. Also the sync goes out between the audio and video no idea why
Any help would be great.
John
http://www.gradeaguitartuition.co.uk/hidden.htm
Message was edited by: john boswell1John,
Hearing it back from a compressed file obviously is going to "skew" things a bit, but I actually fail to see what you don't like about it.
Here's the thing...
When the guitar is good (sounds like yours is), and the player is good (which you are), THAT"S the sound of the guitar.
Yes, mic choice, mic placement, mic pre-amps, size of the room, etc, all play a part, but here's the best kept secret in the biz...
All those things I just mentioned play the smallest part. Don't believe me?
Record that guitar with you playing, with 5 different mic, 5 different mic pres, in 5 different rooms, and you'll be stunned at how similar they all sound. Sure there will be various sonic differences, but those differences would be pale in comparison to a different player playing a different guitar.
Hmm, why not move the mic a bit more to the center hole of the guitar and >get a bit closer.
I would suggest NOT doing this, because of the proximity effect of placing a mic to close to the sound source, unless the mic was set in an omni pattern, and even then, I suggest against it, because a guitar is made to project tone, and when you stick a mic within an inch or two of it, you "choke" all that tone, and it's a very microscopic view of a intended bigger picture.
The "safest" place to place a single mic on an acoustic guitar, is out about 7 or 8 inches, from the 12th or 14th fret. You'll find a very balanced tone here. It's certainly not the only place to out a single mic, but it's the "tried and true" method, that will produce predictable and useable results everytime.
Other than that, a small diaphragm condenser mic will generally sound better on an acoustic guitar than a large diaphragm mic, like the one you're using. Again, that's a safe generalization... not to be written in stone, but will always produce good results.
I think you're recording sounds good. It sounds like you, playing your guitar. Isn't that the goal? -
i need help with this 1 line if some one passed the argument 'A' it would only print out the characters from 0-4 how can this be coded?????????
public class A {
public static void main(String[] args) {
String[] characters = new String[ 130 ];
characters[ 0 ] = new String(" * "); // A
characters[ 1 ] = new String("* *");
characters[ 2 ] = new String("*****");
characters[ 3 ] = new String("* *");
characters[ 4 ] = new String("* *");
characters[ 5 ] = new String("**** "); // B
characters[ 6 ] = new String("* *");
characters[ 7 ] = new String("**** ");
characters[ 8 ] = new String("* *");
characters[ 9 ] = new String("**** ");
for (int nCharacter = 0; nCharacter < args[ 0 ].length(); nCharacter++) {
char aChar = args[ 0 ].charAt (nCharacter);
[\code]Not a very efficient method - but it will work;-public class junk{
public static void main(String[] args) {
String letter = "A";//args[0].toUpperCase();
char c = letter.charAt(0);
int start= getStart(c);
int end = getLast(c);
String[] characters = new String[ 130 ];
characters[ 0 ] = new String(" * "); // A
characters[ 1 ] = new String("* *");
characters[ 2 ] = new String("*****");
characters[ 3 ] = new String("* *");
characters[ 4 ] = new String("* *");
characters[ 5 ] = new String("**** "); // B
characters[ 6 ] = new String("* *");
characters[ 7 ] = new String("**** ");
characters[ 8 ] = new String("* *");
characters[ 9 ] = new String("**** ");
for(int i=start; i<end; i++) System.out.println(characters);
/*for (int nCharacter = 0; nCharacter < args[ 0 ].length(); nCharacter++) {
char aChar = args[ 0 ].charAt (nCharacter); */
private static int getStart(char c){
int temp = 0;
switch(c){
case 'A' : temp = 0; break;
case 'B' : temp = 5; break;
return temp;
private static int getLast(char c){
int temp = 0;
switch(c){
case 'A' : temp = 5; break;
case 'B' : temp = 10; break;
return temp; -
I need advise and help with this problem .
First , I have been with Mac for many years ( 14 to be exact ) I do have some knowledge and understanding of Apple product .
At the present time I'm having lots of problems with the router so I was looking in to some info , and come across one web site regarding : port forwarding , IP addresses .
In my frustration , amongst lots of open web pages tutorials and other useless information , I come across innocent looking link and software to installed called Genieo , which suppose to help with any router .
Software ask for permission to install , and about 30 % in , my instinct was telling me , there is something not right . I stop installation . Delete everything , look for any
trace in Spotlight , Library . Nothing could be find .
Now , every time I open Safari , Firefox or Chrome , it will open in my home page , but when I start looking for something in steed of Google page , there is
''search.genieo.com'' page acting like a Google . I try again to get raid of this but I can not find solution .
With more research , again using genieo.com search eng. there is lots of articles and warnings . From that I learn do not use uninstall software , because doing this will install more things where it come from.
I do have AppleCare support but its to late to phone them , so maybe there some people with knowledge , how to get this of my computer
Any help is welcome , English is my learned language , you may notice this , so I'm not that quick with the respondGenieo definitely doesn't help with your router. It's just adware, and has no benefit to you at all. They scammed you so that they could display their ads on your computer.
To remove it, see:
http://www.thesafemac.com/arg-genieo/
Do not use the Genieo uninstaller! -
my calendar will no longer let me add new event or delete them, it comes up with an error saying "cannot save event, no end date set" or "event does not belong to that event store". can anyone help with this?
Hi,
To configure your ODBC DataSource, go to Control Panel ---> DataSources(ODBC) (If you are in a Windows environment).
Select the tab System DSN. If you have not added your data source, then do so by clicking on the Add button. If you have added the datasource, click on the Configure button to configure it.
Give the datasource name, then the database name.
You have to give the hostname, service name and server name. I guess, in most cases, the datasource name and host name will be the same, service name and server name will be the same. If you are using TCP/IP, the protocol will be onsoctcp.
There will be a file named Services under C:\WINNT\system32\drivers\etc where you have to give the port number for accessing this server.
It will be like this <service name> <portnumber>/tcp
Hope this helps...
best wishes,
Nish -
I need help with this script please ASAP
So I need this to work properly, but when ran and the correct answer is chosen the app quits but when the wrong answer is chosen the app goes on to the next question. I need help with this ASAP, it is due tommorow. Thank you so much for the help if you can.
The script (Sorry if it's a bit long):
#------------Startup-------------
display dialog "Social Studies Exchange Trviva Game by Justin Parzik" buttons {"Take the Quiz", "Cyaaaa"} default button 1
set Lolz to (button returned of the result)
if Lolz is "Cyaaaa" then
killapp()
else if Lolz is "Take the Quiz" then
do shell script "say -v samantha Ok starting in 3…2…1…GO!"
#------------Question 1-----------
display dialog "Around age 11, many boys left their fathers to become…" buttons {"Scholars", "Warriors", "Apprentices"}
set A1 to (button returned of the result)
if A1 is "Apprentices" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#----------Question 2--------
display dialog "Most children were taught
to read so that they could understand the…" buttons {"Music of Mozart", "Bible", "art of cooking"}
set A2 to (button returned of the result)
if A2 is "Bible" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#------------Question 3---------
display dialog "In the 1730s and 1740s, a religious movement called the_______swept through the colonies." buttons {"Glorius Revolution", "Great Awakening", "The Enlightenment"}
set A3 to (button returned of the result)
if A3 is "Great Awakening" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#-----------Question 4--------
display dialog "_______ was
a famous American Enlightenment figure." buttons {"Ben Franklin", "George Washington", "Jesus"}
set A4 to (button returned of the result)
if A4 is "Ben Franklin" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#----------Question 5-------
display dialog "______ ownership gave colonists political rights as well as prosperity." buttons {"Land", "Dog", "Slave"}
set A5 to (button returned of the result)
if A5 is "Land" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#---------Question 6--------
display dialog "The first step toward guaranteeing these rights came in 1215. That
year, a group of English noblemen forced King John to accept the…" buttons {"Declaration of Independence", "Magna Carta", "Constitution"}
set A6 to (button returned of the result)
if A6 is "Magna Carta" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#----------Question 7--------
display dialog "England's cheif lawmaking body was" buttons {"the Senate", "Parliament", "King George"}
set A7 to (button returned of the result)
if A7 is "Parliament" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#--------Question 8-----
display dialog "Pariliament decided to overthrow _______ for not respecting their rights" buttons {"King James II", "King George", "King Elizabeth"}
set A8 to (button returned of the result)
if A8 is "King James II" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#--------Question 9------
display dialog "Parliament named ___ and ___ as England's new monarchs in something called ____." buttons {"William/Mary/Glorius Revolution", "Adam/Eve/Great Awakening", "Johhny/Mr.Laphalm/Burning of the hand ceremony"}
set A9 to (button returned of the result)
if A9 is "William/Mary/Glorius Revolution" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#---------Question 10-----
display dialog "After accepting the throne William and Mary agreed in 1689 to uphold the English Bill of _____." buttons {"Money", "Colonies", "Rights"}
set A10 to (button returned of the result)
if A10 is "Rights" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#---------Question 11------
display dialog "By the late 1600s French explorers had claimed the ___ River Valey" buttons {"Mississippi", "Ohio", "Hudson"}
set A11 to (button returned of the result)
if A11 is "Ohio" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#------Question 12---------
display dialog "______ was sent to ask the French to leave 'English Land'." buttons {"Johhny Tremain", "George Washington", "Paul Revere"}
set A12 to (button returned of the result)
if A12 is "George Washington" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#---------Question 13-------
display dialog "_____ proposed the Albany Plan of Union" buttons {"George Washingon", "Ben Franklin", "John Hancock"}
set A13 to (button returned of the result)
if A13 is "Ben Franklin" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#--------Question 14------
display dialog "The __________ declared that England owned all of North America east of the Mississippi" buttons {"Proclomation of England", "Treaty of Paris", "Pontiac Treaty"}
set A14 to (button returned of the result)
if A14 is "" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#-------Question 15-------
display dialog "Braddock was sent to New England so he could ______" buttons {"Command an attack against French", "Scalp the French", "Kill the colonists"}
set A15 to (button returned of the result)
if A15 is "Command an attack against French" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
#------TheLolQuestion-----
display dialog "____ is the name of the teacher who runs this class." buttons {"Mr.White", "Mr.John", "Paul Revere"} default button 1
set LOOL to (button returned of the result)
if LOOL is "Mr.White" then
do shell script "say -v samantha Congratulations…you…have…common…sense"
else
do shell script "say -v alex Do…you…have…eyes?"
#------END------
display dialog "I hope you enjoyed the quiz!" buttons {"I did!", "It was horrible"}
set endmenu to (button returned of the result)
if endmenu is "I did!" then
do shell script "say -v samantha Your awesome"
else
do shell script "say -v alex Go outside and run a lap"
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end if
end ifUse code such as:
display dialog "Around age 11, many boys left their fathers to become…" buttons {"Scholars", "Warriors", "Apprentices"}
set A1 to (button returned of the result)
if A1 is "Apprentices" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
return
end if
#----------Question 2--------
display dialog "Most children were taught to read so that they could understand the…" buttons {"Music of Mozart", "Bible", "art of cooking"}
set A2 to (button returned of the result)
if A2 is "Bible" then
do shell script "say -v samantha Correct Answer"
else
do shell script "say -v samantha Wrong Answer"
return
end if
(90444)
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