Help with this query please
Hi there,
These are the sample values
declare @table table
Name varchar(50),
flag int
insert into @table
values('Matt', 0),
('George', 0),
('George', 1),
('Lucas', 0),
('Jerome', 0),
('Jerome', 1)
I want to select out where George and Jerome where flag = 0 but leave the records from the same names where flag = 1. All others that only have flag = 0, should stay. So only the names that repeat and have both flag, flag = 0 zero should be selected out.
Thanks for your help.
So desired output is ????
George 0
Jerome 0
declare @table table
Name varchar(50),
flag int
insert into @table
values('Matt', 0),
('George', 0),
('George', 1),
('Lucas', 0),
('Jerome', 0),
('Jerome', 1)
select name,min(flag) flag,count(*) from @table
group by name
having count(*)>1
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
MS SQL Consulting:
Large scale of database and data cleansing
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SQL I need help with this query Please help
List the names of all the products whose weight unit measure is “Gram”. Order the list by product name. Do not use JOINS, but use the IN clause with a sub-query.
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Andy Tauber
Data Architect
The Vancouver Clinic
Website | LinkedIn
This posting is provided "AS IS" with no warranties, and confers no rights. Please remember to click
"Mark as Answer" and "Vote as Helpful" on posts that help you. This can be beneficial to other community members reading the thread. -
Please need help with this query
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set A1 to (button returned of the result)
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do shell script "say -v samantha Correct Answer"
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do shell script "say -v samantha Wrong Answer"
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set A2 to (button returned of the result)
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return
end if
(90444) -
Hello
If I run the following query I correctly get a sum of the invoices for a particular BP for Jan 09
SELECT T1.[SlpName], T0.[CardCode], SUM(CASE WHEN T2.[DocDate] BETWEEN '20090101' AND '20090131' THEN (T2.[DocTotal] - T2.[VatSum]) ELSE 0 END) AS 'JAN 09' FROM OCRD T0 INNER JOIN OSLP T1 ON T0.SlpCode = T1.SlpCode INNER JOIN OINV T2 ON T0.CardCode = T2.CardCode WHERE T0.[CardCode] = 'KEY065' GROUP BY T0.[CardCode], T1.[SlpName]
However I need the value of credit notes to be reflected in the figure so I amended the query to be:
SELECT T1.[SlpName], T0.[CardCode], SUM(CASE WHEN T2.[DocDate] BETWEEN '20090101' AND '20090131' THEN (T2.[DocTotal] - T2.[VatSum])ELSE 0 END) - SUM(CASE WHEN T3.[DocDate] BETWEEN '20090101' AND '20090131' THEN (T3.[DocTotal] - T3.[VatSum]) ELSE 0 END) AS 'JAN 09' FROM OCRD T0 INNER JOIN OSLP T1 ON T0.SlpCode = T1.SlpCode INNER JOIN OINV T2 ON T0.CardCode = T2.CardCode INNER JOIN ORIN T3 ON T0.CardCode = T3.CardCode WHERE T0.[CardCode] = 'KEY065' GROUP BY T0.[CardCode], T1.[SlpName]
When I run this query the output is incorrect ................ Is the fault to do with my JOINS?
ThanksHi Just to clarify
This query, which just totals any invoices for a BP for January, correctly returns a value of £9660.44 :
SELECT T1.[SlpName], T0.[CardCode], SUM(CASE WHEN T2.[DocDate] BETWEEN '20090101' AND '20090131' THEN (T2.[DocTotal] - T2.[VatSum]) ELSE 0 END) AS 'JAN 09' FROM OCRD T0 INNER JOIN OSLP T1 ON T0.SlpCode = T1.SlpCode INNER JOIN OINV T2 ON T0.CardCode = T2.CardCode WHERE T0.[CardCode] = 'KEY065' GROUP BY T0.[CardCode], T1.[SlpName]
This next query, which just totals any credit notes for a BP in January, correctly returns a value of £567.73 :
SELECT T1.[SlpName], T0.[CardCode], SUM(CASE WHEN T3.[DocDate] BETWEEN '20090101' AND '20090131' THEN (T3.[DocTotal] - T3.[VatSum]) ELSE 0 END) AS 'JAN 09' FROM OCRD T0 INNER JOIN OSLP T1 ON T0.SlpCode = T1.SlpCode INNER JOIN ORIN T3 ON T0.CardCode = T3.CardCode WHERE T0.[CardCode] = 'KEY065' GROUP BY T0.[CardCode], T1.[SlpName]
I want a query which return a value of 9660.44 minus 567.73 (ie £9092.71)
My original effort at this returned -£82,608.65 !!!!!!!!!
and Gordon's amended version returned -£40,281.74 !!!!!
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Hi,
I am using SQL Server 2008 Enterprise edition 64 bit on Windows serer 2008 enterprise edition 64 bit.
The below query works fine. I am trying to rewrite the code without using the sub query. In the end i should get the same results for both the query which we are going to rewrite and the below mentioned query.
Can any help me please.
SELECT
t1.DOCUMENT_NO,
RTRIM(CAST(t1."ENVIRONMENT_CD" AS VARCHAR(5))) + '*' + RTRIM(CAST(t1."ORDER_NO" AS VARCHAR(25)))
+
CASE WHEN (SELECT COUNT(DISTINCT S1.TEST_REPORTING_MATERIAL_SID)
FROM dbo.TBLTEST S1 ON S1.DOCUMENT_NO = T1.DOCUMENT_NO
WHERE S1.TEST_REPORTING_MATERIAL_SID > 0
AND S1.COMPANY_CD = T1.COMPANY_CD AND S1.INVOICE_SEQ_NO = T1.INVOICE_SEQ_NO
AND S1.DOCUMENT_ITEM_NO = T1.DOCUMENT_ITEM_NO
AND S1.ORDER_NO = T1.ORDER_NO) > 1 THEN
RTRIM(CAST(t1."TEST_REPORTING_MATERIAL_SID" AS VARCHAR(10)))
ELSE
END as sum_key,
t1.SALES_ANALYSIS_CD
FROM
dbo.TBLTEST_ALL T1
WHERE
t1.TIME_SID >= 20001001 ;
I tried to use a left outer Join , it did not work out. I tried to take the subquery and assign it to a variable and use in the above mentioned query. But i am not getting the same results.
I don't want to use the above query so i am planning to rewrite the code.
Thank You,I doubt that the query you posted works fine, because:
FROM dbo.TBLTEST S1 ON S1.DOCUMENT_NO = T1.DOCUMENT_NO
This is a syntax error. I will have to assume that your inteded query reads:
SELECT t1.DOCUMENT_NO,
rtrim(cast(t1."ENVIRONMENT_CD" AS varchar(5))) + '*' +
rtrim(cast(t1."ORDER_NO" AS varchar(25))) +
CASE WHEN (SELECT COUNT(DISTINCT S1.TEST_REPORTING_MATERIAL_SID)
FROM dbo.TBLTEST S1
WHERE S1.DOCUMENT_NO = T1.DOCUMENT_NO
AND S1.TEST_REPORTING_MATERIAL_SID > 0
AND S1.COMPANY_CD = T1.COMPANY_CD
AND S1.INVOICE_SEQ_NO = T1.INVOICE_SEQ_NO
AND S1.DOCUMENT_ITEM_NO = T1.DOCUMENT_ITEM_NO
AND S1.ORDER_NO = T1.ORDER_NO) > 1 THEN
RTRIM(CAST(t1."TEST_REPORTING_MATERIAL_SID" AS VARCHAR(10)))
ELSE '*-'
END as sum_key, t1.SALES_ANALYSIS_CD
FROM dbo.TBLTEST_ALL T1
WHERE t1.TIME_SID >= 20001001
Here is a query with a left join. Whether it is actually better than the one you have I am not sure.
SELECT t1.DOCUMENT_NO,
rtrim(cast(t1."ENVIRONMENT_CD" AS varchar(5))) + '*' +
rtrim(cast(t1."ORDER_NO" AS varchar(25))) +
CASE WHEN S1."EXISTS" IS NOT NULL
THEN RTRIM(CAST(t1."TEST_REPORTING_MATERIAL_SID" AS varchar(10)))
ELSE '*-'
END as sum_key, t1.SALES_ANALYSIS_CD
FROM dbo.TBLTEST_ALL T1
LEFT JOIN (SELECT 1 AS "EXISTS"
FROM dbo.TBLTEST
WHERE TEST_REPORTING_MATERIAL_SID > 0
GROUP BY DOCUMENT_NO, COMPANY_CD, INVOICE_SEQ_NO,
DOCUMENT_ITEM_NO, ORDER_NO
HAVING COUNT(DISTINCT TEST_REPORTING_MATERIAL_SID) > 1) AS S1
ON S1.DOCUMENT_NO = T1.DOCUMENT_NO
AND S1.COMPANY_CD = T1.COMPANY_CD
AND S1.INVOICE_SEQ_NO = T1.INVOICE_SEQ_NO
AND S1.DOCUMENT_ITEM_NO = T1.DOCUMENT_ITEM_NO
AND S1.ORDER_NO = T1.ORDER_NO
WHERE t1.TIME_SID >= 20001001
Erland Sommarskog, SQL Server MVP, [email protected] -
Can anyone help with this query
create table customer(
customer_email varchar(100) not null
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Please help ASAP
create table purchase (
purchase_id int not null identity(1,1)
,cust_id int not null references customer(cust_id)
,product_name varchar(200) not null
,amount int not null
,constraint pk__purchase primary key clustered (purchase_id)
Write a query that returns one row per customer with the following columns. Don't forget about customers with no purchases.
customer_email
qty of purchase
sum of purchase amountHomework deadline looming?
This will work in versions of Oracle from 9 up, and in all versions of Sybase/ SQL Server (which you seem to wnat based on the CREATE TABLE syntax).
SELECT customer_email, COUNT(*) number_purchaes, SUM(amount) total_purchases
FROM customer c
LEFT OUTER JOIN purchases p ON c.cust_id = p.cust_id
GROUP BY customer_emailTTFN
John -
Help with this problem please GasPump.java
I've been working on this program for a week now and i have not gotten it to complie yet. Could anybody help me out? Your help would be greatly appreciated. Thanks.
public class GasPump {
double pricePerGallon;
double gallons;
int fuelType;
int paymentType;
float washPrice;
String fuelName;
public GasPump ( )
{ pricePerGallon = 2.699; }
public GasPump ( double price)
{ pricePerGallon = price; }
public void setCost(double cost)
{ double pricePerGallon = cost; }
double getCost( )
{ return pricePerGallon; }
public setGrade(int fuelType)
{ String fuelName;
switch (fuelType)
case 1: fuelName = ?Regular Unleaded?
break;
case 2: fuelName = ?Mid grade Unleaded?
break;
case 3: fuelName = ?Super Unleaded?
break;
case 4: fuelName = ?Diesel?
break;
case 5: fuelName = ?Natural Gas?
break;
default: System.out.println(?Unknown fuel type? + fuelType);
fuelName = ?Unknown?;
public String getGrade ( )
{ return fuelName; }
double calcBill (double gallons)
{ return(pricePerGallon * gallons); }
void paymentMethod(int paymentType)
if (paymentType == 1)
payInsideMethod();
else
if (paymentType == 2)
payOutsideMethod();
else
if (paymentType == 3)
payInsideMethod ( );
else
System.out.println(?Unknown payment type?);
void payInsideMethod( )
System.out.println(?Pay cashier inside the gas station?);
void payOutsideMethod( )
System.out.println(?Please pay with your credit card ?);
float carWash (int washType)
washPrice = 0.00f;
if (washType == 1)
washPrice = 7.00f;
else
if (washType == 2)
washPrice = 8.00f;
else
System.out.println(?Unknown wash type?);
return (float)washPrice;
void printReceipt ( )
/* System.out.println(fuelName + ? ? +gallons + ? Gallons purchased at $ ? +
pricePerGallon + ? per gallon ? + ? Total cost is: ? +
pricePerGallon * gallons + ? Total bill is $ :" +
((pricePerGallon * gallons) + washPrice)); */
System.out.printf("%s %.2f Gallons purchased at $%.2f per gallon.\nTotal
cost is: %.2f",
fuelName, gallons, pricePerGallon, pricePerGallon *
gallons);
System.out.printf(" Total bill is $: %.2f", ((pricePerGallon * gallon) +
washPrice));
}sorry my compile errors read
GasPump.java:31: illegal character: \8220
case 3: fuelName = ?Super Unleaded?;
^
GasPump.java:31: illegal character: \8221
case 3: fuelName = ?Super Unleaded?;
^
GasPump.java:33: illegal character: \8220
case 4: fuelName = ?Diesel?;
^
GasPump.java:33: illegal character: \8221
case 4: fuelName = ?Diesel?;
^
GasPump.java:35: illegal character: \8220
case 5: fuelName = ?Natural Gas?;
^
GasPump.java:35: illegal character: \8221
case 5: fuelName = ?Natural Gas?;
^
GasPump.java:37: illegal character: \8220
default: System.out.println(?Unknown fuel type? + fuelType);
^
GasPump.java:37: illegal character: \8221
default: System.out.println(?Unknown fuel type? + fuelType);
^
GasPump.java:37: ')' expected
default: System.out.println(?Unknown fuel type? + fuelType);
^
GasPump.java:38: illegal character: \8220
fuelName = ?Unknown?;
^
GasPump.java:38: illegal character: \8221
fuelName = ?Unknown?;
^
GasPump.java:59: illegal character: \8220
System.out.println(?Unknown payment type?);
^
GasPump.java:59: illegal character: \8221
System.out.println(?Unknown payment type?);
^
GasPump.java:59: ')' expected
System.out.println(?Unknown payment type?);
^
GasPump.java:64: illegal character: \8220
System.out.println(?Pay cashier inside the gas station?);
^
GasPump.java:64: illegal character: \8221
System.out.println(?Pay cashier inside the gas station?);
^
GasPump.java:64: ')' expected
System.out.println(?Pay cashier inside the gas station?);
^
GasPump.java:69: illegal character: \8220
System.out.println(?Pay at the pump with credit card ?);
^
GasPump.java:69: illegal character: \8221
System.out.println(?Pay at the pump with credit card ?);
^
GasPump.java:69: ')' expected
System.out.println(?Pay at the pump with credit card ?);
^
GasPump.java:82: illegal character: \8220
System.out.println(?Unknown wash type?);
^
GasPump.java:82: illegal character: \8221
System.out.println(?Unknown wash type?);
^
GasPump.java:82: ')' expected
System.out.println(?Unknown wash type?);
^
GasPump.java:94: unclosed string literal
System.out.printf("%s %.2f Gallons purchased at $%.2f per
gallon.\nTotal
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GasPump.java:95: unclosed string literal
cost is: %.2f",
^
GasPump.java:97: ')' expected
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^
26 errorsBasically wherever I have a quotation mark or a semi-colon there is a error there. I just started programming so im still trying to get the hang of it -
Possibly corrupt prefs.js file. Need help with this file please.
I've been having a problem with sending/receiving text messages in Yahoo Messenger and I think I've narrowed it to the prefs.js file in Firefox. I'm using Firefox 3.6.25 on Windows XP sp3. The Yahoo Messenger window would not open when the appropriate mobile phone link was clicked. I uninstalled/reinstalled flash without change. I cleared cache, etc., without change. I created a new Firefox profile and I was able to get the Yahoo Messenger window to open. When I copied the prefs.js file from the old profile to the new profile, I encountered the problem again. I opened the prefs.js file with wordpad and noticed that editing should occur in about:config in the currently running Firefox browser. I briefly compared the two about:config tabs from the working profile and the non-working profile. They were significantly different. How do I make a copy of one so that I can paste it into wordpad and make the editing of the other one easier? Where can I find information about the individual parameters and their settings?
Hi,
Please see [[http://kb.mozillazine.org/About:config_entries this.]
[http://kb.mozillazine.org/About:config about:config]
You can try to '''Reset all user preferences to Firefox defaults:''' and '''Make Changes and Restart''' in the [https://support.mozilla.org/en-US/kb/Safe%20Mode Firefox Safe Mode] start screen which would also hopefully solve the issue. You can also try to manually '''Reset''' to defaults the modified entries by right-clicking on the bold entries (user set) in about:config. Clicking on the '''Status''' column header would sort the entries between user set (modified) and the defaults.
An easy way would be to create a [https://support.mozilla.org/en-US/kb/Managing-profiles new profile] and [https://support.mozilla.org/en-US/kb/Recovering%20important%20data%20from%20an%20old%20profile?s=profile&r=1&e=sph&as=s copy/transfer the needed personal data] from the old profile and start using the new profile. You can then delete or troubleshoot the old proile. Firefox stores your personal data and settings in [http://kb.mozillazine.org/Profile_folder another location (profile folder)] separate from its [http://kb.mozillazine.org/Installation_directory folders/files]. A new profile would have the default Firefox settings in '''Tools''' ('''Alt''' + '''T''') > [https://support.mozilla.org/en-US/kb/Options%20window Options] and [http://kb.mozillazine.org/About:config about:config], and usually would also be empty of '''Extensions''' and themes ('''Appearance''') in '''Tools''' > '''Add-ons''', and their settings. Also, a new profile would have no previous stored website cache/cookies/data/preferences: '''Tools''' > [https://support.mozilla.org/en-US/kb/Clear%20Recent%20History '''Clear Recent History'''].
[https://support.mozilla.org/en-US/kb/Profiles?s=profile&r=2&e=sph&as=s Profiles Howto]
[http://kb.mozillazine.org/Profile_folder_-_Firefox Profile Folder & Files] -
Help with one query ( Please reply)
Oracle version : 11.2.0.2.0
I have a table with the following set of rows
with Table_dm AS
( select 1 month_no ,'wk1' week, 120 DM_AMT,300 GRoss_Amt,4 Week_no, 12 Gross_qty,1000 dm_adj_total from dual
UNion all
select 1 month_no ,'wk2' week,120 DM_AMT,300 GRoss_Amt,4 Week_no, 12 Gross_qty,1000 dm_adj_total from dual
union all
select 1 month_no ,'wk3' week,120 DM_AMT,300 GRoss_Amt,4 Week_no, 12 Gross_qty,1000 dm_adj_total from dual
union all
select 1 month_no ,'wk4' week,120 DM_AMT,300 GRoss_Amt,4 Week_no, 12 Gross_qty,1000 dm_adj_total from dual
union all
select 2 month_no ,'wk5' week,200 DM_AMT,400 GRoss_Amt,5 Week_no, 20 Gross_qty,1000 dm_adj_total from dual
UNion all
select 2 month_no ,'wk6' week,200 DM_AMT,400 GRoss_Amt,5 Week_no, 20 Gross_qty,1000 dm_adj_total from dual
union all
select 2 month_no ,'wk7' week,200 DM_AMT,400 GRoss_Amt,5 Week_no, 20 Gross_qty,1000 dm_adj_total from dual
UNion all
select 2 month_no ,'wk8' week,200 DM_AMT,400 GRoss_Amt,5 Week_no, 20 Gross_qty,1000 dm_adj_total from dual
UNion all
select 2 month_no ,'wk9' week,200 DM_AMT,400 GRoss_Amt,5 Week_no, 20 Gross_qty,1000 dm_adj_total from dual
So the data in Grid will be like this
month_no
week
DM_AMT
GRoss_Amt
Week_no
Gross_qty
dm_adj_total
DM_ADJ_Final
1
wk1
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
=1
wk2
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
1
wk3
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
1
wk4
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
2
wk5
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk6
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk7
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk8
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk9
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
I need to calculate DM_ADJ_Final where calculation for DM_ADJ_Final will be like
= dm_adj_total * gross_amt/ (gross_amt (where month_no =1 ) + gross_amt (where month_no =2 )) ( Please refer DM_ADJ_Final column above for calculation with value )You apparently have (or intend) an association between rows where month_no = 1 and month_no = 2.
But what is that relationship? Is the month 2 row always 4 weeks later than the month 1 row?
That relationship needs to be spelled out exactly.
month_no
week
DM_AMT
GRoss_Amt
Week_no
Gross_qty
dm_adj_total
DM_ADJ_Final
1
wk1
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
=1
wk2
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
1
wk3
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
1
wk4
120
300
4
12
1000
1000 * 300 /(300+400) = 428.57
2
wk5
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk6
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk7
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk8
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
2
wk9
200
400
5
20
1000
1000 * 400 /(300+400) = 571.42
I need to calculate DM_ADJ_Final where calculation for DM_ADJ_Final will be like
= dm_adj_total * gross_amt/ (gross_amt (where month_no =1 ) + gross_amt (where month_no =2 )) ( Please refer DM_ADJ_Final column above for calculation with value ) -
Physician/Researcher needs help with this query
Folks,
Thank you in advance for looking at my problem. You are helping to save lives and make this world a better place.
I am trying to find out the earliest date patients took steroid. I have:
select patientid, visitnumber, steroid_start_date from treatments where steroid_start_date is not null and trim(steroid_start_date) != '/'
order by patientid, substr(steroid_start_date, -4)
I then have:
patientid visitnumber steroid_start_date(this is a string column, not date or time, and it has so many junk in it, like /2003 , /)
4 3 03/2004
4 2 01/01/2005
10 2 08/01/2005
10 1 05/01/2002
What I need is:
4 3 03/2004
10 1 05/01/2002
I am not good with group by... having.... max.... How can I limit to one patient per row and this row is their earliest visit?
Thank you very much in advance. You are helping to save lives.Here it is ->
satyaki>
satyaki>select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Prod
PL/SQL Release 10.2.0.3.0 - Production
CORE 10.2.0.3.0 Production
TNS for 32-bit Windows: Version 10.2.0.3.0 - Production
NLSRTL Version 10.2.0.3.0 - Production
Elapsed: 00:00:00.53
satyaki>
satyaki>
satyaki>with t
2 as
3 (
4 select 4 patientid, 3 visitnumber, '03/2004' steroid_start_date from dual
5 union all
6 select 4, 2, '01/01/2005' from dual
7 union all
8 select 10, 2, '08/01/2005' from dual
9 union all
10 select 10, 1, '05/01/2002' from dual
11 )
12 select patientid,
13 visitnumber,
14 steroid_start_date
15 from (
16 select k.*,
17 row_number() over(partition by patientid order by to_date(substr(steroid_start_date,-4),'YYYY')) rn
18 from t k
19 order by patientid
20 )
21 where rn=1;
PATIENTID VISITNUMBER STEROID_ST
4 3 03/2004
10 1 05/01/2002
Elapsed: 00:00:00.11
satyaki>Regards.
Satyaki De.
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