Hide regions in dreamweaver help
I need help please. I am using the server behaviour to show if there is no info.
I have three problems
1. I am a new comer so i am totally lost and learning as i go, now that we are passed the obvious, on to the code.
2. I also have in the list menu the option to select all cars but i dont know how to code for that because my database does not have a field for that.
3. Everything works without the server behaviour to hide records if the query is empty, the only problem is when i search i either get all the records or none at all. The rows are counted correctly but if i use the server behaviour given in dreamweaver i either display everything in my database or nothing from the database.
Please help i have been reading and troubleshooting but nothing is working
SEARCH PAGE:
<form id="searcMennuu" name="searcMennuu" method="post" action="VehicleListing.php">
<select name="vehicles" id="vehicles">
<option value="allCars" selected="selected">ALL</option>
<option value="Sedan">Sedan</option>
<option value="Jeep">Jeep</option>
<option value="Motorbike">Motorbike</option>
</select>
<input name="radioVehicle" type="radio" id="searchSale" value="Sale" />
Vehicles for Sale</label>
<label>
<input type="radio" name="radioVehicle" id="searchRent" value="Rent" />
Vehicles for Rent</label>
<input type="submit" name="searchButton" id="searchButton" value="Search" />
</form>
RESULTS PAGE:
mysql_select_db($database_ddd, $ddd);
$query_rsTest = "SELECT `year`, `model` FROM vehicles";
if (isset ($_POST ['vehicles'])) { // Use $_POST, not $HTTP_POST_VARS
$parSearch = mysql_real_escape_string ($_POST['vehicles']);
$parSearch1 = mysql_real_escape_string ($_POST['radioVehicle']);
if($_POST['vehicles'] == "Sedan") && ($_POST[radioVvehicles'] == "Sale"){
$query_rsTest.= " WHERE vehicle_type LIKE '%$parSearch%' AND vehicle_SR LIKE '%$parSearch1% ";
$rsTest = mysql_query ($query_rsTest, $ddd) or die(mysql_error());
$row_rsTest = mysql_fetch_assoc ($rsTest);
$totalRows_rsTest = mysql_num_rows ($rsTest);
<div class="showPage"><?php echo $totalRows_rsTest ?></div>
<?php if ($totalRows_rsTest == 0) { // Show if recordset empty ?>
<?php do { ?>
<div class="output" id="Results">
<p><?php echo $row_rsTest['year']; ?></p>
<p><?php echo $row_rsTest['model']; ?></p>
</div>
<?php } while ($row_rsTest = mysql_fetch_assoc($rsTest)); ?>
<?php } // Show if recordset empty ?>
You'll get better answers to your PHP & MySql questions in the App Development Forum:
http://forums.adobe.com/community/dreamweaver/dreamweaver_development?view=discussions
Nancy O.
Alt-Web Design & Publishing
Web | Graphics | Print | Media Specialists
http://alt-web.com/
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>
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Hello everyone,
Thank you in advance for dealing with my inexperience and answering my question.
I have been stuck on this for wayyyy too long. Here is my problem. I created a drop down menu for a portfolio website I am building. When I pull this into Dreamweaver the way to link the menu items to the pages is elusive. I have no idea what to do. Please help?
Here is the screenshot. Thank you very much Jennifer
OK, Well no one can actually see this image since it came in so small, but please help me anyway if you can?Thank you for answering my question. I created the graphics in photoshop, sliced them in fireworks and now I am pulling the site in dreamweaver to link it. The dropdown is just a little dropdown menu. I created it in Fireworks because when I tried to create one in Dreamweaver I had to use a spry which was even harder to figure out and get to work. If I knew Html or CSS my life would be much easier but I don't. I don't have much time to learn it right now since I work over time all week, do graphics freelance and I go to school for computer science. I need to get this site up and I just want a fast little fix to get it up. When I have time to learn more I can make this site better or start a better site, but for right now it just needs to work. Is there a way to get what I have working so I can just get this site up. Later I will have more time and more experience to do this better. I am learning so thank you for your experience.
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