Hierarchy count of emp table by job title
Consider Emp table.
I want the hierarchical count by job title wise.
For president the count should be the total number of subordinates, i.e. the total number of emp's - 1 (the 1 is the president himself).
Like that any manager, the count is the total number of subordinates.
The output should be look like this:
Job Subordinates
President xx
Manager xx
I'm not sure what version you are looking into, but hierarchical total example is in 10g documentation (SQL Reference):
<quote>The following example uses a GROUP BY clause to return the total salary of each employee in department 110 and all employees below that employee in the hierarchy:
SELECT name, SUM(salary) "Total_Salary" FROM (
SELECT CONNECT_BY_ROOT last_name as name, Salary
FROM employees
WHERE department_id = 110
CONNECT BY PRIOR employee_id = manager_id)
GROUP BY name;
NAME Total_Salary
Gietz 8300
Higgins 20300
King 20300
Kochhar 20300
</quote>
Similar Messages
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Fetching ename who are all having max(sal) in each of job from emp table
hi all,
i need a query to fetch all the ename who are all having maximum salary in each job category from emp table
thankx in advance
regrds,
punithSQL> select ename,job,sal
2 from emp
3 order by job,sal desc;
ENAME JOB SAL
SCOTT ANALYST 3000
FORD ANALYST 3000
MILLER CLERK 1300
ADAMS CLERK 1100
JAMES CLERK 950
SMITH CLERK 800
JONES MANAGER 2975
BLAKE MANAGER 2850
CLARK MANAGER 2450
KING PRESIDENT 5000
ALLEN SALESMAN 1600
TURNER SALESMAN 1500
WARD SALESMAN 1250
MARTIN SALESMAN 1250
14 rows selected.
SQL> select ename,job,sal from emp
2 where sal in(select distinct max(sal) from emp
3* group by job)
SQL> /
ENAME JOB SAL
FORD ANALYST 3000
SCOTT ANALYST 3000
MILLER CLERK 1300
JONES MANAGER 2975
KING PRESIDENT 5000
ALLEN SALESMAN 1600
6 rows selected.
SQL>Is this what you need ? -
GETTING ROW COUNTS OF ALL TABLES AT A TIME
Is there any column in any Data dictionary table which gives the row counts for particular table..
My scenario is...i need to get row counts of some 100 tables in our database...
instead of doing select count(*) for each table....is there any way i can do it?
similary How to get column counts for each table..in database .For example
Employee table has 3 columns...empid,empname,deptno....i want count(empid),
count(empname),count(deptno) ...is there any easy way for finding all column counts of each table in data base? is it possible?Why does "select count(mgr) from emp" return null and not 13?Good question ;)
Seems that xml generation in principle can't handle »counting nulls«:
SQL> select xmltype(cursor(select null c from dual)) x from dual
X
<?xml version="1.0"?>
<ROWSET>
<ROW>
</ROW>
</ROWSET>
1 row selected.
SQL> select cursor(select count(null) c from dual) x from dual
Cur
0
1 row selected.
SQL> select xmltype(cursor(select count(null) c from dual)) x from dual
select xmltype(cursor(select count(null) c from dual)) x from dual
Error at line 1
ORA-31011: XML parsing failed
ORA-19202: Error occurred in XML processing
LPX-00229: input source is empty
Error at line 0
ORA-06512: at "SYS.XMLTYPE", line 0
ORA-06512: at line 1
but
SQL> select xmltype(cursor(select count(1) c from dual)) x from dual
X
<?xml version="1.0"?>
<ROWSET>
<ROW>
<C>1</C>
</ROW>
</ROWSET>
1 row selected.Looks like a bug to me ... -
Count(*) for all tables
Hi ,
I want the Query to get the table name and count(*) display in excel like this.Can i get count(*) from metadata table .Please let me know ??
ACCT 53
ACCT_CHEQUE 45
EMP 50
DEPT 90Karthick_Arp wrote:
A XML solution.
This one is not mine. This question comes up often in this forum. And once i saw this answer. And i thought its really cool so just saved it in my Google Note Book ;)You need to update your google note book. It doesn't take account of Index Organised Tables.
Based on answer from Laurent Schneider
http://laurentschneider.com/wordpress/2007/04/how-do-i-store-the-counts-of-all-tables.html
SQL> select
2 table_name,
3 to_number(
4 extractvalue(
5 xmltype(
6 dbms_xmlgen.getxml('select count(*) c from '||table_name))
7 ,'/ROWSET/ROW/C')) count
8 from user_tables
9 where iot_type != 'IOT_OVERFLOW';
TABLE_NAME COUNT
DEPT 4
EMP 14
BONUS 0
SALGRADE 5Edited by: BluShadow on Jul 8, 2009 12:00 PM -
How to insert test data of 10,000 records into emp table
Hi I'm new to oracle can anyone please help me in writing a program so that i can insert test data into emp table
Hi,
user11202607 wrote:
thanks sanjay , frank . But how can i insert only 4 deptno's randomly and how can i insert only 10 managers randomly ,
Sorry to pull Your legs and thanks for bearing my question. I want to insert into emp table where it has the empno, ename, sal, job, hiredate, mgr and deptnoThis should give you some ideas:
INSERT INTO emp (empno, ename, sal, job, hiredate, mgr, deptno)
SELECT LEVEL -- empno
, dbms_random.string ('U', 4) -- ename
, ROUND ( dbms_random.value (100, 5000)
, -2
) -- sal
, CASE
WHEN LEVEL = 1 THEN 'PRESIDENT'
WHEN LEVEL <= 4 THEN 'MANAGER' -- Change to 11 after testing
WHEN dbms_random.value < .5 THEN 'ANALYST'
WHEN dbms_random.value < .5 THEN 'CLERK'
ELSE 'SALESMAN'
END -- job
, TRUNC ( SYSDATE
- dbms_random.value (0, 3650)
) -- hiredate
, CASE
WHEN LEVEL > 1
THEN TRUNC (dbms_random.value (1, LEVEL))
END -- mgr
, TRUNC (dbms_random.value (1, 5)) -- deptno
FROM dual
CONNECT BY LEVEL <= 10 -- Change to 10000 after testing
;The interesting part (to me, at least) is mgr. What I've done above is guarantee that the mgr-empno relationship reflects a tree, with the 'PRESIDENT' at its sole root. The tree can be any number of levels deep.
Sample results:
EMPNO ENAME SAL JOB HIREDATE MGR DEPTNO
1 GDMT 2800 PRESIDENT 30-AUG-04 2
2 CVQX 400 MANAGER 24-MAY-06 1 2
3 QXJD 1300 MANAGER 17-JUN-05 1 4
4 LWCK 4800 MANAGER 15-JUN-06 2 2
5 VDKI 3700 CLERK 08-SEP-01 4 2
6 FKZS 2600 CLERK 18-DEC-06 4 1
7 SAKB 700 ANALYST 30-JUN-00 5 4
8 DVYY 300 ANALYST 22-SEP-01 2 1
9 CLEO 2700 ANALYST 27-MAY-08 5 4
10 RDVQ 3400 ANALYST 14-DEC-08 5 4For details on the built-in packages (such as dbms_random) see the [Parckages and Types manual|http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28419/d_random.htm#i998925]. -
Hi,
How to find display the o/p like manager name under dependent employess same like parent child relation ship on noraml emp table:
sample o/p:
name job
xx manger
yy sales
yy1 sales
aa manager
rr marketing
rr1 marketing
Thanks921306 wrote:
so like this i need parent child relationship between the manager under employees....So join the parent entity with the child entity to create the parent-child relationship.
As both entities are in the same table, this means joining the table to itself. E.g.
SQL> select
2 child.ename as CHILD,
3 child.job as CHILD_JOB,
4 nvl(parent.ename,'<none>') as PARENT,
5 parent.job as PARENT_JOB
6 from emp parent,
7 emp child
8 where child.mgr = parent.empno (+)
9 /
CHILD CHILD_JOB PARENT PARENT_JO
FORD ANALYST JONES MANAGER
SCOTT ANALYST JONES MANAGER
JAMES CLERK BLAKE MANAGER
TURNER SALESMAN BLAKE MANAGER
MARTIN SALESMAN BLAKE MANAGER
WARD SALESMAN BLAKE MANAGER
ALLEN SALESMAN BLAKE MANAGER
MILLER CLERK CLARK MANAGER
ADAMS CLERK SCOTT ANALYST
CLARK MANAGER KING PRESIDENT
BLAKE MANAGER KING PRESIDENT
JONES MANAGER KING PRESIDENT
SMITH CLERK FORD ANALYST
KING PRESIDENT <none>
14 rows selected.
SQL> The basic concept is easy - define the parent entity, define the child entity, join the parent to the child.
If some entities will not have parents (root entities), then an outer join is needed from the child entity to the parent entity.
Simply because both entities are in the same table, does not change the logic or approach. It is perfectly valid to self-join a table. -
Finding department and job title of employee in org model
Hi all,
Are there any Function Modules that can find out the department and job title (such as manager, director, etc) of an employee in SRM's org model (SRM4.0)? What DB table(s) is this information stored in?
Thanks!
JayHi,
You can use the FM "BBP_READ_ATTRIBUTES" to read all the attributes of a user in the org structure.
Other FM's;
CRM_EMPLOYEE_GETORGUNIT
DWP_GET_RESPONSIBLE_ORGUNITS
BBPU_GET_ORGUNIT_AND_COUNTRY
BBPU_GET_USERS_OF_ORGUNIT
BBP_OM_USR_READ_WORKPLACE_ADDR
RH_READ_OBJECT
RH_READ_INFTY
BBP_OM_STRUC_GET_ORG_FROM_POS
BR,
Disha.
Do reward points for useful answers.
Do reward points for useful answers. -
Find EMP tables without SAL column
We have EMP tables in several of our schemas. Some of these EMP tables have SAL column missing.
How can i find the schemas whose EMP tables have a missing SAL column from DBA_TAB_COLS view?Hi,
Here's another way, that only requires one pass throught the view:
SELECT owner
FROM dba_tab_cols
WHERE table_name = 'EMP'
GROUP BY owner
HAVING COUNT (CASE WHEN column_name = 'SAL' THEN 1 END) = 0
ORDER BY owner
;This might be more efficient, but, unless you have thousands of tables called EMP, you won't notice it. You might keep this tecnique in mind for similar problems where efficency is imporatant. -
Unable to maintain job title for employees
Hi friends
we getting employees data from R/3 HR .but i am trying to assign the job titles to employees in CRM systems through relationship category but here i am getting error "Maintenance is only possible via an external HR system".here if choose continues i am getting job title etc.. i can give input for job title but thing it is not saving. Could any one please suggest me how to do add the job titles.
whether it can be possible change in CRM or not.
If it is HR how could i add it.
Earlier reply would be appreciated
Thanks in advance
RaoRao,
Have you looked at OSS Note 312090? Maybe you can find something here. The titles in HR is stored in another table as the BP titles. They should be replicated using an R/3 adapter object or kept the same as the BP titles.
If nothing helps you could consider temporarily switch off the block for maintaining the employee in CRM. If I remember this is done by setting key PBPHR to OFF.
Points if this helps.
Regards,
Nico -
Nth Highest Salary from EMP table , need explaination
I am new to the database world and hence learning queries at the initial stages. I want to retrieve the nth highest salary from the EMP table. I was not able to find out the answer by myself , so I searched on google. The following was the answer i got :
SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Enter value for n: 2
SAL
3700
Suppose the table contains salary in the following order :
SAL
2000
3000
3700
4000
3700
2000
So how come I will get the correct answer with the abov query ? I am not able to understand the part --- WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Specially the condition WHERE a.sal<=b.sal is very confusing to me. Can anyone help me please to understand the same.user12328699 wrote:
I am new to the database world and hence learning queries at the initial stages. I want to retrieve the nth highest salary from the EMP table. I was not able to find out the answer by myself , so I searched on google. The following was the answer i got :
SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Enter value for n: 2
SAL
3700
Suppose the table contains salary in the following order :
SAL
2000
3000
3700
4000
3700
2000
So how come I will get the correct answer with the abov query ? I am not able to understand the part --- WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Specially the condition WHERE a.sal<=b.sal is very confusing to me. Can anyone help me please to understand the same.There is many better way to get the nth highest salary
But still if you want to understand the same.
Assuming the data is sorted in ascending order, then
1) a.sal=2000, so a.sal<=b.sal results in count as 3 (not equal to user input)
2) a.sal=3700, so a.sal<=b.sal results in count as 2 (equal to user input)
3) a.sal = 4000 , so a.sal<=b.sal results in count as 1 (not equal to user input)
Hence the answer is 3700
Regards
Anurag -
How to get the select * from emp table output on the console using java
public class software {
* @param args
static final String JDBC_DRIVER = "oracle.jdbc.driver.OracleDriver";
static final String DATABASE_URL = "jdbc:oracle:abc";
private static Connection connection;
private static Statement statement;
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
System.out.println("-------THIS IS THE Class.forNameJDBC_DRIVER");
Class.forName(JDBC_DRIVER);
System.out.println("THIS IS THE Class.forNameJDBC_DRIVER");
connection = DriverManager.getConnection(DATABASE_URL, "abc",
"abc");
System.out.println("THIS IS THE connection abc ,abc");
statement = connection.createStatement();
//Query to find the values in the EMP table.
ResultSet resultSet = statement.executeQuery("SELECT * from EMP");
if(resultSet.next()){
System.out.println("THESE ARE THE VALUES IN EMP TABLE:"+resultSet); /// How can i get all the values record wise on the console ??????
resultSet.close();
catch (ClassNotFoundException classNotFound) {
System.out.println("Driver not Found"+classNotFound.getMessage());
} catch (SQLException sqlException) {
System.out.println("SQL Exception - bad sql");
System.out.println(sqlException.getMessage());
}1sai
Please assign the dukes here and in your previous threads.
See [http://wikis.sun.com/display/SunForums/Duke+Stars+Program+-+How+it+Works]
You are currently the all time career leader in un-awarded dukes, with including this thread 75 unawarded dukes for questions you marked as answered.
It's even worse when you look and see that you have awarded many dukes as well. So you do know how to do it. You're just too lazy and rude to be bothered.
Don't be a lazy wank. -
C# - What's wrong with a table called JOBS? :(
Post Author: Gee
CA Forum: .NET
Hi
I've just moved up to .NET 2005. and am having a big problem right now with one report in particular.
The report uses an Oracle table called "JOBS". It worked just fine in .NET 2003. Now though, it comes up with the dreaded field name not known error.
So, I tried to just do a completely new report with just ONE field from the JOBS table on it. It doesn't want to know!
I then copied (so it was IDENTICAL) the table structure and data to a new one called "JOBSTEST". The simple report worked (once I'd changed it to use the JOBSTEST fields of course)
I deleted the original JOBS table, copied a new JOBS table from the JOBSTEST table and... it didn't work again!
So, what's wrong with having a table called "JOBS"? Because that seems to be the problem!
Oh... it works ok on the development machine. Just not any other. ALL other reports work fine!
Thank you so much for your time in helping mePost Author: Gee
CA Forum: .NET
Hi
I've just moved up to .NET 2005. and am having a big problem right now with one report in particular.
The report uses an Oracle table called "JOBS". It worked just fine in .NET 2003. Now though, it comes up with the dreaded field name not known error.
So, I tried to just do a completely new report with just ONE field from the JOBS table on it. It doesn't want to know!
I then copied (so it was IDENTICAL) the table structure and data to a new one called "JOBSTEST". The simple report worked (once I'd changed it to use the JOBSTEST fields of course)
I deleted the original JOBS table, copied a new JOBS table from the JOBSTEST table and... it didn't work again!
So, what's wrong with having a table called "JOBS"? Because that seems to be the problem!
Oh... it works ok on the development machine. Just not any other. ALL other reports work fine!
Thank you so much for your time in helping me -
How to get row count(*) for each table that matches a pattern
I have the following query that returns all tables that match a pattern (tablename_ and then 4 digits). I also want to return the row counts for these tables.
Currently a single column is returned: tablename. I want to add the column RowCount.
DECLARE @SQLCommand nvarchar(4000)
DECLARE @TableName varchar(128)
SET @TableName = 'ods_TTstat_master' --<<<<<< change this to a table name
SET @SQLCommand = 'SELECT [name] as zhistTables FROM dbo.sysobjects WHERE name like ''%' + @TableName + '%'' and objectproperty(id,N''IsUserTable'')=1 ORDER BY name DESC'
EXEC sp_executesql @SQLCommandThe like operator requires a string operand.
http://msdn.microsoft.com/en-us/library/ms179859.aspx
Example:
DECLARE @Like varchar(50) = '%frame%';
SELECT * FROM Production.Product WHERE Name like @Like;
-- (79 row(s) affected)
For variable use, apply dynamic SQL:
http://www.sqlusa.com/bestpractices/datetimeconversion/
Rows count all tables:
http://www.sqlusa.com/bestpractices2005/alltablesrowcount/
Kalman Toth Database & OLAP Architect
SQL Server 2014 Design & Programming
New Book / Kindle: Exam 70-461 Bootcamp: Querying Microsoft SQL Server 2012 -
How to display required data from emp table?
Hi every one, this is my first post in this portal. I want display the details of emp table.. for that I am using this SQL statement.
select * from emp where mgr=nvl(:mgr,mgr);
when I give the input as 7698 it is displaying the corresponding records... and also when I won't give any input then it is displaying all the records except the mgr with null values.
1)I want to display all the records when I won't give any input including nulls
2)I want to display all the records who's mgr is null
Is there any way to incorporate to include all these in a single query..Hi,
937440 wrote:
Hi every one, this is my first post in this portal. Welcome to the forum!
Be sure to read the forum FAQ {message:id=9360002}
I want display the details of emp table.. for that I am using this SQL statement.
select * from emp where mgr=nvl(:mgr,mgr);
when I give the input as 7698 it is displaying the corresponding records... and also when I won't give any input then it is displaying all the records except the mgr with null values.
1)I want to display all the records when I won't give any input including nulls
2)I want to display all the records who's mgr is null
Is there any way to incorporate to include all these in a single query..It's a little unclear what you're asking.
The following query always includes rows where mgr is NULL, and when the bind variable :mgr is NULL, it displays all rows:
SELECT *
FROM emp
WHERE LNNVL (mgr != :mgr)
;That is, when :mgr = 7698, it displays 6 rows, and when :mgr is NULL it displays 14 rows (assuming you're using the Oracle-supplied scott.emp table).
The following query includes rows where mgr is NULL only when the bind variable :mgr is NULL, in which case it displays all rows:
SELECT *
FROM emp
WHERE :mgr = mgr
OR :mgr IS NULL
;When :mgr = 7698, this displays 5 rows, and when :mgr is NULL it displays 14 rows.
The following query includes rows where mgr is NULL only when the bind variab;e :mgr is NULL, in which case it displays only the rows where mgr is NULL. That is, it treats NULL as a value:
SELECT *
FROM emp
WHERE DECODE ( mgr
, :mgr, 'OK'
) = 'OK'
;When :mgr = 7698, this displays 5 rows, and when :mgr is NULL, it displays 1 row. -
I need to see the caller’s special infos in call screen. Like Company name, Job Title?
Please dont say me, “put these info to name&surname field”, because that, i’m useing Outlook Contact and i cannot change it.
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Lots of people asked same question but there is no any exact answer.
I think it must be a metbod for the seeing this special info in call screen.
Oldest Nokia and Blackberry model phone shows this info, More smart phone iPhone can shows it i think. Please show me, how can i see this infos in call screen.Other than finding an App to do what you want, or putting the info in the name field, you can't, as this is not a feature of the stock iOS.
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