How can i achive this result by writing SQL Query ?

Dear Exparts,
Here is my banner
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Prod
PL/SQL Release 10.2.0.3.0 - Production
"CORE     10.2.0.3.0     Production"
TNS for 32-bit Windows: Version 10.2.0.3.0 - Production
NLSRTL Version 10.2.0.3.0 - ProductionI have two table with relation. Here is the scripts of create table and insert data.
TABLE
CREATE TABLE TAB1
T1_ID NUMBER(5)
, T1_NAME VARCHAR2(100)
ALTER TABLE TAB1
MODIFY (T1_ID NOT NULL);
ALTER TABLE TAB1
ADD CONSTRAINT TAB1_PK PRIMARY KEY
T1_ID
ENABLE;
CREATE TABLE TAB2
T2_ID NUMBER(5) NOT NULL
, T2_T1_ID NUMBER(5)
, T2_RV_NO VARCHAR2(20)
, T2_RV_DATE DATE
, T2_F1 VARCHAR2(20)
, T2_F2 VARCHAR2(20)
, T2_F3 VARCHAR2(20)
, CONSTRAINT TAB2_PK PRIMARY KEY
    T2_ID
ENABLE
ALTER TABLE TAB2
ADD CONSTRAINT TAB2_TAB1_FK1 FOREIGN KEY
T2_T1_ID
REFERENCES TAB1
T1_ID
ENABLE;INSERT DATA
Insert into TAB1 (T1_ID,T1_NAME) values (1,'Test 1');
Insert into TAB1 (T1_ID,T1_NAME) values (2,'Test 2');
Insert into TAB2 (T2_ID,T2_T1_ID,T2_RV_NO,T2_RV_DATE,T2_F1,T2_F2,T2_F3) values (1,1,'00',to_date('01-OCT-2012','DD-MON-RRRR'),'Probation','05','Yes');
Insert into TAB2 (T2_ID,T2_T1_ID,T2_RV_NO,T2_RV_DATE,T2_F1,T2_F2,T2_F3) values (2,1,'01',to_date('06-OCT-2012','DD-MON-RRRR'),'Confirm','06','Yes');
Insert into TAB2 (T2_ID,T2_T1_ID,T2_RV_NO,T2_RV_DATE,T2_F1,T2_F2,T2_F3) values (3,2,'00',to_date('02-OCT-2012','DD-MON-RRRR'),'Probation','07','No');
Insert into TAB2 (T2_ID,T2_T1_ID,T2_RV_NO,T2_RV_DATE,T2_F1,T2_F2,T2_F3) values (4,2,'01',to_date('09-OCT-2012','DD-MON-RRRR'),'Probation','07','Yes');
Insert into TAB2 (T2_ID,T2_T1_ID,T2_RV_NO,T2_RV_DATE,T2_F1,T2_F2,T2_F3) values (5,1,'02',to_date('10-OCT-2012','DD-MON-RRRR'),'Confirm','06','No');Now i want to produce the following reports..
Period:      06-OCT-2012 to 09-OCT-2012
T2_RV_DATE     T1_NAME          T2_RV_NO     Revised_Column     Previous_Value     Revised_value
06-OCT-2012     Test 1          01          T2_F1          Probation     Confirm
                              T2_F2          05          06
09-OCT-2012     Test 2          01          T2_F3          No          YesI just achieve Revised_Column     Previous_Value     Revised_value for a particular name.
Here is my code
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F1' Revised_Column,PREVIOUS_VALUE,REVISED_VALUE
FROM(
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F1',
LAG(T2_F1) OVER (ORDER BY T2_RV_DATE) PREVIOUS_VALUE ,T2_F1 REVISED_VALUE
FROM TAB2,TAB1
WHERE TAB1.T1_ID=TAB2.T2_T1_ID
AND TAB1.T1_ID=:EMP_ID)
WHERE NVL(PREVIOUS_VALUE,'null')<>NVL(REVISED_VALUE,'null')
AND T2_RV_DATE BETWEEN :BEGIN_DATE AND :END_DATE
AND T2_RV_NO<>'00'
UNION ALL
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F2' Revised_Column,PREVIOUS_VALUE,REVISED_VALUE
FROM(
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F2',
LAG(T2_F2) OVER (ORDER BY T2_RV_DATE) PREVIOUS_VALUE ,T2_F2 REVISED_VALUE
FROM TAB2,TAB1
WHERE TAB1.T1_ID=TAB2.T2_T1_ID
AND TAB1.T1_ID=:EMP_ID)
WHERE NVL(PREVIOUS_VALUE,'null')<>NVL(REVISED_VALUE,'null')
AND T2_RV_DATE BETWEEN :BEGIN_DATE AND :END_DATE
AND T2_RV_NO<>'00'
UNION ALL
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F3' Revised_Column,PREVIOUS_VALUE,REVISED_VALUE
FROM(
SELECT T2_RV_NO,T2_RV_DATE,T1_NAME,'T2_F3',
LAG(T2_F3) OVER (ORDER BY T2_RV_DATE) PREVIOUS_VALUE ,T2_F3 REVISED_VALUE
FROM TAB2,TAB1
WHERE TAB1.T1_ID=TAB2.T2_T1_ID
AND TAB1.T1_ID=:EMP_ID)
WHERE NVL(PREVIOUS_VALUE,'null')<>NVL(REVISED_VALUE,'null')
AND T2_RV_DATE BETWEEN :BEGIN_DATE AND :END_DATE
AND T2_RV_NO<>'00'but it's not work for multiple employee id
Thanks in advance
Edited by: Asked to Learn on Oct 6, 2012 9:18 PM

Asked to Learn wrote:
thanks members. i get a solution of my own for my reporting purpos. Thanks..Well why don't you post your solution? Why not be helpful to others like yourself who might search the forum looking for answers? Don't just take, give back.
Cheers, APC

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[SQL] how can i get this result....??(accumulation distinct count)

[SQL] how can i get this result....??(accumulation distinct count)
Hi everybody,
pls tell me how can it possible to get result?
### sample data
date visitor
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10-01 A
10-01 B
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10-01 C
10-01 C
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10-02 C
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10-02 D
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10-04 A
10-04 A
10-04 F
result that i want...like this.
date date_unqiue_visitors acc_date_unique_visitors
10-01 3 3
10-02 3 4
10-03 3 5
10-04 2 5
date distinct visitors : count(distinct visitor)
but how can i get accumulation distinct visitor count???
Thanks to every body..

SQL> select dt,cnt,sum(cnt1) over(order by dt) cnt1
2 from(
3 select dt,count(distinct visitor) cnt,sum(flg) cnt1
4 from
5   (select dt,visitor,(select decode(count(*),0,1,0)
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8                           and visitor = t.visitor) flg
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10-01               3          3
10-02               3          4
10-03               3          5
10-04               2          5
Message was edited by:
        jeneesh
Wrong...

How can I perform this kind of range join query using DPL?

How can I perform this kind of range join query using DPL?
SELECT * from t where 1<=t.a<=2 and 3<=t.b<=5
In this pdf : http://www.oracle.com/technology/products/berkeley-db/pdf/performing%20queries%20in%20oracle%20berkeley%20db%20java%20edition.pdf,
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I'm sorry, I think I've misled you. I suggested that you perform two queries and then take the intersection of the results. You could do this, but the solution to your query is much simpler. I'll correct my previous message.
Your query is very simple to implement. You should perform the first part of query to get a cursor on the index for 'a' for the "1<=t.a<=2" part. Then simply iterate over that cursor, and process the entities where the "3<=t.b<=5" expression is true. You don't need a second index (on 'b') or another cursor.
This is called "filtering" because you're iterating through entities that you obtain from one index, and selecting some entities for processing and discarding others. The white paper you mentioned has an example of filtering in combination with the use of an index.
An alternative is to reverse the procedure above: use the index for 'b' to get a cursor for the "3<=t.b<=5" part of the query, then iterate and filter the results based on the "1<=t.a<=2" expression.
If you're concerned about efficiency, you can choose the index (i.e., choose which of these two alternatives to implement) based on which part of the query you believe will return the smallest number of results. The less entities read, the faster the query.
Contrary to what I said earlier, taking the intersection of two queries that are ANDed doesn't make sense -- filtering is the better solution. However, taking the union of two queries does make sense, when the queries are ORed. Sorry for the confusion.
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How i achive this data by writing exact query ?

Dear Exparts,
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10     02-AUG-2012
10     04-AUG-2012
10     01-SEP-2012
10     10-AUG-2012
11     04-AUG-2012
11     01-SEP-2012
11     01-AUG-2012
10     12-AUG-2012
10     15-JUL-2012I need data like
A                      B
10            10-AUG-2012
10            12-AUG-2012
10            01-SEP-2012
11            01-SEP-2012How we get this data ?
We have to count column B group by Column A. then devided the count_value by 2 and trunc it and base on the result out put will come. the data are the maximum data.
Like when we count group A result will be
A            B
10           3
11           1base on above result my desire outpul will come...
Here is the script
CREATE TABLE TB
    "A" VARCHAR2(20 BYTE),
    "B" DATE
Insert into TB (A,B) values ('10',to_date('02-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('10',to_date('04-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('10',to_date('01-SEP-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('10',to_date('10-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('11',to_date('04-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('11',to_date('01-SEP-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('11',to_date('01-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('10',to_date('12-AUG-2012','DD-MON-RRRR'));
Insert into TB (A,B) values ('10',to_date('15-JUL-2012','DD-MON-RRRR'));Thanks in advance...
Ask2Learn
Edited by: Asked to Learn on Sep 1, 2012 7:55 AM
Edited by: Asked to Learn on Sep 1, 2012 8:38 AM (CHANGE DATA TYPE) SORRY

this ?
with t as
select a,b,round(count(*) over(partition by a)/2) cnt,row_number() over(order by null) rn from tb
),t1 as
select a.*,row_number() over(order by null) rn from tb a
select t1.a,t1.b from t,t1 where t1.rn=t.rn and t1.b>t.cnt order by a;
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10                   4
10                   6
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Or
with t as
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ORAFLEX wrote:
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