How do i create a servlet ?

How do i create a servlet ?

Sun has pretty good tutorials. Try this:-
http://java.sun.com/docs/books/tutorial/servlets/index.html

Similar Messages

  • How to create a servlet  in PAR Application

    Hi Experts,
    I want to create a servlet in PAR application. This servlet should be capable of accessing the functions of other java files included in PAR Application. Servlet should be capable of accessing the functions say doContent(req, resp) of any class of PAR application.
    Is it possible to create Servlet in PAR application?
    I created one servlet but unable to declare its information in Deployment Descriptor.
    Because the deployment which is provide ie portalapp.xml doesnt allow us to write tags like <servlet-name>, <servlet-mapping>, <url-pattern> etc. These are necessary for declaration of servlet.
    So how can i write a complete working Servlet under PAR application?
    Please help and replies will be appreciated.

    Hi,
    Depending upon your usecase there are different ways to implement this logic.
    Check this for example (Read my answer in this post):
    https://forums.sdn.sap.com/thread.jspa?threadID=349151
    Also check these senarios:
    http://help.sap.com/saphelp_nw70/helpdata/en/42/9ddf20bb211d72e10000000a1553f6/frameset.htm
    http://help.sap.com/saphelp_nw70/helpdata/en/42/9ddcc9bb211d72e10000000a1553f6/frameset.htm
    Also the delegation may be interesting for you:
    http://help.sap.com/saphelp_nw70/helpdata/en/a0/44b742cafec96ae10000000a155106/frameset.htm
    Greetings,
    Praveen Gudapati

  • How do i create a single instance of a class inside a servlet ?

    how do i create a single instance of a class inside a servlet ?
    public void doGet(HttpServletRequest request,HttpServletResponseresponse) throws ServletException, IOException {
    // call a class here. this class should create only single instance, //though we know servlet are multithreaded. if, at any time 10 user comes //and access this servlet still there would one and only one instance of //that class.
    How do i make my class ? class is supposed to write some info to text file.

    i have a class MyClass. this class creates a thread.
    i just want to run MyClass only once in my servlet. i am afriad, if there are 10 users access this servlet ,then 10 Myclass instance wouldbe created. i just want to avoid this. i want to make only one instance of this class.
    How do i do ?
    they have this code in the link you provided.
    public class SingletonObject
      private SingletonObject()
        // no code req'd
      public static SingletonObject getSingletonObject()
        if (ref == null)
            // it's ok, we can call this constructor
            ref = new SingletonObject();          
        return ref;
      public Object clone()
         throws CloneNotSupportedException
        throw new CloneNotSupportedException();
        // that'll teach 'em
      private static SingletonObject ref;
    }i see, they are using clone !, i dont need this. do i ? shouldi delete that method ?
    where do i put my thread's run method in this snippet ?

  • How to create a servlet and write its details in DD in PAR Application

    Hi Experts,
    I want to create a servlet in PAR application. This servlet should be capable of accessing the functions of other java files included in PAR Application. Servlet should be capable of accessing the functions say doContent(req, resp) of any class of PAR application.
    Is it possible to create Servlet in PAR application?
    I created one servlet but unable to declare its information in Deployment Descriptor.
    Because the deployment which is provide ie portalapp.xml doesnt allow us to write tags like <servlet-name>, <servlet-mapping>, <url-pattern> etc. These are necessary for declaration of servlet.
    So how can i write a complete working Servlet under PAR application?
    Please help and replies will be appreciated.

    Hi Pankaj,
    I don't think it is possible to write Servlet in portal applications.
    I guess in Portal Application Projects we can develop portal components and portal services only.
    Thanks and regards,
    -Madhu

  • How to create the servlet as acontroller  and how to use it

    how to create the servlet as acontroller and how to use it

    >
    John
    Please update your forum profile with a real handle instead of "914824".
    When you have a problem you'll get a faster, more effective response by including as much relevant information as possible upfront. This should include:
    <li>Full APEX version
    <li>Full DB/version/edition/host OS
    <li>Web server architecture (EPG, OHS or APEX listener/host OS)
    <li>Browser(s) and version(s) used
    <li>Theme
    <li>Template(s)
    <li>Region/item type(s)
    With APEX we're also fortunate to have a great resource in apex.oracle.com where we can reproduce and share problems. Reproducing things there is the best way to troubleshoot most issues, especially those relating to layout and visual formatting. If you expect a detailed answer then it's appropriate for you to take on a significant part of the effort by getting as far as possible with an example of the problem on apex.oracle.com before asking for assistance with specific issues, which we can then see at first hand.
    I am going to have over 50 buttons in a page, Why? This would be a most unusual UI paradigm. I've never seen such a page, which suggests that whatever you want to do is normally done another way. Please explain the requirement in more detail.
    just wanted to know if its possible to do something like this in java.
    Java is not used in programming APEX UI behaviour. Java and JavaScript may share initial syllables, but they are not closely related.
    It's possible to achieve a great deal in JavaScript, but a clear definition of the requirements is necessary. Do you mean the buttons should be dynamically generated? If so, yes, this is possible in JavaScript. What would drive the process?
    Also, i would like to have dynamic action on it, for example, when the button is pressed, fill a string of text into other items(text field) within the page. Without more detail its not possible to make any specific suggestions. For example, I certainly would not want to create 50+ individual dynamic actions relating to different buttons.

  • How to create a Servlet Exception in jsp

    Greetings,
    I would like to know if someone knows how create a servlet exception in a JSP.
    Thx

    What for? new ServletException() - IIRC it's not abstract.

  • How Do I create & run a new servlet in the Weblogic 8.1 Workshop?

    Using the Workshop environment I added a new Empty Application, then a new Web Project,MyServletPrj,then I added a new Java Class and created a famous HelloWorldServlet class.
    Next I built application, started a WebLogic Server and depolyed application to the server.
    I checked through the Administrative console that HelloWorldServlet was deployed as a part of my project.
    How can I run my servlet?
    I tried to run it from the MS Explorer browser
    http://localhost:7001/MyServletPrj/servlet/HelloWorldServlet
    It doesn't work.
    What is the problem?
    Thanks,
    Irina

    hi katzirina ,
    To create or import the Servlet in workshop and to run it, we need to follow the
    steps in workshop as given below.
    1)Create the empty application
    2)Create the webproject under the application
    3)Right click on the webproject and choose the new -> java Class to write the
    servlet in IDE Or choose import option and import the servlet file
    4)Start the weblogic server
    5)Go to tools menu->choose weblogic server->choose weblogic builder
    6) In weblogic builder go to file menu->open your webproject
    then it shows servlet ,filter,security Constriant and tag libraries folders in a builder at left side
    7)Click on the servlet folder and click on the add button at right pane of the builder then you will give servlet name , servlet class name and url pattern.
    After giving the Urlpattern click on the add button which is right to the urlpatern text field.
    8)Click on ok button
    9)click on the save button
    then you will see the servlet mapping elements in web.xml file in workshop IDE what we given in builder.
    10)Exit from the weblogic builder
    11)Right click on the application and clean the application
    12)Build the application
    then it compiles the Servlets files automatically.
    You can see the those class files in .workshop folder which is located under applicaton folder.
    Note :go to the applicaton where it is stored.you should see these files manually because workshop ide shows the navigation from the webproject only. you can't see these files from workshop.
    13)Go to tools menu->weblogic server->weblogic console and test the application using the weblogic console.
    or Directly opent he internet explorer send a request for particular servlet by giving urlpattern.
    --- Anilkumar kari

  • How many instance created for 100 request in servlet?

    Let me know the answer

    STM12 wrote:
    Subject: how many instance created for 100 request in servlet?
    Let me know the answerInstances of what?

  • [Deploy Tool] How to create a  Servlet?

    Hello,
    i try to assemble and deploy a java servlet with the deploy tool in NW4, but to no avail. I managed to use jsps succesfully, but up to now i failed with servlets.
    When i try to access the WAS after deploying my exercise, i get:
    <b>404 Requested resource ( Ue160/servlet/Login.class ) not found.</b>
    The file Login.class, the directory /servlet and the URL mapping are defined in the file tab of 'J2EE Components'. As far as i can see the servlet container is unable to load the class file.
    The servlet name is in red, so something is wrong. But i can build the war-file without any error messages.
    Any hints?
    I can't use the developer studio, because it does not work with NW4.
    Message was edited by: Nico Manicone

    hi jeff
    1. I am not aware of any portal specific screen which can create this screen for you. However to create a servlet you will need to extend from the HttpServlet interface
    2. To direct the request to your servlet from your jsr 168 portlet you could use the PortletRequestDispatcher getNamedDispatcher(String s) declared on PortletContext
    Hope this helps
    anand

  • How to create a Servlet

    Hello All,
    I am trying to learn creating a servlet in oaf. Although I kind of understand the concept of a servlet....have doubts about where the servlet class file lives/resides? Does it matter where it resides....at least for now in the Jdeveloper environment?
    The way I understand it is:
    1) In the oaf page need to place the item in which the servlet result is displayed
    2) In the PR of the CO of the above page, need to find the above item
    2.1) set the source of the above item to be the servlet class while passing in the params into the set source call.
    2.2) Does it matter where the servlet class file resides? ie., can it live anywhere in the project??
    Pls. help me understand this concept.
    Practially in steps2,3 of the servlet wizard of the Jdeveloper what do these do?
    Step#2: URL Pattern
    Step#3: Parameters. Do I have to necessarily set up the params here in this step or can they be dynamically set when the serveletis invoked in the PR of the CO? If yes, could you pls. provide a sample code. If params can be done either way...which way is effective. Reason for asking is....in my other post, I mentioned that while trying to create a dynamic VO, it seemed to force me to explicitly set the sql statement instead of simply running the sql statement associate with the VO of the page (I am not sure why it is like that...but that worked)
    Thanks,
    Edited by: OAF_Monkey on Nov 16, 2012 4:11 PM

    The way I understand (after following several older posts) is
    1) When my destination page (say page2 renders), in the CO need to find the image item/bean (I am assuming bean and an item mean the same)
    2) After finding the item item/bean, need to set its source as "ReadImage" telling it to go get it from the web.xml while passing in the id
    for which it needs to find an image/blob in the db.
    At this point, if it finds the class "ReadImage" then it should get the
    2.1)db connection
    2.2)get the parameter passed in using
          String image_id = request.getParameter("s1");
         2.3)get the sql statement provided
    2.4)get the image/blob as an input stream and write to the output stream using the below
            InputStream in = null;
            in = rs.getBinaryStream("IMAGE");
         Below is my code in the PR of CO
          System.out.println("I am back in the IMG CO : primaykey val is "+ s1 );
    BP1-->  OAImageBean imageItem = (OAImageBean)webBean.findIndexedChildRecursive("SJImage");
          System.out.println("I am back in the IMG CO1 : after finding the image item" );
    BP2-->     if (imageItem !=null ){
          System.out.println("I am back in the IMG CO2 : before setting the source of the image item" );    
    BP3-->     imageItem.setSource("/OA_HTML/WEB-INF/ReadImage?id=" + s1);
          System.out.println("I am back in the IMG CO3 : after setting the source of the image item" + imageItem.getSource());
          }When I ran it in the debug mode (break points shown above BP1,2,3), I can see that the value is getting passed in ok with the 's1' at BP1 and BP2.
    However when it reaches BP3, if I expand all the nodes of the debug window, I can see that in the 'Statisfields of the CO', it shows
    "Failed to establish the database connection." for the "DBCONNECT_ERROR_MSG" node.
    In the "ReadImage" class file the code to get connection is shown below:
        public void init(ServletConfig config) throws ServletException {
            super.init(config);
            try
            Class.forName("oracle.jdbc.driver.OracleDriver");
            catch (Exception exception )
            exception.printStackTrace();
            throw new UnavailableException(exception.getMessage());
        }In the doPost method:
            if (conn == null)
            try
            WebAppsContext ctx = null;
            ctx = WebRequestUtil.validateContext(request, response);
            ctx = WebRequestUtil.createWebAppsContext(request, response);
            conn = ctx.getJDBCConnection();
            stmt = conn.createStatement();
            }Is this code correct to get a db connection? Pls. share thoughts/ideas/suggestions...
    Thanks,

  • How can i create datasource on apache server for ADF application?

    Hi All,
    i my use case i have created simple adf application using ADF BC and want to deploy on Apache server 6.x.
    So my question is that  how can i create Data Source i have goggling and find  two different way to do this.
    1. write following line of code on apache server conf/Context.xml file.
    <Resource name="jdbc/TestDB" auth="Container"
                  type="javax.sql.DataSource"
                   driverClassName="oracle.jdbc.OracleDriver"
                  url="jdbc:oracle:thin:@localhost:dst"
                  username="jagrandb" password="jagrantest" maxActive="20" maxIdle="10"
                  maxWait="-1"/>
    but when i have used this way i got following exception.
    org.apache.tomcat.dbcp.dbcp.PoolingDataSource$PoolGuardConnectionWrapper cannot be cast to oracle.jdbc.OracleConnection
    check link-
    https://forums.oracle.com/thread/2564233
    2. write following line of code apache conf/Server.xml file
    <GlobalNamingResources>
        <!-- Editable user database that can also be used by
             UserDatabaseRealm to authenticate users
        -->
        <Resource name="UserDatabase" auth="Container"
                  type="org.apache.catalina.UserDatabase"
                  description="User database that can be updated and saved"
                  factory="org.apache.catalina.users.MemoryUserDatabaseFactory"
                  pathname="conf/tomcat-users.xml" />
    <Resource name="jdbc/TestDB" auth="Container"
                  type="oracle.jdbc.pool.OracleDataSource"
                  description="User database that can be updated and saved"
                  driverClassName="oracle.jdbc.driver.OracleDriver"
                  factory="oracle.jdbc.pool.OracleDataSourceFactory"
                  url="jdbc:oracle:thin:@//172.31.43.207:1521:dst"
                  username="jagrandb" password="jagrantest" maxActive="20" maxIdle="10"
                  maxWait="-1"   />
      </GlobalNamingResources>
    and add this line in context.xml file inside <context> tag
    <ResourceLink global="jdbc/TestDB" name="jdbc/TestDB" type="oracle.jdbc.pool.OracleDataSource"/>
    but when i have run application i have got following error
    log-
    javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "java.sql.SQLException: invalid arguments in call"
      at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:298)
      at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
      at org.apache.jsp.test_jsp._jspx_meth_sql_005fquery_005f0(test_jsp.java:110)
      at org.apache.jsp.test_jsp._jspService(test_jsp.java:63)
      at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
      at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
      at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
      at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
      at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
      at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
      at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
      at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
      at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
      at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
      at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
      at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
      at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
      at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
      at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:857)
      at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:565)
      at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
      at java.lang.Thread.run(Thread.java:662)
    Aug 2, 2013 5:17:21 PM org.apache.catalina.core.StandardWrapperValve invoke
    SEVERE: Servlet.service() for servlet jsp threw exception
    javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "java.sql.SQLException: invalid arguments in call"
      at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:298)
      at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
      at org.apache.jsp.test_jsp._jspx_meth_sql_005fquery_005f0(test_jsp.java:110)
      at org.apache.jsp.test_jsp._jspService(test_jsp.java:63)
      at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
      at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
      at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
      at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
      at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
      at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
      at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
      at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
      at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
      at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
      at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
      at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
      at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
      at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
      at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:857)
      at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:565)
      at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
      at java.lang.Thread.run(Thread.java:662)
    so what is the solution how to create datasource on apche server which suitable for adf application?
    when i test data source using  following code used 1. way as i mentioned above  its running fine bt not for second.
    <%@ taglib uri="http://java.sun.com/jsp/jstl/sql" prefix="sql" %>
    <%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
    <sql:query var="rs" dataSource="jdbc/TestDB">
    select empname from pay_emphdr where empcd='JK1306'
    </sql:query>
    <html>
      <head>
        <title>DB Test</title>
      </head>
      <body>
      <h2>Results</h2>
    <c:forEach var="row" items="${rs.rows}">
        Foo ${row.empname}<br/>
    </c:forEach>
      </body>
    </html>
    please help me. it is very urgent.
    thanks in Advance
    Manish

    Hi Lindalnci
    i have already tried  this tutorial and in my post i have defined first way to do using this procedure.
    in that case i have got following exception as i have mentioned above
    org.apache.tomcat.dbcp.dbcp.PoolingDataSource$PoolGuardConnectionWrapper cannot be cast to oracle.jdbc.OracleConnection

  • How do I create a session?

    In order to use methods like getValidSessions() in the Session class of the SessionAPI for iPlanet Portal Server, I need a Session object. There is no obvious way to construct one based on the javadocs. I can get one from a SessionID object, but in order to create a SessionID object, I need a HTTP request or an encrypted string, i.e. SessionID( String sid ). How can I create a Session object, or how can I create a SessionID object (which will allow me to get a Session object)? Any help is much appreciated. NOTE: I'm building a plain Java utility to use the Portal Server API to retrieve session and profile information, and I'm not implementing it as a servlet.

    From com.iplanet.portalserver.providers.ProviderAdapater use the getSession() method whish returns com.iplanet.portalserver.session.Session object
    Then from Session class use the method getValidSessions()method

  • How can I run a servlet with Sun Java System Application Server PE 8?

    I've created a package with a TestServlet.class inside, used the deploytool to create a WAR and deployed this using the autodeploy folder.
    The filestructure has been generated and I find the TestServlet.class in
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    The context root is working fine, but I have no clue how I can run the servlet directly via the URL.
    I've tried many things like
    http://localhost:8080/testProject/TestServlet
    http://localhost:8080/testProject/servlet/TestServlet
    http://localhost:8080/testProject/servlet/[packagenamewithpoints]TestServlet
    http://localhost:8080/testProject/servlet/[packagenamewithslashes]TestServlet
    etc etc
    Can somebody tell me please how to write URLs to deployed servlets? Or send me an example url and xml descriptor files?
    Thanks a lot in advance!

    in web.xml use servlet mapping
    <servlet-mapping>
        <servlet-name>TestServlet</servlet-name>
        <url-pattern>/doit</url-pattern>
    </servlet-mapping>then use http://localhost:8080/testProject/doit

  • How can I test a Servlet?

    Hello!
    I want to test a small part of a servlet. That part connects to a database through a DataSource which is obtained in this manner:
    Context ctx = new InitialContext();
    ds = (DataSource) ctx.lookup(dsLookup);
    conn = ds.getConnection();Details about the servlet: runs on a WebSphere application server with db2 database. Runs on the local server in our intranet and I create a Java project in Eclipse with Create project from existing source: path to location on server.
    It's really annoying to start the browser, get to the page I'm interested, make the neccesary request and then see what happens in my code.
    What I've learned so far:
    I can't test it in a main function because I can't get the context. I tried setting the context's properties, still no go.
    I found this: http://www.ibm.com/developerworks/rational/library/08/0219_jadhav/
    but I got lost when it came to adding the resource reference to the project. How can one do that in Eclipse?
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    Thank you very much for your time,
    Iulia

    Thank you for your prompt reply. I still have some questions:
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    Do I have to have a WebSphere application server installed on my local machine?Where and how do I run the servlet?
    Thank you,
    Iulia

  • How to insert the new Servlet Api Class files?

    Hi,
    I need to know how do I add the Servlet Api Class to my java directory
    after i download it from the net? Thanks for your help in advance!

    niceguyme,
    If you downloaded the J2EE 1.3.1 API and installed it to (for example) c:\j2ee131, then what you need to add to your class path is:
    c:\j2ee131\lib\j2ee.jar
    I also add c:\j2ee131\lib\ejb10deployment.jar to the classpath, but it is not necessary.
    there are several ways to add these to your classpath. It depends on what Operating System you are using. On windows 98 type OS, you can edit the autoexec.bat and add these directly to your already existing classpath. Windows NT,2000, and XP: you can add them to the system environment variables classpath. Hopefully you know how to do this on your machine. What I like to do on the windows machine is create a batch file that will start it from within a command prompt. I do this because there are times when I need to compile my code using different versions of the Java api. I am enclosing an example of one for J2se1.4.1 and j2ee1.3.1.
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    @ECHO OFF
    ECHO JDK 1.4.1 and J2EE 1.3.1 are current versions
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    set HOLD_PATH = %PATH%
    set CLASSPATH=.
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    set CLASSPATH=%CLASSPATH%;e:\jdk14\lib\dt.jar
    set CLASSPATH=%CLASSPATH%;e:\jdk14\lib\tools.jar
    set CLASSPATH=%CLASSPATH%;e:\jdk14\lib\htmlconverter.jar
    rem **** J2EE STUFF ****
    set CLASSPATH=%CLASSPATH%;e:\j2ee131\lib\j2ee.jar
    set CLASSPATH=%CLASSPATH%;e:\j2ee131\lib\ejb10deployment.jar
    set CLASSPATH=%CLASSPATH%;%HOLD_CP%
    set PATH=e:\jdk14\bin
    set PATH=%PATH%;"C:\Program Files\TextPad 4"
    set PATH=%PATH%;c:\windows\command
    set PATH=%PATH%;%HOLD_PATH%I hope this helps.
    TJJ

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