How do you break the cycles in "connect by nocycles" query.

I looked at the documentation of the oracle hierarchical queries to see if there is a deterministic way of breaking the cycles.
http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/queries003.htm
I understand that plain connect by query fails if there are cycles in the data, this can be over come by using the nocycles clause. But how does oracle handle the cycles if it finds one, is there a deterministic way of breaking the cycles, or is random? If it is deterministic, Is there a sophisticated algorithm you use to break the cycles?
My sample query is as shown below:
SELECT ename "Employee", CONNECT_BY_ISCYCLE "Cycle",
LEVEL, SYS_CONNECT_BY_PATH(ename, ’/’) "Path"
FROM scott.emp
WHERE level <= 3 AND deptno = 10
START WITH ename = ’KING’
CONNECT BY NOCYCLE PRIOR empno = mgr AND LEVEL <= 4;
Thanks,
Paul

Hi, Paul,
849708 wrote:
Thanks for the very detailed explanation Frank.
It is interesting that the cycles are not broken at the time of the creation of the hierarchies, but at the time of the traversal.The relationship is only defined in the CONNECT BY clause of a query. When you create and populate tables, you don't indicate in any way that certain columns will be used in a CONNECT BY clause. You're free to use any columns you want when you write the query. You can use different columns and different relationships in different queries.
This leads me to one more question:
Lets say there are multiple routes from a given ancestor node to a decedent node, what would be the value of PATH pseudo column. Does it consider the shortest path or the longest path? If the two routes are of the same length? which would be used?The same node can appear more than once as a descendant of the same ancestor. All paths that satisfy the CONNECT BY clause (and the WHERE clause, if there is one) will be included. For example, the following query shows how Prince William is related to one of his ancestors, Anna Sophie (1700-1780):
SELECT     LEVEL
,     SYS_CONNECT_BY_PATH (name, ' \ ')     AS path
FROM     royal
WHERE     name     = 'Anna Sophie of Schwarzburg-Rudolstadt'
START WITH     name     = 'William of Wales'
CONNECT BY     id     IN (PRIOR mother_id, PRIOR father_id)
;The genealogy table I used showed 8 different line of descent, ranging from 10 to 12 generations:
LEVEL PATH
   11  \ William of Wales \ Charles, Prince of Wales \ Elizabeth II \ George
       VI \ George V \ Edward VII \ Victoria \ Victoria of Saxe-Coburg-Saalf
      eld \ Franz Frederick of Saxe-Coburg-Saalfeld \ Ernst Frederick of Sax
      e-Coburg-Saalfeld \ Anna Sophie of Schwarzburg-Rudolstadt
   12  \ William of Wales \ Charles, Prince of Wales \ Elizabeth II \ George
       VI \ George V \ Edward VII \ Albert of Saxe-Coburg and Gotha \ Louise
       of Saxe-Gotha-Altenburg \ Louise Charlotte of Mecklenburg \ Frederick
       Francis I of Mecklenburg \ Charlotte Sophie of Saxe-Coburg-Saalfeld \
       Anna Sophie of Schwarzburg-Rudolstadt
   11  \ William of Wales \ Charles, Prince of Wales \ Elizabeth II \ George
       VI \ George V \ Edward VII \ Albert of Saxe-Coburg and Gotha \ Ernest
       I, Duke of Saxe-Coburg and Gotha \ Franz Frederick of Saxe-Coburg-Saa
      lfeld \ Ernst Frederick of Saxe-Coburg-Saalfeld \ Anna Sophie of Schwa
      rzburg-Rudolstadt
   11  \ William of Wales \ Charles, Prince of Wales \ Elizabeth II \ George
       VI \ George V \ Alexandra of Denmark \ Louise of Hesse-Kassel \ Louis
      e Charlotte of Denmark \ Sophia Frederica of Mechlenburg-Schw. \ Charl
      otte Sophie of Saxe-Coburg-Saalfeld \ Anna Sophie of Schwarzburg-Rudol
      stadt
   11  \ William of Wales \ Charles, Prince of Wales \ Philip, Duke of Edinb
      urgh \ Alice of Battenberg \ Montbatten, Victoria \ Alice, Duchess of
      Hesse \ Victoria \ Victoria of Saxe-Coburg-Saalfeld \ Franz Frederick
      of Saxe-Coburg-Saalfeld \ Ernst Frederick of Saxe-Coburg-Saalfeld \ An
      na Sophie of Schwarzburg-Rudolstadt
   12  \ William of Wales \ Charles, Prince of Wales \ Philip, Duke of Edinb
      urgh \ Alice of Battenberg \ Montbatten, Victoria \ Alice, Duchess of
      Hesse \ Albert of Saxe-Coburg and Gotha \ Louise of Saxe-Gotha-Altenbu
      rg \ Louise Charlotte of Mecklenburg \ Frederick Francis I of Mecklenb
      urg \ Charlotte Sophie of Saxe-Coburg-Saalfeld \ Anna Sophie of Schwar
      zburg-Rudolstadt
   11  \ William of Wales \ Charles, Prince of Wales \ Philip, Duke of Edinb
      urgh \ Alice of Battenberg \ Montbatten, Victoria \ Alice, Duchess of
      Hesse \ Albert of Saxe-Coburg and Gotha \ Ernest I, Duke of Saxe-Cobur
      g and Gotha \ Franz Frederick of Saxe-Coburg-Saalfeld \ Ernst Frederic
      k of Saxe-Coburg-Saalfeld \ Anna Sophie of Schwarzburg-Rudolstadt
   10  \ William of Wales \ Charles, Prince of Wales \ Philip, Duke of Edinb
      urgh \ Andrew of Greece and Denmark \ George I of Greece \ Louise of H
      esse-Kassel \ Louise Charlotte of Denmark \ Sophia Frederica of Mechle
      nburg-Schw. \ Charlotte Sophie of Saxe-Coburg-Saalfeld \ Anna Sophie o
      f Schwarzburg-RudolstadtBy the way, SYS_CONNECT_BY_PATH is a function, not a pseudo-column. Pseudo-columns don't take arguments.
I could have tested all this myself, but currently I do not have access to the database. Is there a publicly available database (through ssh) which I can use in the mean time :)You can download Oracle Express Edition.
http://www.oracle.com/technetwork/database/express-edition/downloads/index.html
It's free if all you're using it for is learning.
You can also get a free workspace in an Oracle-hosted database at apex.oracle.com.
Edited by: Frank Kulash on Apr 4, 2011 6:51 PM

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