How I can change sequential number in RFUMSV00 (Spanish declaration of VAT)
Hi!
How I can change sequential number of Output /Input Tax in RFUMSV00 transaction (Spanish declaration of VAT)?
In input declaration I would like to have one sequential number for input tax and for output tax that appears on in. Is possible with standard Sap or I need a Z-transaction?
Thanks
Dear friend,
Please refer the below note.
SAP Note 849459
Reg
Madhu M
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SARAPPD_PIDM, SARAPPD_TERM_CODE_ENTRY, SARAPPD_APPL_NO 1 SARAPPD_SEQ_NO
We can have a person with one record another one with two or three, we just don't know, each record have a sequence number SARAPPD_SEQ_NO
this SARAPPD_PIDM = 2232040 with will a paramater pass to the function (SARAPPD_PIDM = p_pidm)
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with t as ( -- sample data
select 2232040 SARAPPD_PIDM, 200990 SARAPPD_TERM_CODE_ENTRY, 1 SARAPPD_APPL_NO, 1 SARAPPD_SEQ_NO, to_date('12/03/2008','mm/dd/yyyy') sARAPPD_APDC_DATE, 'S*' SARAPPD_APDC_CODE from dual union all
select 2232040 ,200990 ,1 ,2 ,to_date('12/08/2008','mm/dd/yyyy'), 'D1' from dual union all
select 2232040 ,200990 ,1 ,3 ,to_date('03/18/2009','mm/dd/yyyy'), 'S*' from dual union all
select 2232040 ,200990 ,1 ,4 ,to_date('03/29/2009','mm/dd/yyyy') ,'WL' from dual union all
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) -- end sample data
SELECT * FROM (
SELECT
A.SARAPPD_PIDM,
A.SARAPPD_APDC_CODE,
A.sarappd_apdc_date,
ROW_NUMBER() OVER (PARTITION BY SARAPPD_PIDM, SARAPPD_TERM_CODE_ENTRY ORDER BY SARAPPD_APDC_DATE
DESC) row_num
,lead (SARAPPD_APDC_DATE,1) over (ORDER BY SARAPPD_APDC_DATE) AS next_date
FROM t A
where
SARAPPD_PIDM = 2232040
AND sarappd_apdc_code IN ('SA', 'FA', 'S-', 'F-', 'RF', 'F*','AD', 'W-', 'R2', 'S*', 'HF', 'WL','HD', 'R1', 'HS', 'D2', 'W+')
where next_date >= to_date('3/27/2009','mm/dd/yyyy');Edited by: user648177 on May 1, 2009 8:52 AMThank you
I am getting this result
SARAPPD_PIDM SARAPPD_APDC_CODE SARAPPD_APDC_DATE SARADAP_ADMT_CODE ROW_NUM NEXT_DATE
2232040 S* 12/03/2008 16:30:45 D1 3 03/18/2009 08:58:06
2232040 S* 03/18/2009 08:58:06 D1 2 03/21/2009 13:53:23I only want to retrieve the one with the max date ( 03/18/2009 08:58:06)
I try to add the
and SARAPPD_SEQ_NO = (select max(b.SARAPPD_SEQ_NO)
from SARAPPD b
where SARAPPD_pidm = b.SARAPPD_pidm)
{code}
{code}
but it did not work
{code}
SELECT *
FROM (SELECT A.SARAPPD_PIDM,
A.SARAPPD_APDC_CODE,
A.sarappd_apdc_date,
saradap_admt_code,
ROW_NUMBER() OVER(PARTITION BY SARAPPD_PIDM, SARAPPD_TERM_CODE_ENTRY ORDER BY SARAPPD_APDC_DATE DESC) row_num,
lead(SARAPPD_APDC_DATE, 1) over(ORDER BY SARAPPD_APDC_DATE) AS next_date
FROM saturn.sarappd A, SARADAP
where SARAPPD_PIDM = 2232040
and SARADAP_PIDM = SARAPPD_PIDM
AND saradap_term_code_entry = SARAPPD_TERM_CODE_ENTRY
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-- and SARAPPD_SEQ_NO = (select max(b.SARAPPD_SEQ_NO)
-- from SARAPPD b
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AND sarappd_apdc_code IN
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Where next_date <= saturn_midd.utlq.f_get_adm_freeze_date(saradap_admt_code)
{code}
i now that if I add and row_num=2 it will work, but this is just an example I don't know the row_num of all the records
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How I can change this query, so I can display the name and scores in one r
How I can change this query, so I can add the ID from the table SPRIDEN
as of now is giving me what I want:
1,543 A05 24 A01 24 BAC 24 BAE 24 A02 20 BAM 20in one line but I would like to add the id and name that are stored in the table SPRIDEN
SELECT sortest_pidm,
max(decode(rn,1,sortest_tesc_code)) tesc_code1,
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max(decode(rn,2,sortest_tesc_code)) tesc_code2,
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max(decode(rn,4,sortest_tesc_code)) tesc_code4,
max(decode(rn,4,score)) score4,
max(decode(rn,5,sortest_tesc_code)) tesc_code5,
max(decode(rn,5,score)) score5,
max(decode(rn,6,sortest_tesc_code)) tesc_code6,
max(decode(rn,6,score)) score6
FROM (select sortest_pidm,
sortest_tesc_code,
score,
row_number() over (partition by sortest_pidm order by score desc) rn
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sortest_tesc_code,
max(sortest_test_score) score
from sortest,SPRIDEN
where
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AND sortest_tesc_code in ('A01','BAE','A02','BAM','A05','BAC')
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GROUP BY sortest_pidm, sortest_tesc_code))
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That depends on whether spriden_pidm is unique, and on what you want for results.
Whenever you have a problem, post a little sample data (CREATE TABLE and INSERT statements, relevamnt columns only) for all tables, and the results you want from that data.
If you can illustrate your problem using commonly available tables (such as those in the scott or hr schemas) then you don't have to post any sample data; just post the results you want.
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Always say which version of Oracle you're using.
It looks like you're doing something similiar to the following.
Using the emp and dept tables in the scott schema, produce one row of output per department showing the highest salary in each job, for a given set of jobs:
DEPTNO DNAME LOC JOB_1 SAL_1 JOB_2 SAL_2 JOB_3 SAL_3
20 RESEARCH DALLAS ANALYST 3000 MANAGER 2975 CLERK 1100
10 ACCOUNTING NEW YORK MANAGER 2450 CLERK 1300
30 SALES CHICAGO MANAGER 2850 CLERK 950On each row, the jobs are listed in order by the highest salary.
This seems to be analagous to what you're doing. The roles played by sortest_pidm, sortest_tesc_code and sortest_test_score in your sortest table are played by deptno, job and sal in the emp table. The roles played by spriden_pidm, id and name in your spriden table are played by deptno, dname and loc in the dept table.
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, MAX (DECODE (rn, 1, max_sal)) AS sal_1
, MAX (DECODE (rn, 2, job)) AS job_2
, MAX (DECODE (rn, 2, max_sal)) AS sal_2
, MAX (DECODE (rn, 3, job)) AS job_3
, MAX (DECODE (rn, 3, max_sal)) AS sal_3
FROM (
SELECT deptno
, job
, max_sal
, ROW_NUMBER () OVER ( PARTITION BY deptno
ORDER BY max_sal DESC
) AS rn
FROM (
SELECT e.deptno
, e.job
, MAX (e.sal) AS max_sal
FROM scott.emp e
, scott.dept d
WHERE e.deptno = d.deptno
AND e.job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY e.deptno
, e.job
GROUP BY deptno
;Since dept.deptno is unique, there will only be one dname and one loc for each deptno, so we can change the query by replacing "deptno" with "deptno, dname, loc" throughout the query (except in the join condition, of course):
SELECT deptno, dname, loc -- Changed
, MAX (DECODE (rn, 1, job)) AS job_1
, MAX (DECODE (rn, 1, max_sal)) AS sal_1
, MAX (DECODE (rn, 2, job)) AS job_2
, MAX (DECODE (rn, 2, max_sal)) AS sal_2
, MAX (DECODE (rn, 3, job)) AS job_3
, MAX (DECODE (rn, 3, max_sal)) AS sal_3
FROM (
SELECT deptno, dname, loc -- Changed
, job
, max_sal
, ROW_NUMBER () OVER ( PARTITION BY deptno -- , dname, loc -- Changed
ORDER BY max_sal DESC
) AS rn
FROM (
SELECT e.deptno, d.dname, d.loc -- Changed
, e.job
, MAX (e.sal) AS max_sal
FROM scott.emp e
, scott.dept d
WHERE e.deptno = d.deptno
AND e.job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY e.deptno, d.dname, d.loc -- Changed
, e.job
GROUP BY deptno, dname, loc -- Changed
;Actually, you can keep using just deptno in the analytic PARTITION BY clause. It might be a little more efficient to just use deptno, like I did above, but it won't change the results if you use all 3, if there is only 1 danme and 1 loc per deptno.
By the way, you don't need so many sub-queries. You're using the inner sub-query to compute the MAX, and the outer sub-query to compute rn. Analytic functions are computed after aggregate fucntions, so you can do both in the same sub-query like this:
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, MAX (DECODE (rn, 1, job)) AS job_1
, MAX (DECODE (rn, 1, max_sal)) AS sal_1
, MAX (DECODE (rn, 2, job)) AS job_2
, MAX (DECODE (rn, 2, max_sal)) AS sal_2
, MAX (DECODE (rn, 3, job)) AS job_3
, MAX (DECODE (rn, 3, max_sal)) AS sal_3
FROM (
SELECT e.deptno, d.dname, d.loc
, e.job
, MAX (e.sal) AS max_sal
, ROW_NUMBER () OVER ( PARTITION BY e.deptno
ORDER BY MAX (sal) DESC
) AS rn
FROM scott.emp e
, scott.dept d
WHERE e.deptno = d.deptno
AND e.job IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY e.deptno, d.dname, d.loc
, e.job
GROUP BY deptno, dname, loc
;This will work in Oracle 8.1 and up. In Oracle 11, however, it's better to use the SELECT ... PIVOT feature. -
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