How much char(1) occupies?
HI
Here is the simple issue with iam breaking head ;)
create table abc(a char(1));
(It supposed to occupy *1 byte* for every row(AM I CORRECT?).
DBMS_SPACE.UNUSED_SPACE shows
TOTAL_BLOCKS = 2
TOTAL_BYTES = 16384
UNUSED_BLOCKS = 1
Well,so far so good ( It has one block-8192 bytes free space and one block-8292 gone for segment header).
begin
for i in 1..1000 loop
insert into abc values(1);
end loop;
end;
SO,it should occupy *1000 bytes* totally (AM I CORRECT AGAIN?)
It means rows should have very well contained in that AVAILABLE FREEBLOCK with the size of *8192*.
BUT When i check unused space it shows
TOTAL_BLOCKS = 4
TOTAL_BYTES = 32768
UNUSED_BLOCKS = 0
Why it went for extending when it can contain *1000 bytes* in
*1 block*(8192).I don't think this is anything to do with init or pctincrease,nothing but SIMPLE CONCEPT of storage.
Pls answer me guys relevant to this confusion
Praveen Mohan
Sudeendra, the unused_blocks value of 1 is telling you that you have 1 block that has never been used so the block size worth of space is available for use. The entire 8192 bytes cannot be used to hold row data because block overhead will have to be removed from the total.
I do not know if the total block count includes the segment header block. You might want to compare the total blocks in dba_segments to the total dbms_space.unused_space returned to you. Notice that the total unused bytes is just the unused block count X the block size. The utility works at the block level.
The actual row size including direct overhead (row header and null indicators) should be the average row size from a analyze compute. I do not think the block row table entry is included as row size.
-- Mark D Powell --
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