How the try and catch blocks work?

Question

For the following section of code from the class QueueInheritanceTest...how the try and catch blocks work?
The Class...
public class QueueInheritance extends List {
public QueueInheritance() { super( "queue" ); }
public void enqueue( Object o )
{ insertAtBack( o ); }
public Object dequeue()
throws EmptyListException { return removeFromFront(); }
public boolean isEmpty() { return super.isEmpty(); }
public void print() { super.print(); }
Testing...
public class QueueInheritanceTest {
public static void main( String args[] ){
QueueInheritance objQueue = new QueueInheritance();
// Create objects to store in the queue
Boolean b = Boolean.TRUE;
Character c = new Character( '$' );
Integer i = new Integer( 34567 );
String s = "hello";
// Use the enqueue method
objQueue.enqueue( b );
objQueue.enqueue( c );
objQueue.enqueue( i );
objQueue.enqueue( s );
objQueue.print();
// Use the dequeue method
Object removedObj = null;
try { while ( true ) {
removedObj = objQueue.dequeue();
System.out.println(removedObj.toString()+" dequeued" );
objQueue.print();
catch ( EmptyListException e ) {
System.err.println( "\n" + e.toString() );

Answer 1

If you want a basic introduction to try/catch blocks, read any introductory text or the tutorials on this site.
Here are some:
Sun's basic Java tutorial
Sun's New To Java Center.
JavaRanch. To quote the tagline on their homepage: "a friendly place for Java greenhorns."
In terms of this particular case, it looks like the code is using an exception being thrown to get out of a loop. IMHO that's bad design -- exceptions should be used for exceptional circumstances, and if you use it to get out of a loop, then you're certain it's going to happen, and that means that it's not exceptional.
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