How to apply a new font for missing glyphs in another font?

The situation:
For an article, I want to use Font1, but some of the glyphs are missing in it, and are highlighted with pink boxes. Font2 have much more glyphs than Font1. I can apply Font2 manually for each of the missing glyphs, but it is tedious.
Question:
Is there a way for InDesign to do such substitution automatically? I.e., apply a default font, which can be specified by user, for all the missing glyphs.
If not, how to search/find those missing glyphs with GREP or script? Since InDesign can identify the missing glyphs and marked them with pink boxes, it seems easily (not to identify the unicode ranges which seems not very easy) to find them using GREP, but I failed to find it.
Any one know how to do this? Thanks.

calvyan wrote:
Is there a way for InDesign to do such substitution automatically? I.e., apply a default font, which can be specified by user, for all the missing glyphs.
No. Alas, I might add. There is some sort of auto-catch, specific for Symbol symbols, but no-one knows how it works and you cannot manipulate it yourself.
If not, how to search/find those missing glyphs with GREP or script?
Not specifically, i.e., you cannot search for "any missing glyph". Add a GREP style which changes just the font (make sure it doesn't set the font style as well, or else your Bolds or Italics might disappear). Create a new Preflight profile that checks just for missing glyphs, so you won't miss any.
None of this can be automated though.
.. it seems easily (not to identify the unicode ranges which seems not very easy) to find them using GREP, but I failed to find it.
InDesign's GREP flavor doesn't allow named Unicode blocks (http://www.regular-expressions.info/unicode.html), but I have successfully used character ranges to automatically set the font for Chinese, for example.

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 , h.HrchyId
 , h.Name
 , h.HrchyId - lag( h.HrchyId ) over ( order by h.Hrchyid_sq ) - 1 MissingHrchy
 from x_hierarchy h
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, 'No ' || r.Role Role
, 'Null' Name
, m.Hrchyid_sq Hrchyid_sq
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 from dual
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, x_roles r
where 1=1
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union
select h.HrchyId
, h.Role
, h.Name
, h.Hrchyid_sq
from x_hierarchy h
order by 4
, 1
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 2 Supervisor Mary 2
 3 Clerk Henry 3
 3 Clerk Tyson 4
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 3 Clerk Murry 6
 1 Manager Kirk 7
 2 No Supervisor Null 8
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Query x_missing_hrchy determines for each Hrchyid_sq how many managers are missing:
with ..
select *
from x_missing_hrchy
HRCHYID_SQ HRCHYID NAME MISSINGHRCHY
 6 3 Murry 1
 8 4 Tony 2Murry misses one supervisor and Tony misses two supervisors.
For each missing supervisor I need to create a row. For that I use the connect by clause:
with ..
select m.Hrchyid_sq
, m.HrchyId
, m.Name
, g.HrchyGen
, m.HrchyId - g.HrchyGen MissingHrcyId
from x_missing_hrchy m
, ( select level HrchyGen
 from dual
 , ( select max( MissingHrchy ) MissingHrchy from x_missing_hrchy ) m
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, 5
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 6 3 Murry 1 2
 8 4 Tony 2 2
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select m.HrchyId - g.HrchyGen HrchyId
, 'No ' || r.Role Role
, 'Null' Name
, m.Hrchyid_sq Hrchyid_sq
from x_missing_hrchy m
, ( select level HrchyGen
 from dual
 , ( select max( MissingHrchy ) MissingHrchy from x_missing_hrchy ) m
 connect by level <= m.MissingHrchy
 ) g
, x_roles r
where 1=1
and g.HrchyGen <= m.MissingHrchy
and r.HrchyId = m.HrchyId - g.HrchyGen
union
select h.HrchyId
, h.Role
, h.Name
, h.Hrchyid_sq
from x_hierarchy h
order by 4
, 1
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