How to check special characters in java code using Java.util.regex package

String guid="first_Name;Last_Name";
Pattern p5 = Pattern.compile("\\p{Punct}");
Matcher m5 =p5.matcher(guid);
boolean test=m5.matches();
I want to find out the weather any speacial characters are there in the String guid using regex.
but above code is always returning false. pls suggest.

Pattern.compile ("[^\\w]");The above will match any non [a-zA-Z0-9_] character.
Or you could do
Pattern.compile("[^\\s^\\w]");This should match anything that is not a valid charcter and is not whitespace.

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Removes any characters from
@myString that do not meet the
provided criteria.
CREATE FUNCTION dbo.GetCharacters(@myString varchar(500), @validChars varchar(100))
RETURNS varchar(500) AS
BEGIN
While @myString like '%[^' + @validChars + ']%'
Select @myString = replace(@myString,substring(@myString,patindex('%[^' + @validChars + ']%',@myString),1),'')
Return @myString
END
Go
Declare @testStr varchar(1000),
@i int
Set @i = 1
while @i < 255
Select
@TestStr = isnull(@TestStr,'') + isnull(char(@i),''),
@i = @i + 1
Select @TestStr
Select dbo.GetCharacters(@TestStr,'a-z')
Select dbo.GetCharacters(@TestStr,'0-9')
Select dbo.GetCharacters(@TestStr,'0-9a-z')
Select dbo.GetCharacters(@TestStr,'02468bferlki')
perfect soluction

How to check special characters in java code using Java.util.regex package

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