How to convert a voltage output from a Rogowski coil to its original current waveform ?

I need to measure current using a Rogowski coil. The voltage output of the coil across a 1k load resistance is directly proportional to the "rate of change of current" flowing through the conductor passing through the center of this coil. So the output is actually :
y = M * di/dt ; where M is the mutual inductance of the coil.
I need the output waveform as i(t). This means an integration is required.
Can some one help me out with this ?
I am also told that in the frequency domain this integration means a -20dB/decade attenuation and a constant -90 degree phase shift. This is some thing I cannot work out with Labview since I am new to it. I tried a mathematical integratio
n. But this also does not work.
Could someone help me out with this ?
Regards
PC

To come up with the most straight forward approach, forget for a moment that you are using LV and think about how you would calculate the answer using paper and pencil.
You have an input value that (using the formula you gave) is related to the rate change for a parameter (in this case the current). Given that rate of change, how do you calculate the absolute value of the parameter at any given point in time? It's really just a math problem...
Once you have it worked out on paper, just do the same calculations in LV.
Mike...
Certified Professional Instructor
Certified LabVIEW Architect
LabVIEW Champion
"... after all, He's not a tame lion..."
Be thinking ahead and mark your dance card for NI Week 2015 now: TS 6139 - Object Oriented First Steps

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