How to convert column to row in 10g

Hi ,
i need to convert the column to row in my DB 10g , i cant use the Decode method because i have about 2000 items in MDN column
this is sample of my date ,
MDN             Date
5C4CA98EABA3     20111205235240
5C4CA98EABA3     20110925121833
5C4CA98EABB0     20111025103700
5C4CA98EABB0     20111124103700
5C4CA98EABB5     20111030175717
5C4CA98EABB8     20110925142653
5C4CA98EABB8     20111126175853i need the result to be ,
MDN             Date
5C4CA98EABA3     20111205235240 ; 20110925121833
5C4CA98EABB0     20111025103700 ; 20111124103700
5C4CA98EABB5    20111030175717
5C4CA98EABB8   20110925142653 ; 20111126175853any help please ,
Edited by: 876602 on 15/12/2011 01:33 ص

Note the name of this forum is "SQL Developer *(Not for general SQL/PLSQL questions)*", so only for issues with the SQL Developer tool. Please post these questions under the dedicated {forum:id=75} forum.
Regards,
K.

Similar Messages

How to convert column to row in 10g and calculate the count

876602 wrote:
Hi ,
i need to convert the column to row in my DB 10g , i cant use the Decode method because i have about 2000 items in MDN column
this is sample of my date ,
MDN             Date
5C4CA98EABA3     20111205235240
5C4CA98EABA3     20110925121833
5C4CA98EABB0     20111025103700
5C4CA98EABB0     20111124103700
5C4CA98EABB5     20111030175717
5C4CA98EABB8     20110925142653
5C4CA98EABB8     20111126175853i need the result to be ,
MDN             Date                                   count
5C4CA98EABA3     20111205235240 ; 20110925121833    2
5C4CA98EABB0     20111025103700 ; 20111124103700    2
5C4CA98EABB5    20111030175717                      1
5C4CA98EABB8   20110925142653 ; 20111126175853       2any help please ,
Edited by: 876602 on 15/12/2011 01:33 ص

SQL> with t as
2 (
3 select '5C4CA98EABA3' MDN ,'20111205235240' Dte from dual
4 union all
5 select '5C4CA98EABA3','20110925121833' from dual
6 union all
7 select '5C4CA98EABB0','20111025103700' from dual
8 union all
9 select '5C4CA98EABB0','20111124103700' from dual
10 union all
11 select '5C4CA98EABB5','20111030175717' from dual
12 union all
13 select '5C4CA98EABB8','20110925142653' from dual
14 union all
15 select '5C4CA98EABB8','20111126175853' from dual
16 )
17 select mdn,ltrim(sys_connect_by_path(dte,';'),';') s,rw as "count"
18 from
19 (
20 select mdn,dte,row_number() over(partition by mdn order by mdn) rw
21 from t
22 )
23 where connect_by_isleaf = 1
24 start with rw = 1
25 connect by prior rw = rw-1
26 and prior mdn = mdn
27 ;
MDN          S                                                                                     count
5C4CA98EABA3 20111205235240;20110925121833                                                             2
5C4CA98EABB0 20111025103700;20111124103700                                                             2
5C4CA98EABB5 20111030175717                                                                            1
5C4CA98EABB8 20110925142653;20111126175853                                                             2

How to convert columns into rows using transpose function

Hi
anybody tell me how to convert columns values into rows using transpose function.

Since BluShadow went to all the trouble to put it together, someone should use it.
See the post titled How do I convert rows to columns? here SQL and PL/SQL FAQ
John

How to convert columns to rows

I have 70 columns and I need to convert them into rows. Please help!
Currently, it is showing as listed below
message 1 message 2 message 3 message 4 message 5 .......... message 70
system 1 20 10 40 60 100
system 2 40 30 50 80 110
system 3 60 60 70 90 120
The desire output
system 1 system 2 system 3
message 1 20 40 60
message 2 10 30 60
message 3 40 50 70
message 70

Something like...
SQL> ed
Wrote file afiedt.buf
1 select decode(rn,1,'Empno :'||empno
2                  ,2,'Ename ('||empno||') :'||ename
3                  ,3,'Job ('||empno||') :'||job
4               ) as col
5 from emp
6       cross join (select rownum rn from dual connect by rownum <= 3)
7* order by empno, rn
SQL> /
COL
Empno :7369
Ename (7369) :SMITH
Job (7369) :CLERK
Empno :7499
Ename (7499) :ALLEN
Job (7499) :SALESMAN
Empno :7521
Ename (7521) :WARD
Job (7521) :SALESMAN
Empno :7566
Ename (7566) :JONES
Job (7566) :MANAGER
Empno :7654
Ename (7654) :MARTIN
Job (7654) :SALESMAN
Empno :7698
Ename (7698) :BLAKE
Job (7698) :MANAGER
Empno :7782
Ename (7782) :CLARK
Job (7782) :MANAGER
Empno :7788
Ename (7788) :SCOTT
Job (7788) :ANALYST
Empno :7839
Ename (7839) :KING
Job (7839) :PRESIDENT
Empno :7844
Ename (7844) :TURNER
Job (7844) :SALESMAN
Empno :7876
Ename (7876) :ADAMS
Job (7876) :CLERK
Empno :7900
Ename (7900) :JAMES
Job (7900) :CLERK
Empno :7902
Ename (7902) :FORD
Job (7902) :ANALYST
Empno :7934
Ename (7934) :MILLER
Job (7934) :CLERK
42 rows selected.

How to convert columns into rows

present result
Mat_num        comp_code   disc          amount
800000     SG01      SAPLF005                    0.00
800000     SG01      SAPLF005               31,500.00
6300001    SPM      SAPLF005                    0.00
6300001    SPM      SAPLF005              108,888.00
APS100     SMTP      SAPLF005                    0.00
APS100     SMTP      SAPLF005                    0.00
required format
Mat_num       disc             SG01          SMTP          SPM
800000   SAPLF005   31,500.00           0.00          0.00
800000   SAPLF005        0.00           0.00          0.00
6300001 SAPLF005        0.00         0.00     108,888.00
6300001 SAPLF005        0.00         0.00           0.00
APS100   SAPLF005        0.00         0.00           0.00
APS100   SAPLF005        0.00         0.00           0.00
Plain Text Attachment [ Scan and Save to Computer ]
REPORT Z_CALC2                                 .
TABLES : KNC1.
TYPE-POOLS: SLIS.
type-pools : abap.
field-symbols: <dyn_table> type standard table,
               <dyn_wa>,
               <dyn_field>.
data: dy_table type ref to data,
      dy_line type ref to data,
      xfc type lvc_s_fcat,
      ifc type lvc_t_fcat.
DATA: BEGIN OF ITAB OCCURS 0,
          KUNNR LIKE KNC1-KUNNR,
          BUKRS LIKE KNC1-BUKRS,
          GJAHR LIKE KNC1-GJAHR,
          USNAM LIKE KNC1-USNAM,
          UMSAV LIKE KNC1-UMSAV,
      END OF ITAB.
*Result table
TYPES BEGIN OF RES_ITAB.
* RES_ITAB(10) TYPE C DEFAULE 'ZRES_ITAB'.
INCLUDE STRUCTURE ZRES_ITAB.
TYPES END OF RES_ITAB.
SELECT-OPTIONS : CCODE FOR KNC1-BUKRS DEFAULT 'SG01' TO 'SPM '.
DATA : BEGIN OF COMP_ITAB OCCURS 0,
          BUKRS LIKE KNC1-BUKRS,
       END OF COMP_ITAB.
DATA: COLS TYPE I,
      gap(10) TYPE c,
      Company_title type string .
start-of-selection.
perform get_NUM_COLS.
perform get_structure.
perform create_dynamic_itab.
perform get_data.
* perform write_out.
FORM GET_NUM_COLS.
SELECT KUNNR BUKRS GJAHR USNAM UMSAV INTO TABLE ITAB FROM KNC1 WHERE
BUKRS IN CCODE.
CLEAR ITAB.
*CLEAR RES_ITAB.
LOOP AT ITAB .
     COMP_ITAB-BUKRS = ITAB-BUKRS.
     APPEND COMP_ITAB.
CLEAR COMP_ITAB.
ENDLOOP.
SORT COMP_ITAB BY BUKRS.
DELETE ADJACENT DUPLICATES FROM COMP_ITAB.
DESCRIBE TABLE COMP_ITAB LINES COLS.
ENDFORM.
*Get table structure
form get_structure.
data : idetails type abap_compdescr_tab,
       xdetails type abap_compdescr.
data : ref_table_des type ref to cl_abap_structdescr.
data fld_pos type i value 1.
* Get the structure of the table.
ref_table_des ?=
              cl_abap_typedescr=>describe_by_name( 'ZRES_ITAB' ).
idetails[] = ref_table_des->components[].
loop at idetails into xdetails.
    clear xfc.
    XFC-COL_POS = fld_pos.
    xfc-fieldname = xdetails-name .
    xfc-datatype = xdetails-type_kind.
    xfc-inttype = xdetails-type_kind.
    xfc-intlen = xdetails-length.
    xfc-decimals = xdetails-decimals.
    append xfc to ifc.
    fld_pos = fld_pos + 1.
endloop.
DO COLS TIMES.
    clear xfc.
    READ TABLE COMP_ITAB INDEX SY-INDEX.
    XFC-COL_POS = fld_pos.
    xfc-fieldname = COMP_ITAB-BUKRS .
    xfc-datatype = 'F'.
*    xfc-inttype = 'F'.   'details-type_kind.
    xfc-intlen = 14.
*    xfc-decimals = xdetails-decimals.
    append xfc to ifc.
    fld_pos = fld_pos + 1.
ENDDO.
clear xfc.
    XFC-COL_POS = fld_pos.
    xfc-fieldname = 'RECORD_TOTAL' .
    xfc-datatype = 'F'.
    xfc-inttype = 'F'.
    xfc-intlen = 14.
*    xfc-decimals = xdetails-decimals.
    append xfc to ifc.
endform.
form create_dynamic_itab.
* Create dynamic internal table and assign to FS
call method cl_alv_table_create=>create_dynamic_table
               exporting
                  it_fieldcatalog = ifc
               importing
                  ep_table        = dy_table.
assign dy_table->* to <dyn_table>.
* Create dynamic work area and assign to FS
create data dy_line like line of <dyn_table>.
assign dy_line->* to <dyn_wa>.
endform.
form get_data.
LOOP AT ITAB.
        <DYN_WA>-KUNNR = ITAB-KUNNR.
        <DYN_WA>-USNAM = ITAB-USNAM.
        DO COLS TIMES.
           IF <DYN_WA>
DESCRIBE TABLE <dyn_table>.
*WRITE:/ SY-TFILL.
* Select Data from table.
* <dyn_table> = ITAB[].
*LOOP AT ITAB.
*    RES-KUNNR = ITAB-KUNNR.
*    RES-USNAM = ITAB-USNAM.
*    CASE ITAB-GJAHR.
*        WHEN 2005.
*            RES-UMSAV1 = ITAB-UMSAV.
*        WHEN 2006.
*            RES-UMSAV2 = ITAB-UMSAV.
*        WHEN 2007.
*            RES-UMSAV3 = ITAB-UMSAV.
*    ENDCASE.
*    RES-TOTAL = RES-UMSAV1 + RES-UMSAV2 + RES-UMSAV3 .
* APPEND RES.
*ENDLOOP.
endform.
form write_out.
loop at <dyn_table> into <dyn_wa>.
    do.
      assign component sy-index
         of structure <dyn_wa> to <dyn_field>.
      if sy-subrc <> 0.
        exit.
      endif.
      if sy-index = 1.
        write:/ <dyn_field>.
      else.
        write: <dyn_field>.
      endif.
    enddo.
endloop.
endform.
Edited by: Alvaro Tejada Galindo on Feb 28, 2008 11:56 AM

solved myself

Convert columns to row equivalent to stragg function in oracle sql

Hi,
Sorry i forgot my Oracle version :
SQL> select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bi
PL/SQL Release 10.2.0.3.0 - Production
CORE    10.2.0.3.0      Production
TNS for 64-bit Windows: Version 10.2.0.3.0 - Production
NLSRTL Version 10.2.0.3.0 - ProductionI searched in google but i didn't found the solution.
I looking for a function in discoverer equivalent to stragg sql function.
Note : stragg function convert columns to rows.
Thanks
SELECT   deptno, stragg ('-' || ename)
    FROM emp_test
GROUP BY deptno;
    DEPTNO STRAGG_STR
        10 -CLARK-KING-MILLER
        20 -SMITH-FORD-ADAMS-SCOTT-JONES
        30 -ALLEN-BLAKE-MARTIN-TURNER-JAMES-WARD
3 rows selected.Edited by: Salim Chelabi on 2010-01-29 08:32

Hi again,
*1- I created my function in my schema.*
CREATE OR REPLACE TYPE t_string_agg AS OBJECT
g_string VARCHAR2(32767),
STATIC FUNCTION ODCIAggregateInitialize(sctx IN OUT t_string_agg)
    RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateIterate(self   IN OUT t_string_agg,
                                       value IN      VARCHAR2 )
     RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateTerminate(self         IN   t_string_agg,
                                         returnValue OUT VARCHAR2,
                                         flags        IN   NUMBER)
    RETURN NUMBER,
MEMBER FUNCTION ODCIAggregateMerge(self IN OUT t_string_agg,
                                     ctx2 IN      t_string_agg)
    RETURN NUMBER
SHOW ERRORS
CREATE OR REPLACE TYPE BODY t_string_agg IS
STATIC FUNCTION ODCIAggregateInitialize(sctx IN OUT t_string_agg)
    RETURN NUMBER IS
BEGIN
    sctx := t_string_agg(NULL);
    RETURN ODCIConst.Success;
END;
MEMBER FUNCTION ODCIAggregateIterate(self   IN OUT t_string_agg,
                                       value IN      VARCHAR2 )
    RETURN NUMBER IS
BEGIN
    SELF.g_string := self.g_string || ',' || value;
    RETURN ODCIConst.Success;
END;
MEMBER FUNCTION ODCIAggregateTerminate(self         IN   t_string_agg,
                                         returnValue OUT VARCHAR2,
                                         flags        IN   NUMBER)
    RETURN NUMBER IS
BEGIN
    returnValue := RTRIM(LTRIM(SELF.g_string, ','), ',');
    RETURN ODCIConst.Success;
END;
MEMBER FUNCTION ODCIAggregateMerge(self IN OUT t_string_agg,
                                     ctx2 IN      t_string_agg)
    RETURN NUMBER IS
BEGIN
    SELF.g_string := SELF.g_string || ',' || ctx2.g_string;
    RETURN ODCIConst.Success;
END;
END;
SHOW ERRORS
CREATE OR REPLACE FUNCTION string_agg (p_input VARCHAR2)
RETURN VARCHAR2
PARALLEL_ENABLE AGGREGATE USING t_string_agg;
SHOW ERRORS
*2- I ran my query in my schema with sqlplus.*
SELECT deptno,ename,sal, string_agg(ename)over(partition by deptno) AS employees
FROM   emp_test
order by deptno;
    DEPTNO ENAME             SAL EMPLOYEES
        10 CLARK            2450 CLARK,KING,MILLER
        10 KING             5000 CLARK,KING,MILLER
        10 MILLER           1300 CLARK,KING,MILLER
        20 JONES            2975 JONES,FORD,ADAMS,SMITH,SCOTT
        20 FORD             3000 JONES,FORD,ADAMS,SMITH,SCOTT
        20 ADAMS            1100 JONES,FORD,ADAMS,SMITH,SCOTT
        20 SMITH             800 JONES,FORD,ADAMS,SMITH,SCOTT
        20 SCOTT            3000 JONES,FORD,ADAMS,SMITH,SCOTT
        30 WARD             1250 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
        30 TURNER           1500 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
        30 ALLEN            1600 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
        30 JAMES             950 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
        30 BLAKE            2850 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
        30 MARTIN           1250 WARD,TURNER,ALLEN,JAMES,BLAKE,MARTIN
14 rows selected.
*3- I import this function in discoverer administration*
4- My problem :When i use the function string_agg(ename)over(partition by deptno) in discover deskto i got the error you can't use over in this place.
Any ideas.
Thank in advance.
Regards Salim.

To convert columns into row

Hi All,
I need help in building view which actually can show columns data as row.
e.g.
row is as follows
Name Age Salary
ABC 25 10000
BBC 28 12000
The above tables data I want to get as
Name ABC BBC
Age 25 28
Salary 10000 12000
Thanks in advance.

Even if I don't really understand such requirement, I wrote some times ago such function to play around that :
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field1 field2
field1 field3
field1 field4
field1 field5
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Something like this ?
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when 2 then field3
when 3 then field4
when 4 then field5
end field
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Hi,
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2007 -109712.40 6909.15 4758.72 56.88
2007 -13411.32 19132.9 -5585.07 4362.64
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GLYear GLMonth GLAmount
2007 February -109712.40
2007 March 6909.15
2007 April 56.88
My new table has 3 columns, GLYear,GLMonth,GLAmount.
Can someone please help me with the select statement on how to do this, i can work with the inserts.
Thanks.

I want you to check these form tread they have the same discussion as you. They will definitely solve your problem
http://blog.jontav.com/post/8344518585/convert-rows-to-columns-columns-to-rows-in-sql-server
http://dba.stackexchange.com/questions/19057/convert-rows-to-columns-using-pivot-in-sql-server-when-columns-are-string-data
http://stackoverflow.com/questions/18612326/how-to-convert-multiple-row-data-into-column-data-in-sql-server
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Hello,
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I have a table which is having multiple columns as follows:
Insert into table_1 (X,Y,Z,A,B,C,D,E,F,G,H,I) values (0,0,2,0,0,1,3,0,0,0,0,0);I want to convert the result into a two column, multiple rows i.e., I want the result as follows:
Col1 Col2
X      0
Y     0
Z      2
A     0
B     0
C     1
D     3
E     0
F     0
G     0
H     0
I      0Please anybody help me in writing the query for this..

Is this what you are expecting:
SQL> WITH T AS
2 (
3 SELECT 0 X, 0 Y, 2 Z, 0 A, 0 B, 1 C, 3 D, 0 E, 0 F, 0 G, 0 H, 0 I FROM DUAL
4 )
5 SELECT 'X' col1, X col2 FROM T
6 UNION ALL
7 SELECT 'Y' col1, Y col2 FROM T
8 UNION ALL
9 SELECT 'Z' col1, Z col2 FROM T
10 UNION ALL
11 SELECT 'A' col1, A col2 FROM T
12 UNION ALL
13 SELECT 'B' col1, B col2 FROM T
14 UNION ALL
15 SELECT 'C' col1, C col2 FROM T
16 UNION ALL
17 SELECT 'D' col1, D col2 FROM T
18 UNION ALL
19 SELECT 'E' col1, E col2 FROM T
20 UNION ALL
21 SELECT 'F' col1, F col2 FROM T
22 UNION ALL
23 SELECT 'G' col1, G col2 FROM T
24 UNION ALL
25 SELECT 'H' col1, H col2 FROM T
26 UNION ALL
27 SELECT 'I' col1, I col2 FROM T
28 /
C       COL2
X          0
Y          0
Z          2
A          0
B          0
C          1
D          3
E          0
F          0
G          0
H          0
C       COL2
I          0
12 rows selected.

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I have a web application with a query in it. Now I would like to know how I could make the column and row headers of this webquery in bold font? I havent found any properties in any web item to make this possible. It looks like the only way to do this is CSS, but i dont have any experience with style sheets.
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Thanks in advance.
Rgds,
Richard

Tried this for fun using JavaScript. It appears to work, but is pretty much a hack, and I didn't test it thoroughly.
Place this in a function that is called during onload of the page:
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          eleid='ANALYSIS_interactive_mc'+ct+'_tv';
          if (document.getElementById(eleid)) {
               if(document.getElementById(eleid).parentNode.className=='urLayoutPadless') {
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Hi,
I have 6 columns and 4 rows and i want to convert it into 6 rows and 4 columns and want to display in table control.
plz help me in this ....

Hi Kinjal,
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If my understanding is correct, check the bleow logic:
loop at itab1.
case sy-tabix.
when 1.
   itab2-c1 = itab1-c1.
   append itab2.
   itab2-c1 = itab1-c2.
   append itab2.
   itab2-c1 = itab1-c3.
   append itab2.
   itab2-c1 = itab1-c4.
   append itab2.
   itab2-c1 = itab1-c5.
   append itab2.
   itab2-c1 = itab1-c6.
   append itab2.
when 2.
itab2-c2 = itab1-c1.
modify itab2 transporting c2 index 1.
itab2-c2 = itab1-c2.
modify itab2 transporting c2 index 2.
itab2-c2 = itab1-c3.
modify itab2 transporting c2 index 3.
itab2-c2 = itab1-c4.
modify itab2 transporting c2 index 4.
itab2-c2 = itab1-c5.
modify itab2 transporting c2 index 5.
itab2-c2 = itab1-c6.
modify itab2 transporting c2 index 6.
when 3.
   itab2-c3 = itab1-c1.
modify itab2 transporting c3 index 1.
when 4.
   itab2-c4 = itab1-c1.
modify itab2 transporting c4 index 1.
Endloop.
Finally you will get 6 rows with 4 coulmns.

Converting columns into rows

Dear all....I need to convert all columns into rows in a table. For example table has following columns:
Emp_Cod........Val1......Val2......Val3
1 a b c
Now I wish that each column should display as a value like:
Emp_Cod........Val1
1 a
1 b
1 c
Now the one way to solve this job is to write a union statement for each column but for this I'll have to write equal number of select statements as there are columns.
What I need that is there anyway to write minimum code for this job, is there any alternate way???

SQL> with t as(select 1 emp_code, 'a' val1, 'b' val2, 'c' val3 from dual)
2 select*from t unpivot(v for c in(val1,val2,val3));
EMP_CODE C     V
        1 VAL1 a
        1 VAL2 b
        1 VAL3 c
SQL> col COLUMN_VALUE for a20
SQL> with t as(select 1 emp_code, 'a' val1, 'b' val2, 'c' val3 from dual)
2 select*from t,table(sys.odcivarchar2list(val1,val2,val3));
EMP_CODE V V V COLUMN_VALUE
        1 a b c a
        1 a b c b
        1 a b c c

Converting Column to Rows

Hello,
I am trying to build and SQL to convert columns from multiple rows to the all rows - see below test data and result expected:
CREATE TABLE XX_TEST(NAME VARCHAR2(10),A1 VARCHAR2(10),A2 VARCHAR2(10), A3 VARCHAR2(10),A4 VARCHAR2(10),A5 VARCHAR2(10));
INSERT INTO XX_TEST VALUES('LIST','A','B','C','D','E');
INSERT INTO XX_TEST VALUES('L1','1',NULL,'3',NULL,NULL);
INSERT INTO XX_TEST VALUES('L2','1','5','4',NULL,NULL);
COMMIT
SELECT * FROM XX_TEST;
Result expected:
NAME is Column from table XX_TEST but COLUMN and VALUE are the columns converted to rows-
NAME COLUMN VALUE
L1 A1 1
L1 A2 NULL
L1 A3 3
L1 A4 NULL
L1 A5 NULL
L2 A1 1
L2 A2 5
L2 A3 4
L2 A4 NULL
L2 A5 NULL
Thanks
BS

Hi,
Thanks for posting the sample data in such a useful form!
Whenever you post a question, you should always say what version of Oracle you're using, too.
Displaying multiple columns from one row as one column on multiple rows is called Unpivoting .
In Oracle 11, you can use the SELECT ... UNPIVOT feature to do that.
In any version of Oracle, you can cross-join your table to a Counter that has as many rows as your original table has columns to be unpivoted.
In this problem, we need a self-join of the unpivoted data, to join the rows with name='LIST' to every other row.
WITH     cntr     AS
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 5
,     unpivoted_xx_test     AS
     SELECT     x.name
     ,     'A' || c.n     AS col
     ,     CASE c.n
               WHEN 1     THEN x.a1
               WHEN 2     THEN x.a2
               WHEN 3     THEN x.a3
               WHEN 4     THEN x.a4
               WHEN 5     THEN x.a5
          END          AS val
     FROM          cntr     c
     CROSS JOIN     xx_test     x
SELECT       u.name
,       u.col
,       l.val          AS val1
,       u.val          AS val2
FROM       unpivoted_xx_test     l
JOIN       unpivoted_xx_test     u ON     l.col     = u.col
WHERE       l.name     = 'LIST'
AND       u.name     != 'LIST'
ORDER BY name
,       col
;Output:
NAME       COL VAL1       VAL2
L1         A1 A          1
L1         A2 B
L1         A3 C          3
L1         A4 D
L1         A5 E
L2         A1 A          1
L2         A2 B          5
L2         A3 C          4
L2         A4 D
L2         A5 EThe query above uses some features that were new in Oracle 9, but the basic strategy will work in earlier versions.
If your columns don't have such regular names (A1, A2, A3, ...) then you can use another CASE expression to derive unpivoted_xx_test.col.

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