How to convert Epoch time to Datetime (YYYYMMDDHH24MMSS)

Hi,
In our Oracle db, Datetime is stored as Epoch time (seconds since january 1st 1970). To get a readable date, I have converted those fields as followed:
TO_CHAR(TO_DATE('19700101000000', 'YYYYMMDDHH24MISS')+((DATE_FIELDS-18000) /(60*60*24)),'YYYYMMDDHH24MISS')
Result ex: 20100830135422
The problem is that the resulting fields are in VARCHAR2 instead of DATE so it causes issues in SAP BW reporting development. BW developpers can manage something to make it eventually work but I would like to correct this at the source if it is possible.
I have already tried to add another "TO_DATE" function at the beginning of the previous expression but I get a date in "DD-MMM-YY" format as a result even if I have forced another date format.
Any idea on how I could solve this?
Thanks a lot
Pascale

Ok, there is clearly a disconnect here.
Oracle stores dates in a DATE datatype. This means that, internally, it will store enough information for a 4 digit year, a month, date, hour in 24 hour time, minute, and second. All that information is stored in the DATE datatype inside the database, but, it's stored in an internal format, that has nothing to do with what it will look like when you print it. When you want to retrieve it, Oracle must have a date format string, so that it knows how to display that information. If you do not provide a date format string via the TO_CHAR() function, Oracle has a parameter called NLS_DATE_FORMAT that provides the default format to use. If you have not set the NLS_DATE_FORMAT, it defaults to DD-MON-YY.
So, having said all that, what are you actually trying to do?
You started with this expression:
TO_CHAR(TO_DATE('19700101000000', 'YYYYMMDDHH24MISS')+((DATE_FIELDS-18000) /(60*60*24)),'YYYYMMDDHH24MISS')How is that expression used? In a SELECT statement? Then you probably want it the way it's written above. In an INSERT statement? If so, then if the datatype of the column you're inserting into is DATE, then you probably need to eliminate that outer TO_CHAR conversion, so that the expression returns a date that can be inserted into DATE column.
Tell us more about what you want to do, and perhaps we can offer further help.
-Mark

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Hello,
I wan't to question how to convert epoch time to datetime in sql*loader Oracle. I try this script for convert epoch time to datetime in sql*loader, but error:
Record 1: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 2: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 3: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
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LOAD DATA INFILE 'C:\Documents and Settings\Administrator\My Documents\XL_EXTRACT_211\load.csv'
into table TEMP_TEST_LANGY append
FIELDS TERMINATED BY ','
TRAILING NULLCOLS
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79314313.7066667
79314336.2933333
79314214.3466667
This is my table:
CREATE TABLE TEMP_TEST_LANGY
DATADATA DATE
Thanks
Edited by: xoops on Sep 21, 2011 8:56 AM
Edited by: xoops on Sep 21, 2011 8:58 AM

thanks for your answer, but I asked to use sql loader instead of the external table, which so my question is why can not the epochtime converted to datetime, if there is no way to convert a datetime epochtime using sql loader, so I'm required to use the external table. thank you.
This is my error log:
Column Name Position Len Term Encl Datatype
DATADATA FIRST * , CHARACTER
SQL string for column : "TO_DATE('1-Jan-1970 00:00:00','dd-MM-YYYY hh24:mi:ss') + (:DATADATA/60/60/24)"
Record 1: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 2: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 3: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
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How to convert epoch time stamp to timestamp.

Hi,
I need a help regarding how to convert the epoch Time stamp, to oracle date and time format.
for example,
for epoch time stamp:1204104116656
the time stamp should be :2008-02-13 12:43:00.351
Please help me on the same

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thanks for your answer, but I asked to use sql loader instead of the external table, which so my question is why can not the epochtime converted to datetime, if there is no way to convert a datetime epochtime using sql loader, so I'm required to use the external table. thank you.
This is my error log:
Column Name Position Len Term Encl Datatype
DATADATA FIRST * , CHARACTER
SQL string for column : "TO_DATE('1-Jan-1970 00:00:00','dd-MM-YYYY hh24:mi:ss') + (:DATADATA/60/60/24)"
Record 1: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 2: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Record 3: Rejected - Error on table TEMP_TEST_LANGY, column DATADATA.
ORA-01722: invalid number
Edited by: xoops on Sep 21, 2011 12:33 PM

Converting EPOCH time stamp to time stamp in Oracle

Hi,
I need a help regarding how to convert the epoch Time stamp, to oracle date and time format.
for example,
for epoch time stamp:1204104116656
the time stamp should be :2008-02-13 12:43:00.351
Thanks in Advance
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Convert Epoch Date Time to Date Time format

I am trying to convert Epoch Date time in GMT to Human Readable Date time format in UTC. I used the one below but it returns just the date in GMT but how can get datetime in UTC ?
select To_Char( To_Date( '01.01.1970 06:00:00','DD.MM.YYYY HH24:Mi:Ss') + STARTIME / 86400,'DD.MM.YYYY HH24:Mi:ss') FROM HQ_AVAIL_DATA_RLE;
I refered a couple of forums and applied everything, but still I wouldn't get the timestamp.
Please note that i'm looking for datetime stamp, not just the date.
Thanks in advance!
Edited by: 830754 on Jan 27, 2011 11:18 AM
Edited by: 830754 on Jan 27, 2011 11:19 AM

Works for me. I see date and time (submitted 1000 for STARTTIME):
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01.01.1970 06:16:40Or do you mean something else?

How to convert Epoch time to Datetime (YYYYMMDDHH24MMSS)

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