How to create a destination URI in result query
Hello All,
I have a requirement where on home page when user search for a particular criteria then result should have a link to show the details for that particular item. In result region there are two types of Items Internal and External. Now, this result region is showing details from the master table. Now, I need to add a link on this Item number in a way that when ever user clicks on that link related information of that item should dispaly. For Internal and External we have seprate tables for details. So, I need a dynamic link which can show the details accordingly.
Kindly help on this.
Thanks,
Sandy
Sandy ,
You can approach this way ,
Create an additional item in the table region as "link" , give the destination property for it , get the unique row of
the column ( primary key column of the view object ) .
Your value of the destination property should be like eg : OA.jsp?page=/<yourname>/oracle/apps/ak/employee/webui/EmpDetailsPG&employeeNumber={@EmployeeId}&employeeName={@EmployeeName}&retainAM=Y&addBreadCrumb=Y
Please refer drill down to details exercise in Jdevdoc , you will understand better .
Let me know if its not clear .
Keerthi
Edited by: keerthioaf on Dec 26, 2012 3:38 AM
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