How to create a Pivot table without aggregate function

Question

Dear team
I have the following table. Follow the link to download SQL Script to create table
https://drive.google.com/file/d/0B5nQIsvTifixV2Jkb043bVd2Zlk/view?usp=sharing
I want to create a pivot or cross tab so that it appear like this
LocationDesc
>=360
>=300
>=270
>=240
<240
Port Moresby
John Aita
Mawe Felix
Augustine Eri Luke
Joseph Aura
Robert  ROAKEINA
Port Moresby
Ambane Gigmai
Paul Dem
Henry  Wanpis
Tiniki Bau
William Laki NIGINTS
Port Moresby
June Vutnamur
Alphonse Waieng
Rex TOMARA
Mika OROMOIA
Eveni Ekeni
Mount Hagen
Dominic Kouroi
Senis Ospea
JOSEPH KLAWA
Peter WAI
PHILIP JAMES
Lae 
Henry TIAS
Mathew Dominic
Jobert Idigel
Wagi Jerry
Christopher Bianta
etc
etc
etc
etc
etc
etc
Marsh Narewec

Answer 1

Hi Marsh,
To achieve your requirement, you may reference the below query.
--pivot the table to get the expected output
;WITH cte AS(
SELECT *,ROW_NUMBER() OVER(PARTITION BY LocationDesc,BandGroup ORDER BY BandGroup) AS rn FROM [TmpBandGroup]
SELECT LocationDesc,[>=360],[>=300],[>=270],[>=240],[<240]
FROM cte
PIVOT
(MAX(EmployeeName) FOR BandGroup IN([>=360],[>=300],[>=270],[>=240],[<240])) PVT
ORDER BY LOCATIONDESC
--the pivot result can be validated with the queries below
;WITH cte AS(
SELECT *,ROW_NUMBER() OVER(PARTITION BY LocationDesc,BandGroup ORDER BY BandGroup) AS rn FROM [TmpBandGroup]
,cte2 AS
SELECT RN, LocationDesc,[>=360],[>=300],[>=270],[>=240],[<240]
FROM cte
PIVOT
(MAX(EmployeeName) FOR BandGroup IN([>=360],[>=300],[>=270],[>=240],[<240])) PVT
SELECT LocationDesc, COUNT([>=360]) [>=360] ,COUNT([>=300]) [>=300],COUNT([>=270]) [>=270],COUNT([>=240]) [>=240],COUNT([<240]) [<240]
FROM cte2
group by LocationDesc
ORDER BY LocationDesc
SELECT LocationDesc,bandgroup,COUNT(EmployeeName) FROM [TmpBandGroup] group by LocationDesc ,bandgroup
ORDER BY LocationDesc,bandgroup DESC
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