How to create a relationship between documents

Can you create a relationship between documents so in case the user requests one file he will also be prompted to download the other related file as well automatically

Thanks for Your answer, but main problem is what relation type use to create link between 2 common objects.
Your solution (use class CL_BINARY_RELATION) returns the same error message, because this class is used in FM BINARY_RELATION_CREATE.
In the end I found that solution is to use as relationtype (ORBRELTYP-RELTYPE = 'ASGN').
    CALL FUNCTION 'BINARY_RELATION_CREATE'
      EXPORTING
        obj_rolea      = obj_a
        obj_roleb      = obj_b
        relationtype   = 'ASGN'
      EXCEPTIONS
        no_model       = 1
        internal_error = 2
        unknown        = 3
        OTHERS         = 4.
It seems to work and on both objects (A and B) I can see link (relation).
Best regards,
MD

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How to create the relationship between ESSBASE 11 and DM in OBIEE11

Hi Experts,
I have one requirement that there is one property table named 'Store Master' in DW,and it contains a lot of attribute, such as Open Date, Close Date, IS 24 Hour etc.
But another data source is essbase and based on this source, I create all reports.
In ESSBASE, it has one dimension and hierarchy Location, and it has four level, Country(L1),Region (L2),Province(L3),Store(L4)
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I try to create one relationship in physical layer between Gen4,Location and Store, then drag the open date and close date into Location Dimension in BMM,then Presentation Layer.
When I drag column 'Open Date' ,'Gen4,Location ' and 'Sales' into reports, it will generate the following error message:
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However, when I remove the column 'Open Date'. it will be ok.
So what I missing the steps? Please help me. Thanks.

>
'2. Now, pull the 'Store' column from relational DB onto the Gen5, Location column from Essbase. This action now creates, two logical sources for your 'Store' column.'
If the length from different data source is not same,such as 1001(DM),L_1001(ESSBASE), can I drag the 'Store' column from relational DB onto the Gen5, Location column from Essbase?
I think it does not work.Right?Hi,
I am not sure if you are talking about the length(as in varchar(128)) of the member value being different in different sources, or the member itself is different in both the sources.
I am still assuming, that you are referring to the members not same in both the sources.If it is, the whole concept of federation is based on conforming dimensions. So, it needs that the same dimension information is present in both the sources and then only, you know we can analyze the numbers based on this dimension. So, either the dimension being different in both sources, or the members not present in both the dimensions might lead to incorrect numbers.
So I select Store Attributes in relation DB and Location in ESSBASE in physical layer, then create the physical join, such as right("Hour Sales"."H_Sales".""."H_Sales"."Gen6,Location",4) = "Authorization".""."EDW"."T_EDW_MDM_STORE"."US_CODE", then drag the OPEN_DATE and CLOSE_DATE in relation DB to Location in ESSBASE in BMM,finially drag them into presentation layer.We create physical layer relationships, to send over the same relation to the underlying database during querying. So, creating a physical relationship between essbase cube and relation database would not help here.
When you set up this federation, BI Server sends individual queries to each source and maps the conforming dimension members internally.
Hope I was clear, and this helps.
Thank you,
Dhar

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Hi Experts,
I have one requirement that there is one property table named 'Store Master' in DW,and it contains a lot of attribute, such as Open Date, Close Date, IS 24 Hour etc.
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So I want to know how to create the relationship between Location (ESSBASE) and Store Master (DM).
I try to create one relationship in physical layer between Gen4,Location and Store, then drag the open date and close date into Location Dimension in BMM,then Presentation Layer.
When I drag column 'Open Date' ,'Gen4,Location ' and 'Sales' into reports, it will generate the following error message:
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However, when I remove the column 'Open Date'. it will be ok
So what I missing the steps? Please help me. Thanks.

>
'2. Now, pull the 'Store' column from relational DB onto the Gen5, Location column from Essbase. This action now creates, two logical sources for your 'Store' column.'
If the length from different data source is not same,such as 1001(DM),L_1001(ESSBASE), can I drag the 'Store' column from relational DB onto the Gen5, Location column from Essbase?
I think it does not work.Right?Hi,
I am not sure if you are talking about the length(as in varchar(128)) of the member value being different in different sources, or the member itself is different in both the sources.
I am still assuming, that you are referring to the members not same in both the sources.If it is, the whole concept of federation is based on conforming dimensions. So, it needs that the same dimension information is present in both the sources and then only, you know we can analyze the numbers based on this dimension. So, either the dimension being different in both sources, or the members not present in both the dimensions might lead to incorrect numbers.
So I select Store Attributes in relation DB and Location in ESSBASE in physical layer, then create the physical join, such as right("Hour Sales"."H_Sales".""."H_Sales"."Gen6,Location",4) = "Authorization".""."EDW"."T_EDW_MDM_STORE"."US_CODE", then drag the OPEN_DATE and CLOSE_DATE in relation DB to Location in ESSBASE in BMM,finially drag them into presentation layer.We create physical layer relationships, to send over the same relation to the underlying database during querying. So, creating a physical relationship between essbase cube and relation database would not help here.
When you set up this federation, BI Server sends individual queries to each source and maps the conforming dimension members internally.
Hope I was clear, and this helps.
Thank you,
Dhar

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Thanks for Your answer, but main problem is what relation type use to create link between 2 common objects.
Your solution (use class CL_BINARY_RELATION) returns the same error message, because this class is used in FM BINARY_RELATION_CREATE.
In the end I found that solution is to use as relationtype (ORBRELTYP-RELTYPE = 'ASGN').
    CALL FUNCTION 'BINARY_RELATION_CREATE'
      EXPORTING
        obj_rolea      = obj_a
        obj_roleb      = obj_b
        relationtype   = 'ASGN'
      EXCEPTIONS
        no_model       = 1
        internal_error = 2
        unknown        = 3
        OTHERS         = 4.
It seems to work and on both objects (A and B) I can see link (relation).
Best regards,
MD

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Or
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http://answers.microsoft.com/en-us/office/forum/office_2010-visio/how-to-create-a-relationship-diagram-by-using/2999bd63-1869-42d5-8292-74f8a777c7e0
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hi
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How to create a relationship between documents

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