How to create a socket to send to URI?

Question

I have apache-axis2 accepting a WSDL on some uri <ipaddres:8080/my/service/uri>. I'm trying to have a Java program send a soap message to that URI. When I use the uri <ipaddress:8080> I can create a socket using
new Socket( (InetAddress.getByName(ipaddress), port);But if I do something like
String uri = "/my/service/uri";
new Socket( (InetAddress.getByName(ipaddress+uri), port);I'll get an UnkownHostException. So how would I create a socket that can send to a given uri?

Answer 1

I ended up trying to create an OutputStream from doing an http connection to the uri. I've tried
OutputStream os = null;
URL url = null;
URLConnection conn = null;
url = new URL("http://"+ipaddress+":"+port+path);
conn = url.openConnection();
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setAllowUserInteraction(true);
conn.setUseCaches(false);
conn.connect();
os = conn.getOutputStream();to write I use
void send(byte[] b)
os.write(b);
os.flush();
}The problem is, when I write to the outputstream, according to Wireshark, nothing gets sent across the wire.
System.out.println("output stream ="+os+"."); gives me
"output stream = ."
which is very odd. I'd expect "output stream = null" or "output stream = <some object handle>." What could be preventing me from getting the output stream?