How to display/navigate to specific record in a table with more then thousand records

Question

Hi,
there is a task that I do not know how can be resolved.
There is a query that returns around 1 - 2 thousand records. And all those records have corresponding weight assigned.
After query executing it is necessary to navigate to the records with the highest weight assigned. It can be first record, it can be a record at the end or in the middle of the row set from thousand records.
I have used "DisplayRow"=selected or the code below, but it does not work properly ... when the record that we navigate is in the middle of record set from 2000 records, then users have to scroll down to it.
And I need to position to that specific record after query is executed.
So I used the code below:
public void onButtonClicked(ActionEvent actionEvent) {
DCBindingContainer bc = (DCBindingContainer)BindingContext.getCurrent().getCurrentBindingsEntry();
DCIteratorBinding iterator = bc.findIteratorBinding("ViewVIIterator");
        Row row = iterator.getCurrentRow();
        String bestPosition = (String)row.getAttribute("BestPosition");
        iterator = bc.findIteratorBinding("DetaillVIIterator");
        ViewObject vo = iterator.getViewObject();
        vo.setWhereClause(some_conditions);
        vo.executeQuery();
        RowSetIterator rowSet = iterator.getRowSetIterator();
        Key key = null;
        while (rowSet.hasNext()) {
            row = rowSet.next();
            if (row != null && ((String)row.getAttribute("weight")).equals(bestPosition)) {
                key = row.getKey();
                Key rowKey = row.getKey();
                ArrayList tableRowKey = new ArrayList();
                tableRowKey.add(rowKey);
                this.getRangeTable().setScrollTopRowKey(tableRowKey);
                break;
After the code above I getting the row selected or set as a current, but in case of 2000 records, when my record is in the middle of this record set, I need to scroll down to this record to see it.
And I wanted that I will be navigated to my record with records above and below.
What am I doing wrong above?
Thanks
Alexander

Answer 1

Hi Timo!
thanks for the reply.
version info:
Oracle JDeveloper 11g Release 2 11.1.2.3.0
Studio Edition Version 11.1.2.3.0
Build JDEVADF_11.1.2.3.0_GENERIC_120914.0223.6276.1
IDE Version: 11.1.2.3.39.62.76.1
Product Version: 11.1.2.3.39.62.76.1
1. sorting order is already applied and we to position to a specific record in af:table.
From another side the task can rephrased: I need to position to a specific record and I need to be able to show 500 records before and 500 records after.
So where clause can be like:
:bestPosition > position - 500 and :bestPosition < position +500.
2. I tried to apply your second approach and found that record is selected, but I need to scroll to it down. It happens when first 20 records are displayed in af:table and my record is 480 records below ...
Alexander